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the answer of your question is 7,822,144

Let total salary be x

Let he spend on rent = 2yLet he spend on EMI = yLet he spend on Other expenses = 3y

As per given condition2y + y = 106503y = 10650y = 10650/3 = 3550

Now,Total expenses = (2y + y + 3y)= 6y

Then, 6y = (60/100)*x6*3550 = (60/100)*xx = 355*100 = 35500

Therefore,Rahim monthly salary = Rs 35500

i) (88-55) - 15 = 33 - 15 = 18 ii) 88 - ( 55-15) = 88 - 40 = 48 iii) (675-420)-150 = 255-150 = 105 iv) 675 - (420-150) = 675 - 270 = 405

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the answer will be 176

22 + 88 = 110

94 is the write answer

Let age of priyanka=xLet age of deepika=y

x+y=34y=x+6

x+x+6=342x=28x=14y=20

Therefore, age of priyanka= 14 yearsage of deepika= 20 years

Rupali + Deepali = 34 Rupali = Deepali + 6 Deepali + Deepali + 6 = 34 2*Deepali = 28 Deepali = 14 years Rupali = 14 + 6 = 20 years

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Let his income be Rs.xExpenditure = 66*2/3% of xSaving = 33*1/3% of xA/q,33*1/3% of x = Rs.1200x = 1200*100*3/100 = 3600So his monthly expenses = 66*2/3% of 3600 = Rs. 2400

Rajni monthly income is rupees 21,000 Her monthly expenses are 6/7 offer income how much does she save every month

in a class 13 45 student if 3 upon 5 of a student are boys find the number of boys in the class

10% is saved which is equal to 900 therefore 100 % = 9000 which is option b

9000.

Denote the incomes of the two person by 9x and 7x and their expenditures by 4y and 3y respectively.

Then the equations formed in the situation is given by:

9x – 4y = 2000 ... (1)

7x – 3y = 2000 ... (2)

Step 1: Multiply Equation (1) by 3 and Equation (2) by 4 to make the coefficients ofy equal. Then you get the equations:

27x – 12y = 6000 ... (3)

28x – 12y = 8000 ... (4)

Step 2: Subtract Equation (3) from Equation (4) to eliminate y, because the coefficients of y are the same. So,you get

(28x – 27x) – (12y – 12y) = 8000 – 6000

x = 2000

Step 3: Substituting this value of x in (1),

9(2000) – 4y = 2000

y = 4000

The solution of the equations is x = 2000, y = 4000.

Therefore, the monthly incomesof the persons are Rs. 18,000 and Rs. 14,000, respectively.

20:18 is the correct answer me to

20:18 is answer for this question

the present age of Ajay is 26 years

26 year is the correct answer

ajay age is 26 years

present age of Ajay is 26 years and Navin is 30.

the present age of Ajay is 26 year

answer is 16 right answer

26 is the right answer

26 is answer for this question

ajay's present age is 26 years

26 year is the correct answer

20:18 is all rights answer

26 years is correct you can check

26 years old is the correct answer

present age of Ajay is 26 year and Navin is 30

26 is the right answer

26 is the right answer

26 is the right answer

7.35 is the right answer

7.35 is the right answer

the right age of ajay is 126

the right age of ajay is 26

20:18 is the correct answer h

his present age is 26

Let leena be xTherefore, Ravi = 3x & Ajay = 5(3x) = 15xx+3x+15x=142519x=1425x = 1425/19 = 75Therefore,Leena = x = 75 RsRavi = 3x = 75 • 3 = 225 RsAjay = 15x = 75 • 15 = 1125 Rs

Let their salaries be 9x and 7xlet their expenditure be 4y and 3yso,ATQ9x-4y=2000—(1)7x-3y=2000—(2)so,from (1)x=(2000+4y)/9—(3)put x in (2)7[(2000+4y)/9]-3y=2000(14000+28y)/9-3y=2000(14000+28y-27y)/9=2000y+14000=18000y=4000

now put y in (3)x=(2000+4×4000)/9x=(2000+16000)/9x=18000/9x=2000

so,salary of first person=9×2000=Rs.18000 salary of second person=7×2000=Rs.14000

let he pay in n th terma= 30500d= -1500a+(n-1)d= ln30500+(n-1)(-1500)=325000

Let salary of wife be x.Thus, salary of man = x+600.

According to question,

(x+600/10) + (x/6) = 1500

(3*(x+600)/10*3) + (5*x/6*5) = 1500

(3x+1800/30) + (5x/30) = 1500

3x + 1800 + 5x = 1500*30

8x + 1800 = 45000

8x = 45000 - 1800

8x = 43200

x = 43200/8

x = 5400

Thus, salary of wife = 5400 and salary of man = 5400 + 600 = 6000.

first one answer -98 xy

1) 125/100 = 1.25

2)95/100. = 0.95

3)70/100. =0.70

107 / 100 = 1.07

=1500*12=18000 orphanage

Raju's father donates =

1500*12 = 18000 rupees

sec70sin20 - cos20cosec70

sec(90 - 20)sin20 - cos(90 - 70)cosec70

cosec70 sin20 - sin20 cosec70

As both are same,

=> 0

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as we know sum of all the angles in a quadrilateral = 360°so suppose angle D is xthen x+140+100=360x= 120°

(3x+7)+(2x-19)+x=1806x-12=180x-2=30x=2

angle AOC= 3x+7= 71angle COD= 2x-19= 45angle DOB= x= 32

5 a + a - 7 a = - a

5a+a+(-7a)5a+a-7a6a-7a(-a)

Lets assume that√7 is rational number.ie√7=p/q.suppose p/q have common factor thenwe divide by the common factor to get√7 =a/b were a and b are co-prime number.that is a and b have no common factor.√7 =a/b co- prime number√7= a/ba=√7bsquaringa²=7b² .......1a² is divisible by 7a=7csubstituting values in 1(7c)²=7b²49c²=7b²7c²=b²b²=7c²b² is divisible by 7that is a and b have atleast one common factor 7. This is contridite to the fact that a and b have no common factor.This is happen because of our wrong assumption.√7 is irrational

Ans :- The numbers in a Nielsenratingact as a percentage. Nielsen estimates a total audience for a certain span of time, andratingscount as percentage points in that estimated audience.

Nielsen doesn't say whether that number includes all televisions, or just televisions with the access to programs that it's measuring.

mead or median or mode or range

by using teta method

12 ×15568

total solution with diagram

The answer is 6392915

A)-240B)-672C)-504D)-825

hay friend your answer is it