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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 67951. |
(+42)by (_7) |
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Answer» 42/7=6
if it is -7 then 42/-7 is -6. |
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| 67952. |
9. 20 men can do a piece of work in 12 days, in how many days can 15 menAns. 16 daysfinish the same work. |
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Answer» thanks |
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| 67953. |
_3+4+(_7) |
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Answer» bhai iska kya karna hai plz batai -6 is the correct answer -6 . -6 is correct answer is correct answer -6 0 is correct becase rule or bodmas answer is -6 if this condition -3+4(-7) -6 is the right answer of the following |
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| 67954. |
24, 2x-(7-5x) _79x- (3+4x) 6 |
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| 67955. |
न,; डे Prove that -~ J st cos +sin O(1~-cosB) (1—tan®)2 (ICSE 2015) YL |
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Answer» cos A / (1 - tan A) + sin A /(1 - cot A) = sin A + cos ALHS = cos A / (1 - tan A) + sin A /(1 - cot A) = cos^2A / (cos A - sin A) + sin^2A / (sin A - cos A) = cos^2A / (cos A - sin A) - sin^2A / (cos A - sin A) = (cos^2A - sin^2A) / (cos A - sin A) = (cos A + sin A) (cos A - sin A) / (cos A - sin A) = (cos A + sin A).Hence proved. |
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| 67956. |
what sT glape ot the lime J 2 |
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Answer» If you like the solution, Please give it a 👍 |
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| 67957. |
e बिक न रह अर आज फेल2 ST B गूंदे (भएसन्र थएडाएकत लना साश्डक थमनऊाएव को छा ब्रोएथन याएड थडाक (गायनS I 18 बचत झापव उथन धएडाक (मम 120000 का 0 ST | I वार्विक मबल oAT 10% G=R G TN 1 U 13 29 % 8 727 | Tl 200 o &LT T ऐ़ेको जगा (न्एथछि,नन दिजाव कबि।शक : “5 के आरा |
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Answer» prothom me ti pabe 80hajar ar ditio me pabe 40hajar |
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| 67958. |
18What in the area between a square of side 10 am and two invenedsem-cirolar cross-section each of ds5 om insoribed in the square? |
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| 67959. |
\begin{array}{l}{\text { Solve the following and write the }} \\ {\text { aj } 2 \cos ^{2} \theta-\sqrt{3} \sin \theta+1=0}\end{array} |
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Answer» thank you |
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| 67960. |
Find the value of Îť for which a and b are perpendicular, who(i) a =2i +Aj + k and b =(1-2j + 3k)N, |
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| 67961. |
1 Divide 0.1 in the ratio 1:1. |
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Answer» 1/2×0.1= 0.051/2×0.1= 0.05 |
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| 67962. |
5) State dimension and unit of momentum. |
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Answer» The unit of momentum is the product of the units of mass and velocity. In SI units, if the mass is in kilograms and the velocity is in meters persecondthen the momentum is in kilogram meters persecond(kg⋅m/s)Dimension):ML/T |
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| 67963. |
simplify the ratio 1/3:1/8:1/6 |
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Answer» 1/3*24:1/8*24:1/6*248:3:4 |
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| 67964. |
ANSWER QUESTIONS(1 Mawy(c) 27 -15_79Ans. |
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Answer» 9y=14y-1059y-14y=-105-5y=-105y=-105/-5y=21 |
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| 67965. |
» 201. Students are below 8 years? The no of studentsabove sywars are 213? no. of students of 8 years ofage is 48? what is the total no. of students, |
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| 67966. |
Solve the Initial Value Problem y"- 9y 0 y(0) 2, y'(0) 1 |
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| 67967. |
If 3 sin 0+4 cos 0 =5 then the value of 4sin 0-3cos = |
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Answer» cos = 4/5now after putting values0 will be the answer |
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| 67968. |
The value ofdxisThe value of J st ds180 |
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| 67969. |
sthe value of 2tan 0 + cos?0. |
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Answer» Like my answer if you find it useful |
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| 67970. |
For what value of 6, sin 8 = cos 6 where 0<0 <90°?0 के किस मान के लिए 80 0 न ८०89, 0 <0<90* ? |
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Answer» sint = cost tant = 1 t = 45° |
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| 67971. |
Divide 60 in the ratio 1:2 between Kriti and Kiran |
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Answer» sum of the ratio's 1:2=3kriti 1/3*60= ₹ 20 kiran 2/3*60= ₹ 40 |
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| 67972. |
SECTION -CQuestions:-1. Divide 100 in the ratio 6:4 between Jiya and Kiran. |
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| 67973. |
Q22. A person's present age is two-fifth of the age of his mother. After 8 years, he will be one-half of the age of his motherHow old is the mother at present? |
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Answer» Mother age is 40 in present time Present time mother age is 40 |
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| 67974. |
The sum of the age of mother and a mother and her daughteris 60 years. 12 years ago the mother was eight times as old asher daughter, How old is the daughter at present? |
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Answer» Any short trick |
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| 67975. |
Find YZ from the following triangle using Pythagoras theorem. |
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| 67976. |
13 Sthana said, tig myby 5and addling 8 to it g'ivesCame ansuoc as Subtsactingาทanmumbers |
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| 67977. |
Write the equation 4-5x-3y in the term of axtby+c-0 and indicate the valuesof a, b, c. |
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| 67978. |
Manish is indifferent to the bundles (4,7) and (4, 8) Indicate, whether Manish has monotonic preferenceor not? |
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Answer» The preferences is monotonic because his bundles shows the more goods to less goods and monotonic preference implies more andmore consumption of two sets of goods to get maximum satisfaction...He will choose (4,8) first |
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| 67979. |
Without using Pythagoras's theorem show that the points (4, 4) (3, 5) and (-1, -1) are the vertices ofright angled triangle |
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| 67980. |
6. Without using the Pythagoras theorem, show that the points (4, 4), (3, 5) and(1,-1) are the vertices of a right angled triangle.nale of 30 with the positive direction |
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Answer» PLEASE LIKE IT, IF YOU FIND THE ANSWER HELPFUL. very good I'm satisfied with your answer and also thanks for giving answer |
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| 67981. |
कर पृथ्वी से जादि वृक्ष की जड़ सेवी को छूता है, 40 मीटरR1 (त) इनमें से कोई नहीं |
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| 67982. |
sandhiya said 8,15,17 are Pythagorean triplets do you agree with sandhiya or not give reasons |
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Answer» yes because 17² = 289 and 15²+8² = 225+64 = 289 so, 17²=15²+8² thanks |
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| 67983. |
Identify the Pythagorean triplets' from the following(i) 3, 7, 9(ii) 7, 24, 25(iii) 4, 5, 7 |
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Answer» option 1 and 3 aren't Pythagorean triplets whereas option 2. 7, 24,25 is a Pythagorean triplets. |
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| 67984. |
1.Find the zeroes of the following quadratic polynomials and verify the relationshipberween the zeroes and the coefficients0) 40-4+1-3-7xe)r- is(iv) 4+8(v) 3x-x-4 |
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| 67985. |
Miscellaneous Problems: Set 11. Solve the following.(ii) (72) ÷ (-12)(v) (-104) (-13)(iii) (-24): (2)(vi) 25% (-4)(iv) 125 +5 |
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Answer» i) -16*-5=80ii)72/-12=-6iii)-24/2=-12iv)125/5=125v)-104/-13=8vi)25*-4=-100 |
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| 67986. |
Evaluate: \left| \begin{array}{ccc}{5} & {13} & {17} \\ {30} & {68} & {105} \\ {25} & {66} & {84}\end{array}\right| |
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| 67987. |
What does-7 4 Indicate about the positionsof-and-4 on the number line?1-is located on the left of -4-2is located on the right of-4is located on the right of 0 and-4 is located on the left of 0is located on the left of 0 and -4is located on the right of 02 |
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Answer» -2/7 > -4 so -2/7 is right of -4 second option is correct |
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| 67988. |
write the Pythagorean triplets whose smallest number is 18 |
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Answer» If you find this solution helpful, Please give it a 👍 thanks |
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| 67989. |
What sign conventions are used forreflection from a spherical mirror? |
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Answer» The following sign convention is used for measuring various distances in the ray diagrams of spherical mirrors: Object is always placed to the left of mirror All distances are measured from the pole of the mirror. Distances measured in the direction of the incident ray are positive and the distances measured in the direction opposite to that of the incident rays are negative. Distances measured along y-axis above the principal axis are positive and that measured along y-axis below the principal axis are negative. |
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| 67990. |
Write the pythagorean triplets whose smallest number is 18. |
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| 67991. |
17.Without using phthagorean theorem show that (4, 4) (3, 5) and(-1, -1) are the vertices of a right angled triangle. |
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| 67992. |
40+ 40= |
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Answer» 40+40= 80 will be the answer |
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| 67993. |
40 is divided in two parts such that I in of first number is equal to the Ia ofthe second number. If first number is x. Then the equation for this is(a) x=40-r1 4040 1 |
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Answer» Let the two no. be x and 40-xAccording to question=(1/5) x = (1/3) (40-x) =x/5= 40-x/3 |
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| 67994. |
3. Evaluate 13 17 515 20 12 |
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| 67995. |
4.Findthe sum of the following using the column nmeth(b)e-r +(a) аг + 2ab + b2, a2-2ab-b2, a2 + b2(c) 6a-5b+ c, - 2a + 4b - 2c, b-c, a-2ab -b, ay2 |
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| 67996. |
2) If a and b are natural numbers and a > b, then show thata2 -b), (2ab) is a pythagorean triplet.(a2 + b2), (Find two phthagorean triplets using any converilent value ofa and b |
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| 67997. |
Answer the following questions:1. Simplify -3b (ab + b2) + 300 and find its values for a = 3 and b = 4. |
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Answer» Given:a=3; b=4 -3b(ab+b²)+300=-3ab²-3b³+300=-3(3)(4²)-3(4³)+300=-144-192+300=-36 |
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| 67998. |
Find the perimeter of a rectangular field whose length is 4 times its width and which has area20736 sq. m. |
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Answer» l=4w area 40736=l*w 4w*w = 20736 so w*w = 5184 w = 72m so l = 288m so perimeter = 2(l+w) = 2(288+72) = 720m |
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| 67999. |
2) If a and b are natural numbers and a >b, then show that(a2 + b2), ( a2-b?), ( 2ab ) is a pythagorean triplet.Find two phthagorean triplets using any converilent value ofa and b. |
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| 68000. |
a3+b3=35 a2+b2=13 |
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