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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 70151. |
IC. E. E. (Bihar) 76; P. U. 42; B. U. 59; R. 0.8319.If the roots of the equation ax2 + bx+ c0 bear to one another theratio 3 4, prove that 1262 49ac[RU, 66] |
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| 70152. |
aoume PaulIS 165 m, findThe length and breadth of a rectangular park are in the ratio 5:2. A 2.5-m-wide pathrunning all around the outside of the park has an area of 305 m2. Find the dimensions ofthe park |
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| 70153. |
increased by ell aidsame. Find the base and the altitude of the triangle.18. Two angles of a triangle are in the ratio 4 :5. If the sum of these angles is equal to the thiraangle, find the angles of the triangle.ronm from one port to another in 9 hours. It covers the samel lrmh find the speed of the |
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| 70154. |
100 = 340100 x 100 = 426 100y = 15.: Seema made a profit of 15%.Practice Set 33Id them for 448aganlal bought trousers for 400 and a shirt for 200 and sold theme250 respectively. Which of these transactions was more profitablc? |
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| 70155. |
Solution : 2y? - 4y - 30= 2(y? - 2y - 15)..taking out the common= 2(y2 - 5y + 3y - 15) ........= 2 (y(y - 5) + 3y - 5)]= 2(x - 5)(y + 3)Practice Set 6.11. Factorise.(1) x + 9x + 18(4) Sy? + 5y - 10(7) m-23m + 120(10) 2x + x - 45(2) x? - 10x + 9(5) p² - 2p - 35(8) m - 25m + 100(11) 20x2 - 26x + 8Let's learn.Factors of a + bWe know that, (a + b)' = a + 3b + 3ab + b |
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Answer» x²+6x+3x+18x(x+6)+3(x+6)(x+3) (x+6)x=-3x=-6 x^2 + 9x + 18 = 0; x^2 + 6x + 3x + 18 = 0; x( x + 6) +3 ( x + 6)=0; ( x + 3) ( x + 6); x = -3 & -6; 2) x^2 - 10x +9 =0,; x^2-9x -x + 9= 0; x( x - 9)-1( x - 9); ( x-9)( x -1)=0; x = 1 & 9; 3) 5y^2 + 5y -10=0; =5 y^2+10y - 5y - 10 =0; 5y( y +5) -5( y + 5)=0; (5y -5)(y +5); y =5/5; y = -5 |
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| 70156. |
PRACTICE SET 9.2 (Textbook pages 57 and 58)1. John sold books worth * 4500 for apublisher. For this he received 15%commission. Complete the following activityto find the total commission John obtained. |
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Answer» 900 is correct answer. |
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| 70157. |
JAR 2. ΗτηTable CodingrfraTS | 3 | 1 | 6 | 8 | 5 | 4 | 9(a) 6491(b) 6419(c) 4691(d) 4961L IV E4 6 91 |
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| 70158. |
CSA of a cone is 308 cm^2 and its slant height is 14 cm. Find(i) radius of the base(ii) TSA of the cone. |
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Answer» 1.use CSA formula of cone and find radius.2.after finding radius use TSA formula and find TSA |
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| 70159. |
ts for Real Numberso simplify the following?\begin{array}{l}{\text { (ii) }\left(5^{2}\right)^{\prime}=} \\ {\text { (y) } 7^{3} \cdot 9^{3}=}\end{array} |
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| 70160. |
Multiple Choice duestillls tidusThe measure of x in the given figure is(a) 82°(b) 35°(c) 63°(d) 47°The area of the field ABGFEA is(a) 7225 m2(c) 7235 m29.82°10.(b) 7230 m2(d) 7240 m245 m10 m D3550 m11. The height of a wall is six times its width andthe length of the wall is seven times its height. |
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| 70161. |
2) If the lengths of the sides of a triangular plot of land are 20 m, 21 m ades of a triangular plot of land are 20 m, 21 m and 13 m. what is its area? |
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Answer» By using Heron's formulaes=(20+21+13) / 2s=27 To find area:square root of [s*(s-20)*(s-21)*(s-13)]= [27*(27-20)*(27-21)*(27-13)]=[27*7*6*14]=15876=126therefore area = 126 m^2 |
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| 70162. |
RUHiMArHMATICSEyample 3 : The sides of a triangular plot are in the ratio of 3:5:7 and its perimeThemes:walEyample 3: The sides of a triangular plot are in the ratis 300 m. Find its areaSolution: Suppose that the sides, in metres, are 3x. 5r and 7 |
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| 70163. |
Practice Set 10.21. Divide and write the quotient and the remainder.(1) (y^2 + 10y + 24) รท(y + 4)(2) (p+ 7p - 5) (p + 3)(3) (3x + 2x2 + 4x3) รท (x-4) |
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| 70164. |
9. A square lawn is surrounded by a path 2.5 m wide. If the area of the path is 165 m2. findthe area of the lawn. |
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| 70165. |
36 cm. What ts its thira side13 Find the cost of fencing a square park ofside 250 m at the rate of20 per metre. |
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Answer» If you like the solution, Please give it a 👍 please write clearly |
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| 70166. |
3. Area ofa rectangular field is 36 m'and its length is 9 m. What will be the minimum cost to fenceitaround at 5 per metre? |
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Answer» Area=length*breadth36=9*breadthbreadth=36/9=4mFor fencing, perimeter=2(length+breadth)=2(9+4)=2*13=26mCost of 1m=Rs5Cost of 26m=26*5=130Rs |
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| 70167. |
Practice Set 4.1In Î LMN, is an altitude andmedian. (write the names of appropriatsegments.)XY |
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Answer» LX is an altitude and LY is a median. |
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| 70168. |
Practice Set 15.2Lengths of the diagonals of a rhombus are 15cm and 24 cm, find its area. |
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| 70169. |
From a circular card sheet of radius 14 cm, two circles of radius 3.5 cm and a (rectangle of length 3 cm and breadth 1cm are removed. (as shown in the adjoining10.。figure). Find the area of the remaining sheet. (Takeπ= |
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| 70170. |
6.Devika has a square piece of cloth of area 9 m² and she wants to make16 square-shaped scarves of equal size out of it. What should possibly be thelength of the side of the scarf that can be made out of this piece? |
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Answer» Let lenght of each piece be xconvert 9m^2 in cm^2i.e. 90000 cm^2now 16=90000÷x^2x^2=90000÷16x=300÷4x=75cm75cm =0.75 m0.75m is your answer |
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| 70171. |
a rectangular solid of metal 42 em by 30 cm by 20 em, a conicalcavity of base radius 14 cm and height 20 cm is drilled out. Find thesurface area of remaining solid.iin the form of a cylinder of base radius12 m |
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Answer» Total surface area of cuboid = 2(ℓb + bh + ℓh) = 2 (42 × 30 + 30 × 20 + 20 × 42) = 2 (1260 + 600 + 840) = 2 × 2700 = 5400 cm2 Diameter of the cone = 14 cm Radius of the cone =14/2 = 7cm Surface area of remaining part = 5400 + 550 – 154 = 5796 cm2 |
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| 70172. |
12 ^ { \frac { 2 } { 5 } } \cdot 5 ^ { \frac { 2 } { 5 } } |
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| 70173. |
tsleg59. One side of a right-angled iriangular scarf is 80 em and its longest side is 1 m. Find its costat the rate of 250 per m2 |
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| 70174. |
The length of the hypotenuse and a side of a right angled triangular plot of landare 41 m and 9 m respectively. What is the area of the plot?a 150 m2 |
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| 70175. |
9. In the given figure p is a transversal of the lines mi2and n and 41- 60° and 22- ofa right angle.Prove that m|n. |
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| 70176. |
Devika has a square piece of cloth of area 9 m2 and she wants to makebe the16square-shaped scarves of equal size out of it. What should possiblylength of the side of the scarf that can be made out of this piece? |
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Answer» let the length of side of smaller Square be 'a'area of cloth=9 m^2so, 16*a^2=9=>a^2=9/16=>a=3/4 meteres. |
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| 70177. |
In Fig. 6.14 , lines $ X Y $ and $ M N $ intersect at 0 . If$ \angle P O Y=90^{\circ} $ and $ a : b=2 : 3, $ find $ c $ |
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| 70178. |
9. The cost of putting a fence around a square fieldat 36 per metre is ? 5040. Find the length ofeach side of the field. |
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Answer» The cost of fencing is 5040. thus the perimeter will be 5040/36=140. Now each side will be 140 /4 that is 35m. |
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| 70179. |
Practice Set 3.4n I* Jan 2016, Sanik on second day, 12 on thdecides to save R 10, 111. Oday. If she decides to save like this, then on 31* Dec 2016 what would be her tosaving? |
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| 70180. |
AnswersPractice Set |
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Answer» (x+6) (x+3)x² + 3x + 6x + 18x² + 9x + 18 |
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| 70181. |
17The altitude of a triangle is three-fifth of the length of the corresponding base. If thealtitude is decreased by 4 cm and the corresponding base is increased by 10 cm, the areaof the triangle remains the same. Find the base and the altitude of the triangle. |
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| 70182. |
\begin{array} { l } { \text { Use a suitable identity to get } } \\ { \text { (i) } ( x + 3 ) ( x + 3 ) } \end{array} |
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Answer» Use (a+b) (a+b)(a+b)² = a² + b² + 2ab So,(x+3) (x+3) = (x+3)²x² + 3² + 2×x×3x² + 9 + 6x |
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| 70183. |
if ∆ PQR ∆P= 55° ,∆Q = 75° then find longest side and sturtest side of angle |
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| 70184. |
A drain cover is made from a circular metal plateof radius 14 cm having 21 holes each of12,diameter0.5 cm. Find the area of remaining plate. |
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| 70185. |
\frac { ( 2 n ) ! } { n ! } = \{ 1 \cdot 3 \cdot 5 \dots ( 2 n - 1 ) \} 2 ^ { n } |
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| 70186. |
\frac { ( n + 1 ) ( n + 2 ) ( n + 3 ) \dots \ldots ( n + r ) } { r ! } |
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| 70187. |
In ∆ABC, angleA =90°. Which is its longest side? |
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| 70188. |
9. One side of a right-angled triangular scarf is 80 cm and its longest side is 1 m. Find its costat the rate of250 per m2 |
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| 70189. |
45. How long will a man take to walk round theboundary of a square field containing 9 hectares atthe rate of 6 km/hour ? (1 hec. 10000 sq.m.) |
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Answer» 9 hectare = 9 × 10⁴ m² Side length of square field = √(Area)= √(9 × 10⁴ m²)= 3 × 10² m= 300 m= 0.3 km Time = Distance / Speed= 4L / v= (4 × 0.3 km) / (6 kmph)= 0.2 hour= 12 minutes It takes 12 minutes for him to walk round the boundary for once. |
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| 70190. |
0999089...夢,,7. The product of two numbers is 944 andHCF is 4. Find their LCMSolution:..ItO9D999 |
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| 70191. |
line4) find the equation ofiwhich is equidistantfrom the lines n=-2 and u=6 |
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| 70192. |
(iv) 2(ax-by) + Îą + 4b = 0, 2(bx + ay) + (b-4a) =0 |
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Answer» please like my answer if you find it useful |
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| 70193. |
Practice Set 10.1quotient and the remainder.(2) 40d(-10a) |
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| 70194. |
IfA-B 귀then prove that A2-4A + 51 = 0. |
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| 70195. |
ORIf the area, base and corresponding altitude of a parallelogram are , x-3 and x+ 4 respectivelythen find the value of x.111i nnd its nerimeter is 84 cm. Find its area. |
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Answer» Area of parallelogram= base × corresponding altitude x² = (x-3)(x+4) x² = x²+4x-3x-12 0 = x-12 x = 12 Like my answer if you find it useful! |
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| 70196. |
1-Use suitable identity to get products(A 4a- 4a |
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Answer» (4a -1/3)(4a -1/3)=(4a -1/3)^2=(4a)^2 +(1/3)^2 -2(4a)(1/3)=16a^2 +1/9 -8a/3 |
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| 70197. |
will be needed?A metal plate measuring 42 cm by 14 cm is cut up into small squares of side length 7 mm. How manyisquares will be cut?m and nerimeter is 700 m |
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Answer» Area of metal plate = 42×14= 588 cm2Area of square = 7×7 = 49 mm2= 0.49 cm2 So the number of squares can be cut are= 588/0.49= 1200 squares. |
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| 70198. |
Volume(cm)e volume of a cylinder is 660 cm3. Find its height if its radius is 5 cm.d ito lateral (curved) surface area =5cm |
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Answer» Volume of cylinder is 660 cm^3radius of cylinder is 5 cm660 = 22/7 ×5×5×h660×7/22×5×5=h8.4=hheight h is 8.4 cm |
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| 70199. |
5 + 55 + 55 + \dots \dots \dots n |
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Answer» thanks so much my problem is solved Kon si class main hoo |
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| 70200. |
4. Iftwa zeroes ofthe polynomíalr-6r'-26f+138r-35 are 2 ±,f, ind other zeroes. |
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