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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 67901. |
5. Given p: 25 is a multiple of 5; q:25 is a multiple of 8. Write the compound statementconnecting these two statements with "and ", "or In 60th cases check the validity of thestatement. |
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| 67902. |
U, ,1,11, 15, 7n 7, 9, 11,11. Which of the following pairs of sets are disjoint?(i) (1, 2, 3, 4] and (x: x is a natural number and 4s s6)(11) la, e, i, o, u} and {c, d, e, f}(ii) f) l:c is an even integer) and (x:x is an odd integer).Solution :c:c 1S an |
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| 67903. |
101. When n is divided by 6, the remainder is 4. When 2n is dividedby 6, the remainder is(A). 2(C) 4(B) 0(D) I |
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Answer» Answer:A)2Explanation:Given:n/6= remainder 4Hence n=10i.e when 10/6 remainder is 4now 2n=2×10=202n/6=20/6remainder is 2 |
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| 67904. |
18. A number when divided by 56 gives the remainder 29. If it is divided by 8, then thereis -(a) 2(b) 7(c) 5(d) 6 |
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Answer» 85 divided by 8 a reminder gives 5 85 divided by 8 give remainder of 5 number divided by 56 then reminder is 29 then the number is 56+29=85so 85 is divided by 8 then reminder is 5 |
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| 67905. |
d be divided by (-7) to obtain 1221240) be divided to obtain 16What should be divided by6. Evaluate: |
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Answer» -7/x=12X=-7/12=-0.583 -7/x=12 x=-7/12 =-0.583 -7/12 is answer of following question |
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| 67906. |
4)Find 6 times as many as 2 divided by 6 |
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Answer» 2 divided by 6 is (1/3)6 times 1/3 is 2. thq u |
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| 67907. |
11Find the smallest number which on beingdivided by 8, 12 and 15 leaves remainder 6, 10and 13 respectively. But when divided by 23 noreminder is left. |
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Answer» the answer to the above question is 253. please mention in comments if you want solution. ❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤ |
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| 67908. |
5.IfA (1, 3,5, 7, 9) and B (2,4], show thatAnB is disjoint set. |
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| 67909. |
Find the ratio in which the line segment joining the points-3, 10) and (6, 8) is dividedby ( 1,6., ininino ASyand B- 4. S) is divided by the |
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| 67910. |
68. HOTS The radius ot the circumcircle of a right-angled triangle, is 3 cm and the altitude drawn to thehypotenuse is 2 cm long. Find the sum of the areas of the three disjoint seg ments of the circumcircloeCBSE 2015formed by the sides of this triangle. |
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Answer» we know that the hypotenuse of a right angle triangle is the diameter of the circleHence we have hypotenuse =2*3=6cm altitude= 2cm Hence area is =2*6/2=6cm^2 Like my answer if you find it useful! |
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| 67911. |
i ti le volume of a cube ise volume of a cube of side 1 cm ísio On me volume of a cube is 1 cubic-unit. The name of the cube number of 1 cm. cubes in the following solid |
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Answer» v = a³ = 1³ = 1 cm³ |
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| 67912. |
icalpitoftรถplilS12m deep. What is its capacity in klioiresdeight circular cone is 9856 cm. If the diameter of the base is 28 ce volume of aThect to d height of the coneing in curved surface area of the cone(i) slant height of the come |
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| 67913. |
Find the tolalPbookshelf22cm37 In fig the shape of a solid csopper piece (made oftwo pieces withdimensions as shown in the figure) is shown. The face ABCDEFA isthe uniform cross section. Assume that the angle at A,B,C,D,E and Fare right angles. Calculate the volume of the piece. |
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| 67914. |
PageIfysinuty then dan is equals to |
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| 67915. |
A circus tent is cylindrical to a height of 3 mconical above it. If its base radius is 52.5 nmslant height of the conical portion is 53 m, findárea of the canvas needed to make the tent. |
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| 67916. |
Multiply the following.8x (3x^2 +19x-2) |
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| 67917. |
Solve : 19x - 13 = 11x + 35 |
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| 67918. |
सिक-' वि न. 7 AT13. Divide ¥ 1450 petween Sanya and T.the ratio 2 : 3 P |
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Answer» Let Sanya get share 2xLet Tanya get share 3x Then,2x + 3x = 14505x = 1450x = 1450/5 = 290 Therefore,Share of Sanya = 2*290 = Rs 580Share of Tanya = 3*290 = Rs 870 tnx a lot |
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| 67919. |
13. -10x3уг + 15x-уз-5x2y2 divide by 5x2y2 i |
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| 67920. |
y- 6)030°63°2x + 7Fig, 8.52 |
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Answer» As they have given 2 pair of sides equal,thus by symmetry, we can say:=> y-6° = 30°=> y = 36° And,=> 2x + 7° = 63°=> 2x = 56°=> x = 28° |
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| 67921. |
6x3+x2-19x+6 divided by 2x-3 |
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| 67922. |
4(x-9) -8(x-9) =5x-17 |
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Answer» 4(x-9) - 8(x-9) = 5x - 174x - 36 - 8x + 72 = 5x - 17-4x + 36 = 5x - 1736 + 17 = 5x + 4x53 = 9xx = 53/9 |
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| 67923. |
14. 7(3x -1) 6 (2x 3) 8( -2)+1 |
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Answer» 7(3x - 1) - 6(2x+3) = 8(x-2) +121x - 7 - 12x - 18 = 8x - 16 +19x - 25 = 8x - 159x - 8x = 25 - 15x = 10 |
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| 67924. |
2 x+3 y+9 x-6 x-2 x+9 y |
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| 67925. |
3x+4y=62x+5y=7 |
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Answer» 3x+4y = 6=> x = (6-4y)/3now put this in the 2nd equation we get 2(6-4y)/3 = 7-5y => (12-8y)/3 +5y = 7 => 4-8y/3+5y = 7 so, 7y/3 = 3 or y = 9/7so ,x =( 6-36/7)/3 x = 6/21 = 2/7 I'm glad that you solved it for me but the question has to be done using elimination method. |
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| 67926. |
x ^ { 3 } - 2 x ^ { 2 } - 9 ; 5 x ^ { 3 } + 2 x + 9 |
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| 67927. |
d surface Area of Solidslume and5m long and 3.5 m wide is dug to a certain depth. If the volurme otit 5 m long and 3.5what is the depth of the pit ?A p2233e volume of earth taken out of it is 143 1 5 m deen is dug 2 |
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Answer» Thank you |
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| 67928. |
al. If tan A =%, dan B =%, andtar(A+B)- tan A+ taus BIntan a tane. Andsin?0+B) + cos?C9+B) ? |
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Answer» tan(A+B)=1/2+1/3/1-1/2*1/3=5/6/5/6=1henceA+B=tan^-1(1)=π/4hencesin^2(π/4)+cos^2(π/4)=1/2+1/2=1 |
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| 67929. |
RESULTWhen A and B are disjoint sets, then we hagen(A U B) = n(A) + n(B). |
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Answer» By definition of disjoint set we mean that there won’t be any common elements in both the sets. Therefore A intersection B will be null. Therefore,n(A intersection B)=0 In general,n(A union B) = n(A) + n(B) - n(A intersection B) Since A and B are disjoint sets, n(A union B) = n(A) + n(B) |
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| 67930. |
N UV किक लिन0 न ६ - 0809 &+ 0८०४ 2 (0ey Su1M0110]1 M) 24 |
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| 67931. |
20What length of tarpaulin 3m wide will be required to make a conical tent otheight 8m and base radius 6m? Assume that the extra length of material thatwill be required for stitching margins and wastage in cutting is approximately20cm (UseT-3.14) |
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| 67932. |
nd the mean of the marks obtained by the stA granary is in the shape of a cuboid ofsp s candimensioni 10 m x 8mx4m. If a bag of graSection, a granary?ace of 0.80m3, how many bagmany bags can be stored u10 mx 8mX4m. If a bag of grain ocupies a |
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| 67933. |
--sin2 A+ sin A0sin(x+y) sin x cos y + cos x sin yllusing Eq. (ii)]the correct option is (a).12. The maximum value of A1 1 + sin θ 11 is1+cos θ 1 11where, Ois real number)re(b) 2/3(e) 22/3Solution Given, A1 1+sin1+cos θAplying C,+ C -C and C, C -C,, we get000-1(-sin 0cos8sin θ-cos θsin 2021+cos θ-cos θr maximum value of A, sin 2θ will be minimum. |
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| 67934. |
relationship Detweeil he lil. Divide-6r++19x +6 by -3x2+ 5x + 2 and verify the division algoDivide-6xx 19x+ |
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| 67935. |
\sin ^{2} \frac{\pi}{8}+\sin ^{2} \frac{3 \pi}{8}+\sin ^{2} \frac{5 \pi}{8}+\sin ^{2} \frac{7 \pi}{8} |
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Answer» sin(π/8) sin(π/8) + sin(3π/8) sin(3π/8) + sin(5π/8) sin(5π/8) + sin(7π/8) sin(7π/8) sin(π/8) = cos(7π/8) sin(3π/8) = cos(5π/8) cos(7π/8) cos(7π/8) + cos(5π/8) cos(5π/8) + sin(5π/8) sin(5π/8) + sin(7π/8) sin(7π/8) = 1 + 1 = 2 |
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| 67936. |
-13Divide the sum of -Divide the sum of 18 and by the product of - 31 andandhe product of -- 31and |
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| 67937. |
\operatorname { sin } ^ { 2 } \frac { \pi } { 8 } + \operatorname { sin } ^ { 2 } \frac { 3 \pi } { 8 } + \operatorname { sin } ^ { 2 } \frac { 5 \pi } { 8 } + \operatorname { sin } ^ { 2 } \frac { 7 \pi } { 8 } = 2 |
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Answer» Sin²π/8+sin²3π/8+sin²5π/8+sin²7π/8=sin²π/8+sin²3π/8+sin²(π/2+π/8)+sin²(π/2+3π/8)=sin²π/8+sin²3π/8+cos²π/8+cos²3π/8=(sin²π/8+cos²π/8)+(sin²3π/8+cos²3π/8) [∵, sin²Ф+cos²Ф=1]=1+1=2 Ans. |
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| 67938. |
न ox—(3+4%) _ 6A 2x—(7-5x) 7 |
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| 67939. |
P 2 }.v )(x° + 2x)%-7(x+2x)-y(x*+2x)+ 7y |
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Answer» (x*x+2x)(x*x+2x)-7(x*x+2x)-y(x*x+2x)+7y = x*x*x*x+4x*x*x+4x*x-7x*x-14x-yx*x-2xy+7y = x*x*x*x+4x*x*x-3x*x-14x-yx*x-2xy+7y |
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| 67940. |
9x-(3 + 4x) 62x-(7-5x) 7 |
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Answer» (9x-3-4x)/(2x-7+5x)=6/7(5x-3)/(7x-7)=6/77(5x-3)=6(7x-7)35x-21=42x-4221=7xx=3The value of x is 3. |
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| 67941. |
1. Find the following product(v) (10 +a) (8-a) (vi) (4-x)(9+) (vii) (8r-5)(7x+3) (vii) (11t-9) (3t+2)(ix) (7-2k) (9+ k) (x) (2x+7) (2x-7) (xi) x-4) (3x-8)(xii) (7x+8)(9-20)u) (x+ 8) (x-n) (2-3) (2-IVvill |
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| 67942. |
किए दि पर बिक S गाD ) ot and pare t L A 6८८०-०८st L)L oy b el T8 v, |
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| 67943. |
In the figure, PQ is a diameter of a circle withcentre O. QR is a tangent to the circle equal toOQ. OT is perpendicular to PR. QT is producedto cut the circle at S. Prove that SP ST. |
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| 67944. |
prowides molsture for vegetation over a wide areaot prowide breeding grounds for mosquitoes like stin ponds or artificlal lakes. The ground-water is afrom contamination by human and animal wastQ UE S TIO Nd couout the raditional systems of water har |
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Answer» Taanka is atraditional rainwater harvestingtechnique indigenous to the Thar desert region of Rajasthan. A Taanka is a cylindrical paved underground pit into whichrainwaterfrom rooftops, courtyards or artificially prepared catchments flows. |
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| 67945. |
P "If we divide any positive integer 'a' bythen the remainder will be 0 and 1 onlv? JustiTodo. |
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Answer» (a²-bc)²=a⁴- 2a²bc+b²c². How can we get b²c²,instead of bc². |
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| 67946. |
Divide:0) 4x by 2x |
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Answer» 4x^2÷2x =2x |
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| 67947. |
OD UV PUUSUTIS.If we divide any positive integer 'a' by 3 then the remainder will be 0 and 1 only? Justify. |
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Answer» SOLUTION:The given statement the values of remainder r ,when a positive integer a is divided by 3,are 0 and 1 only is FALSE. According to Euclid's division Lemma, a = b q+ r Here, b = 3 a = 3 q + r, Where 0 ≤ r < 3 and r is an integer. Therefore , the values of r can be zero ( 0 ) , one ( 1 ) or two ( 2 |
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| 67948. |
ओर का कोरम)९-_7+#+C.</ |
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Answer» Area of Triangle =under root s(s-a)(s-b) (s-c). ... Please like my answer... √s(s-a)(s-b)(s-c) plice like my anser |
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| 67949. |
07: Divide using long divisionand find the auotient: -(i) 4.32 by 8 0 41.67 by 3(in) 57.28 by 16 (1) 24.312 64 6Q8: - Simplify:-2.12.8+[705={(2.75-2:25)x3373) 8 4 = f (6-2) X +0-1} |
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Answer» (12/5-2/5)×1/4=(12-2/5)×1/4=10/5×1/4=1/2 is the right answer. |
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| 67950. |
011KOUL CSILLICUIUIU11. Divide the largest 5 digit number by 653. Check your answer by the division algorithm.igible h02 |
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Answer» please answer do please |
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