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70551.

Establish the relation between Cp and Cv.

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Relation between Cpand Cv(Meyer’s relation)

Let us consider one mole of an ideal gas enclosed in a cylinder provided with a frictionless piston of area A. Let P, V and T be the pressure, volume and absolute temperature of gas respectively as shown in below figure.

A quantity of heatdQis supplied to the gas. To keep the volume of the gas constant, a small weight is placed over the piston. The pressure and the temperature of the gas increase toP + dP and T + dTrespectively. This heat energydQis used to increase the internal energydUof the gas. But the gas does not do any work(dW = 0).

∴dQ = dU = 1 × Cv× dT …... (1)

The additional weight is now removed from the piston. The piston now moves upwards through a distance dx, such that the pressure ofthe enclosed gas is equal to the atmospheric pressureP. The temperature of the gas decreases due to the expansion of the gas.

Now a quantity of heatdQ’is supplied to the gas till its temperature becomesT + dT. This heat energy is not only used to increase the internal energydUof the gas but also to do external workdWin moving the piston upwards.

∴ dQ’ = dU + dW

Since the expansion takes place at constant pressure,

dQ ′ = CpdT

∴ CpdT = CvdT + dW …... (2)

Work done, dW = force × distance == P × A × dx

dW = P dV (since A × dx = dV, change in volume)

∴ CpdT = CvdT + P dV …... (3)

The equation of state of an ideal gas is

PV = RT

Differentiating both the sides

PdV = RdT …... (4)

Substituting equation (4) in (3),

CpdT = CvdT + RdT

Cp= Cv+ R

Cp - Cv = R…... (5)

This equation is known as Meyer’s relation.

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70552.

Q7.Q8.The angles of the triangle are in the ratio 2:3:4. Find the measure of each of the angle.Two acute angles of a right angled triangle are equal. Find the measure of each angle.

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oues 7. let angle 1 = 2x let angle 2 = 3x let angle 3 = 4x2x+3x+4x = 180°9x = 180°x = 180/9x = 20° 1st angle = 2× 20 = 40°2nd angle = 3× 20= 60°3rd angle = 4×20= 80°

1st angle =2×20=40° 2nd". = 3×20=60°3rd". =4×20=60°

x=45°is the correct answer

70553.

5.A photograph of a bacteria enlarged 50,000 timesattains a length of 5 cm as shown in the diagram.What is the actual length of the bacteria? If thephotograph is enlarged 20,000 times only, whatwould be its enlarged length?

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Let the actual length of bacteria be ‘x’& enlarged length be y cm.

Here the number of times the photograph of bacteria was enlarged & the length of the bacteria are in directproportion.

5/50000=x /1

X= 1/10000

x=0.0001cm

x=10^-4

Hence, the actual length of bacteria is10^-4

Let the length of the bacteria when thephotograph of bacteria was enlarged 20000 times be y

5/50000 = y/20000

y × 50000 = 5× 20000

y= 5× 20000/50000

y= 2cm.

Hence, the enlarged length of the bacteriais 2cm.

==

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70554.

12la)10 men can finish a piece of work in 10 days, whereas it takes 12 women tofinish it in 10 days. If 15 men and 6 women undertake to complete the work,how many days will they take to complete it?la) 2(6) 4(c) 5(d) 11

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10 men = 12 women

5 men = 6 women

15 men and 6 women = 20 men

10 men can finish the work in 10 days

20 men can finish the work in 5 days.

70555.

the cost of 12 pens is equal to the SP of15 pens .find the loss percent

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70556.

0. The cost of 12 pens is equal to the S.P. of 15 pens. Find the loss percent11Chiltothen 0.1971

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20% is the correct answer

70557.

14. Amar walks round a 72mx 56 m rectangular field at the rate 3 kmhour. How much time will he take to take two roundsof this field.

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70558.

5. If the cost price of 12 pens is equal to the selling price of 15 pens, find the gain or loss per cent.

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70559.

a local delivery driver, is paid s3 50 per mile driven plus a daily amount of $75 On Monday, he isassigned a route that is 30 miles long. How much is he being paid for that day

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For 1 mile cost is $ 3.50

For 30 miles cost will be $3.50 × 30= $105

Total amount = $105 + $75 = $180

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70560.

14:TR220६005 (#द न शेड + कट ०)जि: 5०-00 & Bloke BBk ()~tie 2०818 हैT NG

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70561.

. 3 ]N~ 4 — — — X —Mg. R 35 ®B £ T3 रगा 1| N

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70562.

Megha bought 45 bags at Rs 900 each. She sold 30 of them at Rs 1000 each and theremaining bags at 800 each. Find her gain or loss per cent.

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70563.

x 1 3 find value of x2. Iftringle uhose werticeg are (

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70564.

39. In AABC, if AD is the bisector of ZA, showCV that AB > BD and AC > DC.in tringle in which

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70565.

Paga No.5.The angle of ain the ratio 2:3trafio measure ofthe triangle.Tringle aretheory bond the4 . Find theeach angle of

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80 is the right answer

70566.

A length of a bacteria enlarged 50,000 times attains a length of5 cm. What is the actual length ofthe bacteria? Ifthe length isenlarged 20,000 times only, what would be its enlarged length?

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70567.

9. 3 men or 5 women can do a work in 12 days. How long will 6 men and 5 women takedo it?6 do(b) 6 doua

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Given : 3 men or 5 women can do a work in 12 days.

Required : how long will 6 men and 5 women take to do it.

Since 3 men's work = 5 women's work

Therefore, 1 man's work = 5/3 women's work

6 men is equivant to 6*5/3 = 10 women

Total workers in term of women available for work are 10 +5 = 15 women

5 women can complete in 12 days

1 woman can complete 12*5 = 60 days

Therefore, 15 women can complete the work in 60/15 = 4 days

Thus, the work can be completed by 6men and 5 women working together in 4 days.

70568.

d) We have to move six steps to the left of -3e reach -2 when we move 4 steps to the righ(b) WEXERCISE 6.1Write opposites of the following:(a) Increase in weight (b) 30 km northd) Loss of Rs 700Represent the following numbers as integers with appropra) An aeroplane is flying at a height two thousand metre) A submarine is moving at a depth, eight hundred n(e)100 m above sea level

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Decrease in weight30 km southProfit of Rs 700100 m below sea level

70569.

Bunty and Bubly go for jogging every morning. Bunty goes around a square80m and Bubly goes around a rectangular park with length 90m and breadthboth take 3 rounds, who covers more distance and by how much

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70570.

Mrs. Salls flew her private jet a totalof 9075 miles to Bermuda for hervacation. She and her best friend, Mrs. Simek, packed 18 suitcases. Thetrip took them 55 hours. How many miles per hour did the jet fly?rip foONS

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Total distance jet fly = 907.5 milesTotal time taken = 5.5 hours

We knowDistance = Speed*Time907.5 = Speed*5.5Speed = 907.5/5.5 = 825/5 = 165 miles/hr

Jet flew 165 miles per hour

70571.

A person driving along the road moves at a rate of 56 miles per hour driven. How far does the person driven 1.5 hours? Show the calculation you use in your answer and give your answer proper units.

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Distance=rate x timeDistance=(56 mi/hr)(1.5 hr)Distance=84 miles

70572.

the stock does he sell?6. Rajesh had a packet of 20 sketch pens. He gave 12Ketch pens. He gave 12 to Krishna and 6 to Meena. Whatleft with him?of the packet did he give to Krishna and Meena? What fraction of the packawaAjit and Kunal paidand 2 of the total

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12/20=6/10 given to krishna6/20=3/10 given to meenA2/20=1/10 is left

70573.

r tie hhst t3 multiples ot14 Find the sum of the odd numbers between O and so

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1+3+5+7--------49Hereit will be an Arithmetic seriesFirst term= 1Comman difference= 2Number of terms = 25So formula = n/2[2a+(n-1)d]= 25/2[2+24*2]625

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70574.

| लिर व थी ४ ९८८ [6 £6) » ६ (६०१८ go¢ 0) तह ६४ [216 66 ) % P :fifl(”\r%'o'w)B os (C®) x (a1 (270-0) x दिल 1९0६8)

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70575.

1-cos θ .1 + cos θ8.6 R)(cosec θ-cot θ)' =1.os A 1+sin A 2secA1 +sin A cos Atan θ(iii) 1-cotcot θtan θ1+ sec Asec Asin2 A1 - cos Acos Asin A+ 1=cosec A +cot A

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70576.

triangle in which ) PRIPO) andively such that OS-R .prove that OT-RS.isRthe venue. A POR is an isosceles tringle in whicheproduced to S&T respectively such that QS - RT- T? why?

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70577.

d tie luss percent.r. Manjeet bought two bags for? 650 each. He sold one of them at a gain of 6% and the other at aloss of 2%. How much did he gain.

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stander 9 Gujarati pepar

Gujarati pepar the best

70578.

the length Apa hectangle:thats 12iS

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70579.

In an APa3 Men a s, d-3, an so tind n and sp

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We have, a= 5, d=3 and an=50

> a+(n-1)d= 50

> 5+(n-1)3=50

> 3(n-1)=50-5

> n-1 = 45/3

> n-1 = 15+1 = 16

Putting n = 16, a= 5 and l = an = 50 in Sn= n/2(a+l),We get

S16 = 16/2( 5 + 50) = 8 × 55 = 440

Hence, n= 16 and S16 = 440

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70580.

Two trains leave a railway stationthe same time. The first train travtowards west and the second train twards north. The first train travelskm/hr faster than the second trainafter two hours they are 50 km. apafind the average speed of each trair

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Two trains leave the railway station at the same time.The first travels due west and second train due north.The speed of the first train is 5 km faster than the second train.After two hours they are 50 km apart. Find the average speed of the trains:Let s = the speed of the northbound trainThen(s+5) = the speed of the westbound train:This is a right triangle problem: a^2 + b^2 = c^2The distance between the trains is the hypotenusedist = speed * timeThe time is 2 hrs, so we havea = 2s; northbound train distanceb = 2(s+5) = (2s+10); westbound distancec = 50; distance between the two trains:(2s)^2 + (2s+10)^2 = 50^24s^2 + 4s^2 + 40s + 100 = 2500:Arrange as a quadratic equation4s^2 + 4s^2 + 40s + 100 - 2500 = 08s^2 + 40s - 2400 = 0

70581.

y,yy|9, x, x, y9r'ySameLike/0/2 |Apa-4,Pg1,p, q, q(vi)|Following simple steps will help you to deConcentrate on ineicieAsor unlike termsi) Ignore the numerical coefficients. Coal(a) Check the variables in the terms. They mm) Next, check the powers of each variable in t hes in the terms. They must bewers of each variable in the tenlike terms, two things dotermsin deciding like terms, two thingsie order in wnot mattervarabNote thatcoefficients of the terms and (2) the otermsorder in which theEXERCISE 12.1Get the algcbraic expressions in the following cases1.arithmetic operations.0 Subtraction of z from y(i) One-half of the sum of numbers x and yi) The number z multiplied by itself.One-fourth of the product of numbers p andq(Gv)(v) Numbers r and y both squared and added.g.Number 5 added to three times the product of numbe(vi)(vi) Product of numbers y and z subtracted from 10.(vii) Sum of numbers a and b subtracted from their product2. (6) Identify the terms and their factors in the following expresi

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70582.

3. Radha's grandma was ill. The doctor gave her a bottle with200 mL of medicine. She has to take the medicine everymorning for 10 days.

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70583.

Ravi is driving 440 miles to visit his grandma.He drives at a rate of 55 miles per hour.How many hours will it take him to get dof the way there?

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(3/4)th of the distance is (3/4)*440= 330 miles. Time taken = Distance / Speed= 330/55= 6 hours.

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70584.

1.Evaluate lim sin 2θ

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there is a better way... write sin4x = 2 sin2x * cos2x

thus limit is 1/2cos2x = 1/2

70585.

1 a x2 + 7x + 12d x² - 7x + 12

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LG go kg go off go oh go oh

weg ye qr yr et te weg ye qr te

kg go kg go kg go off go oh go oh

et ya hm ya gm re j ya fm tell ye

KS ah LG DJ is DJ if DJ if DJ is DJ

LG ho kg go off go oh go oh

your question is not complete please retake your quetion , what is find=?

(-3, - 4) is the best answer

d. (3,4) is the best answer

70586.

(C) 4 3y2(D) 3x 4y 2The sum of a number and its reciprocalis 7. If the number is x, then which ofthe following is the quadratic equationcontaining x?(A) x2+7x +1 0(B) x2 +7x +2 0(C) x2-7x +1-0(D) x2-7x-10R ROUGH WORK

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no. is xx+1/x=7x²+1=7xx²-7x+1=0

70587.

\cos \left( 40 ^ { \circ } + x \right) = \sin 30 ^ { \circ } , \text { find } x

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70588.

CU2C 1 ) = fo

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37 is the correct answer me

x__ 7 and y is equal to the 3

70589.

\operatorname { sin } ( x ^ { \circ } + 40 ^ { \circ } ) = \frac { 1 } { \sqrt { 2 } }

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70590.

If cos ( 40 - x) = sin 30 find the value of x

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Cos(40°+x)=sin 30°=1/2. (Sin30°=1/2)

So cos (40+x)=1/2

Which means 40°+x=60°

because cos60°=1/2

Thus 40°+x=60

x=60°-40°=20°

X=20°

70591.

20.If cos (40° + x) = sin 30°, find the value of χ.

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cos(40°+x ) = sin 30°cos(40°+x) = 1/2cos(40°+x) = cos 60° 40+x = 60 x= 20°

70592.

s ( 40 ^ { 0 } + x ) = \operatorname { sin } 30 ^ { \circ }

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cos (40+x) = 1/2

We know that cos 60 = 1/2

40+x = 60

x = 20

70593.

1 + \operatorname { cos } ( 40 ^ { \circ } + x ) = \operatorname { sin } 30 ^ { \circ }

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As we know,sin(90°-α) = cosα

∴sin30° = sin(90°-60°) =cos60°∵cos(40°+x) = sin30°⇒cos(40°+x) = cos60°⇒40°+x = 60°⇒x = 20°

70594.

Simplify thefo

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-12 is the simplified answer of the question

70595.

1 63. एक साइकिल को 2,850 रु० में बेचने से :एक दुकानदार को 14% का लाभ होता € | - ।यदि लाभ कम करके 8% रखा जाए, तो :विक्रय मूल्य होंगा- :. (A) 2.600 To (B) 2.700 To: (C) 2800 Fo (D) 3.000 Fo

Answer»

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70596.

Without solving the following quadratic equation, find the value of 'p for which the roots are equal

Answer»

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70597.

sin 5xple 1. Evaluate: (i) limx→ 0 tan 3x

Answer»

As we know lim x->0 sinx/X=tanx/X=1hencelim x->0 sin5x/5x*5x*3/tan3x*3hence5/3(sin5x/5x*3x/tan3x)=5/3

70598.

Evaluate limx0 sin 3x

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70599.

Evaluate . limEvaluate : x->sin 7x - sin 3xsin x

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70600.

sin x40. Prove that lim-= 1

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sin inverse xLim --------------------x ->0 x

Form is 0/0 , apply L'Hopitals rule

1Lim --------------------x ->0 √(1-x²)

Put x = 1 we get

1

Proved