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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 81151. |
The length of the side of a grassy square plot is 80 m. Two walking paths each 4 m wideare constructed parallel to the sides of the plot such that they cut each other at the centofthe plot. Determine the area of the paths. |
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Answer» Length of one path=80mbreadth=4m so,area of one path =80X4 area reqired= 2[80X4] - {4X4} = 640 -16 =624m^2 |
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| 81152. |
length of the side of a grassy square plot is 80 m. Two walking Daofthe plot. Determine the area of the paths.paths each4 m widllel to the sides of the plot such that they cut each other at the cemrthe sid |
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Answer» Length of one path=80mbreadth=4m so,area of one path =80X4 area required= 2[80X4] - {4X4} = 640 -16 =624 |
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| 81153. |
a basket contains 3 apples and 5 chocolates. The number of ways a child can pick 2 apples and 3 chocolates is |
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Answer» Number of ways to pick 2 apples from 3=3C2=3No of ways to pick 3 chocolates from 5=5C3=10total ways to pick 2 apples and 5 chocolates are 13. |
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| 81154. |
sible values of aDer such thatof aSol. ItaSol Commutative proultiple Choice Questions (Mental Ability)) the correct answer in each of the following:In a school of 6,422 students, ratio of girls to6. 1+6is equboys 5: 8,5th of the girls and th of the boystook part in a school camp. Fraction of the totalstrength took part in the camp isexceeds its 2,Yb)c)(a(a1"Y 44.The missing rational number in the series given7. In the given nurational numbоАthe students are girls.a)40the number of girls :8. Rational nur1+1three types of fruits se1+1(a) 48kg of these are orange9. Which ofgreatest?- 10 - 19the rest are melonshasket'9.3mr-nt |
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Answer» Xi Convert in Hindu Arabic number |
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| 81155. |
A basket contains 350 eggs. If,12% of the eggs are rotten then how many eggs are goodenough to be sold.6, |
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Answer» Total eggs = 350Percentage of eggs rotten = 12%Number of eggs rotten= percentage/100*totalNumber of eggs rotten = 12/100*350= 42eggsEggs good enough to sold= total eggs - rotten eggs= 350-42= 308So, 308 eggs are good enough to sold. |
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| 81156. |
1. Write the next three natural numbers after 10999.whole numbers occurring inst hef |
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Answer» Next three natural numbers after 10999 are 11000, 11001, 11002 next three natural number 11000 11001 11002 |
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| 81157. |
(1)Set of even natural numbers |
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Answer» (2,4,6,8,10,.......) (2,4,6,8,10,12,14,16,......) 2,4,6,8,10,12,14,......... 2,4,6,8,10….........,........... 2,4,6,8,10,12,14 This is right answer in increasing order like 2,4,6,8,10....... etc can divide it from to so they are called even number 1,2,3,4,5,6,7,8,9,10.......... divided from 2 you can find even number |
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| 81158. |
(i)Set of even natural numbers |
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Answer» all numbers which come in table of two or divided by 2 All the counting number which is divisible of 2 is know as even natural number. Al numbers which is divisible by 2 is even natural number set 9f even natural no. E =2,4,6,8...... |
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| 81159. |
1) The sum of the squares of two consecutiveeven natural numbers is 100. Find thenumbers |
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Answer» Let the two consecutive even natural numbers be x and x +2. As per the given condition. x2+ (x + 2)2= 100 ∴x2+ x2+ 4x + 4 = 100 ∴ 2x2+ 4x + 4 – 100 = 0 ∴ 2x2+ 4x – 96 = 0 Dividing by 2 we get, x2+ 2x – 48 = 0 ∴ x2– 6x + 8x – 48 = 0 ∴ x (x – 6) + 8 (x – 6) = 0 ∴ (x – 6) (x + 8) = 0 ∴ x – 6 = 0 or x + 8 = 0 ∴ x = 6 or x = – 8 x is an natural number ∴ x cannot be – 8 ∴ x = 6 And x + 2 = 6 + 2 = 8 |
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| 81160. |
12. Thesum of squares of two consecutive naturalnumbers is 421. Find the numbers. |
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Answer» Let the two consecutive natural numbers be x and (x + 1) Given x2+ (x + 1)2= 421x2+ x2+ 2x + 1 – 421 = 02x2+ 2x – 420 = 0x2+ x – 210 = 0x2+ 15x – 14x – 210 = 0(x + 15)(x – 14) = 0Hence x = -15 or 14Since x is a natural numberThus x = 14x + 1 = 15Therefore the two consecutive numbers are 14 and 15. |
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| 81161. |
Find the mean of first 10 even natural numbers. |
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| 81162. |
If the sum of the reciprocals of two consecutive natural numbers is 23, find th132'numbers |
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| 81163. |
Solve for $ x : \frac{1}{(a+b+x)}=\frac{1}{a}+\frac{1}{b}+\frac{1}{x},[a \neq 0, b \neq 0, x \neq 0, x \neq-(a+b)] $ |
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| 81164. |
4. Divide 3000 into two parts such that the simple interestper annum is equal to the simple interest on the second par|lent at 9% per annum and the other atthe first pait for 2 years at 9% per annum.12. |
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| 81165. |
EXERCISE 6A. Addthe following expressions:3 2 45 353y +4z. y-2x-82, 5x-2y-3z-3x2- 4)5x-22x2 -8, 8x27x -9, 3+7x2 -2x4 3 35 5 4 2 32 468 11 95 743 5 92 352 4 3 4 5tract:8xy from 7xy(ii) x2 from(iv) (a2 +b2c-y) from (Au-5x),2-y) from (2x -3y +6xy)act (2a -3b + 4c) from the sum of (a +3b - 4act the sum of (8m -7n +6p2) and (-3m - 4m-n-p)(vi) (x-y + 3 |
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Answer» Crop only the question that you want a solution for. We will not be able to provide solutions to multiple question |
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| 81166. |
8.+1 x-12x-12x +1)+(x+3) = 5x + 4(x-1)+b(x-1)=c(x-1)-d(x, |
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Answer» (2x+1)+(x+3)= 5x+4=> (2x+x)+(1+3) = 5x+4=> 3x+4 = 5x+4=> 5x-3x = 0=> 2x=0=> x= 0 |
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| 81167. |
(3) Two circles touch each other externally. Their diameters are 8 cm and 6 cmrespectively. Find the distance between their centres. |
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| 81168. |
OA = 7 cm, find the area of the shadedo. The area of an equilateral triangle ABC is 17320.5cm2. With each vertex of the triangle as centre, acircle is drawn with radius equal to halfthe lengthofthe side of the triangle (see Fig. 12.28). Find thearea of the shaded region. (Use p 3.14 and1.73205) |
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| 81169. |
EXERCISE 2.3In tI./Divide the polynomial p(x) by the polynomial g(x) and find the quotient and rin each of the following:(i) p(x)=x3-3x2 + 5x-3,) p(x) =x4-3x2 + 4x + 5,İİİ) p(x) = x4-5x + 6,g(x)-x2-2g(x) =x2 + 1-xg) 2-r |
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Answer» c)remainder is -5x+10 a) remainder is 7x-9 |
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| 81170. |
id basket contains there types of fruitsweguning, 191 Ig in all. If s4 kgof these be Babbles, at leg be brangeswhat is the weightand the rest bearsofthepears in the 3 astet? |
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| 81171. |
hasket contains three types of fruits weighing 19. kg in all. 18 kg of these beleke be oranges and the rest pears, what is the weight of the pears in the bar |
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| 81172. |
2.14 The digits of a two digit number differ by 3. If the digits are interchanged and the resultingnumber is added to the original number, we get 143. What can be the original number? |
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Answer» Let the unit digit be x Tens digit =>x+3 10(x+3)+x digits interchanged=10x+x+3 10(x+3)+x+10x+x+3=143=>10x+30+12x+3=143 =>22x+33=143 22x=143−33 22x=110 x=110/22 x=5 Original number = 85. |
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| 81173. |
of whole numbers or multiplicative identity forwhole numbers.EXERCISE 2.21. Find the sum by suitable rearrangement:(a) 837 + 208 + 363 (b) 1962 + 453 + 1538 + 64714. nthuranitobla reronce |
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| 81174. |
8. The two digits of a two-digit number differ by5. If the digits are reversed, the sum of the twonumbers is 99. Find the numbers. |
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| 81175. |
12.The digits of a two-digit number differ by 3. if the digits are interchanged, and the resultingnumber is added to the original number, the sum is 143. Find the original number(4) |
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Answer» Let us assume, the x is the tenth place digit and y is the unit place digit of the two-digit number. Also assume x > y Therefore, the two-digit number is 10x + y and reversed number is 10y + xGiven: x - y = 3 ---------------1 Also given: 10x + y + 10y + x = 14311x + 11y = 143x + y = 13 ---------------2 Adding equation 1 and equation 2 2x = 16x = 8 Therefore, y = x - 3 = 8 - 3 = 5 Therefore, the two-digit number = 10x + y = 10 * 8 + 5 = 85 |
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| 81176. |
4.The mean of first 'n' natural numbers is x. What is the mean of first 'n' even naturalnumbers |
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Answer» Mean of 1st n even no. =n(n+1)/2 |
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| 81177. |
The ratio of income to expenditure of a family is 7: 6. Find the savき14000. |
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| 81178. |
1. The product of two consecutive natural numbersis 42. Find the numbers. |
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Answer» let the numbers be n and n+1,n×(n+1)=42=>n(n+1)=6×7=>n(n+1)= 6(6+1)=> n=6so, the required numbers are 6 and 7 let the first no be xand the second consecutive no be ( x + 1 )according to condition of problem x ( x + 1) = 42x² + x - 42 = 0 -42 /\ -6 7( x - 6 )(x + 7 ) = 0Therefore x = 6 or x = -7but x = -7 is not possible therefore x = 6 the No's are 6 and 7 |
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| 81179. |
year and 16% for the second year.Find the compound interest on 14000 at 16% per annum for |
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| 81180. |
(0 Find the remainder (without division) when 23 3x2 +7x 8 is divided by(2000)diig 3x2 5x 9 by (3x 2).5x 9 by (3x |
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Answer» If you like the solution, Please give it a 👍 |
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| 81181. |
“0x+1 X o X4 |
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| 81182. |
5) X4 X +x +1X b =} x-1 |
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Answer» please like my answer if you find it useful thnku |
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| 81183. |
The radii of two circles are 8 cm and 6 cm respectively. Findthe radius of the circle having area equal to the sunf of theareas of the two circles. |
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| 81184. |
2. The radii of two circles are 8 cm and 6 cm respectively. Findthe radius ofthe circle having area equal to the sum of theareas of the two circles. |
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Answer» thnx .. |
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| 81185. |
3. A basket contains three types of fruits weighing 19 kg in all. If 8 kg of these be apples,3-kg be oranges and the rest pears, what is the weight of the pears in the basket? |
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Answer» 8whole 1by 18 is correct answer |
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| 81186. |
brass utensil weighing yong4". Find threc conescutive whole numbers whose sum is more than 14 budiait at the ten's place is twice the digit ainthan 54,TnSinthe digits is added to he |
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| 81187. |
The digits of a two-digit number differ by 3.If the digits are interchanged and thenew number is added to the originalnumber, we get 165. What is the originalnumber? |
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Answer» x-y=3 is a first equation...x+10y= 165 is a correct answer.... |
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| 81188. |
8 The digits of a two digit number differ by 7. If the digits are interchanged and theresulting number is added to the original number we get 121. Find the originalnumber. |
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Answer» let the two digit number be 10a+ba - b=7..........(1)10a+b+10b+a=12111a+11b=121a+b=11.........(2)(1)+(2)2a=18; a=9then b=2then the number is 92 divide 32÷20983443563 |
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| 81189. |
The digits of a two-digit number differ by 3. If thedigits are interchanged, and the resulting number isadded to the original number we get 143. What canbe the original number? |
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Answer» Let us assume, the x is the tenth place digit and y is the unit place digit of the two-digit number. Also assume x > y Therefore, the two-digit number is 10x + y and reversed number is 10y + xGiven: x - y = 3 ---------------1 Also given: 10x + y + 10y + x = 14311x + 11y = 143x + y = 13 ---------------2 Adding equation 1 and equation 2 2x = 16x = 8 Therefore, y = x - 3 = 8 - 3 = 5 Therefore, the two-digit number = 10x + y = 10 * 8 + 5 = 85 |
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| 81190. |
Natural Numbers: The numbers used for counting are called natural numbersThus, 1. 2. 3. 4. 5.........etc. are all natural numbers.sallad hela min |
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Answer» 6,7,8,9,and so on is the answer of this question 6,7,8,9,and so on is the answer of this question |
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| 81191. |
cutive natural numbers whose yuaa two consecutive natural numbers whose seve natural numbers whose square have the sum 313.35. The ... |
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| 81192. |
18.00 for 2years at 10% per annum compounded annually. |
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| 81193. |
(i) 18000 for 2 years at 10% pa. compounded annually. |
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| 81194. |
pler(i)(ii)(iii)p(x) =x3-3x2 + 5x-3,p(r) =xa_ 3x2 + 4x + 5,p(x) = x4-5x + 6,g(x) =x2-2g(x) = r + 1-xg(x) = 2-r38 |
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| 81195. |
\lim _ { x \rightarrow a } \frac { f ( x ) } { g ( x ) } = \frac { \lim _ { x \rightarrow a } f ( x ) } { \lim _ { x \rightarrow a } g ( x ) } |
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| 81196. |
NCERT प्रश्नविभाजन एल्गोरिथ्म का प्रयोग करके, निम्न में p(x) को g(४) से भाग देने पर भागफल तथा शेषफरकीजिए(i) par) = ४ - 3x + 5-3,g(x) = 2-2(ii) p(x) = r - 3x +4x + 5,g(x) = x +1-४(iii) p(x) = x - 5x +6,g(x) =2-2 | |
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Answer» second number correct hai second number correct answer I) is the correct answer I) is the right answer of the following i) is the correct answer |
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| 81197. |
504 cones, each of diameter 3.5 cm and height 3 cm, are melted and recast into ametallic sphere, Find the diameter of the sphere and hence find its surface area.[Use Ď -]7 |
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| 81198. |
G) p(x)x-3x2+5r-3, g() -2(ii) p(x)=x4-3x2 + 4x+ 5, g =1+1-x(iii) p(x) =x4-5x + 6, , g(x) = 2-F |
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| 81199. |
Q. 6. Metallic spheres of radäa iom 8m and licn respectivey are mehet omsingle solid sphere. Find the radius of resuling sphere.3 |
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Answer» Let r1, r2 ,r3 be the radius of the given 3 spheres & R be the radius of a single solid sphere. Given : r1= 6cm, r2= 8cm, r3= 10 cm Volume of first metallic sphere (V1)= 4/3π(r1)³ = 4/3 π (6)³ Volume of second metallic sphere (V2)= 4/3π(r2)³ = 4/3 π (8)³ Volume of third metallic sphere (V3) = 4/3π(r3)³ = 4/3 π (10)³ Volume of single solid sphere(V)= 4/3πR³ A .T.Q Volume of 3 metallic spheres= volume of single solid sphere V1+V2+V3 = V 4/3 π (6)³+ 4/3 π (8)³+4/3 π (10)³= 4/3πR³ 4/3π(6³+8³+10³) = 4/3 πR³ 216+ 512+ 1000 = R³ 1728= R³ (12×12×12) = R³ 12³= R³ R= 12 Hence, the radius of the resulting sphere = 12 cm |
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| 81200. |
Threemetallicspheresofradii6cm.,8cm.and10cm.respectivelyaremelted to form a single solid sphere. Find the radius of the resulting sphere.A solid metallic sphere of diameter 28 cm is melted and recast into a number2of smaller cones, each of diameter 45 cm and height 3 cm. Find the numberof cones so formed.2 MARKS PROBLEMS |
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Answer» Let r1, r2 ,r3 be the radius of the given 3 spheres & R be the radius of a single solid sphere. Given : r1= 6cm, r2= 8cm, r3= 10 cm Volume of first metallic sphere (V1)= 4/3π(r1)³ = 4/3 π (6)³ Volume of second metallic sphere (V2)= 4/3π(r2)³ = 4/3 π (8)³ Volume of third metallic sphere (V3) = 4/3π(r3)³ = 4/3 π (10)³ Volume of single solid sphere(V)= 4/3πR³ A .T.Q Volume of 3 metallic spheres= volume of single solid sphere V1+V2+V3 = V 4/3 π (6)³+ 4/3 π (8)³+4/3 π (10)³= 4/3πR³ 4/3π(6³+8³+10³) = 4/3 πR³ 216+ 512+ 1000 = R³ 1728= R³ (12×12×12) = R³ 12³= R³ R= 12 |
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