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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 70801. |
person is running along a circular track of area625 Ď m2 (Ď-22/7) with a constant speed. Find thedisplacement in 15 seconds if he has to complete therace in 30 seconds. |
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Answer» area of circular track= 625π m^2 πr^2=625π r^2=625 π will get cancelled when it will go on L.H.S. r= √ 625 r=25 perimeter of circular track=2r =2*22/7*25 =44*25/7 =1100/7 =157.14 m the person has to run distance of 157.14 m speed of person= distance/time distance=157.14 m time= 30 seconds speed= 157.14/30 =5.23 m/s displacement= speed* time time=15 seconds speed=5.23 m/s displacement= 5.23*15 displacement in 15 seconds = 78.45 m |
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| 70802. |
வரை !In the given figure, AB II CD andfiqure. AB CD and EF is a transversal. If 21 = 70°, then find all other anglesO |
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Answer» angle1=5=70°angle1=3=70°(vertical opp. angle)angle 5=7=70°(vertical opp. angle)angle4= 4+3=180°4+70=1804=110°=2(vertical opp. angle ) also8=6=110° hope this will help you like my answer and make it best answer Put angle one as 70 degree than u have to apply t alternate angles, voa ANGLES Put angle one as 70 degree than you have to apply alternate angle, voa ANGLES angle 4= angle 2= angle 6= angle 8= 110angle= angle 3= angle 7= angle 5= 70 |
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| 70803. |
7. Reema has 24 cups and 18 saucers. Find the ratio of the following in the simplest form:(a) Cups to saucers(c) Cups to the wholĂŠ crockery(b) Saucers to cups(d) Saucers to the whole crockery |
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Answer» cups to saucer18/24=6/8=3/4=3:4 |
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| 70804. |
A triangle and a parallelogram have the same base and the same area. If the sides ofthe triangle are 26 cm, 28 cm and 30 cm, and the parallelogram stands on the bas28 cm, find the height of the parallelogram. |
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| 70805. |
Al a particular bakery, the ratio of flour to milk in an cake batter is 5.7. If the flour used is 12 cupsfind the quantity of milk in the batter(a) 9 cups(b) 168 cups(c) 6.3 cups(d) 8 cups |
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Answer» flour to milk=5:7flour = 12 cups so milk =7×12/5=16.8 cups |
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| 70806. |
Mr Barua ordered 925 cups of ice creamfor his party. At the end of the party,189 cups were left. How many cups ofice cream did the guests have? |
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Answer» for the answer subtract the values to find how much was left925-189=736 cups were used. |
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| 70807. |
32. A square room having one side equal to 12 m is to be paved with square tiles of side 50 cm. Thnumber of tiles required to pave the room is(A) 96(B) 625(C) 576(D) 144 |
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Answer» 144 is the answer..... 144 is the correct answer 144 is the right answer......... please like my answer I hope it help you 144 is the correct answer 576 is correct answer 144 is the correct answer 144 the correct answer of the given question |
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| 70808. |
Perimeter of an isosceles triangle is 50 cm. If one of the two equal side is 18 cm, find the third side. |
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Answer» perimeter of triangle is sum of all sides therefore let third side be xsox+18+18 = 50x = 50-36x = 14cm |
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| 70809. |
5, How manycups of drinking chocolate can be prepared from 14 cups?23 |
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| 70810. |
Find the volume area of the curved surface and the total surceradius of base are 20 cm and 28 cm respectivelyofindet Who |
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Answer» v=22/7*28*28*20=49280c. s. a=2*22/7*28*20=3520T. S. A=c.s.a+base area3520+2464=5984 |
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| 70811. |
13. The 4th term of a G.P. is square of its second term, and the first term is - 3. Find i7th term.f 2rd to |
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| 70812. |
B-1.The third term of a G.P. is the square of the first term. If the second term is 8, find its |
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| 70813. |
11. InthePQ = Pven figure <A = <D = 90°,AP = DQ and AR-PD. Prove that |
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| 70814. |
ven figure, find the measure of ZCAB, ZABC, A9. CABC, ZACB.105°Dand win the. |
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Answer» Angle BAC = 45angle ACB = 75nowangle B + 75+45= 180Angle B = 180-120° = 60 Angle BAC = 45; Angle ACB = 75; Angle B +75 + 45 =180;; Angle B = 180 - 120=60 Angle BAC = 45°Angle ACB = 75°Then,Angle B + 75+45 = 180 (linear pair)Angle B = 180-120=60 Plz like my answer and accepted as best Plz ans=1) angle CAB = angle FAE =45°(Vertic. opp.)3) Now in triangle ABCACB = (180-105)°=75°2) We now that the sum of triangle=ABC+BAC+ACB=180°=ABC+45°+75°=180°=ABC=180°-120°=60° Hope its help you |
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| 70815. |
ven figure, AB II CD and CA CE. Find the values of4,y and z.yo |
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| 70816. |
Fig. 14.270. Two rooms of floor sizes 5 m by 3 m and รณm by 5m were to be tiled with square tiles of side 50 cm.osmany tiles will be needed in all?Review of Chapter |
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Answer» Area of first room A1= length * breadth= 5*3 = 15 sq m Area of second floor A2= length * breadth= 6*5 = 30 sq m Area of tile At= side*side =.5*.5=.25 sq m Let number of tiles required = n Then,n*At = A1 + A2n = (15 + 30)/.25n = 45*100/25 = 45*4n = 180 Therefore number of tiles required = 180 |
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| 70817. |
s. Two rooms of floor sizes 5 m by 3 m and 6 m by 5 m were to be tiled with square tiles of side50 cm each. How many tiles will be needed in all? |
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Answer» Area of floor=n(area of tile)5*3=n(.5*.5)15*100/25=nn=60Area of floor=n(area of tile)5*6=n(.5*.5)30*100/25=nn=120So total tiles=120+60=180 |
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| 70818. |
8. Two rooms of floor sizes 5 m by 3 m and 6 m by 5 m were to be tiled with square tiles of side50 cm each. How many tiles will be needed in all? |
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Answer» Area of first room= length*breadth=5*3 m²=15 m² Area of second room= length*breadth=6*5 m²=30 m² Total area of rooms= 30+15 m²=45 m² Area of square tile= 0.5*0.5 m²=0.25 m² Number of tiles required=45/0.25=180 tiles |
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| 70819. |
There are 26 rooms in a schoo! 4 plants areplanted in the each room. It 2 cups of water ispowered in one plant then how many cups ofwater should be required for all the plants ?(A) 32 cups(B) 106 cups(C) 112 cups(D) 208 cupsom inone |
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Answer» 26×4=104 ... 104×2=208 |
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| 70820. |
10. Along a highway 50conical pillars are constructed. Each pillar has base diaineter 28 cm and vertical heighti8cm. find the total cost of painting these pillars at the rate of Rs. 120 per m.(Take T 22) |
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Answer» given radius = 14cm and height = 18cm curved surface area of cylinder = 2 π r h = 2* 22/7* 14* 18 = 1584 sq. cm = 1584/10000 sq. m now C.S.A. of 50 such pillars = 1584/10000 * 50 = 7.92 sq. m cost of painting 1 pillar = Rs.120 cost of painting 100 such pillars = 7.92 * 120 = Rs. 950.40--------------Ans. |
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| 70821. |
8. In a librarythere are 990 books. If the number of English books is 4 times the number ofMathematics books and the number of Mathematics books is twice the number of science books.Find the number of books of each subject. |
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| 70822. |
4. The 4hterm of a G.P.Determine its 7 term.is square of its second term, and the first term is 3 |
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| 70823. |
9.The 10th term of an A.P. is - 4 and its 22nd term is 16. Find its 38th term. |
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| 70824. |
pcney angles, findxll-4 90. Solve to get the value of x.]5. If the angles (13x + 30)° and (5x + 6)° are supplementary angles, find the measures ofthese angles.Hint: 13x +30 +5x +6 180. Solve to get the value of r and hence find the measure of the angles]6. If an angle exceeds its complement by 20°, find the angle.7. If the supplement of an angle is three times its complement, find the angleg[Hint: Let the measure of the required angle ber. Then 180-r-3 (90-x)]8·The supplement of an angle is one-third of itself. Determine the angle and its supplement.9. Two complementary angles are in the ratio 2:3. Find the angles.10. Two supplementary angles are in the ratio 4:5. Find the anlan |
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Answer» 6.one angle is xother is x+20 x+x+20=902x=70x=35°and other angle is55° |
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| 70825. |
19. If a, b, c are in A.P, then show thatb+c, ca, a + b are also in A.P.are also in A.P(ii)1(iii) (b+cP-a2, (c +α)2-b2, (a +6P(iv)AP.- c are also inalb rel bie a clatb are also in A.P+ c)beca ab20. If a2, b2, e2 are in A.P., prove that(i)1,1,1 are also in A.P.(00)are also in A.P |
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| 70826. |
ven figure shows twohe gi parallelgents XY and X'Y'at the points A and Brespectively to the creleith centre OAnother tangent CD is drawn parallel to ABat the point P. Show that a circle with P ascentre and OP as radius will pass throughCand D |
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Answer» So, AC || BD We know, rangers is perpendicular to the radius at the point of contact. So, angle OAC = angle OBD = 90 in quadrilateral ACDB, AB|| CD AC || BD Angle BAC= 90 Hence, it is clear that Quadrilateral ACDB is a rectangle So, angle C = angle D = 90 Now in quadrilateral OACP, Angle A = 90 Angle C =90 Angle OPC = 90 and angle AOP = 90 This implies quadrilateral OACP is a rectangle. So, OA = PC [ we know opposite sides are equal of rectangle] similarly, quadrilateral OBDP is a rectangle This implies OB = PD Also OA = OB = OP [ theses are the radii of the same circles ] So, PC = PD = OP This implies , points O, C and D are equidistant from point ap Hence, A circle with centre P and radius OP will pass through C and D |
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| 70827. |
d) 4 × 120 × 125 + 8 x 120125-2 x 120 × 1254. There are two book shops in a shopping complex. Shop Book Fair' sold 300 copies ofbooks in a week. Shop 'Book Depot' sold 325 copies of fiction in a week. Find the total numbeof books sold in a week. Name the properry of wimole numbers used for finding the rotalfourh person is educated in |
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Answer» Given:- there are two books shops in a shopping complex.Shop ' book fair' sold 300 copies of fiction books in a week.Shop 'book depot' sold 325 copies of fiction in a week.Total number of books sold in a week= 300 + 325 = 625The property of whole numbers used for the question is additivity property. tnku |
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| 70828. |
18. P, Q& Rare respectively, the mid points of sides BC, CA & AB of a triangle ABC. PR & BQmeet at X. CR & PO meet at Y. Prove that XY-BC. |
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| 70829. |
36 chairs can be kept in a room. How many rooms will be requiredto keep 36,036 chairs? |
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Answer» Chair required is36036/36=1001 rooms Plz accepted as best Plz like my answer Plz 1 room --- 36 chairsx rooms ---- 36036 chairs x=36036/36x=1001 hloplx like me plzplz |
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| 70830. |
In a class test, the number of students passed in various subjects are given below.SubjectEnglish Mathematics HindiDrawingNumber of10students passed152520 |
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Answer» the answer for this question is 45 |
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| 70831. |
angles of dileral are in the ratio 3:5:9 13. Find all the ang |
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| 70832. |
3. The ratio of 7 to 3' term of an A.P is 12:5. Find the ratio of 13 to 4 term. |
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Answer» thank you so much |
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| 70833. |
The angles of quadrilateral are in the ratio 3:5:9:13. Find all the angles ofquadrilateral. |
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Answer» Let X be the common multiplehence3x+5x+9x+13x=360...as sum of angles of a quadrilateral30x=360X=12hence angles will be3*12=36°5*12=60°9*12=108°13*12=156° 3 x +5x +9 x +13x = 360 30x = 360x = 360 over 30 |
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| 70834. |
The angles of quadrilateral are in the ratio 3 :5:9:13. Find all the angles of quadrilateral. |
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Answer» let the ratio be xso angles are 3x, 5x, 9x ,13xSum of all angles in quadrilateral3x + 5x + 9x + 13x = 360°17x + 13x = 360°30x = 360°x = 360°/30x = 12°so angles are 36°, 60°, 108°, 156° |
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| 70835. |
Dae alaseExercise 411. Fill in the blanks.◆ The length of the boundary of a figure is called the paine seof the figure.The perimeter of a square is 4 xThe perimeter of a rectangle is 2xThe perimeter of a figure made of line segments is the·of the lengths of the segments.?Find the perimeter of the following figures. |
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Answer» I) perimeter II) sideIII) length and breadth IV) sum |
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| 70836. |
5are25,2245, 41 resultefore, four rational numbers between 3 andtprove t, Exercise 2.1r line? s, becaB CDarrow best shows the position of 3 on the numberresand20y three rational numbers between 77 and 2(0.1 ando.ando anyfive rational numbers between (i) 4 and |
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Answer» 1) 11/3 = 3(2/3) which is greater than 3 and 3.5 also and since C is < 3.5 so, D will the correct answer . 2) 3 rational numbers between -7/11 and 2/11 are-6/11 , -5/11 , -4/11 please video sum annuipuinga |
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| 70837. |
1) Determine the dimensions in the given figure that will givetotal area of 27m .Explain Your answer2x+3 |
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Answer» length×breath= area of rectanglex(2x+3)=272x^2+3x-27=02x^2+9x-6x-27=0x(2x+9)-3(2x+9)=0(2x+9)(x-3)=0either 2x+9=0, x= -9/2 (neglected because length not be in -ve)so x-3=0, x=3length= 2x+3= 2×3+3=9mbreath= 3m Area of rectangle = 27 m^2. l × b = 27 m^2(2x + 3) × x = 27 m^22x^2 +3x - 27 = 02x^2 - 6x + 9x -27 = 02x(x - 3) + 9(x - 3) = 0(x - 3) (2x + 9) = 0x = 3 and x = -9/2Now, l = 2 × 3 + 3 = 9 m b = x = 3 m |
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| 70838. |
The number of students in a hostel, speaking different languages is given belowDisplay the data in a pie chart.Language Hindi English Marathi TamilBengaliTotalNumberof students4012912. |
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| 70839. |
3L) Us Lk e 9 तल कर dive 18903. duschरैक. &na ००८४LS el asceet s AYo e 4,००2oty |
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Answer» Let two parts be x and (20-x) Then,As per given condition x = (20-x) + 82x = 28x = 28/2x = 14 Therefore two parts are 14 and 6 |
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| 70840. |
et us now lakSample 10 : In Fig. 6.48,ACBBC2 BDAC AD90°tms and CDL AB. Prove thatSolutionΔ.ACD ~ Δ ABC.(Theorem 6.7) A |
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| 70841. |
uodi icif, Prove that:Vsec θ + ITV sec 0-1t lengths. et usationCons |
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| 70842. |
EXERCISE Iplhs of ae in the ratio 3 s9 13. Find all the angles |
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Answer» let the ratio be xso angles are 3x, 5x , 9x ,13x therefore sum of angles in quadrilateral is 360°3x + 5x + 9x + 13x = 360°30x = 360x = 360/30 = 12so angles are 36, 60, 108, 156 |
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| 70843. |
30001 .41 4 #: 4242 m2Exercise 4.1Using Heron's formula, find the area of a triangle whose sides are(i) 10 cm, 24 cm, 26 cm(ii) 1.8 m, 8 m, 8.2 m |
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Answer» i) a =10 cm , b = 24 cm and c = 26 cm. ∴ s = (a + b + c )/ 2 s = (10 + 24 + 26) / 2 = 30 cm. By Heron’s formula Area = √(s(s-a)(s-b)(s-c) = √30*(30-10)*(30-24)*(30-26) = √30*20*6*4 = √14400 = 120 ii) a =1.8 cm , b = 8 cm and c = 8.2 cm. ∴ s = (a + b + c )/ 2 s = (1.8 + 8 + 8.2) / 2 = 9 cm. By Heron’s formula Area = √(s(s-a)(s-b)(s-c) = √9*(9-1.8)*(9-8)*(9-8.2) = √9*7.2*1*0.8 = √51.84 = 7.2 Like my answer if you find it useful! |
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| 70844. |
13 Marks)2x +3TooIs.Aly one(l) Determine the dimensions in the given figure thatwill give total area of 27 m2. Explain your answer. |
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Answer» length × breadth = area(2x + 3)(x)=27 2x^2 +3x - 27=02x^2 +9x -6x - 27=0x(2x + 9) -3(2x + 9)=0(x-3)(2x+9)=0x=3,-9/2sides cannot be negativeso, x=3then breadth= 3mlength=2x + 3 = 6+3=9m |
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| 70845. |
EXERCISE 8.1The angles of quadrilatcral are in the ratio 3: 5:9:13, Find all the angles of the |
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Answer» thank u |
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| 70846. |
EXERCISE 8.1The angles of quadrilateral are in the ratio 3:5: 9: 13. Find all the angles of thequadrilateral.. |
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| 70847. |
represents a solid coGiven linder surmounted by consisting 3basemounted by a cone atother31 6of the vcylinond a heone end and hemisone ahe volume of thecylinuend ana hemisphere at thesolidrati OFinmes.e 22 cmchildren6.5 cm77 cmus 2 cm12.8 cmw man |
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| 70848. |
cos 30° x sin 60°93)cos 60°(A) o(C) 1(B) 0.5(D) 1.50001 |
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| 70849. |
67 × .67× .67-.001.67 × .67 + .067 + .017.(a) 0-66 (b) 0669 (c) 06757 (d) 057 |
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Answer» The answer for this question is option - (d) |
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| 70850. |
2. मान ज्ञात कीजिए:Sec (90° — 6) Cosec 0 — tan (90° - 0) (001 0 + Cos® 25° + (005 65%3 tan 27° tan 63° |
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