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tq so much

by basic subtraction 36.285 - 12.578 = 23.707 kg

13kg 650 g = 13,650 g13,650 / 21= 650 g 650 g milk will be given to each student..

13kg 650g 13.650g13.650 / 21 650 G650g milk will be given to each student.....

13kg.650g=13,650g13,650/21=650g650g milk will each get.

mereko bhi koi ans kar do

50. people can speak in hindi and English

Each family gets = 3*680/408

= 680/136

= 5 litres

thnks☺️☺️

Total height of the tent = 85 m

Diameter of the base = 168 m

Therefore, radius (r) = 84 m

Height of the cylindrical part = 50 m

Then height of the conical part = (85 - 50) = 35 m

take base DE=4cm and E as centre angle 60.and do a arc

suppose number is xso 2x+4=25/6so 2x=25/6-4=(25-24)/4=1/4so x=1/8

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this is wrong in book answers

book answer is ₹37.65

Speed =45 x5/18 m/sec

=25/2 m/sec

Time = 30 sec.

Let the length of bridge bexmetres.

Then,(130 +x)/30=25/2

2(130 +x) = 750

x= 245 m.

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Length of train = 140 m Speed of train = 72 km/hr = 72*5/18 = 20 m/sec

1) Time train take to cross poleDistance = speed *time140 = 20 * timetime = 140/20 = 7 sec

2) Time train take to cross platformDistance = speed *time140 + 220 = 20 * time360 = 20*timetime = 360/20 = 18 sec

C.P of 6 oranges = Rs 10 C.P of 10 oranges = Rs 20Total C.P of 16 oranges = Rs 30C.P of 1 orange = 30/16 = 1.875S.P of 12 orange = 21.6 S.P of 1 orange = 21.6/12 = 1.8Loss = C.P - S.P = 1.875-1.8 = 0.075Loss% = 0.075*100/1.875 = 4%

15km/h is the right answer

15km/h is the right answer

15km/h is the right answer

15km/h is the righg answer....

15km/h is the right answer.....

15,km /hour is the speed when it increase

15km/h is the right answer

Given that Ravi starts for his school at 8.20 am.

Let the distance be x km.

Let the time taken by Ravito reach the school be y.

(1) Given that he travels at a speed of 10km/hr and reaches by 8 minutes late.

x/10 = y + 8/60

x/10 = y + 2/15 --- (1)

(2) Given that he travels at a speed of 16km/hr and reaches by 10 minutes early.

x/16 = y - 10/60

x/16 = y - 1/6. ----- (2).

on solving (1) and (2), we get

x/10 - x/16 = 2/15 + 1/6

3x/80 = 9/30

x = 9 * 80/3 * 30

= 8 km. ----- (3)

Substitute (3) in (2), we get

8/16 = y - 1/6

y - 1/6 = 8/16

y - 1/6 = 1/2

y = 1/6 + 1/2

= 2/3 hours

= 2/3 * 60

y = 40 minutes.

Ravi starts school at 8.20am + 40 minutes = 9.00AM.

His school starts at 9.00AM.

Whentwo coins are tossed simultaneouslythen the possible outcomes obtained are {HH, HT, TH, and TT}. Here H denotes head and T denotes tail. Therefore, a total of 4 outcomes obtained ontossing two coins simultaneously.

A = Exactly one is head = {HT, TH}

So, P(A) = 2/4 = 1/2

1)total possible outcomes are 8

(1) When we toss three coins simultaneously then the possible of outcomes are: (HHH) or (HHT) or (HTH) or (THH) or (HTT) or (THT) or (TTH) or (TTT)

So, total possible outcomes = 8

(2) Probability of getting at least two heads= 4/8 = 1/2

1. No. of possible outcomes =82 . probability of getting at least two heads=4/8 =1/2

Cost price of 16 fruits = 30Selling price of 12 fruits = 21.60Selling price of 1 fruits = 21.60/12= 1.8Selling price of 16 fruits = 16*1.6 = 25.6Gain % = [(SP - CP) /cp] *100= [(25.6-21.6)/21.6] *100= 400/21.6= 18.5%

Area ot parallelogram = base × height7× 3.25 = 22.75 dm²a) 1 dm² = 100 cm²22.75 dm² = 22.75 ×100 cm² = 2275 cm²

Let height =hBase =b

Area of this triangle =hb/2

If the each is double of old than

Area =2h*2n/2

Area =2hb

Area is four times of old triangle

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Let the distance between school and home be x km.The difference of time when he goes to school with these two different speed is 10 min = 10/60 hour.Now,(x/3)-(x/4)= 10/60Or, x/12 = 1/6Or, x = 12/6= 2 km.

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plz ans in short

distance=2592kmlet time taken be tthen speed=2tspeed=distance/time2t=2592/tt²=1296t=36hrs

if tan (3a +15) = √3 find the value

distance=2592kmlet time taken be tthen speed=2tspeed=distance/time2t=2592/tt²=1296t=36hrs