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17. A die is thrown once. Find the probabilitygetting:(i) a prime number(ii) a number greater than 3(ii) a number other than 3 and 5(iv) a number less than 6(v) a number greater than 6.

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1)1/22)1/23)2/34)5/65)0

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(2) The sum of two numbers is 60. The greater number is 8 more than thrice the smallernumber. Find the numbers.

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Let the smaller number be x and greater number is yAccording to questionx + y = 60 .......(1)y = 3x + 8 .....(2)

solving (1) and (2)x + 3x + 8 = 604x = 52x = 13So, y = 39 + 8 = 47So numbers are 13 and 47

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Rashid spent ? 35.75 for Maths book and 32.60 for Science book. Find the totlamount spent by Rashid.

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sin -2sinProve that sec0-2coste- cos 0

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n Fig. 6.15. PORPOS2 PRTig. 6.14PRQ, then prove thtリ

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ushid spent 35.75 for Maths book and R 32.60 for Science book. Find the totalamount spent by Rashid.hT 15.80 find the total

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(3/4)^6*(3/4)^x=(3/4)^16

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Given:(3/4)^x ×(3/4)^6=(3/4)^16since base are equal6x=16x=16/6=8/3

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3434Find the shortest distance between the lines2and3 44

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5. A petrol tank is 10 m long and 4 m wide. Itcan contain 120000 1 of petrol. What is thedepth of the tank?1 -1000/s 6. The length. width and height of a cake is15 cm, 10 cm and 6 cm respectively. Aftercutting it into pieces, it is distributed amongchildren equally. If ench child got 100 cmof the cake, calculate the number of chilwho got the cakeof1 of match boxes contains 12ramatchtor measures 4 cm by

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3Timehou

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ere are two poles, one each on either bank of a river, just opposite to each other. One po60 m high. From the top of this pole, the angles of depression of the top and the foot of thepole are 30° and 60 respectively. Find the width of the river and the height of the other poleisher

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14Find the value of a and b ,when a + b v15-V3V5+13

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maine bhi pucha koi nhi bata raha

😁

1

2

3

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a) An object moves 18 m in the first3 s, 22 m in the next 3 s and 14 m inthe last 3 s. What is its averagespeed?(Ans: 6 m/s)

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6m/s it is the correct answer

6m/s is the right answer

Hiaverage speed=total distance /total time.=18+22+14/3+3+3=54/9=6 m/s is the average speed.

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(ii) The sum of two numbers is 97. If the greaternumber is divided by the smaller, thequotient is 4 and the remainder is 12. Findthe numbers.Solution :

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let the greater number is equal to x and the smaller number the be ythen x + y is equal to 97it is given that when we divide the greater number by the smaller number the reminder is 12 so 12 should be subtracted from the greater number so that the smaller number completely divides itso x-12=4yx=12+4ybut x + y is equal to 9712+5y=975y=85y=17 and x=80

x+y=97;; x-12=4y; 12+5y=97; 5y=97-12=85; y=85/5=17, x+17=97; x=97-18=80

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Prove that \frac{\sin 5 x-2 \sin 3 x+\sin x}{\cos 5 x-\cos x}=\tan x

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part 1

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0 cm and its heigllis cll.. Length of the fence of a trapezium shaped field ABCD is 120 mBC-48 m, CD 17 m and AD 40 m, find the area of this field. SAB is perpendicular to the parallel sides AD and BC.

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10 280.0wid spent 35.75 for Mallar2. Rashid spent 35amount spent by Rashid.3. Radhika's mother gave hermount given to Radhika by the parents.er gave her 10.50 and her father gave her 15 80, find themm 20 cm cloth for her shirt and 2 m Sem cloth for her trouseehought by herpins How much

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Here Answer

Radhika mother gave her money =10.50

her father gave her money =15.80

total amount given to Radhika by the parents = 10.50+15.80=26.3 money

hope this will help you like my answer and MARK IT AS BEST ANSWER.

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(v) Through (3, 15) and (16,5)% througlJ,li (U, ).4 Find the slope of a line (i) which bisects the first quadrant angle (i) which makesan angle of 30° with the positive direction of y-axis measured anticlockwise(3, 15) and (16, b)/ hrough(

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A box of chocolates was distributed among 8 children and each child got 5 chocolates. If this box ofchocolates is distributed among 10 children, how many chocolates wll each child get?

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If each gets 5 chocolates, then 8 children gets 8×5=40 chocolatesIf the box is distributed among 10 children, each will get 40/10=4 chocolates

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length of cloth is required for each SH !18. A rope of length 15 m is divided into 12 pieces of equal lengths. Find the length of eachpiece.oli flood Hou

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15÷12=1.25 m Thetefore, the length of each piece of the rope is 1•25m.Verify.1.25×12=15m

To find this divide 15 by 12hence15/12=1.25m

That is the answer. Got it dear...

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16.The line L given bypasses throughthe point (13,32). The line K is parallel to Land has the equation-+-=1. Then thedistance between L and K is IAlEEE-2010]23LI15V15

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(ii) the coefficient of x in 3-212x + 6x2.(iii) the coefficient of x’ in 2x - 3+x?(iv) the coefficient+(v) the constant term in 5x² +7x-r.4. Determine the degree of each of the following polynomials.6) 4x – 5x + 6x (ii) y?(y-y) (iii) (3x - 2)(2x° +3x2x

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For1) it is not at all a polynomial2)degree=5

4 ques 1 part

pls ans 4 ques 1 part

2)The coefficient of x is -2 root 2 in (ii)

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- R S e -1. HCF (306, 657) = 9 दिया है तो LCM (306, 657) 74 करें ।अं B A g

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LCM*HCM = Product of numbers

Given HCF = 9

9*LCM = 306*657LCM = 306*657/9LCM = 306*73 = 22338

thqq

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4. Which of the following can be the sides of a righttriangle?2.5 cm,6.5cm, 6cm.(ii) 2 cm, 2em, 5 cm.(1.5 cm, 2cm, 2.5 cmIn the case of right-angled triangles, identify theright anglesere

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Karan has n€ chocolates. He gave his younger brother 5 chocolates and distributed the remaningequally between his friend and himself. How many chocolate did his friend get in terms of n?

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Karan has n chocolatesyounger brother got 5so he got n-5and the rest equallyhence n-5/2

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numbers is 64699, HCF is 97e numbers is 2231. Find thetwoand one of theother number.is

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We knowLCM*HCF = Product of numbers

Given LCM = 64699, HCF = 97,One number = 2231

Let other number be nThen,64699*97 = 2231*nn = 64699*97/2231n = 29*97n = 2813

Other number is 2813

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LLUCLL LLLILLIU.5. If sin x =and x lies in Quadrant III, find the values of cos x and cotx.

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EXERCISE 3.21e of other five trigonometric functions in Exercises 1 to 5Find the values of other five1. cos x=-5, x lies in third quadrant.

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anjan has 60 chocolates. He gave 2- of them to Rashi. How many does Rashiget? How many are left with Ranjan?512

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Total chocolates Ranjan has = 60Chocolates given to Rashi = (5/12)x60= 25Chocolates left with Ranjan= 60-25= 35

thanks

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Question 8). X had 20 chocolates, Y had 50 chocolates and Z had 80 chocolates After 15 days10 chocolates. Y eaten up 25 chocolates and Z used up 40 chocolates. What fraction did each eif each has eaten up an equal fraction of her/his chocolates?

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Fraction of chocolate eaten by X =10/20=1/2Fraction of chocolate eaten by Y =25/50=1/2Fraction of chocolate eaten by Z =40/80=1/2

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(ix) Rank correlation coefficient was given by :(a) Karl Pearson(b) Spearman(c) Marshall(d) Fisherकोटि सह-सम्बन्ध गुणांक किसने दिया ?(अ) कार्ल पियर्सन(ब) स्पियरमैन(स) मार्शल(द) फिशर ।(x) Circular test is satisfied by :(a). Fisher(b) Marshall-Edgeworth(b) Paasche(d) of theseवृत्तीय परीक्षण दिया गया है :(अ) फिशर द्वारा(ब) मार्शल-एजवर्थ(स) पाश्चे।1x10=10(द) इनमें से कोई नहीं ।c-374( 6 )

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karl pearson rank correlation coefficient was given

1)karl pearson2)fisher3)Marshall edgeworth4)passche

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LI SUILLUSUL SULLUL15. A man had 10672540 with him. He gave 4836980 to his wife, 3964790 to his sothe rest to his daughter. How much money was received by the daughter?

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the society still short of15. A man had 10672540 with him. He gave 4836980 to his wife, 3964790 to his son andthe rest to his daughter. How much money was received by the daughter?111 Gogul lui

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1. (81) + (81) का सरलीकृत मान क्या है।

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(3^4)^-1/4+(3^4)^1/41/3+3= 10/3thanks

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what is the range of correlation coefficient

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[-1,1] is the range of correlation coefficient

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ORFind HCF of 81 and 237 and express it as a linear combination of 81 and 237 i.e., HCF (81, 237) 81x +237y for some x and y.

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Cos x=-1/2,x lies in third quadrant

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cos x =--1/2 lies in third quadrant.

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cosx = -1/2

x = cos^-1(-1/2)so, x = 240°

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************НАProve that.M11Ert1и(а(і)

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, x lies in third quadrant2cos x

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cosx = -1/2 x is in third quadrant so x = 180+60 = 240

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ert each part of the ratio to percentage(a

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(a) 3:13+1=4so each parts 3/4*100,1/4*10075%,25%

(b) 2:3:52+3+5=10so each parts 2/10*100,3/10*100,5/10*10020%,30%,50%

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Which is the largest and the2.UUL3.Pawan had 60 chocolates. He gave away 10 chocolates to Rahul. Rahul already had 55chocolates. So who had more chocolates finally and by how much?

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So ,Chocolates left with Pawan = 60-10=60But , Now , Rahul has = 55+10=65 chocolates .So , Rahul has more chocolates than Pawan .

rahul had more chocolate finally.by 15 chocolates

Rahul has more chocolates 65chocolates

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a. Look at the bar graph given belowMathematics for Class 620000TStudy the bar graph carefully and answer the questions gven below(t) In which week was the production maximum?(u) In which week was the production mintmum?Citl) What is the average production during these five weeks?(iv)How many cycles were produced in the first 3 weeks?dfrrnt mndes of transport to school, as show

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I) 2nd week II) 4rth weekIII) 720 is average production during these 5 weeks. IV) 2400 cycles

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sl L ey W -, \‘Q"‘ “n {(1) 6 x6x6x688 B v b w A w b

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The correct answer is 6⁴=1296

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A mantlis wife gave away one-tenths of her share to charity. If she donated * 1000 toman left one-fourth of his property each to his son and daughter and therest to his wife.His wife gnind how much property did the man leavef she donated 10000 to charity

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If 5^6 x 5^2x = 5^10 then find x

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if (X/5 +3, Y-4/5) = (7/5, 3/5), find X and Y.

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Given:(x/5 + 3, y - 4/5) = (7/5, 3/5)

Then,x/5 + 3 = 7/5x/5 = (7-15)/5x/5 = - 8/5x = - 8

y - 4/5 = 3/5y = 3/5 + 4/5y = 7/5

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5 ^ { 6 } \times 5 ^ { 2 x } = 5 ^ { 10 } , \text { then find } x

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\{ 81 ^ { - \frac { 3 } { 4 } } \times \frac { 16 ^ { \frac { 1 } { 4 } } } { 6 ^ { - 2 } } \times ( \frac { 1 } { 27 } ) ^ { - \frac { 4 } { 3 } } \} ^ { \frac { 1 } { 3 } }

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[81¾ ×16¼/(6-²) × (1/27)^-4/3 ]⅓= [(3)³ ×2*6² ×27^(4/3)]⅓= [27×72×81]^(1/3)= 54

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\frac 3 x - 3 4 < \frac 3 4

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By canceling 4now we have 3x-3<33x<6x<6/3x<2