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sum integers = 76, one =-53,, 76-53=23; (or) 76 -(-53)= 76 + 53 = 129

just occurred to me that I tend to think of integrals primarily as indefinite integrals and sums primarily as definite sums. That is, when I see a definite integral, my first approach at solving it is to find an antiderivative, and only if that doesn't seem promising I'll consider whether there might be a special way to solve it for these special limits; whereas when I see a sum it's usually not the first thing that occurs to me that the terms might be differences of some function. In other words, telescoping a sum seems to be just one particular way among many of evaluating it, whereas

Let three consecutive even integers beX-2, X, X+2,

according to data, their sum is 0,

(X-2) + (X) + (X+2) = 0,

3X = 0,

X = 0,Now the three integers are -2, 0, +2

Let the measures of ∠A be xº and measure of ∠B be yº.

Seg AB is the diameter of a circle and C is a point on the circumference.

∴ m ∠C = 900[∵ The angle subtended by a diameter at any point on the circle other than its end points is a right angle]

In ∆ ABC,m ∠A + m ∠B + m ∠C = 1800[∵ Sum of measures of the angles of a triangle is 1800]∴ x + y + 90 = 180∴ x + y = 180 – 90∴ x + y = 90 ........eq. no. (1)As the given condition,∠ B = ∠ A – 100∴ y = x - 10∴ x – y = 10 ......... eq. no. (2)Adding equations (1) and (2)x + y = 90x – y = 102x = 100∴ x = 100/2∴ x = 50Substituting x = 50 in equation no. (1)x + y = 90∴ 50 + y = 90∴ y = 90 – 50∴ y = 40The measures of angle of ∆ ABC are 50º, 40º and 90º.

thanks u

Let the cost of books be x.No. of books = 6No. of CDs = 2Rate of CDs = Rs. 45 eachTherefore, cost of CDs = 45*2= Rs. 90Cost of books + Cost of CDs = Total amountx + 90 = 540x = 540 - 90x = Rs. 450

Therefore, cost of one book = 450/6= Rs. 75

Cost of one book is Rs. 75

1,7×3=215,-4×4=16 is the best answer

1)21v)-16 is the right answer

(i) 21(v) -16

are the products and the best answer.

21 and -16 are the products of the above questions

no question of this question

2 - 6 = - 4

Correct Ans = - 4

-4 the correct answer of the given question

-4 is the right answer

-4 is the right answer

-4

the correct answer is -4 of the following question

4 is the correct answer

-4 is the answer of the following

-4 is the correct answe

-4 is the right answer

2-6=-4, correct answer=-4

2-6=-4 correct answer =-4

when 6 is less than 22-6-4is correct answer

2-6=-4best answer..........

thank you

Let salary of worker be aGiven ((15/100) xa = 11250(3/20) xa = 11250a = 3750x20Annual salary = 750000Monthly salary = 750000/12 = 62500

Circumference of circle = 2πr

Area of circle =πr2

New circumference after increase in radius = 1.15 × 2πR

Since circumference∝ radius of circle, radius increases by 15%

R = 1.15r

New Area =πR2= π(1.15r)2= 1.3225πr2

So, area is increased by 32.25%.

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a) 4a ÷ (5-a)

b) x/3 - 15

thanks

1) 0 1 2. 2). 2 4 5 3). 2 3 5

1) 0. 1

2)2.4.5

3)2.3

1). 0 12). 2 4 53). 2 3

(64-15/64)^1/2(49/64)^1/2= 7/8Answer

tq

please specify the question which should be answered

Circumference=2πr=2*22/7*1.4=2*0.2*22=8.8m^2

thank u

let X be common multiple hence according to question4x=12X=3hence first person will get 3x=3*3=9and third will get 7*3=21

the correct answer is 150

distance covered = 300 km

let the speed of the train = x km/hr

time (t1) = distance/ speed

t1 = 300/ x------(1)

2) distance = 300 km

speed = (x- 10) km

t2 = 300 / (x-10)----(2)

given t2-t1 = 1 hr

300/(x-10) - 300/x = 1

[300x - 300(x-10)]/ (x-10)x =1

300x -300x +3000 = (x-10)x

3000 = (x-10) x

let x= 60

3000 = (60-10) *60 [true]

thereforespeed of the train = x = 60km/hr

60 km/hr is the correct answer .....

(K-5)/(R-5)=3/4K+R-10=70K+R=804K-20=3R-154K=3R+5so K=(3R+5)/4(3R+5)/4+R=807R+5=3207R=315so R=45so K=35so K:R=35/45=7/9

Let the two numbers are N1 and N2

We have been given LCM =2310

HCF = 33

N1 (1st number) = 330

N2 (2nd number) = x, let

Now, the rule states that Product of two numbers is always equal to the product of their HCF and LCM.

So, N1 x N2 = HCF x LCM

330 * x = 2310 * 33

x = 2310*33/330

x = 231

So our 2nd number N2 is 231.

I) 22/7*r^2*h = 308022/7*r^2*(h-5) = 2310r^2*h = 3080*7/22= 28022/7*r^2*h-22/7*r^2*522/7*280-22/7*r^2*5 = 231022/7(280-r^2*5) = 2310280-r^2*5 = 2310*7/22= 735-r^2*5 = 735-280= 455r^2 = 455/5= 91therefore r = root 91ii) r^2*h = 280h = 280/91therefore h = 3.07iii) height = 3.07/2csa + base area = 2*22/7*root 91*3.07/2+ 22/7*root 91^2= 295.64 root 91 cm^2

height of mountain =2310+18000=10310

height of the mountain is =2310+18000=20310