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Total matches = 25

Percentage of match the team won = 80%

Percentage of match the team loss = 100%-80%=20%

Hence, number of matches team loss = 20% of 25 = 0.20*25 = 4

Ans: The team lost 4 matches in one session.

SP = 240 GAIN = 20% CP = 240/1.2 = 200 SP = 272 GAIN PERCENT = (272-200)*100/200 = 72/2 = 36%

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Volume of cube = a³ = 6³ = 216

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option(c)

To prove that√5 is irrational numberLet us assume that√5 is rationalThen√5 =(a and b are co primes, with only 1 common factor and b≠0)⇒√5 = (cross multiply)⇒ a =√5b⇒ a² = 5b² ------->α⇒ 5/a²(by theorem if p divides q then p can also divide q²)⇒ 5/a ----> 1⇒ a = 5c(squaring on both sides)⇒ a² = 25c² ---->βFrom equationsα andβ⇒ 5b² = 25c²⇒ b² = 5c²

⇒ 5/b²(again by theorem)⇒ 5/b-------> 2

we know that a and b are co-primes having only 1 common factor but from 1 and 2 we can that it is wrong.This contradiction arises because we assumed that√5 is a rational number∴ our assumption is wrong∴√5 is irrational number

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2 is appearing 3 times which is more occurrence than any other number so mode=2.

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cubitfoot pace foot pace

Volume = a³

=> a³= 13824=> a = ³√13824 = 24 cm

Volume of cube = (edge)^313824=(edge)^3Edge = cube root(13824)Edge = 24 cm

No. of 5cm cubes that can be cut =volume of 20cm cube /volume of 5cm cube= 20^3/5^3= 20×20×20/5×5×5=4×4×4= 64

Therefore, 64 cubes can be cut off

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64 is correct answer of given question option c

64 is the correct answer of this question

64 is 100% guaranteed correct answer

64 is the correct answer

64 is the best answer

64 is the correct answer

a)The bride seems unimpressed. She discerns sorrow and misery that invariably mar the happiness of marriage. Like a saint with profound wisdom, the daughter says that all the joys of life are transitory. They come and go, ceding place to suffering and disappointment.She feels a life in the lap of Nature gives enduring happiness. The charm of the woods never disappears.

b)The calling of the forest is pristine and pure. The brook in the forest falls relentlessly. They are a treat to the eye. Narrating all these, the daughter says she is leaving the home for the wilderness of the forests.

If points are collinear, then area is 0

Area=(1/2)[2(k+3)+4(-3-3)+6(3-k)]

0=(1/2)[2k+6+4(-6)+18-6k]

0=(1/2)[2k+6-24+18-6k]

0=(1/2)[-4k+36]

0=-2k+18

k=18/2=9

total =45avg=45/5=9

Means

1,3,5,7....n+1a=1d=2Sum=(n/2)[2+(n-1)2]=(n/2)(2n)=n^2Mean=Sum/n=noption a is correct

avg= 102+56+40+80+230+124/6

average = total score/ total no of matches= 102 + 56 + 230 + 40 + 180 + 124/6= 732/6= 122so his average score is 122 runs per match.

122 average score runs per match is the best answer.

the average score is 122 runs per march

the right answer is 122

avg score is 122 is the best solution.

Let α and β are zeroes of the polynomial = x² - (k + 6)x + 2(2k –1).

On comparing with ax²+bx+c=0a= 1, b= -( k+6) , c = 2(2k –1)

Sum of zeroes (α+β)= -b/a = -(-(k+6))/1α+β= (k+6)…………....(1)

Product of roots = c/a = 2(2k –1)/1α.β= c/a = 4k -2…………(2)

Given: (α+β) = ½(αβ ) (k+6) = ½( 4k -2)[From eq 1 & 2]2 (k +6 )= 4k -22k +12 = 4k -22k -4k = -2 -12-2k = -14k = 14/2

k = 7

1,3,5,7,9 these are the odd natural numbers

Bowler A = 85 runs in 10 overs

Bowler B = 56 runs in 6 overs

For 1 over,

Bowler A = 85/10 = 8.5

Bowler B = 56/6 = 9.3

SO, Bowler B is better

cos(60°) = 1/2

1 - tan²(30°)-------------------1 + tan²(30°)

1 - (1/√3)²-----------------------1 + ( 1√3)²

1 - 1/3---------------1 + 1/3

2/3-------------- 4/3

= 1/2

sar iska answer kya hoga

(-13)×{10+(-6)}(-13)×{10-6}(-13)×4=-52

5 the term will be5*5+42910th term = 50+45415th term = 75+4= 7920th term = 20*5+4104