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5 * ( m + 5 ) = 5m + 25

a) 5 plus 8 is 13. 2 more than 13 is 13+2 = 15. b) product of 5 and 9 is 45. 3 less than the product is 45 - 3 = 42.

thq u

Since, 96 =2× 2× 2× 2× 2× 3and, 404 = 2× 2× 101So, HCF of 96 and 404 = Product of common prime factors =2× 2 =4LCM = 2× 2× 2× 2× 2× 101× 3 = 9696

Answer:b)9Explanation:(3/4)=(1/12) ×(9)=3/4

b (3/4)=1/12)×(9) =3/4 =9

Wet surface = curved surface upto water level + bottom circleradius of the cylinder r = 7/2height of the cylinder h = 4Area of wetted surface = Curved surface area of the cylinder + Area of base circle = 2πrh + πr2⇒ πr(2h + r)

⇒22 x 7(8 + 3.5)7 x 2⇒ 11 x 11.5 = 126.5 m2

median is 5 th element as no.of elements is even.x+2=24x=22

π×(15)2×h=43π(10)3

Therefore,h=43×10×10×1015×15=52527cm

5 plus 20= 5 + 20= 25Ans) 5 plus 20 is 25 .

Let Marked price of article is MP

Given, CP = 600

After 10% discount on marked priceSP = MP(1 - 10/100) = MP(9/10)

After 20% gain on cost priceSP in terms of CP= CP(1 + 20/100)= CP(6/5)

Thus, MP(9/10) = CP(6/5)MP = 600*6*10/45 = 36000/45 = 800

Marked price of article should be Rs 800

Ans:974+(3)+7+(6)+13+(12)+25+(24)+49+(48)

4+(3)+7+(6)+13+(12)+25+(24)+49+(48)

130=y {vertically opposite angle }y=x {alternate angles are equal}

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thank you sir

thanks you bro😉

((956+479)(956+479)+(956-479)(956-479))/(956×956+479×479)) = (956×956+2×956×579+479×479+956×956-2×956×579+479×479)/(956×956+479×479) = 2(956×956+479×479)/(956×956+479×479) = 2

40 ÷ 2 + 30 ÷ 6 ÷ 5 - 4*12 + 6*6 + 4= 20 + 5÷5 - 48 + 36 + 4= 20 + 1 - 12 + 4= 25 - 12= 13

8*8÷4*2-12+35+7-5

Total fare = 1600 + 20% of 1600= 1600 + 320 = 1920

3 is the answer.4x21=8416x6=96?x18=54so ?=54/18=3

250 cakes at rate of 7so C.P.=250*7=1750now gain need is 20%so S.P.= 1750*1.2=2100now 10 cakes are spoiled so remaining are 250-10=240so required price=2100/240=8.75 per cake

Euclid division lemma:-a=bq+r

324=96(3)+3696=36(2)+2436=24(1)+1224=12(2)+0

hcf of 324 and 96 is 12.

Now find the hcf of 12 and 56,56=12(4)+812=8(1)+48=4(2)+0hcf of 12 and 56 is 4.

Therefore, hcf of 56.96 and 324 is 4

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30 % of A = 0.25 of B

3A/10 = B/4

12A = 10B

A/B = 10/12

A/B = 5/6

A : B = 5 : 6

0.25 of B = 1/5 of C

B/4 = C/5

B/C = 4/5

B : C = 4 : 5

A. B. C

5. 6

× 4. 5

20. 24. 30

so A : B : C = 20 : 24 : 30

or, A : B : C = 10 : 12 : 15 (B)

30°/• of A=0.25 of B, 3A/10=B/4; 12A=10B; A/B = 10/12; =5/6; 0.25 of B=1/5 of C ; B/C=4/5; A: B : C 5 . 6 x 4 .5/20.24.30 So A: B : C=20 : 24 : 30 OR A: B : C =10: 12 : 15

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solution

Let the 100% of A be 100हमने माना कि ए का 100% 100 है

30% of A = 25% of B .... (1)प्रश्न के अनुसार दिया गया है कि ए का 30% भी के 25% के बराबर है

30% of A = 30अतः ए का 30% 30 होगा

=> B =30×100/25=120तब बी का मान हम इस तरह ज्ञात करेंगे

Then,

30% of A = 20 % C .... (2)अब दिया गया है कि ए का 30% सी के 20% के बराबर है

c=30×100/20=150

100 % of A = 120% of B = 150% of C

Ratio of A : B : C =10:12: 15अर्थात यह अनुपात इस प्रकार से होगा

a:b:c=10:12:15