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72501.

If the CP of 6 articles is equal to SP of 7 articles, Find the gain percent.

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thank u so much

72502.

Tow unbiased coins are tossed once. What is the probability of getting one head?

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The probability are {HH,HT,TH,TT}

Getting one head = {HT,TH}

= 2/4 = 1/2

72503.

profll Ol I0SS 70.7. Mithun purchased 100 articles for 5000. He sold 50 articles at a loss of 10%. If Mithunneither wants to make any profit or suffer any loss, at what price Mithun should sell tremaining 50 articles?

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72504.

A vendor buys Jemons at ?25 per dozen and seills them at the rate of 5 for 12. Find his ganor loss per cent6

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thank you sir

72505.

If the C.P. of 6 articles is equal to S. P. of 4 articles, find the profit or lese per cent

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72506.

Angelica is working with functionmachines. She has the two machinestherm in order so that the output of thefirst machine becomes the input ofthe second. Her initial input is 6.a. In what order must she put the machines to get a final output of 5?b. Is it possible for her to find an initial input that will get a final output of -5If so, show how she could do that. If not, explain why not.

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x = 6a. Second machine first.y = x² - 6 = 36 - 6 = 30y = √x - 5 = √30 - 5 = √25 = 5

b. Yes, it is possible. Give the input initially in the first machine. y = √x - 5 = √6 - 5 = 1 y = x² - 6 = 1 - 6 = -5

72507.

[ee — lo=7/o

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100-10/10=90/10=9

72508.

"V Jo ən[ea at pur, I = Yus + OSS QUISIT MOOTTOTY 1-14.

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72509.

3m=5m-8/5

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3m = 5m - 8/5

8/5 = 5m - 3m

8/5 = 2m

m = 4/5

72510.

if a scooterist drives at the rate of 24 km/hr from his home, he reaches his work5 minutes late. But if he drives at the rate of 30 km/hr, he reaches his workplace 4 minutes early.(a)Find the distance of his work place from his home.

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72511.

EXERCISE 18BInthe given figure, ABCD is a quadrilateral in whichAC = 24 cm, BL 1 AC and DM 1 AC such that BL = 8 cm andDM 7 cm. Find the area of quad. ABCD

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72512.

210Mathematics for Class 8EXERCISE 18B1. In the given figure, ABCD is a quadrilateral in which8 cm andAC = 24 cm, BL AC and DM丄AC such that BLDM 7 cm. Find the area of quad. ABCD

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thank uu

72513.

EXERCISE 18B. In the given figure, ABCD is a quadrilateral in whichAC -24 cm, BL 1 AC and DM L AC such that BL 8 cm andDM = 7 cm. Find the area of quad. ABCD.

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72514.

Sandeep has a road map with a scale of' 1 cm representing 16 km. He drives on a road foWhat would be his distance covered in the map?He drives on a road for 121o.

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72515.

L.IH,3 is added tU llumerator and denominator it becomesthe Fraction.The Angles of elevation of the top of a towtwo points at a distance of 4m and 9m fromof the tower and in the same straight linewcomplementary. Prove that the height ofis 6m.

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72516.

Find the cost price/selling price.S.P=795Gain % = 6%

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my question answer me

72517.

A man bought a scooter forき32,000 and sold it after losing-th of its cost price. Find the loss percentand selling price.6.

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wrong

72518.

18 articles were sold at an average priceof 15. The cost price of 12 articles waseach. Find the cost price of each ofthe remaining 6 articles if there was noprofit/loss in the transaction.

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Cost price of 12 articles = 12*16 = Rs 192

Selling price of 18 articles = 18*15 = Rs 270

Cost of remaining 6 articles= 270 - 192= 78

Cost price of each article= 78/6 = Rs 13

72519.

6 If the selling price of a flower vase is of its cost price, find the loss56per ci0 nt uhat nrice shou

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Thnku

72520.

submarine floating 1200m below the sea level. V U 18 C VOLVOX NANGQ4. A certain freezing process requires the room temperature be lowered from 35째C at therate of 7째C every hour. What will be the temperature at the end of 10th hour.fe ry correct questinn and 2 marks are awarded

Answer»

Initial Temperature = 35° CRate of change in temperature = 7° C/hourTime = 10 hours

So, in 10 hours the temperature would be decreased by 10*7 = 70°C.

So, Final Temperature = 35 - 70 =- 35°C

72521.

3. Find the area of pentagon ABCDE in which BL 1 AC, DM丄ACand EN丄AC such that AC = 18 cm , AM = 14 cm , AN = 6 cmBL = 4 cm . DM = 12 cm and EN-9cm.

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72522.

3. Find the area of pentagon ABCDE in which BL L AC, DM 1AC14 cm , AN-6 cm,and EN-L AC such that AC = 18 cm , AMBL = 4 cm , DM = 12 cm and EN = 9 cm.

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72523.

A driver starts from Kapasdih and drives 45 km in 1 hour. He covers the same distanceevery hour and is 25 km from Kumharpur after 4 hours. How far is Kumharpur fromKapasdih?

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72524.

17. On seling an exhaust fan forき7350, a man gainsof its cost price. Find the cost price6of the fan.

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72525.

Assume π#-, unless stated otherwise.1. A solid is in the form of a cylinder with hemispherical ends. The total height of the solid is 19 cm and the diameter of thecylinder is 7 cm. Find the volume and total surface area of the solid.7. Find the volume of a Gulab iamun in the form of a right circular cvlinder with hemispherical ends whose total length is 2.7 cm

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72526.

RULI SCTg a wall IULIEU, a suupkeeper lusUSTO. TOT TOW MU U putut1325, a man gains 6%. For how much should he sell it to2. On selling a calculator forgain 12%?

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to help drive your career at its peak

gain 12% he sell calculator upto rupee =₹ 2650

72527.

which he purchased the washing machine.H) On selling a toaster for1,325, a man gains 6%. For how much should he sell it toearn 12% profit?r his showroom at? 1,200 per piece. He spentfor 1.500

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hit like if you find it useful

72528.

17. On selling an exhaust fan for7350, a man gainsof its cost price. Find the cost price6of the fan.

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72529.

: A man sold two cycles for 3000 each, gaining 20% on one and losingthe other. Find his gain or loss percentage on the whole transaction?SP= * 3000

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Gain = Rs.600selling price with 20% gain = Rs.3600

loss = Rs.720selling price with 20% loss = Rs.2880

cost price> selling priceloss = cost price - selling price = Rs.3000 - Rs.2880 = Rs.120loss% = 120/3000*100 = 4%he sold sold his cycle with 4% loss.

72530.

3. A solid is in the shape of a cone surmounted on a hemisphere, theradius of each of them being 3.5 cm and the total height of the solid is 249.5 cm. Find the volume of the solid.CBSE 20127

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72531.

A man sold two washing machines for79900 each. He sold one at a gain of 10% andthe other at a loss of 10%. Find his gain orloss % in the whole transaction.

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For 1st washing machine :

Cp = 9900

Profit %= 10%

Sp = 9900 + 9900 /100 * 10 ( taking out the percentage) = Rs 10,980 Profit = Rs 990

For 2nd washing machine:

Cp = 9900

Loss % = 10 %

Sp = 9900 - 9900/100*10 = Rs 8910

loss = Rs 990

Balance on whole transaction = 10980 - 8910 = 1980

Therefore his profit is = 1980And profit % = 1980 / 19800 (9900 * 2) * 100 = 10 %

answer is coming 1 percent loss

72532.

10% प्रतिवर्ष की दर से ₹700 का कितने वर्षों में मिश्रधन ₹847 हो गए

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2 सालों में ₹700 847 में बन जाएंगे

interest = 847-700=147N= 100×I/P×R100×147/700×102.o years required

72533.

A man sold two cycles for rs 3000 each. Gaining 20 % on one and losing 20 % on other. Find his gain or loss percentage on the whole transaction?

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Total selling price = 6000Cost price of first cycle be CP1Cost price of second cycle be CP2

Then,For first cycle3000 = CP1(1 + 20/100)3000 = CP1(6/5)CP1 = 500*5 = 2500

For Second cycle3000 = CP1(1 - 20/100)3000 = CP1(4/5)CP1 = 750*5 = 2500 = 3750

Total CP = 2500 + 3750 = 6250

Loss % = [(Total CP - Total SP) / Total CP] *100 = [(6250-6000)/6250]*100= (250/6250)*100=.04*100= 4%

There is loss of 4% in whole transaction

72534.

During the annual function of a school,a Women's Self-helf Group had set upa snacks stall. Their sales every hourwere worth 960-R830,7 945,䚏800.847, 970 respectively. What was theaverage of the hourly sales?96

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72535.

0.4By Eulid division algorithioapsind the .pair of no 847 D2160arece prime or not.

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Using Euclid's algorithm .

a = bq + r.

847 , 2160 .

2160 = 847 × 2 + 466 .

847 = 466 × 1 + 381 .

466 = 381 × 1 + 85 .

381 = 85 × 4 + 41 .

85 = 41 × 2 + 3 .

41 = 3 × 13 + 2 .

3 = 2 × 1 + 1 .

2 = 1 × 2 + 0 .

HCF( 847 , 2160 ) = 1 = 1 .

Hence, this pair is co-prime numbers .

72536.

2. During the annual function of a school,a Women's Self-helf Group had set up"a snacks stall. Their sales every hourwere worth 960, 830, 945, 800,*847, 970 respectively. What was theaverage of the hourly sales?

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960+830+945+800+847+970÷6

average = total sales / total no. =960+830+945+800+847+970/6=5352/6=892 rs.

average of the hourly sales=total sales income /total hour then5352/6=892ruppes

72537.

The measurements of some rectangles are given in the table below. However, they areincomplete. Find the missing information.TenothBreadthAreaPerimeter14 cm12 cm1 O20 cm60 cm150 cm15 cm

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72538.

12. On selling a calculator for1325, a man gains 6%, For how much should he sell it togain 12%?lor losehw much should he sell it to gain

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72539.

. On selling a calculator for * 1325, a man gains 6%. For how much should hegain 12%?

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106%=13251%= 1325/106= 12.5112% = 12.5 × 112= 1400hope it will help you

72540.

12. On sellinggain 12%?a calculator for1325, a man gains 6%. For how much should he sell it toFor how much should he sell it to gain1 400 a doo lor loses40

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72541.

A, onea are in the ratio 2:3 4. Find the anglesIA one acute angle is twice the other, find tdhe measares are of equal measure and the third angle is 20 more

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72542.

A solid is in the shape of a cone standing on a hemisphere with both their radii beingequal to 1 cm and the height of the cone is equal to its radius. Find the volume ofthe solidin terms of

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72543.

ual to the sum of the interior opposite anglesORQ1prove that exterior angle of a triangle is eqProve that the sum of the three interior angles of a triangle is 180

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72544.

A man sold two chairs for 500 each. On one he gains 20% andHis net gain or loss per cent ison the other he loses 12%.

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72545.

Calculate H.C.F. of 513, 1134 and 1215.

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By Prime factorization method

1215= 3×3×3×3×3×5= 3^5 ×5¹

1134= 3×3×3×3×2×7= 3⁴×2¹×7¹

513= 3×3×3×19= 3³× 19¹

H.C.F= 3³= 3×3×3= 27

Hence, the HCF of 513,1134 and 1215 is 27.

72546.

(2) Two poles of height a metres and b metres areP metres apart. Prove that the height h of thepoint of intersection N of the lines joining thetop of each pole to the foot of the opposite poleA.ab+ bisa t metres.

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72547.

SOLUCIUC1SIL.nd the height of a triangle whose area is 224 mº and base is 28 m

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72548.

arascending 1 kmoscending nd to be 60°. Find the height of the mountain.At the foot of a mountain, the elevation of the summit is 45°,towards the top of the mountain up a slope of 300 inclination.,kmbeie dlevation is foundMost Important) IHOTS

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72549.

24.Form an equation for the following:If 3 is added to two times a number it gives 15.

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72550.

3. The HCF of two numbers 847 and 1650 is 11. Find their LCM4. With what number should be 1679 divided to obtain 27 as quotient and 32remainder?5. A number when divided by 54 gives 15 as quotient and 17 as remainder find the number.!

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dividend= divisor×quotient + remainder1679=a×27 + 32 =61

so, the number will be 61

Let the divisor be ydividend =divisor×quotient+remainder1679 =y×27+321679-32= 27y1647 = 27yy = 1647/27y = 61