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addition of root=-b/a=1/4multiplication of root=c/a=-1/4so a=-4 b=1 c=1so equation is ax^2+bx+c=0-4x^2+x+1=04x^2-x-1=0

Area to be coloured=area of square - area of circle

in circle radius =35cmarea of circle=πr²=22/7×35×35=22×35×5=3850cm²

in square the side of square =diameter of circlediameter=2×radius

=2×35cm=70cm

area of square=side²(side×side)=70×70=4900cm²

area to be painted=4900-3850cm²=1050cm²

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5x/13 = 85

5x = 1105

x = 221

Length : breadth = 5 : 3 suppose length is 5x and breadth is 3x length is 8 m more than breadth 5x = 3x + 8 2x = 8 x = 4 length = 20m breadth = 12m area = length × breadth = 20×12 = 240 sq.meter

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the cost price is 550

The total number of workers is x= 27200/85 = 320

What did margie write in her bairy

al most 9.2% value of profit

We know that,angle subtended by an arc at the centre is double the angle subtended by the same arc at any point on the circle.

Consider the minor arc XY, that subtends ∠XOY at the centre and ∠XZY at the circle.

Now, ∠XOY = 2 ∠XZY .......(1)

Consider the minor arc YZ, that subtends ∠YOZ at the centre and ∠YXZ at the circle.

Now, ∠YOZ = 2 ∠YXZ .......(2)

adding (1) and (2), we get ∠XOY + ∠YOZ = 2∠XZY + 2 ∠YXZ

⇒∠XOZ = 2[∠XZY + ∠YXZ]

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Tn = a + (n-1)d T2 = 12 = a + d T5 = 21 = a + 4d a + 4d - a - d = 21 - 12 3d = 9 d = 3 a + 3 = 12 a = 9 T10 = a + 9d = 9 + 9*3 = 9 + 27 = 36

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The bag contains 2 White, 3 Black and 4 Red balls.

So, total 9 balls are there in the bag; among them 3 are Black and 6 are non-Black balls.

Three balls can randomly be drawn in (9C3) = 84 ways.

1 Black and 2 non-Black balls can be drawn in (3C1)*(6C2) = 45 ways.

1 non-Black and 2 Black balls can be drawn in (6C1)*(3C2) = 18 ways.

3 non-Black balls can be drawn in (3C3) = 1 way.

So, three balls drawn in (45 + 18 + 1) = 64 ways will have at least one Black ball among the drawn ones.

So, the probability of getting at least one Black ball among the three drawn =

(64 / 84) = (16 / 21).

S=(n/2)(2a+(n-1)d)S10=5(2a+9d)150=5(2a+9d)150/5=30=(2a+9d)

30=(2a+9d).... (1)

S9=9/2(2a+8d)126=9/2(2a+8d)126*2/9=30=(2a+8d)28=2a+8d......(2)

Subtract 2 from 1

2=d

a=28-8d/2=28-16/2=12/2=6

t10=a+9d=6+9(2)=6+18=24

Sol: List price (marked price) of an article = Rs 800 Discount percentage = 15 % Discount = 15 % of 800 = 15/100 x 800 = Rs 120 Selling price of the article = List price - Discount = 800 - 120 = Rs 680 Profit = 40/3 % Cost price = Selling price x (100) / (100 + g) = 680 x (100) / (100 + 40/3) = 680 x (300) / (340) = 600 The cost price of the article = Rs 600.

What is science please tell me fast answer

<DCE=[180-(53+<DEC)]°=[180-(53+<BAC)]°=[180-(53+35)]°=(180-88)=92°. SO, <DCE=92°

wrong answer

a)Centrifugationb)chromatographyc) Sublimation

Let total days they take to complete remaining task be x

As amount of work remain same.

Thus, 45*16 = 45*6 + (45+30)*x45(16 - 6) = 85*x75x = 450x = 450/75x = 6

Therefore, remaining task will be completed in 6 days

inΔABCAB=AC∴∠ABC=∠ACB(angles opposite to equal sides of a triangle are equal)......1inΔDBC,DB=DC,∴∠DBC=∠DCB(angles opposite to equal sides of a triangle are equal)......2subtract 2 from 1∠ABC-∠DBC=∠ACB-∠DCB(equals subtracted from equals gives equal)=∠ABD=∠ACDdivide both the sides by∠ACD⇒∠ABD/∠ACD=1∴∠ABD:∠ACD=1:1

1) (3^0 - 4^0) + (5^0 + 4^0) + (5^0 + 4^0) = (1+1) + (1+1) + (1+1) = 2+2+2 = 6

2) (25^5/2 - 25^7/2)/25^5/2 = (5^5 - 5^7)/ 5^5 = 5^5(1 - 25)/5^5 = - 24

3) (-2/5)^-6 * (-2/5)^4 = (-5/2)^2x (-2/5)^[-6+4] = (-5/2)^2x (-5/2)^2 = (-5/2)^2xBase are same power will be equalTherefore, 2 = 2x x = 1

Let the marked price be xSeema's cost price = 6x/7Seema's selling price = 6x/5Seema's profit = 6x/5 - 6x/7 = 12x/35

Seema's profit percent = [12x/35]/[6x/7] * 100= 40 %

Construction: Join pointsAandC and letACandDBintersect atG.

LetDBintersectEFatH.

Proof:

Diagonals of a parallelogram bisect each other.

⇒AG=CG.

By the midpoint theorem,EF∥AC.

⇒△EHB∼△AGBand△FHB∼△CGB.

⇒EH/AG=EB/AB andFH/CG=FB/CB.

ButEB/AB=1=FB/CBsinceEandFare the midpoints ofABandBCrespectively.

⇒EH/AG=FH/CG⇒EH/FH=AG/CG=1

⇒EH=FH.

⇒DBbisectsEF.

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how triangle EHB~ triangle AGB

4lm(l-m) - 6l*l(m-m*m) - 3m*m(2l*l-l) + 2lm(l-m) = 6lm(l-m) - 6l*l*m + 6l*l*m*m - 6l*l*m*m + 3l*m*m = 6l*l*m - 6l*m*m - 6l*l*m + 3l*m*m = -3l*m*m

seema works for 25 -2.5 = 23.5hours

10 hours is the correct answer of the given question

10 hrs. is the correct answer of the following question

Seema completes 1/20 part of a work in a day so to complete the work it will take 20 days.

PurchaseDaybook(PurchaseRegister)is thebookof original entry in which all the transactions relating to only creditpurchaseare recorded. Cashpurchasesdo not find place inpurchasedaybookas they are recorded in Cashbook. At the end of every monthpurchasedaybookis total-led.

560 rupees

If the amount of the closing stock is already known and is recorded in the books, it is given in the Trial Balance itself. If it is so, it means that both the opening as well as closing stocks have been adjusted in the purchases. ... In other words, Adjusted purchases = Net Purchases + Opening Stock - Closing stock.

a)parallelogram digonal bisects each other.x + 5 = 20x = 15y + 15 = 25y = 10

b)opposite sides so parallelogram are equalso,25 = 3y + 13y = 24y = 24/3y = 8