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let us take x=0.254-(1) and bar on 54 has then 2 numbers are repeating so we should multiply 100 to x

=0.254..... into 100 =025.4545......100x=25.4545......-(2)

(2)-(1)=100x–x=25.4545......–0.2545499x=25.2000......x=25.2.../99

59 and 61 are prime number

59 and 61 is prime number

thanks for keeping the correct answer

LHS

( cosecA - cotA )²

= ( 1/ sinA - cosA/sinA )²

= ( 1 - cosA/ sinA )²

= ( 1 + cosA )²/ sin²A

= ( 1 - cosA )²/ 1 - cos²A

= ( 1 - cosA ) ( 1 - cosA )/ ( 1 + cosA ) ( 1 - cosA )

= 1 - cosA / 1 + cosA

.°. RHS

dint understand the question

please post a clear picture of the question

As its an equilateral triangleso x= 60°thanks

total 180°3x=180x=60

since, the sum of Angeles of a triangle=180°therefore x+x+x=180° 3x=180° x=180°÷3 x=60°

it can be 60 degree equilateral triangle

Each angle = x,total summation = 3 * x,as we know,total summation of the angle in a triangle is of 180°,hence,3 * x = 180°,Or,x = 60°,so,value of x = 60°.

As its an equilateral triangle .so x = 60°

Uses of Diamond:1)Diamond membranes are durable, resistant to heat, and transparent, making them highly useful. Because diamonds are so hard and durable, they are ideal for grinding, cutting, drilling, and polishing. When used as an abrasive, very small pieces of diamond are embedded into grinding wheels, saw blades, or drill bits.2)The most common uses for diamonds outside of fine jewelry are for industrial applications. Because diamonds are so strong (scoring a 10 on the Mohs Hardness Scale), they are extremely effective at polishing, cutting, and drilling

Let the ages of Jayant, Prem and Saransh 10 years ago be 2x, 3x and 4x years respectively.

Then, (2x + 10) + (3x + 10) + (4x + 10) = 93

=> 9x = 63

=> x = 7.

Saransh's present age = (4x + 10)

= 38 years.

Let age of Pavani be xThen age of Mother be 50 - x

Ten years agoAge of Pavani = x - 10Age of Mother = 50 - x - 10= 40 - x

Then, (x - 10)*(40 - x) = 30040x - x^2 - 400 + 10x = 300x^2 - 50x + 700 = 0

For this equation:Discriminant =(-50*-50) - 4*1*700 = 02500 - 2800 = - 300

Since Discriminant is less than zero. So given equation have no real roots.

Therefore, its not possible

1X+2X+3X+(10×3)=906X=90-306X=60X=10B=2XB=2×10=2020+10=30✔️

Let 10 years ago age of A, B and C are x, 2x and 3x respectively

Present age of A, B and C are(x + 10), (2x + 10), (3x + 10) respectively

As per given condition(x+10) + (2x+10) + (3x+10) = 906x + 30 = 906x = 60x = 60/6 = 10

Therefore,Present age of B = 2x + 10= 2*10 + 10= 30 years

i) x=0ii) x=-1iii)-2,-3iv) x=4

X=0X=-1X= -2,-3X=4

0,-1,-2,-3 ,4 is the correct answer of the given question

x=0x=-1x=-2,-3x=4

The least no. which is multiplied is 4 × 6× 6144

X³ - 3x² - 9x - 5

= x³ + x² - 4x² - 4x - 5x - 5

= x²( x + 1) - 4x ( x + 1) - 5(x + 1)

= (x + 1)(x² - 4x - 5)

= (x + 1)(x² -5x + x - 5)

= (x + 1)(x - 5) (x + 1)

hence, (x +1), (x -5) and (x +1) are the factors of given polynomial .

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from left to right, value of y= f(x) are in order

3,5,7,9,11,13,15

Answer for ii)

7240 correct answer

money in his account now = 6025 - 2085 + 3200 = 7140 rs.. ANS..

money in his account now=6025-2085+3200=7140...Ans

7140 is the right answer.

the answer is 2.7

7)let angle be xthen supplementary=180-xacc. to question 5x=180-x6x=180x=30°so angles are 30° & 150°8)if one angle is x then other is its supplementary i.e. 180-xacc. to question x+30=180-x2x=180-30=150x=75°angles are 75°,105°

(cotA -cosA)/(cotA + cosA) = (cosecA-1)/(cosecA+1)

(cotA -cosA)/(cotA + cosA)

((cosA/sinA)-cosA)/((cosA/sinA)-cosA) cotA=cosA/sinA

taking cosA common from numretor nd denominatr nd cancelling it we get

((1/sinA)-1)/((1/sinA)+1) since 1/sinA=cosecA

therfore

(cosecA-1)/(cosecA+1)

13 kg is right answer of this question .please like my answer and accept as best.

y= 52x+3y= 11=> 2x +3(5)=11=> 2x = 11-15=> 2x = -4=> X = -2.

Please hit the like button if this helped you

(y-x)-(1/2){(2x+y)-(6x+5y)}

(y-x)-(1/2){2x+y-6x-5y}

(y-x)-(1/2){-4x-4y}

(y-x)+(2)(x+y)

=y-x+2x+2y

=x+3y

2x + 3y = 2 ....(1)

x - 2y = 8 .....(2)

2 × (1) + 3 × (2)

4x + 6y = 4

3x - 6y = 24

7x = 28x = 4

So, 2y = x - 8

2y = -4

y = -2

f(x) =y=2x-3x=(y+3)/2inverse of f(x) =(x+3) /2

Good Job bro

Work done by A in one day =1/40and by B =1/60hence if they work together1/40+1/60=100/2400=1/24hence they can complete work together in 24 days

Thanks

Total cost = Rs. 176Rate of charge = 25 paise per sq.cm = Rs. 0.25 per sq.cm

Total cost of painting cone = Total surface area of cone * Rate of charge=> Total surface area of cone = Total cost of painting cone / Rate of charge= 176/0.25= 704 sq.cm

Let radius of cone be r cmslant height (l) = 25 cm

Total surface area of cone = πr(r+l)=> 704 = πr(r+l)=> 704 = 22r(r+25)/7=> 704*7/22 = r^2+25r=> 224 = r^2+25r=> 0 = r^2+25r-224=> 0 = r^2+32r-7r-224=> 0 = r(r+32)-7(r+32)=> 0 = (r-7)(r+32)=> 0 = r-7 or 0 = r+32=> r = 7 or -32

Discarding negative value as radius cannot be negativeTherefore, radius of cone = 7 cm

By Pythagoras Theorem, height of cone = (l^2-r^2)^1/2= (25^2-7^2)^1/2= (625-49)^1/2= (576)^1/2= 24 cm

Therefore, volume of cone = πr^2h/3= 22*7*7*24/3*7= 1232 cu. cm

r-q is the set of irrational

1) Sum of (3x - y +11) and (-y - 11)= 3x - 2y

Now as per given condition(3x - 2y) - (3x - y - 11)= - y + 11

2) Sum of (4 + 3x) and (5 - 4x +2x^2) = 2x^2 - x + 9Sum of (3x^2 - 5x) and (-x^2 + 2x + 5) = 2x^2 - 3x + 5

Now as per given condition(2x^2 - x + 9) - (2x^2 - 3x + 5)= 2x + 4

Let the dimensions of the cubiod are length = l cm, breadth= b cm, height = h cm

given lb =15sq cm --(1)bh = 20 sq cm --(2)lh = 12 sq cm ---(3)multiply (1) ,(2 ) and (3)

lb*bh*lh = 15*20 *12

(lbh)²=3600∴

lbh = √3600volume of the cubiod = 60 cu cm

The cube total surface area is 6a²but when on of its part is taken off the remaining total surface area is 5a²so cost will be5a²×cost of painting; where a=edges of cube5*25*25*0.15=468.75