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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 70201. |
height on the longest side.The base of an isosceles triangle is 48 cm and one of its equal sides is 30 cm. Find theof the triangle.area17.nd its nerimeter is 32 cm. Find its area. |
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Answer» thank you bhaithank thank thank thank thank thank thank you bhai |
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| 70202. |
\frac{21}{20}+\left(\frac{-15}{4}\right)+\frac{9}{2}+\left(\frac{-21}{8}\right) |
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| 70203. |
Teachings of Jesus u6. Mention the role of the Apostles in the spreading of Christianity. |
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Answer» TheApostles of Jesustraveled from Jerusalem to other parts of the world after thecrucifixion of Christ. Their main purpose was to spread the teachings ofJesuswhen he was still alive. Some of them also founded the Apostolic Sees, and they led early Christians in their religious gatherings in private homes referred to as house churches. The entire community of Christians wascalled a “church”, originating from aGreekword that means congregation, gathering or assembly. A large population of Early Christians were travelers or merchants, and they went to various places including Asia Minor |
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| 70204. |
Write four more rational numbers in each of the following patterns3 -6 -9 -125 10' 15 204 8 12 |
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| 70205. |
(10b + a)-(10a + b) = 9(b-a). |
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Answer» 0 is the right answer (10b+a) -(10a+b)10(b-a) -1(b-a)(b-a)9is correct answer o is the right answee 10b+a-10a+b=9b-9a=9(b-a) (10b+a)-(10a+10b)10(b-a) (10 b+ a) -(10 a +b)=9(b-a) Sahi hai |
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| 70206. |
7. Add :1) 6a2-7a-9 and 9a2 + 10a + 5 |
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Answer» ANS:- OF YOUR QUESTION IS 15a²+3a-4 |
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| 70207. |
4% â 4a% + (2 - 85% = |
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| 70208. |
ल्प तर 4a+5b - किसे 24a-5b |
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Answer» a/b=8/3 4a+5b/4a-5b [4(a/b)+5(b/b)]/[4(a/b)-5(b/b)] [4(8/3)+5]/[4(8/3)-5] (32/3+5)/(32/3-5) (32+15)/(32-15) =47/17 |
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| 70209. |
अल. 112 f BeosB+12 5111 05 {3 then tan® = —-m‘ o= e ० by |
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Answer» 5cosx + 12sinx = 13, 5 + 12tanx = 13secx, Squarin both-sides,25 +144tanx^2 +120tanx = 169sec^2x=169(tan^2x +1),25(tanx)^2 - 120tanx + 144 = 0,(5tanx - 12)^2 = 0, tanx = 12/5 Hello i didn't understand |
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| 70210. |
3) -3, 522(x-a)-(x + a)= 0 , then x is4)2)3)2a1) 04a4a. |
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Answer» 2x * 2a= 0 x = 0/4a = 0 |
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| 70211. |
alem ABCD, if 4A (2+25) and 4B (3x-5), find the value of xind the measure of each angle of the parallelogram |
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| 70212. |
26f + 1 38 r-35 are 2 ± V 3 find other zeroes.10is divided by another polynomial x2r +ktw o /e roes of the poly nomial r'6r'r |
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Answer» Please like the solution 👍 ✔️ |
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| 70213. |
3. If diagonal of a square is 13 cm then find its side.d ito nerimeter is 112 |
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| 70214. |
p(x)=6x³-x²-10x-3,g(x)=2x-3,find the remainder and verify by remainder theorem |
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| 70215. |
Prove that (3x + 7) is a factor of P() 6r+ 29+ 44x+ 21lor hicootor of AD such that the |
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| 70216. |
EXERCISE 10AConvert each of the following fractions into a percer920415i) 47100(iii)8(v) _19500(vii) 23(vi) |
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| 70217. |
10a mFind the perimeter of a rectangular table top with sides 1 m 15 cm, and 80 cm. |
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Answer» Sides are 1m15cm = 115cm and 80cm perimeter = 2(115+80) = 2(195) = 390 cm |
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| 70218. |
5. If one zero of the polynomial (a2+ 25)2 +36r +10a is the reciprocaloftheother,findthevalue of a. |
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| 70219. |
40a(-10a) |
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| 70220. |
-A is a square matrix of order 3 with Al = 4, then write the value of l-2A. |
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| 70221. |
(i)乖Δ ABC 궉 a = 4, b = 12, LB-30-m sin A1 |
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Answer» by using sin formula of ∆ sinA/a = sinB/b. sinB= sin30= 1/2 => sinA= asinB/b = 4*(1/2)/12 = 4/24 = 1/6 |
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| 70222. |
(b) 60C)8(a) 403. If the area of square with side a is equal to the area of a triangle with base a, then the altitude of thetriangle is(b) a(c) 2a(d) 4a2ntruntd on tha same hase such that their areas are equal. If the |
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| 70223. |
In parallelogram ABC, 24-14x-5)"and LB = (3x + lor Find LA and al. |
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| 70224. |
ind quotient and remainder when polynomial - 6x 5xdivided by 2x2 +1.llx + 1 isčéż ! |
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Answer» Like my answer if you find it useful! |
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| 70225. |
6. What is the largest number which when divides 63, 77 and 112 leaves3, 5 and 4 as remainders respectively ? |
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Answer» number needs to divide 63-3=60,77-5=72 and 112-4=108so HCF of 60,72,108 is the required number60=2^2×3×572=2^3×3^2108=2^4×3^3so HCF=2^2×3=12so 12 is the greatest number which when divides 63,77 and 112 leaves 3,5 and 4 reminders respectively. |
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| 70226. |
0.00TL4. If two Zeroes of the polynomial6x-2x+1381-28 ure. Pred other yeroes |
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| 70227. |
138r-35 are 2z 3. find other zeroIf the polynomial r'-6r'+ lor'-25x + [o is divided by another polynomial -2the remainder comes out to be + a. find k and a |
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| 70228. |
5. If the polynomial xt-6r+ 16x2-25x + 10 is divided by another polynomial*-2x+kthe remainder comes out to be x + a, find k and a. |
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| 70229. |
4. If c., B, y are zeroes of polynomial 213 -4 +6r 90, thest find the value of a+ |
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Answer» Like if you find it useful |
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| 70230. |
OLED - UAUIMA--15. When x5 - 5x4 + 9x3 - 6x2 - 16x + 13 is divided by x2 – 3x + a, the quotientand remainder are x3 - 2x2 + x + 1 and - 15x + 11, respectively. Find thevalue of a.Remainder and Factor Theorems |
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Answer» Jdkskkkskskkdkfkkfkdkkdkfkfkkd plz like my answer dfhbfujgg |
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| 70231. |
300 ।।200+10+7100+10+8=118प्रकार निशा व अदिति ने घटाकर देखा और अदिति के पिताजीअधिक बारिश हुई।आप भी सरल व विस्तारित दोनों तरह से घटाइपविस्तारित तरीकासरल तरीका762=700+ 60+2400+00+3- 403=762-563395-206ऐसे70से सौ-सौ घटाते हुए पाँच संख्याएँ लिखिए। /से दस-दस घटाते हुए नौ संख्याएँ लिखिए। आके खेत में 750 क्विंटल चावल पैदा हुए। इनमें से उनताइए, अब उसके पास कितने क्विंटल चावल शेष रह |
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Answer» 1 ans .199 2 ans .189 1ans.199. 2ans. 189.......... |
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| 70232. |
If 2515 is divided by 13, then remainder is(A) 1(C) 12(B) 3(D) none of these |
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Answer» 25×25×25×25×25×25×25×25×25×25×25×25×25×25×25=630644910620370505625630644910620370505625/13=48511146970797731201ans.(d) |
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| 70233. |
\left. \begin{array} { l } { t ^ { 2 } - ( \alpha + \beta ) t + ( \alpha + \beta ) ( \alpha - \beta ) = 0 } \\ { t ^ { 2 } + 2 \alpha t + \alpha ^ { 2 } + \beta ^ { 2 } = 0 } \\ { t ^ { 2 } - 2 \alpha t + \alpha ^ { 2 } - \beta ^ { 2 } = 0 } \\ { t ^ { 2 } + 2 \alpha t + 2 \beta = 0 } \end{array} \right. |
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| 70234. |
EXERCISE 10AFind each of the following ratios in the simplest form:4 to 563(l) 84 patse to 3(il1) 4 kg to 750 g(vi) 2.4 km to 900 1(iv) 1.8 kg to 6 kg(v) 48 minutes to 1 hour |
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Answer» nice answer........... |
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| 70235. |
If α and β are the zeroes of the polynomial ar + bx + c. Find the value of1)(ii) a2 + P |
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Answer» Given : ax² + bx + cSo,α + β = -b/a αβ = c/a ii)So, ( α + β)² = α² + β² + 2αβ b²/a² - 2c/a = α² + β² i) ( α - β)² = α² + β² - 2αβ ( α - β)² = b²/a² - 2c/a - 2c/a α - β = √(b²/a² - 4c/a) |
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| 70236. |
b quare - 2a squareapon b square +2a square |
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Answer» (b*b - 2a*a)/(b*b + 2a*a) If you find this answer helpful then like it. |
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| 70237. |
what is a square plus 17 square equals 19 square? |
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Answer» Let the no. be xx²+ 17² = 19²x² = 19²-17²x = 8.4 |
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| 70238. |
In trianbngle ABC LB = 90 , the hypotenuse AC = 1.5 cm and the side BC = 1.2 cm. Calculatethe side AB |
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| 70239. |
312, 945Hint. Two numbers are co-primes if thetr HCF is 1and 963, leaving the remainder 6 in each case.63 learing remainders 9 and 525.Find the greatest number which divides 615 |
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Answer» The number will be HCF of 609 and 957609 = 3 x 7 x 29957 = 3 x 11 x 29So HCF = 3 x 29 = 87. |
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| 70240. |
77+77 |
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Answer» 154 77+77the answer is 154 |
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| 70241. |
If the zeroes of the polynomial x' 3x, x + l arelftwo zeroes of the polynomial ra_ 6r3-26r' + 13gr-35 are 2 Âą-3, find o |
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Answer» Relation between roots of equationax^3 + bx^2 + cx + d = 0 Let roots are x, y, z Then, x + y + z = - b/a xy + xz + yz = c/a xyz = - d/a Thus for equation X^3 - 3X^2 + X +1= 0 Sum of rootsa-b + a + a +b = -(-3)/13a = 3a=1 Product of rootsa(a+b)(a-b) = 1a(a^2 - b^2) =1b = 1 a = 1, b = 1 |
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| 70242. |
19, If the polynomial6x+83-5x2+ar+bisexactlydivisiblebythepolynomial2x-5,4then find the values of a and b. |
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| 70243. |
¢ PR RGPy <218 |
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Answer» 1000 ml= 1 litre1 ml = 1/1000 litre3125 ml= 3125/1000= 3.125 litre |
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| 70244. |
19. If the polynomial 6r +8find the values of a and b- 5x2 + ar +b is exactly divisible by the polynomial 2x2- 5, then4 |
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Answer» since the the above polynomial is exactly divisble by 2x^2 -5..it means that the remainder is 0 therefir we can write it as 6x^4 + 8x^3 - 5x^2 + ax + b = (2x^2 - 5)× g(x) where g(x) is a polynomial of 2nd degree simplifying this furthur..we can arrive at 6x^4 + 8x^3 - 5x^2 + ax + b = (√2x -√5)(√2x +√5)× g(x) now r.h.s become 0 when x =√(5/2) and x = -√(5/2) by substituting x =√(5/2) 6(25/4) +8(5√5/2√2) - 5(5/2) + a(√5/√2) +b =0 25 + 20(√5/√2) + a(√5/√2) +b =0 -----(1) by substituting x = -√(5/2) 6(25/4) - 8(5√5/2√2) - 5(5/2) - a(√5/√2) +b =0 25 - 20(√5/√2) - a(√5/√2) +b =0 -----(2) (1) + (2) 50 +2b =0b = - 25 (1) - (2) 40(√5/√2) + 2a(√5/√2) =0a = -20 hope this will help you :) thanks |
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| 70245. |
Match the following(A) Expression(ii) 5x-x+2(ii) xy+5(iv) ab+b+a+5Type of polynomial(a) binomial(b) monomial(c)polynomial(d) trinomial |
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Answer» 1. monomial2. Trinomial3. binomial4. polynomial |
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| 70246. |
f α, β are zeroes of the polynomial x2-2x-1(20) and (p)of the polynomial x -2x -15, then form a quadratic polynomial whose zeroes are |
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| 70247. |
EXERCISE 2.1Which of the following expressions are polynomials in one variable annot? State reasons for your answerWrite the coefficients of ax' in each of the following:(ii) 2xWrite the degree of each of the following polynomials:2+x2 +xnve oneexample each of a binomial of degree 35, and of a monomialfollowing polyi, 4- 5x +4x+7x(ii) St-7(iv) 3Classify the following as linear, quadratic and cubic polynomials:es of a Polynomialhe polynomial px) 5x-2x2 +3x-2.ace x by 1 everywhere in p(x), we get=5-2+3-2that the value of p(x) at x 1 is 4.p(0) 5(0)- 2(0)+ 3(0)-2=-2 |
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| 70248. |
سالي الا لا ام لا3,3732x3.73 - 732 x 7323.75+ 73بمهام |
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Answer» 2 is the answer of this question 2 hìiiiiiiiiiii hogaaaaa🤔🤔🤔🤔🤔🤔🤔🤔🤔🤔 |
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| 70249. |
in the libraryDivide the polynomial (or+1L-10x-7) by the binomial (x+ 1). Write the quotientand the remainder13. |
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| 70250. |
मा - 6०298 - J{ के 03956 2980० द1+023S) 1-929 |
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