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69101.

Malli donated L of hersalvry to a vidousschoolashran Isaldry was spent onHoteller Hasselbaai is, kod mene21000Find her monthly SalaryPrepare a list of propertiesA+

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69102.

(Use π = 3.14)The number of sides of two regular polygons are in the ratio 5 4 and thedifference between their interior angles is 6°. Find the number of sides in thetwo polygons

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69103.

Two sides of a triangle are given by the rootsof the equation -5x+6 0 and the anglebetween the sides is T/3.Then the perimeterof the triangle is

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69104.

Two sides of a triangle are 6 cm and 8 cm. Ifheight of the triangle corresponding to 6 cmside is 4 cm; find:

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area of traingle is :1/2 x 6 x 4=12cm^2

69105.

The lengths of two sides of a triangle are 6 cm and 8 cm. Between which two numbers can length dthe third side fall?

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In triangle sum of 2 sides must be greater than the 3rd side.

So, the third > 8 - 6 = 2 and also the third < 8 + 6 = 14.

So, the answer is 2 < third side < 14.

The third side lies between(2,14).

69106.

2. Two positive numbers x and y are inversely proportional. If x increases by 20%, then percentagedecrease in y is:

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tnx ur answer is correct 😊

69107.

1 Find the pecentage increase or percentage decrease in each case.Last year the bus fare was 50. This year it is 60

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69108.

riangle, the measure of two sides are 6 cm and 7 cm. What can be the measure of third side?

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a²+b² = c²

6²+7² = c²

c = √36+49

c = √85

69109.

13. A man had 720000000 with him. He spent 13607085 on buying a school building Howmuch money to left with him?

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69110.

13. A man had 20000000 with him. He spent 13607085 on buying a school building, Howmuch money is left with him?

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69111.

4. Siya sold her old computer for 16,500. If she suffered a loss of 5,500, find the loss percent.eller bus lemon

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69112.

Nikhil started a business with an initial capital of Rs. 100000. If he suffered a loss of 13%in the first ear. then find the capital for second year.

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69113.

1)The measures of angles of a triangle are in ratio 5:6:7. Find the measures.TC on

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We know that the sum of all angles of a triangle is180. Then let the angle be xSo, 5x+6x+7x=180X=12

69114.

1)The measures of angles of a triangle are in ratio 5:6:7. Find the measures.Try0

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69115.

Anil bought a house at 485000 and spent themoney on its maintenance 52000. After then,he sold it for 620000. Find his profit.

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House is bought for Rs.485000

Extra expenses = 52000

So total cost price = 485000 + 52000

= 537000

Then, it is sold for Rs.620000

That is Selling Price (SP) = Rs.620000

Profit % = ((SP-CP)/CP)*100

Profit % = ((620000–537000)/537000)*100

Profit % = 15.45%

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69116.

A cottage industry produces a certain number of pottery articles in a day. It was oon a particular day that the cost of production of each article (in rupees) was 3 more thentwice the number of articles produced on that day, If the total cost of productionday was Rs 90, find the number of articles prodĂşced and the cost of each article.6.production on that

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69117.

as well as tiat of 3o lerIs Is J00.ILLUSTRATION 4.12In an A.P. of 99 terms, the sum of all theodd-numbered terms is 2550. Then find the sum of all the 99terms of the A.P

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We know that: S(n) = (n/2){ T(1) + T(n) }

Given that:

(50/2){ T(1) + T(99) } = 2550 T(1) + T(99) = 102

Now sum of all the 99 terms:

(99/2) {T(1) + T(99)} = (99/2)*102 = 5049

69118.

\left. \begin{array} { r } { ( n + 2 ) ! = 2550 \times ( n ! ) } \\ { F \text { ind } n } \end{array} \right.

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69119.

Example 1: The price of a skirt is decreasedfrom 3000 to 2550. What is the percentagedecrease?

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69120.

e other two Sides6,cottage industry produces a certain number of pottery articles in a day It was observerda particular day that the cost of production of each article (in rupees) was 3 more thance the number of articles produced on that day. Ifthe total cost of production on thatday was 90, find the number of articles produced and the cost of each article.

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The total cost of production= Rs.90

Let the number of pottery articles produced bex.Therefore, cost of production of each article = Rs (2x+ 3)

the total cost of production = no. ofpottery articles produced× cost of production

A.T.Q

90.= x(2x+ 3) = 0

⇒ 2x²+ 3x– 90 = 0⇒ 2x²+ 15x-12x– 90 = 0⇒x(2x+ 15) -6(2x+ 15) = 0⇒ (2x+ 15)(x– 6) = 0

Now 2x+15=0⇒2x= - 15

⇒x= -15/2⇒x– 6 = 0

⇒x=6

⇒x= -15/2 orx= 6

As the number of articles produced can only be a positive integer, therefore, x can only be 6.

Hence, number of articles produced = 6Cost of each article = 2 × 6 + 3 = Rs 15.

69121.

4t.other two sides.5. A cottage industry produces a certain number of pottery articles in a day, It was observedon a particular day that the cost of production of each article (in rupees) was 3 more thantwice the number of articles produced on that day. If the total cost of production on thatday was Rs 90, find the number of articles produced and the cost of each article.hoce nerimeter is 28 meters and whose area is 40

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69122.

10his money and after losing 30% of his remainder he had ? 1260 left. How17. manAspent%ofhad he at first?miuch money

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69123.

10.IJ17, A man spent 1 0% of his money and after losing 30% of his remainder he had t 1260 left. How much moneyhad he at first?

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69124.

tt)18(c)30(d)1520. A man purchased a car for t 135000 and spent 25000 onrepairs. At what price was the car sold if he suffered 10%oss on it(a) 170000 144000 (c) 121500 (d) 150000

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69125.

Ratio and Proportion.*880 between Rajan and Kamal in the ratio56&amp; Divide 880 b

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69126.

speeds in metre/sec:(b) 446 km/hr

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44460 secend per hour

44460 second per hour is the right answer

kn/h se meter/sec m446×5/18=123.89

kn/h decimal meter / sec m446×5/15=123.89

123.89 m/sec is the best answer

123.89 m/sec is the correct answer of the given question

69127.

20. Anil spent 4 of his monthly income on food, 3 on other expenses and donated of hiincome for the education of orphan children. If he was left with 10, 000, find his mont

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Let the monthly income be x

All money and left money must combine to get the amount x. So,

1/4x +2/5x + 1/6x + 10000= x

implies

15x + 24x + 10x - 60x = -600000 (multiplied equation by 60 on both sides)implies

-11x = - 600000implies

x= 55,555.5

that's his monthly income

69128.

iseli300at4%for3yearssmont(n) final amountp.a.ow long will it take a certain sum of money to triple itself at 133% per annumsimple interest?yoars At the same

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SI = P*R*T/100

Let P = a, SI = 2a, R = 40/3%,T =?

Then,2a = (a*40/3*T)/100T = 2*100*3/40T = 15 years

69129.

CATETAGE-usingofeuclid'sas240 andalgorithm2550find theHOE

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288> 240a=288 and b=240288=240×1+ 48240=48×5+0there fore HCF of 288 and 240 is 48

288> 240a=288 and b=240288=240×1+ 48240=48×5+0there fore HCF of 288 and 240 is 48

288>240;a=288 and b=240; 288=240+48; 240=5×48; Hcf=288 and 240 is 48

69130.

W T R R SNH.70. (a+b)=F (8-8) - दूँ तर ०9 &gt; ? (दौन उत्तर नॉदवा.)

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69131.

LEVEL-2tage industry produces a certain number of pottery articles in a day. It wase inved on a particular day that the cost of production of each article (in rupees) was 3than twice the number of articles produced on that day. If the total cost ofction on that day wasR 90, find the number of articles produced and the cost ofrticle.INCERT

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69132.

\quad \text { Find } \sum _ { r = 1 } ^ { n } ( 2 r - 8 )

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thanks

69133.

17, A man spent 10% of his money and after losing 30% of hisremainder he had t 1260 let. How much moneyhad he at first?

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69134.

In the class 8h in DAV school the average score ofgirls and boys is 73 is 71 respectively. The average scorefor the whole class 71.8. The percentage ofboys is(a) 50% .(b) 40%(c) 60%(d) 70 %

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1

2

69135.

Am gets 499% marks in an examination. His score is 294. His friend Rajan ges14in the same examination. Express Rajan's score as per cent.

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let total marks be XX×49%=294X×(49/100)=294X=(294×100)/49X=600

Rajan marks in percentage =(372×100)/600=62% ans.

69136.

B) Attempt any one.i) Find n if "Ps - 420"Ps)

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ⁿP₅=42×ⁿP₃or, n!/(n-5)!=42×n!/(n-3)!or, 1/(n-5)!=42/(n-3)(n-4)(n-5)!or, 1=42/(n²-3n-4n+12)or, n²-7n+12=42or, n²-7n-30=0or, n²-10n+3n-30=0or, n(n-10)+3(n-10)=0or, (n-10)(n+3)=0Either, n-10=0or, n=10Or, n+3=0or, n=-3∵, n can not be negative ;∴, n=10 Ans.

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69137.

(c) Ps Rs 2.500, R ::8% per annum, n-3 years

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69138.

The price of car was र72000 last year. It hai increased by 25% this year. What is the price now??

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69139.

Last year, oranges were available at ? 24 perdozen; but this year, they are available at50 per score. Find the percentage changein the price of oranges [!score=20.]

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69140.

14.Amit sold an umbrella for Rs 680, losing 15%. The cost price of the umbrella isa) Rs 782b) Rs 800c) 578d) none

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SP = 680loss % = 15 %let CP be x so,According to question,x - 15% of x = 680x - (15/100) × x = 680x - (3x/20) = 68017x/20 = 680x = (680×20)/17x = 800So, CP is Rs 800option (b) is correct

69141.

Sita bought an umbrella from a shop at Rs 255 after getting a discount of 15%on the marked price.What was the marked price of the umbrella?

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69142.

4. The sum to co of the series -5, 25,-125, 625,can be written as(a) 2 (-5)hÎŁ_5kk-1(b) ÎŁ5k(c)(d) nok-1

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As the series is in the increasing powers of (-5)Henceanswer will be sum of k from 1 to infinity (-5)^kHence option a

bna dijiye na

home work hey

69143.

हि; Find जीप) रहा8% 8 the (9191: लिSIS + Jon+ &amp;S RE e

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5√5 x*x + 30x + 8√5 = 5√5 x*x + 20x + 10x + 8√5 = 5x(√5x + 4)+2√5(√5x+4) = (5x+2√5)(√5x+4)

69144.

Tlheurem &amp;s o ne is dron arallel as ome side ef a triangle a innere theecher co sidies n omines ps the cher two sids are dvided in the sune

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thanks

69145.

neXsolid wooden toy is in the shape of a right circular五emisphere. If the radius of the hemisphere is 4.2 cm andof the toy is 10.2 cm, find the volume of the wooden toy.comounted on aurmounted by conical roo

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V = (4/3)πr³So the volume of a hemisphere will be half of that, which is (2/3)πr³

The volume of a cone of base radius r and height h is:V = (1/3)πr²h

We are told that r = 4.2 cm

The total height of the toy is made up of (the height of the cone) + (height of hemisphere)So the height of the cone = 10.2 - 4.2 = 6 cm

So the volume of the toy = (volume of hemisphere + volume of cone)= (2/3)π * 4.2³ + (1/3)π * 4.2² * 6= 155.2 cm³ + 110.8 cm³= 266 cm³

69146.

1.f(x) = t2-1,x&gt;2(A)lim f(x)=ミ2(B) | |rlin n+f(x) =(C) What does this imply about the lim f(x)? Explain.

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A) lim x→2- is 2(2)-3 = 1 B) lim x→2+ is (2)²-1 = 3

since both are not equal so, limit at x→2 is not defined.

69147.

12. Kanika scored 33 marks in English. This is twice of what she scored last year. How manymarks did Kanika score last year?

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plz choose my answer the best answer

16.5 is the right answer

kanika scored 33 marks

The twice scored last year

33+33 =66

Ans.in last year kanika scored 66 marks in english

66 is the correct answer

66 is the correct answer

69148.

the divisor.3. HExample 1 Find the quotient and the remainder whenx* +1 is divided by x-1.

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put X=1hence(1)^4+1=1+1=2

69149.

TOTESSimllall!EXAMPLE 1. Evaluate :

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69150.

EXAMPLE 1.Compare the fractions and

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In order to compare fractions denominator should be same

For 5/6 and 8/9Take LCM of 6 and 9 which is 18

Now fraction will become 15/18 and 16/18 respectively Now 16/18 >15/18

Thus 8/9>5/6