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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 68701. |
Prove the identity1-cote1-tanθ |
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| 68702. |
1. What do you mean by online identity? List some threats to your online identity |
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Answer» Internet identity(IID), alsoonline identityorinternetpersona, is a socialidentitythat anInternetuser establishes inonlinecommunities and websites. Itcanalso be considered as an actively constructed presentation of oneself.ThreatsTo Your Security When Using Social Media Having YourIdentityStolen.Identitythieves gather personal information from social media sites. ... Getting Your Computer Or Social Profile Hacked. Hackers love social networking, going right to the source to interject malicious code. ... Inadvertently Letting Stalkers Find You. ... Letting Burglars Know Your Whereabouts. |
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| 68703. |
14. A is thrice as fast as B, & able to finish a work in 60 days lessthan B. Find the time in which they can do it working together. |
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| 68704. |
5. A bucket can hold 16 1 of water. Ritapoured 5 1 750 ml of water in it. Howmuch water can this bucket hold more? |
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Answer» Given:-A bucket can hold 16 litres of water.Rita poured 5 l 750 ml of water in it. ∴Amount of water that the bucket can hold more=16 litres-5 litres 750 ml=10 litres 250 ml |
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| 68705. |
Prove the identity1-cote 1- tane |
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| 68706. |
Show that the diagonals of a parallelogram divideit into four triangles of equal area |
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| 68707. |
(ii) 11 r-31/3-3-1/3, show that 3x3-9x-10 = 0 |
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| 68708. |
An open tank is in the shape of a cube. The measure of its inner edge is 25 cm. Calculatethe cost of painting the inner sides at the rate of ? 0.15 per sq cm. |
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Answer» Answer: Hence the cost of painting the inner side of the tank is rupees 468.75 Step-by-step explanation: Surface area of the tank is: = 5 x 25 x 25 = 3125Cost of painting is : 3125 x 0.15 = 468.75
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| 68709. |
29. Calculate the value of load resistance40Ω60 ΩR, to which maximum power may betransferred from the circuit shown inFig. 2.69. Determine also the value of+maximum powerAns: R73.332 Px 5.45 w]120V |
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Answer» Please post only Mathematics question in this section |
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| 68710. |
Find the product with the help of identity rule.(x-5)(x-5) |
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Answer» x(x-5) - 5(x-5)= x^2 - 5x - 5x + 25= x^2 -10x + 25 |
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| 68711. |
P can finish a piece of work in 30 dayswhile Q can finish it in 40 days. In howmany days can P and Q workingtogether finish it? |
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Answer» P can finish a work in 30 days so 1/30Q can finish a work in 40 days so 1/40so if both will work together then 1/30+1/40=(4+3)/120so in 120/7 days they will complete the work |
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| 68712. |
1 litre to 750 ml |
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Answer» 1000:750=4:3 is the simplest ratio 4:3 is the correct answer 1000:759100:754:3correct answer the following question correct answer is 4:3 4:3 Is the correct answer of the given question 4:3 ratio is the right answer bhaiyya 1000:750=4:3 is the correct answer the correct answer for question is 1000:750 4:3 4:3 is the right answer |
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| 68713. |
Find the product with the help of identity rule(x-5)(x-5) |
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Answer» (x-5)(x-5)=(x-5)^2=x^2-10x+25 |
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| 68714. |
Show that the diagonals of a parallelogram divideit into four triangles of equal area. |
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| 68715. |
[है)- | [ड॥+,[$) ९०शक A 26 = .2 X8 (m) 7L =6V gl (M) - |
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| 68716. |
10.Find the value of a and b-2 - 6V |
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| 68717. |
an do a piece of work in 3 days B can do it is ó days. How long will A and B take to complete thework working together?i A cfi:- |
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Answer» A's 1 day's work=1/3 B's 1 day's work=1/6(A+B)'s 1 day's work=1/3+1/6=2+1/6=3/6=1/2DaysSo they can do in 2 days together |
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| 68718. |
x and y together finish a work in 8 days. Ifx alone can do it in 24 days, y alone willbe able to do it in.(a) 3 days (b) 5 days (c) 7 days (d) 12 days |
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Answer» (X + Y)'s one day work = 1/8 X's one day work = 1/24 Hence, Y's one day work = (1/8 - 1/24)= (3 - 1)/24= 2/24 = 1/12 Therefore, Y alone will complete work in 12 days (d) is correct option Thanku |
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| 68719. |
Reada. Mrs. Sharma bought1nd L 750 ml in the evening. How much milk did she buy?afternoon and 2s 56 L 750d to it. How |
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Answer» question was un clear |
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| 68720. |
Of four equal equilateral triangles, two are cut vertically into halvesand two whole are put together to make a rectangle:3 cmIfaside of the triangle is 1 metre, what is the arethe rectangle?a and the perimeter of |
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| 68721. |
Question numbers 7 1012 ully 2Express 2431 as a product of its prime factors.?꡸ |
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Answer» The prime factors of2431 = 11*13*17 what is the lcm of this number 2431 |
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| 68722. |
5. The capacity of a water jug is 500 ml. The water level is 200 ml below the top.the level of water in jug. |
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Answer» So if 200ml below the top means 500-200 ml above the base= 300ml level of water |
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| 68723. |
yeats an28. A certain sum of money at simple interest amounts to Rs. 1012 inRs. 1067.20 in 4 years. The rate of interest per annum is |
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Answer» Let Sum of money = P, Rate of Interest = R, Simple Interest = SI We know, SI = P*R*T/100 For T = 2 1/2 years1012 = P + P*R*5/2001012 = P(1 + R/40)........(1) For T = 4 years1067.20 = P + P*R*4/1001067.20 = P(1 + R/25)........(2) Now, 1012/ = (1 + R/40)/1067.20 (1 + R/25) 253/266.8 = 25(40 + R)/40(25 + R 253*40(25 + R) = 266.8*25(40 + R) 253*8(25 + R) = 266.8*5(40 + R) 50600 + 2024R = 53360 + 1334R 2024R - 1334R = 53360 - 50600 690R = 2760 R = 2760/690 = 4% Therefore, Rate of Interest = 4% make a o one I ok k |
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| 68724. |
A alone can do a piece of work in 12 days and B alone can do the same work in15 days. A works alone for 4 days. In how many days will A and B togetherthe remaining work? |
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Answer» answer is getting 4 4/9 A can do work in 12 days so in one day he can complete=1/12B can do work in 15 days so in one day he can complete=1/15if both work together then in one day work can complete=1/12+1/15=(5+4)/60=3/20 A alone work for 4 days s0 work done 4/12=1/3remaining work 1-1/3=2/3now both are working together so days required=(2/3)/(3/20)=(2×20)/9=40/9=5 days. |
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| 68725. |
a can complete a piece of works in 3 days b&a together can fill the same piece of work in 2 days how many days does it take to complete the work alone |
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Answer» 5 days I hope you will understand please like it as a best 1 day = 1/xA and B complete the work in 2dayA and B = 1/21/3+1/x=1/21/x=1/2–1/31/x= 1/6x= 6 answer |
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| 68726. |
Mrs. Sharma mixed 32 2 500 ml of water with 28 L650 ml of orange syrup to makedrinks for a birthday party. How many litres of drinks did she make? |
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Answer» total water quantities = 32l 500mltotal orange 🍊 syrup quantity=28l 650mltotal quantities make a drink 🍻🍹🍻 = 32l 500ml+28l 650ml= 61l 150 ml ans. Tota quantity of water mixed with orange syrup = 32 l 500 mlTotal quantity of orange syrup = 28 l 650 ml Total quantity of drinks she made for the birthday party is = 32 l 500 ml + 28 l 650 ml = 61 l 150 ml Ans- She made 61 l 150 ml of drinks for the birthday party.
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| 68727. |
W 4. A and B can do a piece of work in 18 daysand C in 24 days, C and A in 36 days. In howmany days can they do it all workingtogether?(a) 16 days(b) 17 days(C) 15 days(d) of these |
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| 68728. |
B, C and D enter into a partnership. A and B together put in as muchas C and D together, B puts in twice as much as C, D as much as B and Ctogether. What share should each receive out of a total profit of Rs 10000? |
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| 68729. |
How long will a boy take to run round a square field of side 35 metres, if he runs at the rate of9 km/h? |
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Answer» Perimeter of the square field=(35×4)m=140 m Speed=9 km/h=2.5 m/s∴Time taken to cover the perimeter=perimeter/speed=140/2.5=56 secs |
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| 68730. |
13. How long will a boy take to run round a square field of side 35 metres, if he runs at the ra9 km/h? |
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| 68731. |
If the mean of the following data is 17.45, find the value of P.यदि निम्न आँकड़ों का माध्य 17.45 है, तो P का मान ज्ञात कीजिए।X, | 15 | 16 | 17 | 18 | 19 | 203| 8| 10 | |
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| 68732. |
IlIBle of water molecules?10. Calculate the number of molecules of suiphur (S,) pres11. Calculate the number of aluminium ions present in 0.051 B16 g of solid sulphur.aluminium oxide. |
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Answer» The molecules formula of sulphur is given to be S8 ( it Contains 8 atoms of sulphur ). So , the molecular mass of sulphur molecule is 32 × 8 = 256 u. This means that 1 mole of sulphur molecules is equal to 256 grams. Now, 256 g of sulphur = 1 mole of sulphur molecules So, 16 g of sulphur = 1/ 256 × 16 mole of sulphur molecules = 0.0625 mole of sulphur molecules Also, 1 mole of sulphur molecules = 6.023 × 10²³ molecules So, 0.0625 mole of sulphur molecules = 6.025 × 10²³ × 0.0625 molecules = 3.76 × 10²² molecules 1 mole of aluminium oxide (Al2O3) = 2*27 + 3 * 16 = 102 g i.e., 102 g of Al2O3 = 6.022 * 1023 molecules of Al2O3 Then, 0.051 g of Al2O3 contains = = 3.011 * 1020 molecules of Al2O3 The number of aluminium ions (Al3+) present in one molecule of aluminium oxide is 2. Therefore, the number of aluminium ions (Al3+) present in 3.011 * 1020 molecules (0.051 g ) of aluminium oxide (Al2O3) = 2 * 3.011 * 1020 = 6.022 * 1020=6142.44 |
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| 68733. |
4. Observe the following patter112= 1211012 1020110012 10020011000012 = 1 2 1100000012 |
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Answer» as patterns follows we put number of as given in number that are squared100001² = 1000020000110000001² = 100000020000001 |
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| 68734. |
ai7. A and B can do a job together in 12 days. If A is 2 times as efficient as B, then how many days shall Balone take to complete the work? |
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| 68735. |
(b)There are 60 students in a class. 10% of them scored marks above 90, 15% ofthem scored between 80 and 90, 15% of them scored between 70 and 80 andthe rest scored below 70. How many students scored marks below 70? Findtheir percentage also. |
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| 68736. |
A wire is bent to form a square of side 22 cm. if the wire is rebent to form a circle, find its radius.Find the area of circular garden with diameter 8 m. |
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| 68737. |
5 A alone can do a piece of work in 8 days. A and B together can finish the same work in 6 days.If B alone is doing the work, how long will he take? |
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Answer» Let the work to be done is W rate of doing work / day for A = W/8 suppose rate of doing work for B is x and both A and B can finish W work in 6 days so , 6*(w/8 +x) = W => 3w/4 +6x = W=> 6x = w-3w/4 = w/4 so , x = w/4*6 = w/24 so, rate of doing work for B per day is = w/24 zo, B can do whole w work in 24 days. |
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| 68738. |
A and B can do a piece of work in 12 days B and C in 15 days c and a in 20 days how much time will A alone take to finish the work |
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| 68739. |
5Working together A & B will complete a job in45 days of a works alone to completes halfthe job & then B takes over & completes.the remaining half of the job, they will completethe task in 20 days. Blow long boy will A alonetake to do the job if B is more efficient than Art |
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Answer» hey Gloria my name is harsh ray it you have any doubts regarding maths you can clear your doubts in my whatsapp by the way I am an iitan 9634854418 |
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| 68740. |
Suyashscored10 marks more in second test than that in the first.5 times the score of the second test is the same as square of the score in thein the first test.find the score in first text। |
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Answer» Let the marks in his 1st test be xMarks in 2nd rest=x+10As given in question 5 times the score of second test = square of 1st So marks in First test is 10 |
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| 68741. |
10.Find the value of p, if the mean of the following distribution is 20.15217319 20+ p 234 5pt:6 |
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| 68742. |
acircle.FindtheareaFind the pennicter o a sA wire in the shape of a square of side 22 cm is cut and bent again in the form of |
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Answer» Length of wire = Perimeter of square = 4*22 = 88 cmCircumference of circle = Length of wire = 88cm=> 2*(22/7)*r = 88=> r = 14=> Area = (22/7)*r*r= (22/7)*14*14= 616 sq cm PLEASE HIT THE LIKE BUTTON thanks |
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| 68743. |
When the side of a square increases by 5 cm, the area of the square increases by 135 cm2. Find thelength of the side of the square.22. |
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| 68744. |
A and B, working together can finish a ptece of work in 6 days, while A alone can do it in9 days. How much time will B alone take to finish it? |
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Answer» I awant full answer 😅😅😅 |
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| 68745. |
3. A and B, working together can finish a piece of work in 6 days, while A alone can do it in9 days. How much time will B alone take to finish it? |
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| 68746. |
II. Problem on distance, ratos, PUWI Uis)2-=120. The perpendicular distance from origin to the line -pseca pcos ec a3) p tan 204)|p|1) p sin 202) p cos 20 |
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| 68747. |
Ajita score 10 more mark in is mathematic test out of 30, 9 mark would have been the square of actual mark how many mark did she get in text |
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Answer» If 9 is the square of the actual mark,the the actual mark is the root over of 9 that is 3.Therefore he actually would have got 3 marks |
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| 68748. |
(11) A person found that30,600 in his R.D.passbook after one yearWhat is his monthly contribution towards the R.D.? |
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Answer» Monthly contribution = 30600/12 =₹2550 |
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| 68749. |
A microscope is focussed on a mark on a sheet of paper. When a glass slab of 3 cm thicknessis placed over the mark, the microscope had to be raised by 1 cm to bring the mark into focusmark into focusagain. What is the refractive index of the glass?lAns. 1.5]lul hauing 22 cm side. When viewed from |
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| 68750. |
. The average marks of ten students is 60. If the highest mark is excluded, the averageis 59. Find the highest mark. |
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Answer» the total sum of all marks = avg*no. of students = 60*10 = 600 now on excluding one number, the total marks = 59*9 = 531 so, the highest marks = 600-531 = 69. |
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