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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 69151. |
\sqrt { \sec ^ { 2 } \theta + \csc ^ { 2 } \theta } = \tan \theta + \cot \theta 7. Prove the result: \/(SECQG + cose |
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| 69152. |
Among a group of 90 students, 40 like lmathematics and 60 like chemistry. If 6 studentslike neither, find how many like both thesubjects. (90 i 8 |
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| 69153. |
Among a group of 90 students, 40 likemathematics and 60 like chemistry. If 6 studentslike neither, find how many like both thesubjects. (90駉44呵射何370 40顎啊万1 |
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Answer» hence 16 students like both. Aur ek question hain plz solved kar do |
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| 69154. |
f o5.ne Jon SeCO S a |
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Answer» (cos)/(1-sin)=3so (1-sin)/cos=1/3sec-tan=1/3now sec^2-tan^2=1so (sec-tan)(sec+tan)=1so sec+tan=3and sec-tan=1/3sec+tan+sec-tan=3+1/32sec=10/3so sec=5/3 |
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| 69155. |
atb. f(x)=, llim f(x) 1 and-linnof(x)=1, t(x) 1, then prove thatf(-2) f (2) 13,f(x)=,2.x +1 x-0 |
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| 69156. |
41. If f"(x)-4x3-2such that f(2)=0, then find f(x) |
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Answer» f'(x)=4x^3-3/(x^4)=4x^3-3x^(-4)f(x)=4x^4/4-3x^(-5)*(-4)+c where c is a constant =x^4+12/x^5+cf(2)=02^4+12/(2)^5+c=016+12/32+c=0c=-16-12/32so f(x)=x^4+12/(x)^5-16-12/32 |
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| 69157. |
ax2 + b23. f(x) =ー2lim f(x) = 1 and lim f(x)-1, then prove that f(-2)-f (2) = 1.x-10 |
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| 69158. |
-DG o5 0 W & थे छा. ७ SR |
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Answer» sin A = cos A;tan A = 1;A = 45°2A = 90° hit like if you find it useful |
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| 69159. |
Example 1 : If f (x)x-2x +7, find f (0) + f (2).Solution : We have, |
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Answer» f(x) = x⁴-2x+7 f(0) = 0+-2(0)+7 = 7 f(2) = 2⁴-2*2+7 = 16-4+7 = 19 f(0)+f(2) = 7+19 = 26 Like my answer if you find it useful! how do you think about us, based on year experience |
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| 69160. |
train gt down at station X, 75% of the remaining gt dom at station Y40% of the passengers from athe remaining 12 passengers were taken to station Z, find the original number of14 |
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Answer» Let the total percentage at starting of the bus=100%Then 40% got down at station X, So remaining in the bus=60%Then 75% of the remaining got down at station Y= 60% -75% of 60% Remaining passengers= 60%-45%=15% So 15% passengers= 12 passengers So 100% passengers= 80 passengers |
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| 69161. |
ADATEofferentiatethefollowing functions.Wo S. t. 2le cose? |
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| 69162. |
An Indian FestivalDiwali |
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Answer» Diwali(also:DeepavaliorDipavali) is one ofIndia's biggestfestivals. The word 'Diwali' means rows of lighted lamps. It is a festival of lights and Hindus celebrate it with joy. During this festival, people light up theirhousesandshopswith Diyas (Small cup-shaped oil lamp made of baked clay). They worship the LordGaneshafor good welfare and prosperity and GoddessLakshmifor wealth and wisdom. |
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| 69163. |
A kite is Bying at a height of 60 m above the ground. The string attached to the kdetemporarily tied to a point on the ground. The inclination of the string with the groundus 60) Find the length of the string, Msunung that there is no slack in the string.ildiine. The angle of |
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Answer» part 1 |
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| 69164. |
If f: R→ ( 0 , 2 ) defined by-Xf(x)=ex -e-x.+ 1is invertible find f-1(X).e +e |
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| 69165. |
if f(x)=x^2+5x+1,find f(1)and f(0) |
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| 69166. |
X-1(ii) if f(x) =when x # 1 and f(x) =When x = 1, find f (1), if it exists.CVBe |
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Answer» x=2 equate f(x)=x-1÷2x-7x+5=-1/3 |
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| 69167. |
Let f be the function defined by the rule f (60) = 4x2 + 2x - 3. Find f (2): f (-1); f(a) andflf (1)). |
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Answer» f(x)=4x^2+2x-3; f(-1)=4(-1)^2+2(-1)-3=4-2-3=4-5=-1 f(2)=4(2)^2+2(2)-3=4(4)-4-3=16-1=15 |
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| 69168. |
State the domain and the range of the following functions. Exhibit them by a formula. |
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Answer» i) The domain is x - [0,4] The range is y =[0,16] formula y = x² ii) The domain is = [1,5] The range is = [3,11] formula is y = 2x+1 tysm |
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| 69169. |
A person is flying a kite at an angle of elevation Îą and the length of thread fromhis hand to kite is p. |
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| 69170. |
A kite is flying at a height of 60 m above the ground.The string attached to the kite is temporarily tied to a |
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Answer» A kite is flying at a height of 60 m above the ground. The string attached to the kite is tied at the ground. It makes an angle of 60° with the ground. Assuming that the string is straight, find the length of the string. (√3 =1.73) |
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| 69171. |
1. (a) The position of a particle movingin a straight line isgiven byx acosnt +bsin nt, Prove that itexecutes SHM of period 2n/n andamplitude va +b2, 1,25 |
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Answer» Here is the detailed derivation of amplitude. |
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| 69172. |
erthe following questions:Give one word for trembling of the Earth. |
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Answer» Trembling of earth means shaking of earth and one word for it is tremor. |
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| 69173. |
Ill Answer the following.11 If f(x)x2-1 find f (2)? |
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Answer» Givenf(x)=x^2 -1f(2)=(2)^2 -1=4-1=3 |
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| 69174. |
EXERCISE 8.11、In ΔΑ BC, right-angled at B. AB-24 cm. BC7 cm Determine .sin A, cos A(i)(i)sind, cos C |
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| 69175. |
16. What are the possible expressioare given below?Volume: 3x2-12r |
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Answer» 3x² - 12x Factorization gives possible expression 3x ( x - 4) 3 ( x² - 12x) x(3x - 12) |
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| 69176. |
Factorise the expressio(i) ax^2 + bx |
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Answer» x(ax+b).............. |
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| 69177. |
\begin{array}{l}{\text { LHint: Write the expressio }} \\ {\frac{1+\sec A}{\sec A}=\frac{\sin ^{2} A}{1-\cos A}}\end{array} |
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| 69178. |
02 qdentify the numerical coefficients of terms (other than constants) in the followingexpressio(Gv) 100m(vii) 3.14rIdentify terms whigh contain(ii) 1+1+7+7 Gii) x+2xy + 3y(v)-p+pq ) 12 a 08 b(vim) 2 0+ b)1000n(x) 0.1 y +001 y4.(a) |
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Answer» 1. -32. 1,1,13. 1,2,34.100,1000 |
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| 69179. |
ve the following (4- 11) identities:sind C |
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Answer» a) LHS: sin^4 + cos^4 + 2sin^2cos^2 - 2sin^2cos^2Look at the first three terms, it is the square of sum so it becomes (sin^2 + cos^2)^2 - 2sin^2cos^2 With Pythagorean theorem, sin^2 + cos^2 = 1therefore it becomes: 1 - 2sin^2cos^2 LHS = RHS |
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| 69180. |
7. tE two positive integers p and e are written as p-The sum of first a terms of an AP is given by Swritten as p a ani2+ 3n. Find the sixteenth term of the AP.. te which the pair of linear equations kr + y = k2 and r + ky-1 have infinitely |
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| 69181. |
EXERCISE 8AExpress each of the following ratios in simplest form:(1) 24 : 40(ii) 13.5 15tiv) 스-2 |
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| 69182. |
If the sum of first 'n' terms terms of an AP is given by Sn=4n²-3n, then find nth terms of an AP |
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| 69183. |
EXERCISE 14.2Factorise the following expressions.a^2 + 8a+ 16 (Gi) p^2-10 p + 25 (ii) 25m^2 +30m + 9 |
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| 69184. |
EXERCISE 8.11.Find the ratio ofthe following.(a)Speed ofa cycle 15 km per hour to5 m to 10 km(b)Convert the following ratios to percenta(a) 3:472% of25 students are good mmatema2.3, |
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| 69185. |
EXERCISE 14.2Factorise the following expressions.(i) a2+8a + 16 (ii) p-10 p +25(iv) 49y + 84yz+36z(vi) 121b2-88bc +16c.(vii) (1+m)2-4l.25 mp +30m+9(iii)(v) 4x2-8x +4Find the Polletwing expressio n(Hint. Expand (1+ m) first) |
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| 69186. |
Prove the following identities: |
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| 69187. |
itable identities(i) (102)^{3} |
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Answer» Use (a+b)² = a² + b² + 2ab So,(102)²= (100+2)² = 100² + 2² + 2×100 × 2= 10000 + 4 + 400= 10,404 102×102=10404 and agine 102 = 1061208 |
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| 69188. |
Q,12, Sum of the first n terms of an AP is53n Find the AP and also find its 16 |
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| 69189. |
The height of the ladder on fire brigade is 41 metre. The lower end ofthe ladder was kept at a distance of 9 metre from the building as shownin the figure. Find the height on the building at which the other end ofthe ladder can reachQ.9 metre |
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| 69190. |
Q.9.A dice is thrown. Find the probability of getting even number |
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| 69191. |
Convert the following ratios to percentage(a) 3:4 |
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Answer» 3:4 = 3/4 in percentage 3*100/4 = 300/4% = 75% thank you |
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| 69192. |
EXERCISE 8Afollowing ratios in simplest form(ii) 13.5: 15 |
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| 69193. |
if tan A=20/21,then find the values of trignometric ratios |
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| 69194. |
20. The graph of a linear polynomial is :(a) straight line (b) parabola(c) any curve |
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Answer» option (a) straight line is the right answer. straight line is correct answer straight line is the right answer. The graphof a constantpolynomialis a horizontal line. A constant poly- nomial does not have any roots unless it is thepolynomialp(x) = 0. arelinear polynomials. Alinear polynomialis the same thing as a degree 1polynomial straight line is the correct answer option B) parabola is the correct answer option A) straight line this the correct answer straight line is the correct answer |
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| 69195. |
The sloped the curve y=x^{3}-x \text { at } x=2 is(a) 10 (b) 11 (c)5 (d) 12 |
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Answer» to find slope differentiate wrt Xhence dy/dx=3x^2-1henceat X=2=3*(2)^2-1=3*4-1=12-1=11 |
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| 69196. |
The set of points where the tangent to the curvey3-3xy + 2-0 is horizontal is-A) {(1,1)} B) {(0,0)}C) {(0,1)} D) null |
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Answer» thank u |
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| 69197. |
trignometric identities |
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Answer» i want for class 10 can anyone quickly answer. please |
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| 69198. |
गुणा करो-28. (a + b +4 - b को4 + b) - (a-b) से। |
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| 69199. |
108. ७... के... किसे... मान के... लिए... असमिका&2 +80 2 99+14 सत्य है?(1) b>-5, b<4A2} b25, b<-4(3) -4<b<54) उपर्युक्त में से कोई नहीं |
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Answer» Now we will solve this after solving put b= 525-5-146 which is greater than 0now put for b greater than equal to 5and b is less than(-5) Answer- Option B |
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| 69200. |
\left(a^{4}+b^{4}\right)\left(a^{2}+b^{2}\right)(a+b)(a-b) गुण निका |
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