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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 67301. |
3m + 50Ifm: n = 2:3, then the value of smisequal to |
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| 67302. |
UseEuclid'sdivision algorithm to find the HCF of(ii)0) 135 and 225196 and 38220(iii) 867 |
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| 67303. |
Use Euclid's division algorithm to find the HCF of(0)135 and 225 (i) 196 and 38220867 and 225iii) |
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| 67304. |
पप्ड् 49-1B lu' |
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Answer» q=1/2 is the correct answer of the given question q=1/2 is the correct answer q=1/2 is a right answer 👈👍👍👏🌎✍️🇨🇮 Q=1/2 is the correct answer q=1/2 is the correct answer |
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| 67305. |
( \frac { 5 } { 8 } ) ^ { - 7 } \times ( \frac { 8 } { 5 } ) ^ { - 4 } |
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| 67306. |
[ \sqrt{\frac{225}{729}}-\sqrt{\frac{25}{144}} \div \sqrt{\frac{16}{81}} |
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| 67307. |
\sqrt{\frac{225}{729}}-\sqrt{\frac{25}{144}} \div \sqrt{\frac{16}{81}} |
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Answer» (15/27 - 5/12) ÷ 4/9 = 180-135/324 ÷ 4/9 = 45/324 * 9/4 = 45*9/324*4 = 45/36*4 = 45/144 = 5/16 |
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| 67308. |
8+X7-xTE + x! |
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Answer» By l' hospitallawwe will diffrentiate ittill its not a 0/0 formso5x^4/3x^2 5/3*x^25/3*(-2)^25/3*4= 20/3 |
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| 67309. |
m.21) A tailor stitches a curtain of length 8 m. But later he found that he had to stitch 9How much more cloth should be stitched now? |
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Answer» 9 1/7-8 3/15=64/7 - 123/15=260-861/106=33/35 |
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| 67310. |
To stitch a shirt, 2 m 15 cm cloth is needed. Out of 40 m cloth, how many shirts can bestitched and how much cloth will remain? |
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| 67311. |
\frac { 8 } { 5 } + 0 = \frac { 8 } { 5 } = 0 + \frac { 8 } { 5 } |
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Answer» 8/5 + 0 = 8/5 0 + 8/5 = 8/5 Hence, proved |
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| 67312. |
9. In the adjacent figure 5.44, DABCD is atrapezium. AB | DC. Points M and N aremidpoints of diagonal AC and DBrespectively then prove that MN AB.Fig. 5.44 |
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| 67313. |
Writ the degree of the given polynomialsii) m3n 3m n + mn |
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Answer» i) degree-2ii) degree-10 |
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| 67314. |
X is a point on the side BC of AABC. XM and XN are drawn parallel to AB and ACrespectively meeting AB in N and AC in M. MN produced meets CB produced at T.Prove that TX2-TB TC |
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Answer» Here is your answer: XM || AB, XN || AC TX² = TB x TC BN || XM For ΔTXM we have BN || XM Now we will use BASIC PROPORTIONALITY THEOREM TB/TX = TN/TM --- (this is equation 1) XN || AC XN || CM In ΔTMC we have XN || CM Again we will use BASIC PROPORTIONALITY THEOREM TX/TC = TN/TM --- (this is equation 2) Now we will compare equation 1 and equation 2 TB/TX = TX/TC TX² = TB x TC (proved) |
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| 67315. |
A8C. M and N are points on the sides AB and AC nepectivelssch that BM CN IfB 2C then show that MN BC |
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Answer» AB = AC (Sides opposite to equal angle are equal)Subtracting BM from both sides, we getAB – BM = AC – BM AB – BM = AC – CN (∵BM =CN)AM =AN∴∠AMN =∠ ANM (Angles opposite to equal sides are equal) Now, in ∆ABC,∠A+ ∠B+ ∠C=1800----(1)(Angle Sum Property of triangle)Again In ∆AMN,∠A + ∠AMN + ∠ ANM =1800----(2)(Angle Sum Property of triangle)From (1) and (2), we get∠B+ ∠C= ∠ AMN + ∠ ANM 2∠B = 2∠ AMN∠B = ∠ AMN Since, ∠B and ∠ AMN are corresponding angles. ∴ MN ‖ BC |
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| 67316. |
2+5+4+8+5+8+5+5+4= |
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| 67317. |
(-8)+(-5)[] (-8)-5 |
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Answer» -8-5= -13 so -13 + (-13) = -26 |
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| 67318. |
11 α and B are different complex numbers withIME 1 , then find 11αβ |
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| 67319. |
In the question given below whichone number can be placed at the signof interrogation?841/78422519684729169 |
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Answer» 15² = 22514² = 19613² = 16913 + 14 + 15 = 42 27² = 72928² = 78429² = 84127 + 28 + 29 = 84 Herethey are following a certain analogy as15² = 22514² = 19613² = 16913 + 14 + 15 = 42so 42 will be the answer to this 27² = 72928² = 78429² = 84127 + 28 + 29 = 84 so this is in middle |
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| 67320. |
ssg= X7 |
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| 67321. |
Divide : 55\left(x^{4}-5 x^{3}-24 x^{2}\right) \text { by } 11 x(x-8) |
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Answer» 55(x*x*x*x-5x*x*x-24x*x)/11x(x-8) = 5x*x(x*x-5-24)/x(x-8) = 5x(x-8)(x+3)/(x-8) = 5x(x+3) |
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| 67322. |
Divide:15 by |
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Answer» 5/2 is the correct answer 5/2 is the correct answer of the given question. -15by-3/22by11=-15÷-3=-5and 22÷11= 2 so your answer is -5/2 -15/22 ÷ -3/11 = -15/12 × 11/-3 =-165/-36=165/36 5/2 is the correct answer |
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| 67323. |
KAMPLE 8 Two hundred students of 6th and 7th classes were asked to name theirfavourite colour so as to decide upon what should be the colour of theirschool building. The results are shown in the following table. Representthe given data on a bar graph. |
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Answer» Question you have submitted is incomplete. Please post a complete question. Question you have submitted is incomplete. Please post a complete question. |
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| 67324. |
3. A shirt can be stitched using 2-m of cloth. How many shirts can be stitched using 31m of cloth! |
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Answer» Total cloth= 63/2one shirt needs= 9/4now9/4*x = 63/2x= 63/2*4/9= 63*4/2*9= 14 teashirt |
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| 67325. |
15. Using laws of exponents (-22-3 |
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| 67326. |
rea of curved part of a cylinder is 1000 Ď square cm and its diameter is 20 cmfind the height of the given cylinder? |
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Answer» If you find this solution helpful, Please like it. |
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| 67327. |
2: Using Identity (II). find) (4p-3) |
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| 67328. |
5. In the given figure, MN II AB, BC 7.5 cm, AM4 cm and MC = 2 cm. Find the length of BN. |
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| 67329. |
Wi wएज | पा |
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| 67330. |
58 fromWI- |
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Answer» Bhai pur question to do please 1/3 is the right answer 1/3 can be written as 2/6now that you have the same denominator, just subtract the numerators. 2/6 -1/6 = 1/6 1/3 is your right answer. 1/3 is the correct answer 1/3 is the right answer. 1/3 is the answer....... 1/3 is the correct answer. the correct answer is 1/3 ....... the correct answer is1/3........ the answer is 1/3..... |
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| 67331. |
Wi(x+y): Vxy=4:1200Wx |
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| 67332. |
6. Find the length of the side of the square having area(a) 841 sg cm(b)3136 sq m(c) 676 sq cnm |
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Answer» area of square = a²where, a is the side of square (1) length of square = √841 = 29cm (2) length = √3136= 56cm (3) length = √676= 26cm |
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| 67333. |
merals as imeVxVII1of the follo |
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Answer» V=5X=10I=1VXVIII= -5+10+5+1+1+1=13 |
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| 67334. |
the cyide4. Aclosed circular cylinder has diameter 20 cm and height 30 cm. Find the total surface area of the cylinder.(n=314) |
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Answer» Total area of cylinder= 2*pi (r*h + r*r)= 2*3.14(10*30 + 10*10)= 2*3.14(300 + 100)= 2*3.14(400)= 800*3.14 = 314*8= 2512 cm^2 |
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| 67335. |
z) the hme4mĂ3mĂ2.31 m.essel is 113. Two cylindrical vessels are filled with milk. The radius of one wheight is 40 cm, and the radius of other vessel is 20 cm and height is andntain the milk5 c45 cm. Find theradius of another cylindrical vessel of height 30 cm which may just cotwo ih and 20 eminiamter Find its weight if the wood weighs |
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| 67336. |
FUN AT HOME1.Draw and colour two ball-like things. Also, name them. |
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Answer» football sun |
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| 67337. |
4111(3) AABC AB=3cm, AC=3cm BİR LAS(37) 70 (a) 65**3cm, AC=3cm sit ZA=54" 26 ZB=?(#) 55° (2) 50°TO |
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Answer» 180-50/2=130/2=65 is the best answer b) 65 65 is the correct answer. |
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| 67338. |
(xyz - 4) (xyz -2) |
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Answer» (xyz - 4) (xyz - 2) = (xyz)² - 2xyz - 4xyz + 8 = (xyz)² - 6xyz + 8 |
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| 67339. |
15 Divide 24(xyzt xyz+ xyz) by 8xyz |
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| 67340. |
6, Construct a rhombus BEND in which diagonalBN5.6 cm and DE6.5 cm. |
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| 67341. |
9. The height of a right cylinder is 16 cm and the radius of its base is 12 cm. Find the radius of thesphere whose volume is equal to the volume of the given cylinder1) 10cm2) 12cm3) 14cm4) 16 cm |
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| 67342. |
rallelogram is 300 cm IIf the base is 20 cm, ind the correspondinygThe area ol aaltiiiudeud altitude of a parallelogram are 320 cn' and 16 cm respectively, find |
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Answer» Area of parallelogram = base * height => 300 = 20* height=> height = 300/20=> height = 15cm |
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| 67343. |
'पण्ट = (4~ T 4 (IR |
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Answer» x^2 + 2ax - b^2 - 2ab = (x^2 - b^2) + (2ax - 2ab) = (x - b)(x + b) + 2a(x - b) = (x - b)(x + b + 2a) |
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| 67344. |
46. Give the complements of the follo47. Give the supplements of the follo48. Find the values of x in the follow64°49. In the figure, the transversalcShow that m n |
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Answer» It is a right angle64+x=90x=90-64x=26° |
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| 67345. |
he rallExpress cach of the folloi) a dozen to a scowiratio in itssimplest fo(ii) 85:250 |
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Answer» The ratio of the dozen of the score will be, One dozen = 12 and one score = 20. So, a dozen to score = 12 / 20 = 12: 20. Since the common factor of both the term is 4, divide both numerator and denominator by 4. (12 ÷ 4)/ (20 ÷ 4) = 3/5 = 3: 5. |
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| 67346. |
Construct the RHOMBUS "BEND"Where BN = 5.6 cm & DE = 6.5 cm |
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| 67347. |
(iii) Rhombus BENIDBN 5.6 cnmDE 6.5 cm |
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Answer» 1 2 |
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| 67348. |
A fish with a mass of 3 kg causes a fishing pole to bend 9 cm . If the amount of bending varies directly as the mass, how much will the pole bend for a 2 kg fish |
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| 67349. |
1. Evaluate the follo |
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Answer» (2/5)×(3/7) = (6/35) hit like if you find it useful |
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| 67350. |
Calculate the volume of a cylinder of height 30 cm having the radius of the base7 cm.ple:72 |
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Answer» Volume of cylinder= πr²h=(22/7)*7*7*30 cm³= 4620 cm³ |
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