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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 72351. |
\left. \begin{array} { l } { 3 ( x - 3 ) = 15 } \\ { 7 - 3 x = 18 } \end{array} \right. |
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| 72352. |
\left. \begin{array} { l } { 3 \frac { 2 } { 5 } a } \\ { 3 = 20 } \end{array} \right. |
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Answer» 3 2/5 = 17/5 = 17/5 *100 = 340% everything is wrong |
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| 72353. |
\left. \begin{array} { l } { 3 x - y = 3 } \\ { 9 x - 3 y = 9 } \end{array} \right. |
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| 72354. |
\begin{array}{l}{3 x-2 y+3=0} \\ {4 x+3 y-47=0}\end{array} |
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| 72355. |
16. The price of an article has been increased from220 to253. Find the percentage increase inthe price of the article. |
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Answer» Increase in price = 253-220 =33 rs % increase =(33/220)×100 =(3/20)×100 =3×5=15% |
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| 72356. |
489. Robin says, "If Jai gives me 40, he will have haltas much as Atul, but if Atul gives me 40, then thethree of us will have the same amount." What is thetotal amount of money that Robin, Jai and Atul havebetween them?(a) * 240(b) * 320(c) * 360(d) 420 |
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Answer» Clearly, we have : J - 40 =1/2A ...(i) A - 40 = J ...(ii) A - 40 = R + 40 ...(iii) Solving (i) and.(ii) simultaneously, we get : J = 120 and A= 160. Putting A 160 in (iii), we get R = 80. Total money = R + J + A= Rs.(80 + 120 + 160) = Rs.360 |
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| 72357. |
A and B throw a die alternatively till one of them gets a 6 and wins thegames. Find their respective probability of winning, if A starts first. |
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Answer» Given:A and B throw a dice simultaneously till one thus gets a 6 and wins this game. Now, consider winning of A LetSandFbe the following events. S: obtaining a six by A F: not obtaining a six by B A can win the following way: (i) He obtains a six in the first trial (ii) A fails to obtain a six, B fails to obtain and then A obtains a six (iii) A fails, then B fails, then A fails, then B fails to obtain and finally A obtains a six and so on Obtaining a six by A and not obtaining a six by B are independent events P(A wins)=P(S)+P(FFS)+P(FFFFS)=1/6+1/6*(5/6)^2+1/6*(5/6)^2=1/6*(1/1-5/6)^2)=1/6/1-25/36=6/11 |
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| 72358. |
16 A school team won 6 games this year against4 games won last year.What is the per cent increase? |
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Answer» percentage increase6-4/42/4*10050 percentage |
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| 72359. |
.7. A gambler wins Rs 6 with probability 0.2 and losses Rs 4 with probability 0.3, find his expected gain |
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Answer» expected gain = 6×0.2-4×0.2 = 1.2-0.8 = 0.4 |
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| 72360. |
106. Bipasha's present age is 1/3d of her father Monish's age. 10 years from now Monish's agewill be twice the age of his son Sumant's age. If three years ago Sumant was 10 years oldthen how old is Bipasha currently?(1) 11 years(2) 12 years(3) 13 years (4) 15 years |
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Answer» Let Monish present age be mLet Sumant present age be nThen Bipasha age = 1/3(m) After 10 years m +10 = 2(n+10)m = 2n + 10 Three years agon-3 = 10n = 13m = 2x13 + 10 = 36 Bipasha age = 1/3(m) = 1/3(36)= 12 years |
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| 72361. |
Rekha is 25 years younger than her mother. In 12 years, her mother will betwice as old as Rekha. How old is each now? |
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Answer» described it.write clearly |
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| 72362. |
3.that a tangent to a circle is perpendicular to the radius drawn from the pointof contact |
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Answer» i didn't understand this answer |
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| 72363. |
14. A hall 36 in long and 214. A hall 36 n lonwalls at Rs 8.40 per m2 is Rs 9408. Find the height of the hall, 36 <24-Asea |
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| 72364. |
: A tangent at any point of a circle is perpendicular to the radius atthe point of contact. |
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| 72365. |
4. Onions were packed in sacks each weighing 18 kg 500 g. How many such sacks can be loadedin a truck with a carrying capacity of 3,182 kg?5. The nanulation of a metro city was 1 37 28 24 10. .. 1 4 |
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Answer» 1kg=1000g18kg 500g=18×1000+500 18500g3182kg=3182×1000 =3182000 gsacks can be loaded in a tuck=truck carrying capacity ÷ weight of one sack=3182000 ÷ 18500=172 onion sacks will be loaded in a truck |
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| 72366. |
8. Simplify after removing the brackets :x-(x-y-z)-(y-x-y) (i) x+y+z-(x + y - z)(i) 7x? - {3x² - 2x + 3) (iv) 8x-[(3x + 4y +(4x - 2y + 2)}]9. Simplify: |
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| 72367. |
Multiple Choice Questions (MCQs)12. The curved surface of a cylindrical pillar is264 m2 and its volume is 924 m3. The diameterof the pillar is(a) 5 m(c) 10 m(b) 9 m(d) 14 m |
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| 72368. |
\left. \begin array l 3,9,27,81,243,729 \\ \text (A) 1458 \\ \text (B) 1823 \\ \text (C) 2187 \\ \text (D) 2923 \end array \right. |
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| 72369. |
Can the following two matrices be multiplied and if so compute their product\left[ \begin{array}{rrrr}{4} & {2} & {-1} & {2} \\ {3} & {-7} & {-3} & {-3} \\ {2} & {4} & {-3} & {1}\end{array}\right] \cdot \left[ \begin{array}{rr}{-3} & {3} \\ {-3} & {5} \\ {3} & {1}\end{array}\right]= |
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| 72370. |
Rajiv and Robin play 12 games of chess. Rajivs 6 games, Robin wins 4 games and 2 gameswinend in a draw. They agree to play3 more gamesCalculate the probability that out of these 3games, two games end in a draw. |
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Answer» Look at all the possible outcomes there are 3^3 or 27 of them. AAA AAB AAD ABA ABB ABD ADA ADB ADDBAA BAB BAD BBA BBB BBD BDA BDB BDDDAA DAB DAD DBA DBB DBD DDA DDB DDD Probability that two games end in a draw = 5/27 |
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| 72371. |
sm of Ritu's age and Ashu's age is 25. Ritu is 12 years old. Write an equation to find Audna's agesum o |
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Answer» type answer please dikhayen |
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| 72372. |
10. Medicine is packed in boxes, each weighing 4 kg 500 g. How many suchboxes can be loaded in a van which cannot carry beyond 800 kg?1 |
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Answer» 178 boxes loaded in a van 4kg.500 by 800kgs=500/4.500=177.78 178 boxes loaded in a van 178 boxes loaded in the van 178 boxes loaded in a van weight of 1 box = 4 kg 500 g = 4.5 kg loading capacity of van is not more than 800 kg. ER. RAVI KUMAR ROY number of boxes placed = 800/4.5 = 177.777... Hence 177 boxes can be loaded in the van.. ANS... |
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| 72373. |
\sin ^{2} 75^{\circ}-\sin ^{2} 15^{\circ}=\frac{\sqrt{3}}{2} |
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Answer» Sin²A - sin²B= Sin (A+B).Sin(A-B) Now sin²75 - sin²15 = sin 90 . sin 60 = 1.√3/2= √3/2Ans |
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| 72374. |
2/ For what value of 8, sin 6 = cos 8 where 0 <6 < 90%?9 के किस मान के लिए आए 6 - ८05 0, 0 <6 < 90% ?09ा२/अथवाExpress sin’ 8 in terms of cos? 6.sin® B %1 cos? 6 के पदों में व्यक्त कीजिए।हि के |
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Answer» 2. sinθ = cosθ sinθ------ = 1cosθ tanθ = 1 θ = 45° 3. |
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| 72375. |
. Suppose A and B are two equally strong table tennis players. Which of thefollowing two events is more probable?(i) A beats B in exactly 3 games out of 4(ii) A beats B in exactly 5 games out of 8. |
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| 72376. |
8.Express the following with positive exponents(a) 2-6 (b) 5-3 (c) (x2)39 Simplify |
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Answer» 1) (2)^-6 = (1/2)^6 2) (5)^-3 = (1/5)^3 3) (x)^-6 = (1/x)^6 |
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| 72377. |
10x10 |
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Answer» 100 is the best answer |
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| 72378. |
6A farmer increases his output of wheat in his farm every year by o loeat in his farm every year by 8%. This youproduced 2187 quintals of wheat. What was the yearly produce ofago?ne yearly produce of wheat two years |
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Answer» present production=2187 let production a year ago=Xthen, X×108%=2187 X=(2187×100)/108 X=81×25=2025 let production 2 years ago=Ythen, Y×108%=2025 Y=(2025×100)/108 Y=1875 quintal. ans y=1875 quintal.is answer |
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| 72379. |
18. If A and B are two matrices such that AB-B and BA - A, then Al |
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| 72380. |
(VI)I0207. The students of Class VIl of a school donated 2401 in all, for Prime MinisterNational Relief Fund. Each student donated as many rupees as the number ofin the class. Find the number of students in the class. |
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| 72381. |
N N TNGSimply : [543 o+ V18â |
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| 72382. |
500g to 1 kg. |
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Answer» 1 kg = 1000 g 500 g / 1 kg = 500 g / 1000 g = 1/2 |
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| 72383. |
cofrectmealinstead of 78 and 59 instead of 69, find thewages of 216 workers is ?79. If one worker left, the mean was calculated again andwas found to be 82. Find the wages of the worker which had left.in 3 STIccessive games on the same course: |
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Answer» Total wage = 216*79= 17064.New total wage = 215*82= 17630. According to the question, wage of the worker = Rs. -566, which cannot be possible. Hence question is wrong. PLEASE HIT THE LIKE BUTTON |
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| 72384. |
Try These a1. Write the simplest form of:15752. Is 4. in its simplest form?uivalent? |
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Answer» 1) 1/52) 2/9 3)1/34) 21/145) 10/3 2)49/64 is in its simplest form since it cannot be solved further 1) 1/52) 2/93) 1/3 4) 21/145) 10/3 |
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| 72385. |
DecimalsEXERCISE 3Ahe following into a fraction in its simplest form:avert each of(n .8followin(11) .75(i11) 06uv) 285h of the following as a mixed fraction |
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Answer» ans*(¡) 8/10(ii) 75/100(iii) 6/100(IV)285/1000 |
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| 72386. |
Express each of the following ratios in simplest form(i) 24: 40(ii) 13.5 15(iv) 1.192(v) 4:5:6 9Express each of the following ratios in simplest form: |
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| 72387. |
2. If 5g of grass is required to cover an area of 1 m, then what weight of grass in kg would be requiredto cover a football field of dimensions 120m x 90m?(a) 27 kg(b) 54 kg(c) 81 kg108 kg |
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Answer» mass of grass required is 5g/m² now area of field = 120×90 = 10800m² so total mass of grass = 10800*5 = 54000g in kg it is = 54000/1000 = 54kg option b thanks |
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| 72388. |
The simplest form of |
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Answer» 69/92 (3*23) / (4*23) 23 gets cancelled then, 69/92 = 3/4 |
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| 72389. |
In an election, there were 5 candidates. The adjoining pie-chartgives the votes secured (in percentage) by each candidate. Observethe pie graph and answer the following questions.(i) Who won the election?(ii) Who secured minimum number of votes?iii) If total number of votes polled were 4200, then by howmany votes the winning candidate defeated his nearest |
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Answer» 1) c won the election2) d got the lowest votes(45°) 3)360° = 4200 votes1° = 4200/36011.6then 121° = 1411.6nearest votes 85° then 85° = 11.6991 votesdifference = 1411-991420 votes |
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10x9 +10* log, 103/10(A) 10-r10 + C(C) (10-x+C(B) 10x10 C(D) log(10C |
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| 72391. |
(c) 10 yearsĺ3 15) 10(c)-10(b) 11 |
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Answer» Please hit the like button if this helped you |
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| 72392. |
24.On her birthday, Amisha donated 2 toffecs to each children of an orphanage and 15 chocolates toadults working there. Taking the total items distributed as x and the number of children y, writealinear equation in two variables for the above situation.Write the equation in standard form.(i) How many children are there if total 61 items were distributed?(ii) What values does Amisha possess? |
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Answer» 1. Total no of toffees to children = 2y Total no of toffees to adults = 15 2y + 15 = x is the standard form 2. 2y + 15 = 61 2y = 61-15 y = 46/2 y = 23 3. Caring, kind, socially active. Like my answer if you find it useful! a ) the answer is 17b ) the answer is 2 |
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| 72393. |
9. Can a polyhedron have 10 faces, 20 edges and 15 vertices. |
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Answer» no it cannot haveits not possible sorry wrongly posted yesFormula isFace+ Vertices= Edge+2SOLVE: Face=10 ,Vertices=15 = Edge=20+2 next is10+15=20+225=22means : 25 is unequal to 22. next is 10+15=20+225=22means : 25 is unequal to 22 we will use Euler's formula10 +15 = 20+225=22unequal |
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| 72394. |
8. Can a polyhedron have 10 faces, 20 edges and 15 vertices? |
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| 72395. |
126 FundsReal estate / 720Shares108 , 18Gold6. The following pie diagram representsexpenditure on different items inconstructing a building. Answer thefollowing questions.a) Find the expenditure on each of theitems if the total construction cost is5,40,000.expenditure?expenditure?b)Which is the item having the maximumc)Which is the item having the minimumBricksementLapo . 1000( 1 745090°SteelTimber |
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| 72396. |
Varsha bought 3kg 500g of sugar, 250g of salt and 200g of tea. find the total weight of the items bought by her? |
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Answer» 3 kg 950g hzncbnxnxjxndbjdud 3 kg 950g hzncbnxnmmm total weight is 3kg 950g. total weight of all = 3 kg 950 gm.. 3kg 500g+250g+200g=3kg 950g the total weight is 3 kg 950 g total weight of item is 3kg 950 g 3kg950 gm is right answer.. |
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| 72397. |
The mean of 100 items was found to be 64. later on it was discovered that 2 items were misread as 26 and 9 instead of 36 and 90 . find the correct mean |
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Answer» thank you |
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| 72398. |
व... की डा N के T R UGN T T N८ 1८8 शुट (2९ & b bl ० ट ) Disjide DIE 18810 L6 Bl %G 30 Dk | 3 0 €C hith BE ISk | Lab 1)8 |
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Answer» 5300000*105/100=55650005565000*105/100=5843250 |
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| 72399. |
li mean of'two items is ls and Il.l. is 9. find our their G.M |
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Answer» Let the two numbers be p and q. Since the arithmetic mean of the two numbers is 16, we take: (p+q)/2 = 16 => p+q = 32 … (1) Now, since the harmonic mean of the two numbers is 9, we have: 2/(1/p + 1/q) = 9 => 2/[(p+q)/pq] = 9=> 2pq/(p+q) = 9 => pq/(p+q) = 9/2 … (2) Now, by placing the value of p+q in equation (2), we take: pq/32 = 9/2 => pq = 9*32/2 … (3) Therefore, the geometric mean of p and q is: sqr(pq) = sqr(144) = 12 Like my answer if you find it useful! hindi ma translation |
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| 72400. |
+८05: ही.£ l : 3CBSE 2 Evalute the following: - sinZ25° 4 sintes* + v/3ftanse tan15° tan20® tan7s® ta 185°)n |
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Answer» Sin²25° + Sin²65° + √3 ( Tan5° × Tan15° × Tan30° × Tan75° × Tan85° ) . Sin²(90-65° ) + Sin²65° + √3 ( Tan5° × Tan85° × Tan15° × Tan75° × Tan30° ). Cos² 65° + Sin²65° + √3 ( Tan5° × Tan(90-5°) * Tan15° × Tan(90-15°) * Tan 30° ). Sin²65° + Cos²65° + √3 ( Tan 5° × Cot5° * Tan15° × Cot15° * 1/√3 ). Sin²65° + Cos²65° + √3 ( Tan5° × 1/Tan5° * Tan15° × 1/Tan15° × 1/√3 ). 1 + √3 ( 1 * 1 * 1/√3 ) 1 + √3 ( 1/√3 ) 1 + √3 × 1/√3 1 + 1 2 Like my answer if you find it useful! |
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