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Thedegreeof thezero polynomialis either left undefined, or is defined to be negative (usually −1 or ). Like any constant value, the value 0 can be considered as a (constant)polynomial, called thezero polynomial. It has no nonzero terms, and so, strictly speaking, it has nodegreeeither.

Well, it depends.

Mathematical practice shows that sometimes it is useful to define the degree of the zero polynomial to be zero, sometimes to define it to be−∞−∞and sometimes to leave is undefined. Which option one chooses depends on what one is trying to do.

This is quite different with what happens with the degree of all other polynomials, which is always defined in the same way (*) But don't think that if for the slightiest of reasons we were to fnd it useful to change the definition to do something we wanted, we would.

(*) Actually, that is not exactly true: we sometimes put degrees on polynomials which are different from the usual ones, but usually only on polynomials with more than one variable.

The soil around existing plants is cultivated (by hand using a hoe, or by machine using a cultivator) to destroy weeds and promote growth by increasing soil aeration and water infiltration. Soil being prepared for the planting of a crop is cultivated by a harrow or plow.

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In a parallelogram sum of adjacent angles are supplementaryA+B =1802x+10+3x-25=1805x-15=1805x=180+155x=195x=195/5x=39

The features of Deccan Plateau are as follows:-

●The Deccan Plateau lies to the south of the Satpura Range and extends till Cape Comorin.●It is composed of many very old crystalline rocks. ●It slopes towards the east.●Its height can vary from 300 m to 900 m above the mean sea level.

Let us assume that 5 - root 3 is rational. Then it can be written in the form

5 - root3 = p/q

or 5 - p/q = root3

It implies root3 is a rational number [Since 5 - p/q are rationals]

But this contradicts to the fact that root 3 is irrational. Hence our supposition was wrong. Therefore 5 - root 3 is irrational.

4√2 ko multiple kardo 1/4se,

The percentage of marks obtained by Mohnish in Mathematics. -45/75 * 100 = 60%

60%

Let 1st no. be xincrease by 10%x+x/10=11x/10now decrease 10%11x/10-(11x/10)/10=99x/100the decrease is x-99x/100x/100decrease % is 1%

See the diagram.

ΔABD andΔPQD are similar, as the corresponding sides are parallel. x/z = BD / QD => 1/x = QD /(z * BD)

ΔCDB andΔPQB are similar, as corresponding sides are parallel. y/z = BD/ BQ => 1/y = BQ / (z * BD)

Add the two equations: 1/x + 1/y = (BQ + QD) / (z * BD) = 1 /z

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let 2+√3 be rationalso 2+√3 can be written in p/q form2+√3= p/q√3= p/q-2 = p-2q/q√3 is irrational irrational is not equal to rational so our assumption is wrongso 2+√3 is irrational

V= IR12/2.5*10^-3= R4.8kohm= R

Tan A = sinA/cosA

Cot A= cosA / sinA

Sin²A+ cos²A= 1____________________________Answer:1+tan²A/1+cot²A = tan²A

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ΔABD andΔPQD are similar, as the corresponding sides are parallel. x/z = BD / QD => 1/x = QD /(z * BD)

ΔCDB andΔPQB are similar, as corresponding sides are parallel. y/z = BD/ BQ => 1/y = BQ / (z * BD)

Add the two equations: 1/x + 1/y = (BQ + QD) / (z * BD) = 1 /z

According to the question,55% of votes - 45 % of votes = 8756Let the total number of votes be x.Then, 55 % of x - 45 % of x = 8756=> (11/20 - 9/20) * x = 8756=> 2x/20 = 8756=> x/ 10 = 8756=> x = 87560

Suppose total no. of votes is xand Candidate with 66% votes be m and Candidate with remaining 34% votes be n.

Given that,m-n = 144=> .66x - .34x = 384 (putting values of m and n)=> x = 384/.32=> x = 1200

Let x people cast their votes

First got votes = .75xSecond got votes = .15xThird got votes = 800

Then,As per given condition.75x + .15x + 800 + 380 = xx - (.90x) = 1180.10x = 1180x = 1180/.10x = 11800

Therefore, Number of people cast votes = 11800

(A) is correct option

full answer

from the equation 1 and 2..we prove that ABOC is a square

Let radius ( r ) = x

l = 2x

h =√ l² - r²

h =√ ( 2x )² - x²

h =√ 3x²

h =√3 x

∴ Ratio of r and h = x :√3 x

r : h = 1 :√3

winner get =62% votelosser get= 38% vote their difference = 24 24 = 432 1= 432/24= 18therefore 100% vote = 18×100=1800

winner got = 68%looser got = 100 - 68 = 32%difference of both = 68 - 32 = 36 %LET total number of votes = X

A/Q

32% of X = 432(32/100)x X = 432X = (432 x 100)/32X = 1350 votes (ANS)

Let p( x ) = k² x² - 2kx - 3

If ( x + 1 ) is a factor p( x ) then

Remainder p ( - 1 ) = 0

k² ( - 1 )² - 2 k ( - 1 ) - 3 = 0

k² + 2k - 3 = 0

k² - k + 3k - 3 = 0

k ( k - 1 ) + 3 ( k - 1 ) = 0

( k - 1 ) ( k + 3 ) = 0

k - 1 = 0 or k + 3 = 0

k = 1 or k = - 3

Given: PR > PQ & PS bisects ∠QPR

To prove: ∠PSR > ∠PSQ

Proof: ∠PQR > ∠PRQ — (i) (PR > PQ as angle opposite to larger side is larger.)

∠QPS = ∠RPS — (ii) (PS bisects ∠QPR)

∠PSR = ∠PQR +∠QPS — (iii) (exterior angle of a triangle equals to the sum of opposite interior angles)

∠PSQ = ∠PRQ + ∠RPS — (iv) (exterior angle of a triangle equals to the sum of opposite interior angles)

Adding (i) and (ii) ∠PQR + ∠QPS > ∠PRQ + ∠RPS

⇒ ∠PSR > ∠PSQ [from (i), (ii), (iii) and (iv)]