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det(kA) = k^n det (A) where n is ordersodet (3A) = 3^3 det(A)therefore k= 27,option (4) is correct

16 × 3/4=48/4=12 rupeesthe values of 3/4 of 16 rupees is 12 rupees.

12 is the correct answer of the given question

16×3/4=12 rupees is the right answer

correct answer is 12 please like .....

in

Diameter=49mRadius=49/2=24.5 m

Area of circle=πr²=(22/7)*(24.5)² m²=1886.5 m²

Area of a circle with radius 1/π

8 cm is the right answer

8 cm is the right answer of this question

8 cm and 4 cm respectively

8cm is the first and 4cm is2nd

8cm is the right answer

QR code is the trademark for a type of matrix barcode first designed in 1994 for the automotive industry in Japan. A barcode is a machine-readable optical label that contains information about the item to which it is attached.

8 cm is the correct answer

the following question is 8

Hey!

Age of Seema's sister : 5 years .

Let her sisters age be X years .

According to the given question:---------------------------------------------------

1/4 x + 2 = 5

1/4 x = 3

X = 12 years ..

Hence her sister Seema is 12 years old

Let seema's age be x yearsAge of seema's sister is 5 yearsAcc to ques5-2=1/4x3*4=xx=12So seema's age is 12 years.....Hope this helps u...

12 yrs the correct answer of the given question

the right is 12th years

12yrs. is the right answer

seems age = x years, age of seema's sister is 5 years, 5-2 = 1/4x, 3 x 4 = x = 12, seema's age is 12 years

12 yrs is the correct answer of the given question

Sushil present age=5 yearsMother present age=28 years

Let after n years, mother will be double of age of Sushil

28+n=2(5+n)28+n=10+2n28-10=2n-n18=n

So, after 18 years, mother will be double of age of Sushil

A= p(1+r)^n

here. r = 12.5/100 = 0.125 , n = 2 and p = 2025

A = 2025*(1+0.125)^(2)A = 2025*(1.125)² = 2562.89

𝑬𝒙𝒑𝒍𝒂𝒏𝒂𝒕𝒊𝒐𝒏

We know that formula for compund interest=A=P(1+R/100)^nwhere 𝑵 𝒊𝒔 𝒕𝒉𝒆 𝒕𝒊𝒎𝒆so 6773.76= 5400(1+12/100)^n=>112/100^n=677376/5400×100=>112/100^n=12544/1000=>n=2

Circumference of circle=2πr=2(22/7)(49)=308m

Rounds=3080/308=10 rounds

Area of square garden = 8464 m².

Side² = 8464

Side => ✓8464 = 92 m

Distance covered by man in one round = Perimeter of square = 4 × side = 4 × 92 = 368 m

Therefore,

Distance covered by man in three rounds = 3 × Perimeter of square = 3 × 368 = 1104 m.

good

x^2 10x +25= x^2 +5x +5x + 25=x(x+5) +5(x+5)=(x+5)(x+5)Hence (x+5)(x+5) is the answer.

Let x represent the number of years.

In x years, Sushi will be 5 + x years old, and the mother will be 28 + x.

At that time, the mothers age will be twice Sushi's, which gives:

28 + x = 2(5 + x)

28 + x = 10 + 2x

2x + 10 = x + 28

2x - x + 10 = 28

x + 10 = 28

x = 28 - 10

x = 18

let the original price be XX*18/100=added amounthence X +0.18X=23601.18X=2360X=2360/1.18=2000rupeesand price of gst 0.18x=360rupees

Speed of car = 22.82 km/hrTime taken = 2.8 hr

Distance covered= Speed * time= 22.82*2.8= 63.9 km

1 round of field= perimeter of the field =2(length+breadth) =2(220+150)m =2(370)m =740mtotal distance covered=7 rounds of the field =7×740m=5180m

Length of Reactangular Park = 50 mWidth of Reactangular Park = 25 m

Perimeter of Reactangular park= 2(Length + Width)= 2(50 + 25)= 150 m

As athlete takes 10 rounds, therefore total distance covered = 10*150= 1500 m or 1.5 km

as it is from resthence u=0a=v-u/ta=8-0/2=4m/s^2henceforce required=ma=3*4=12N

(2) 40 years is the correct option

According to the question, I = P = (P*r*5)/100=> 100= r*5=> r= 20%

For amount to become 5 times, I = 5P-P = 4PTherefore, 4P = (P*r*t)/100=> 4= (20*t)/100=> t = 20 years.

thanks

Solution:(b) 1/6

Explanation:Only 2 testswill be needed to find the faulty machines ifwe can find one faulty machine in eachtest

The probability thatwewilltest a faulty machine in the first test is 2/4=1/2 (there are 4 machines and 2 of them faulty)

Now that one faulty machine has been identifiedwe are leftwith 3 machineswith one of them being faulty. The probability thatwe will test the other faulty machine in the second test is 1/3. So the probabilitythatwewill require 2 tests to find the faulty machines is 1/2*1/3=1/6

0=u-2*20u=40 m/s. !

all formula face

(A)30/61

The reason being:

The probability of A throwing ‘6’ is 5/36. So, the probability of A not throwing ‘6’ is 1 – 5/36 = 31/36. The probability of B throwing ‘7’ is 6/36. So, the probability of B not throwing ‘7’ is 1 – 6/36 = 30/36.

The probability that somebody wins is [1-{(31/36)(30/36)}]. So, The probability of winning of A provided that somebody wins = (5/36)/[1-{(31/36)(30/36)}] = 30/61.

3560 is correct answer the following question

Probability of A winning….

Possible events =6 ( In a die there are equal chances of getting 1,2,3,4,5 and 6)

Favorable events or outcomes= 1 (One must get only 3 to win)

Probability of getting a 3 or winning = No.of favourable outcomes/ no.of possible outcomes.

= 1/6 =0.166..

Or,= 1/6*100=16.6%.

Since , B also need a 3 to win as in case of A, so the probability is same ,i.e, 16.6%.

Therefore probability of their winning is 16.6% and 16.6%.

Answer: C)10Explanation:

Let Ajay age be x and Vijay age be yy-5=xx+y=25y-5+y=252y=30y=15now x=15-5x=10Therefore Ajay age is 10Vijay age is 15

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ANSWER= OPERATION IS 3