Saved Bookmarks
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 68251. |
o. The volume of a cube IS7th of the longest rod which can be kept inside a rectangular box is 17 cm. If thelength and breadth of the box are 12 cm and 8 cm respectively, find its inner height. The leng |
|
Answer» Length of the longest rod = Length of the diagonal of a room = √(12^2+ 8^2+ h^2)= √(144 + 64 + h^2 = √(289) = 17 m.hence144+64+h^2=289h^2=81h=9cm just one step above hence i can't understand |
|
| 68252. |
4)If a man covers 10.2 km in 3 hours, find the distance covered by him in 5 hours |
|
Answer» Speed =10.2/3kmphtime =5hrnew distance =10.2*5/3=17km |
|
| 68253. |
Walking at the rate of 4 km/hr a man covers a certain distance in 2 2 hours.time will be taken by the man to cover the same distance, if he oye4.cyeles at 12 kmr |
| Answer» | |
| 68254. |
271were examined in a hospital by a doctor and the number of heart beats peranded and summarised as follows. Find the mean heart beats per minutemen, choosing a suitable methodThirty women werewwote were recordor these womencheart beats 65-68 68-71 71-74 74-7777-80 80-83 83.86Suruber of beerthper minute2438Number of women7arbat fruit vendors were collin |
| Answer» | |
| 68255. |
Thirty women were examined in a hospitalminute were recorded and summarised asfor these women.chonninaamber of heart beats/minutesble method.71-74ined in a hospital by a doctor and the other d etmarised as shown. Find the mean hen you1Im on our 11-16 7471020 11-83 839amber of women74-77117In a retail market, fruitday chickers 132.89 |
| Answer» | |
| 68256. |
are 42 boys and 18 girls in a class. What is the percentage of boys in the class?m won 6 hockey matches and lThere |
| Answer» | |
| 68257. |
41. There are 500 eggs in a box.25 sotbroken, of the remaining eggs weresold. The number of eggs left is(A) 80(B) 88(C) 40 (D) 36 |
|
Answer» Answer:B)88Explanation:Given:Number of eggs = 500. no. of eggs broken = 3/25 × 500 = 60 no. of eggs remaining = 500 - 60= 440 No. of eggs sold = 4/5 × 440 = 352 no. of eggs still remaining = 440 - 352 = 88. Thus 88 eggs were left. |
|
| 68258. |
CP of the articleAshopkeeperbought 200 eggs out ofwhich 38 were broken, he sold the remaining eggs at the rate of 48 perdozen and thusgained 8%. Find his total investment. |
| Answer» | |
| 68259. |
The coach of a cricket team buys 3 bats and 6 balls for R 3900. Later, she buys anotherbat and 3 more balls of the same kind for R 1300. Represent this situation algebraicallyand geometricallyThe cost of 2 kg of apples and lkg of grapes on a day was found to be 160. After amonth, the cost of4 kg of apples and 2 kg ofgrapes is 300. Represent the situationalgebraically and geometrically. |
| Answer» | |
| 68260. |
fed 3 ts62Din |
| Answer» | |
| 68261. |
9. The length of the longest rod which can be kept inside a rectangular box is 17 cm. If thelength and breadth of the box are 12 cm and 8 cm respectively, find its inner heightinner |
|
Answer» So the length of the longest rodwhich can kept in the room is= 17.hence height of room =root under 17^2 -(12^2 +8^2)》root under (289-208)》root under 81.》9 cm.is the height of room. |
|
| 68262. |
3. Compute the area of the trapezium shown in thefigure :D 6 cm c17 cm8 cm6 cm O |
| Answer» | |
| 68263. |
Thirty women wereminute were receomen were examined in a hospital by a doctor and the number of heart beats perwere recorded and summarised as follows. Find the mean heart beats per minutethese women, choosing a suitable method.Sumber of heart beats 65-6868-7171-7474-77 1 77-8080-8383-86per minuteNumber of women2374alat fruit wondo |
| Answer» | |
| 68264. |
There are 6 boys and 4 girlsplaying hockey in the ground.How many players areplaying in the ground? |
|
Answer» Boys playing in the ground=6Girls playing in the ground=4Total players playing in the ground =?= Boys +Girls= 6+4=10 =10 players are playing in the ground 6+4=10 players are playing in the garden Total players in the ground=Boys playing in the ground +Girls playing in the ground. =6+4=10 Total players in the ground=Boys playing in the ground +Girls playing in the ground. =6+4=10 6+4=10 player are playing in the garden 6+4=1010 players are playing in the ground. 10 is the right answer..... 10 is the right answer .... 6 boys + 4 girls = 10 players 6+4=1010 players are playing in the ground 6+4=10players are playing in the ground 10 is right answer ......... 10 players are playing in the ground 6 Boy+ 4Girls. =10 players are playing in the ground girls=6boys=46+4=10 girls=6boys=4total=10total no of players=20 10 players are playing in the groud 6 boys+4girls=10 players total 10 players in the ground 6+4=10 player are playing in the ground 6+4=10players are playing in the ground 6 boys + 4 girls =10 players in the ground 6+4= 10 players playing in the ground 6+4=10 total girls and boy 10 players are playing in the ground 10 player's playing in the ground boys player are-6and girl player are-46+4=10 answer 10 plyeys are playing in the ground 10players are in the ground 10 player in ground in match playing 6+4=10 players playing 10 Players are playing in the ground 10 players are playing in the ground. (1)ans=6+4=10 playing boys playing is the ground_6 girl playing is the ground--4total playing in the ground players?4+6=10total players=10 10player will be playing in the ground 10 player playing in the ground boys playing in the ground _6 girls playing in tha ground _4 total players in the ground boys +girls 10 players plying to ground 10player in the ground 10 player is playing hockey 6+4=10 iska shi answer 10 hi h 10 player ate playing in ground6+4=10 Boys=6Girls=4Total players playing in ground=? Boys+girls=total players6+4=10 10 players are playing in ground Total Number of players playing in the ground =no of boys playing hockey+no of girls playing hockey Now,Hence Toatal Number of play 6 boys and 4 girls=6+4= 10 player playing in the ground 6 boys and 4 girls are playing in the game so there are 10 players due to who play in the game they are called as players and it doesn't matter who boys or girl Boy playing in the ground=6Girls playing in the ground=4total players playing in the ground=?boys + girl= 6+4players are playing in the ground=10 10 player play hockey in the ground 6 boys and 4 girls is call to 10 players in the ground playing hockey match There are 10 players are playing in the ground. 6+4=10player are playing in thr ground ten players are playing in the hockey ground 10players are playing in tha ground they are 10 playing in the ground 10 players playing in the ground Boys playing in the ground=6girls playing in the ground=46+4=10 6+4=10 players are playing in ground 6+4 player are in ground 6+4 matlab 10 players 6boys+4girls=10 player playing in the ground 6+4=10 10 players are playing in the ground the boys are= 6 and girls are =4 so total number of players is 6+4=10 Players are playing in ground 6+410players are playing in ground 10 right answer ..... 6+4+2=12 are in ground 10 players in ground 6+4 10 is the right answer boys playing in the ground=6girls playing in the ground=4total players playing in the ground=?total players=boys+girlstotal players=6+4total players=10 10 player in a ground 6+4 = 10 |
|
| 68265. |
56.There are 500 eggs in a box.got broken,25of the remaining eggs were sold. Thenumber of eggs left is |
|
Answer» Total number of eggs = 500 Number of eggs broken = 3/25 Number of eggs sold = 4/5(500 - 3/25) Remaining eggs= 500 - 3/25 - 4/5(500 - 3/25)= 500 - 400 - 3/25 + 12/125= 100 - 3/25 + 12/125= (12500 - 15 + 12)/125= (12500 - 27)/125= 12473/125= 99.784 |
|
| 68266. |
nk is 21.600To of the weight of the suitcase. If the weight of the trunk is 21the total weight of the suitcase and the bag?The weight of the suitcase = x the weight of the trunk= 21.60 kg = 13,20 kg = 14.40 kgThe weight of the bag = to the weight of the suitcase=+* 14.40 kg = 1.44 kgthe required weight = 14.40 kg + 1.44 kg = 15.84 kg.2EE361. A bus covered 27.35 km in the first hour, 25.45 km in the second hour, 36.50third hour and 30 km in the fourth hour. How many kilometres did it cover in fourOn din Sonch har |
|
Answer» Hey man in the next few years ago when I first started with a lot of fun you can find a job in my life |
|
| 68267. |
17.18.(c) 6 वर्ग केदिए गए चित्र में, 30P) का क्षेत्रफल होगा ।(a) वर्ग इकाई(b) वर्ग इकाई(C) 7 वर्ग इकाई(d) 25 वर्ग इकाई7.00(0. 0) |
|
Answer» option b is the correct answer of the given question |
|
| 68268. |
they are equal in ae base PC) = ar(ADPQ).4. Find the area of a trapezium whose parallel sides are 9 cm and 6 cmrespectively and the distance between these sides is 8 cm. GOD6 (i) Calculate the area of quad. ABCD, given in Fig. (i).(ii) Calculate the area of trap. PORS, given in Fig. 1).Bom R .D 17 cmmamssite17 cm0 cm9 cm08 cm8 cm |
|
Answer» 4 5(1) 5(2) |
|
| 68269. |
In figure, CP and CQare tangents to a circlewith centre O. ARB isanother tangent touchingthe circle at R. If CP 11cm and BC -7 cm, thenfind the length of BR.O. |
| Answer» | |
| 68270. |
Q.4. A motorist travelled the distance between twhich is 65 km, in 2 hours and 10 minuteFind his speed in metre per minute. |
|
Answer» 1 km=1000m65km=65000m2h10min=130mimspeed=65000/130=500m/min please tell me how to solve it |
|
| 68271. |
MATHEMATICS4 Thirty wonen were examined in a hospital by a doctor and the number onutewere recorded andsummarised as follows. Find the mean heartbeats per minutefer these women, choosing a suitable method. ns159pe-rofbeantheats|65.68166-71171-74174.77177.80180-83183per minuteNumberof women244 |
| Answer» | |
| 68272. |
LORUMis a mammal that lays eggs. |
|
Answer» the answer is platypus platypus is the right answer the correct answer is platypus |
|
| 68273. |
Find the number of ways of arranging 6 players to throw theplayer may not throw first.cricketballsothattheoldess |
| Answer» | |
| 68274. |
5x - [4y â{7x - (83z - 2y) + 4z - 3(x + 3y - 22)}] |
| Answer» | |
| 68275. |
7x+3y=22 में यदि y=1/2,x का मान ज्ञात |
|
Answer» rong answer Which step you found error? |
|
| 68276. |
Solve for x and y:1760.4x +3y 1.2, 7x-2y |
|
Answer» hit like if you find it useful |
|
| 68277. |
EKERCISE-11.37ABC is a triangled, right angle at C. IfAB 25 cm and AC-7 cm Find R |
|
Answer» answer is 24 this question ABC is right angled at C so AB*AB = AC*AC + BC*BC so BC*BC = 25*25 - 7*7 = 625 - 49 = 576 BC = 24 cm |
|
| 68278. |
bight and a the semi -- vertical angle of a right circular cone, then its9. If h be the height and a thevolume is given byo'ah tan’a2. #h tan’a3. şah'tan'a4. pahitan a321 |
|
Answer» Answer:1.(1/3)πh^3 tan^2 α Explanation: Semi vertical angel =αheight = h unitslet radius = r units tanα =radius/heightradius, r = h tanαnow, volume = (1/3)πr²h =(1/3)π×(htanα)²×h =(1/3)πh³tanα² cubic units |
|
| 68279. |
. x+v/x-1 x-vx-1সরল করি : "' x-x2-1 x+vx2-1 |
| Answer» | |
| 68280. |
If 49e_ b = | 7x+-| | 7x--, find the value of b. |
| Answer» | |
| 68281. |
Sachin is given consumer Only two good XxxI whose frices are 22 andal por unit respectivelyIf he choose the combination of two goods withMUx=4 and Muy 4 Is the consumer is givenenquilibrium |
|
Answer» mux/px=muy/py4/2=4/12 is not equal to 4so the consumer is not equilibrium |
|
| 68282. |
12. If (x:y)3:4, then (7x +3y):(7x-3y)? |
|
Answer» x:y=3:4x/y=3/4 7x+3y/7x-3y Divide every term with y 7(x/y)+3 / 7(x/y)-3=7(3/4)+3 / 7(3/4)-3 =21/4 + 3 / 21/4 -3 =33/4 / 9/4 33/9 |
|
| 68283. |
If 49r2-H-(7x +)(7x-).Then find the value ofb |
| Answer» | |
| 68284. |
6x+7x-20 |
|
Answer» 13x-20 it is the answer easy 13x-20 easiest question in scholr |
|
| 68285. |
6x^2 - 3-7x |
|
Answer» Rearrange equation6x² - 7x - 36x² -9x + 2x -33x(2x - 3) + (2x-3)(3x + 1)(2x -3) when we add or subtract the middle terms we should get eq 1 and by do product of middle terms we should the constant but here it is not coming Can specify your question ? and like that when we product the middle terms we should get constant No, that is incorrect. When you do product you should get 6x² × (-3) = -18x² like here -9x × 2x = -18x², that is concept ok thanks |
|
| 68286. |
1. AABC is righ-angled at A. IfAB 9 cm, AC 12 em, then find thelength of BC |
|
Answer» ABC is right angle triangle, angle A=90° Apply pythagoras theorem, BC²=AC²+AB²=12²+9²=144+81=225 BC=√225=15 cm |
|
| 68287. |
how that the diagonals of a square are equal and bisect each other at righ a |
| Answer» | |
| 68288. |
sec2 Ďii The(iv) If sin(0-60°) cos0 then(v) If the volume of two righheights is 1:3, then the ratio3:1 (vi)The valus |
| Answer» | |
| 68289. |
S. Show that the height of a right circular cylinder of maximum volume that can beinscribed in a given right circular cone of height h is |
|
Answer» let the base of this triangle lie on the x-axis, with the two sides of the triangle symmetrical to the y-axis. let the base of the triangle = 2R, height = H side of the triangle in quad I has equation y = H - (H/R)x base of the cylinder = x height of the cylinder = y = H - (H/R)x so, cylinder volume is ... V =*x*[H - (H/R)x] = H[x- x/R] dV/dx = H[2x - 3x/R] set dV/dx = 0, x(2 - 3x/R) = 0 x = 2R/3 ... the cylinder radius for max volume so height of the cylinder=y=H-(H/R)(2R/3) y=H/3 |
|
| 68290. |
3) The diagonals of parallelogram, intersect each other at righangles. The parallelogram is:a) a rectangle b) rhombus c) parallelogram d) trapezSaya ingin ko po ang producer |
|
Answer» In anyrhombus,the diagonals(lines linking opposite corners)bisect each otherat rightangles(90°). That is,each diagonalcutsthe otherinto two equal parts, andtheangle where they cross is always90degrees. |
|
| 68291. |
(Vx-1 +Vx+24-10/x-1 )=---when 1<x<26a..Ob.._1Vx+1C..2/x-1-3d.. of these |
|
Answer» d is a correct answer option (a) is the correct answer |
|
| 68292. |
mt udove ule floor. Find the height.2. A tent of height 3.3 m is in the form of a right2.2 m surmounted by a right circulartent at the rate of 7500 per m.m is in the form of a right circular cylinder of diameter 12 m and heightred by a right circular cone of the same diameter. Find the cost of canvas of theantor 36 m and height |
| Answer» | |
| 68293. |
1Vx |
| Answer» | |
| 68294. |
(i) 5x, 7x, -6x |
|
Answer» Adding terms 5x, 7x , -6x 5x + 7x + (-6x) 12x - 6x 6x thank |
|
| 68295. |
Divide X²+3X+1,3X⁴+5X³-7X²+2X+2 |
| Answer» | |
| 68296. |
1. Add the following expressions:(i) 5x, 7x,-6x |
|
Answer» 5x+7x+(-6x)x(5+7-6)x(5+1)6x 5x + 7x =12x12x - 6x = 6x 5x+7x(-6x) x(5+7-6) x(5+1) 6x |
|
| 68297. |
लिVx o" —t |
|
Answer» put √x=tthen solveI,e x^2=t^4so lim(x->1)(t^2+t+1)=1+1+1=3 |
|
| 68298. |
1. Add the following expressions:(i)5x, 7x,-6x |
|
Answer» 5x + 7x - 6x = 12x - 6x = 6x |
|
| 68299. |
Vx(a) limx +1 |
|
Answer» IF WE PUT DIRECT LIMIT TO THIS DENOMINATOR IS NOT ZERO SO ANSWER IS 1/2 OR 0.5 |
|
| 68300. |
of their volumes.20. The diameter of a right circular cone is 8 cm and itsvolume is 48 Ď crn3. Find the height.fn right circular one is 314 cm2 and its height is 15 cm. Find the volume |
|
Answer» awesome and thankyou |
|