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sin210=sin(180+30)= cos30=V3/2

correct answer is √3/2

sin210= sin(180+30) = sin 30=3/2

sin 210= sin (180+30)=sin(90+90+30)= 1+1+1/2=2+2+1/2=5/2

the best answer is 3/2

3/2is the correct answer

answer is√3/2 perfect

LHS =cosA/(1+sinA) +(1+sinA)/cosA

={cos²A +(1+sinA)²}/cosA.(1+sinA)

={cos²A+1+sin²A+2sinA}/cosA.(1+sinA)

use sin²∅ +cos²∅ =1

=(1+1+2sinA)/cosA(1+sinA)

=2(1+sinA)/cosA(1+sinA)

=2/cosA

=2secA = RHS

sum of interior angles of a triangle = 180=> x + 50° + 60° = 180° x + 110° = 180° x = 180° - 110° x = 70°

Cost of ploughing = total area x cost of poulghing per 1 ( or given ) metre .

In the given question,

Cost of ploughing per metre= Rs 10 per m^2

Cost of ploughing the whole area = Rs 1540

= > Total area x Rs 10 / m^2 = Rs 1540

= > Total area = Rs 1540 / Rs 10 m^2

= > Total area = 154 m^2

As the given field is circular in shape, it's area should be πr^2.

Let the radius of the field be a,

Area of the field = 154 m^2 ( from above )

= > ( 22 / 7 ) x a^2 = 154 m^2

= > a^2 = 154 x 7 / 22 m^2

= > a^2 = 7 x 7 m^2

= > a^2 = 7^2 m^2

= > a = 7 m

Hence the radius of the circular field = 7 m.

Area of circular field = 1540/10 = 154Area of circle = πr²154 = 22/7 × r²49 = r²7 = r

Let Muli's salary be x.

Money spent on food = 3/10 of x = 3x/10

Money spent on rent = 2/3 of x = 2x/3

Money left with him = 2100

(3x/10) + (2x/3) + 2100 = x

x - (3x/10) - (2x/3) = 2100 ( LCM = 30)

30x/30 - 9x/30 - 20x/30 = 2100

(30x - 9x - 20x ) / 30 = 2100

x/30 = 2100

x = 2100 * 30 = 62,000

Answer:

Muli's salary = 62,000

3/10=2100 so 1 =(2100÷3)×10= 7000

your answer is wrong...

Here is a similar question.

Area of path is area of park with path - area of rectangular park area of park =lxb=45x30=1350 cm2area of park with path is =45+2.5+2.5 x 30+2.5+2.5 = 1750cm2area of path = 1750-1350=400 cm2

Let w = √( sin x + cos x ) , V = sin x + cos x

So y = sin w w = √v and V = sin x + cos x

dy / dw = cos w dw / dv = 1/(2√v) and dv/ dx = cos x – sin x

Thus dy / dx = ( dy / dw ) × ( dw / dv ) × ( dv / dx )

= cos w × 1/(2√v) × ( cos x – sin x)

= cos [√( sin x + cos x ) ] × 1/ [ 2 √(sin x +cos x) ] × ( cos x – sin x)

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integrate sin^4 x.dx=>[sin^2(x)]^2

=>[(1 -cos(2x)/2)]^2

=>1/4[1 + cos^2(2x) - 2cos(2x)]

=>1/4[1 - 2cos(2x) + (1 + cos(4x)/2 ]

=>(1/4) - (1/2)cos(2x) + (1/8) + (1/8)cos(4x)

=>(3/8) - (1/2)cos(2x) + (1/8)cos(4x)

so ∫sin^4(x)dx = 3/8∫dx - 1/2∫cos(2x) dx + 1/8∫cos(4x) dx

∫sin^4(x)dx = (3/8)x - (1/2)sin(2x)*(1/2) + (1/8)sin(4x)*(1/4) + c

∫sin^4(x)dx = (3/8)x - (1/4)sin(2x) + (1/32)sin(4x) + c

cost of pen = qcost of exercise book = q - 30cost of rubber = (q-30)/4q + (q - 30) + (q - 30)/4 = 1299q - 150 = 5169q = 666q = 74

132is right answer of this question

Total surface area of cylinder= 2*pi*r (r + h)

Given TSA = 1188, r = 7, h =?

1188 = 2*22/7*7(7 + h)7 + h = 1188/447 + h = 108/4 = 27h = 27 - 7h = 20 cm.Height of cylinder is 20 cm

Let the mother and her daughter's age be x and y years respectively.

x+y=60 ----(1)x-y=30-----(2)

Add (1) and (2):

2x= 90 => x=45 years

Therefore, Mother's age is 45 years and daughter's age is (60-45)=15 years.

sin (38°)-------------- cos(52°)

sin (90° - 52°)---------------------- cos(52°)

cos(52°)------------cos(52°)

1

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First of all,change the 88 km into cm.which will 88 km = 8800000 cmDiameter of given wheel = 56 cmthen, radius of the wheel = 28 cmWe know that,circumference of the wheel = 2πr2×22/7×28 =176 cmthen we just divide it out.8800000/176.= 50000SO WHEEL HAVE TO BE ROTATED 50000 TIMES TO REACH THE DISTANCE OF 88 KM.

Area of door=2*1=2m^2

Area of wall= 3.6*4.5=16.2m^2

the area to be painted= area of wall-area of door=16.2-2=14.2m^2 ans.

thanks

x= 416*4-15= 64-1549yearsI hope you will be able to understandplease like the solution 👍 ✔️

2(l+b)h = LSA2(12+8)4 =2(20)4 = 40*4 = 160m²cost of whitewashing 4 walls =160*8 = Rs 1280area of 5 walls = LSA+ l*b = 160 + (12*8) = 160 + 96 = 256m²cost of whitewashing vd ceiling = Rs 1280 +(96*8) = Rs 1280 + 768 = Rs 2048

Length of carpet = (12 - 4) = 8 mWidth of carpet = (10 - 4) = 6 m

(a) Area of carpet= length * width= 8*6 = 48 m^2

(b) Cost of carpet = 48*50 = sh 2400