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723 is the total sum of this calculation

723 is the answer of this question

723 is the sum of these numbers

723 is the right answer

Total answer of this calculation is 723

732 is the correct answer

723 is the correct answer

55555 is correct answer

{ 36 × (-56)} + { (-56) × (-46) }

=> (-56) { 36 + ( -46) }

=> (-56) { -10 }

=> 560

1). 32÷16×8+5=212). 300÷30×4+16=563). 25-7+8×3=424). 45+12×7-20=109, answer

thankyou....

negative integers: -5,-2,-49,-37,-25,-4,-12positive integers: +4,7,+26,19,+8,5,27

negative numbers;- -49, -37, -25, -12, -5, -4, -2, positive numbers: 4, 5, 7, 8, 19, 26, 27

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thx

Area of plastic sheet=length×breadtharea=300sq.cmlength=30cmbreadth=?300=30×breadthbreadth=300/30=10cm

89 65 54 32 2178 73 67 31 2244 37 21 17 799 83 78 59 55

answer (a )89 65 54 32 21(b)78, 73, 67,32,22(c)44,37,21,17,7

a) 89 65 54 32 21b) 78 73 67 31 22c) 44 37 21 17 7d) 99 83 78 59 55

-7/5 or -21/15 should be added in the given quedtion.

its wrong

its right answer

i am sorry

300 is the answer by using 1/2 × b× h

3x-2y+4=0A. (2,5)3(2)-2(5)+4=06-10+4=010-10=00=0A lies in the equation

B. (1,2)3(1)-2(2)+4=03-4+4=03+0=03 not equal to 0Thus point B does not lies in the equation

C. (4,8)3(4)-2(8)+4=012-16+4=016-16=00=0The point C lies on the equation

D. (-2,-1)3(-2)-2(-1)+4=0-6+2+4=0-6+6=00=0the point D lies on the equation

Plastic is a good insulator.

insulator that is 2nd

Total amount of sugar is 14kg 400g = 14400gmand 1 bag contains = 200g

so, no of bags required is = 14400/200 = 72 bags

since area of plastic sheet=length×breadtharea=300sq.cmlength=30cmbreadth=?300=30×breadthbreadth=300/30=10cm

n=1(3N-2)=1/2N(3N-1)3(1)-2 = 1/2 (1) (3(1)-1)3-2 = 1/2 (2)1=1

*n=k1+4+7+10...+(3k-2)=1/2k(3k-1)

*n=k+11+4+7+10+...+(3k-2)+3(k+1)-2 = 1/2(k+1)(3(k+1)-1)1/2k(3k-1)+3k+3-2=(k+1)(3k+2)/23/2k²-1/2k+3k+1=3k²+5k+2/23k²-k/2 + 3k+1=3k²+5k+2/23k²-k+6k+2/2 = 3k²+5k+2/23k²+5k+2/2 = 3k²+5k+2/2

501.949200617 is the number

Let the number be x

x × x = 251953

x² = 251953

x = √251953

x = ± 501.94

501.94 × 501.94 = 251953

and

-501.94 × -501.94 = 251953

501.94 is the correct answer of this question

(sinA+cosecA)²+(cosA+secA)²

=sin²A+cosec²A+2sinAcosecA+cos²A+sec²A+2cosAsecA

=sin²A+cos²A+cosec²A+sec²A+2sinA×1/sinA+2cosA×1/cosA

=1+cosec²A+sec²A+2+2

=5+(1+cot²A)+(1+tan²A)

=7+tan²A+cot²A

Identities used:1+tan²A=sec²A

1+cot²A=cosec²A

sin²A+cos²A=1

cosecA=1/sinA

secA=1/cosA

i dont understand first step

V=πr^2h=3.14*25*20=1570litres

this not correct answer

volume of a cone=1/3pie*r*r*h(i) r=3.5 cm and h=9 cmso volume=1/3*22/7*7/2*7/2*9=11*7/(3*2)=77/6cm^3(ii) r=10 dm and h=21 dmso volume=1/3*22/7*10*10*21=22*10*10=2200dm^3

ii) 3.8 , beacuse probability can not exceed 1.

iv) -0.8, because probablity can not be negitive.

vi) -2/5, because probablity can not be negitive.

please send the clear image of question

but the right answer for this question is = (c) = 5 bottles hope this will help you like my answer

by basic multiplication5×7=35

The equation will be

z×z = z²

5x-68=x

5x-x=68

4x=68

x=68/4

x=17

HCFof 96 and 404 by prime factorisation method:-Since, 96 =2× 2× 2× 2× 2× 3and, 404 = 2× 2× 101So, HCF of 96 and 404 = Product of common prime factors =2× 2 =4LCM = 2× 2× 2× 2× 2× 101× 3 = 9696

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volume of conical vessel = volume of cylinder

so, π*(10)²h = 1/3*(π)*(5)²*(24)

=> h = 1/3*(25)*(24)/100 = 2 cm

Diameter of the vessel = 4 cm

Radius of the vessel = 2 cm

Rise in water level = 0.8 cm

Volume of the increased water level = πr²h

= 22/7 × (2)²× 0.8 = 10.06 cu cm.

Volume of 300 lead balls = 10.06 cu cm

But, volume of 300 balls = 300 × 4/3 × 22/7 × (r)³

⇒ 300 × 4/3 × 22/7 × (r)³= 10.06

⇒ (r)³ = 10.06 × 1/300× 3/4× 7/22

⇒ (r)³≅ 0.008

⇒ r = 0.2