Explore topic-wise InterviewSolutions in .

Could u post a clear picture please?

AP is the tangent to the circleOA _|_ AP (Radius is perpendicular to the tangent at the point of contact)∠OAP = 90 degreesIn angle OAP,Sin∠OPA= OA/OP = R/2R = 1/2∠OPA = 30In Angle ABP,AP = BP∠PAB =∠PBAso 60+∠PAB +∠PBA = 18060+2∠PAB = 180∠PAB = 180 - 60/2∠PAB = 60Butas∠OAP = OBP = 90OAP = OBPso,60 + x = 90x = 30therefore,∠OTS = OST= 30

10/3=3.333... And 7/8=0.875 and 1/7=0.1428571425

Answer:

We know that:-

Tangent from an external point to a circle are equal,

∴ PA=PB -----eq (1)

∴ CA = CQ----eq(2)

∴DB=DQ--------eq(3)

Step-by-step explanation:

From the figure we know that

PA=PC+AC

PA=PC+QC [∵ from eq(2) we know that QC=AC]

Substituting the given values, we get

12=PC+3

PC= 9cm

Similarly we can find PB

PB=PD+DB

PB=PD+QD

12=PD+3

PD=9cm

So PC+PD= 9+9=18cm

So 18 cm is the our answer.

Enjoy Maths!

Amout of lemon juice = 39.6l=39600ml1ml=1 cubic centimetre.∴39600ml=39600cm³

height of juice in glass=14cmdiameter of glass = 6 cmvolume of cylinder =πxr²xhvolume of juice in glass= (22/7)×6²×14cm.=(22/7)×36×14=22×36×2=1584∴number of glasses filled = 39600/1584=25

∴number of glasses filled = 25.

but in our answer of book no. of glass is 100 but many2 thnk u 4 answering the question

3=1+5/89×4=098+3×187643575456446

3 yers of 5112 of intrest pc.offered. by.sime

Let principal amount = P,Rate of Interest = R

For compound interestA = P(1 + R/100)^n

When,n = 2, A = 1368013680 = P(1 + R/100)^2.....(1)

n = 3, A = 1641616416 = P(1 + R/100)^3..... (2)

Divide eq(1) and eq(2)

16416/13680 = (1 + R/100)(16416 - 13680)/13680 = R/1002736/1368 = R/10R = 27360/1368R = 20

Therefore, Rate of Interest is 20 % per annum

Given: In an examination a candidate has to secure 40% marks to pass . The candidate gets 212 marks and fails by 28 marks.

let the maximum marks of the examination = x

therefore, acc. to the question,

40% of x = 212+28

40% of x = 240

x = 240*100/40

x = 600

Like my answer if you find it useful!

let total no of vote=xaccording to the question candidate who got 40% vote,defeated by 15000 votesthat means(no of votes of winner-no of votes for losser=15000)((60*x)/100)-(40*x)/100)=15000after solving we got x=75000no of vote polled by winning candidate=((3*75000)/5)=45000

4u^2 + 8u = 04u(u + 2)=0Zeros of polynomial are4u =0u = 0(u+2) = 0u = - 2

In ∆AOB, draw a perpendicular line from O which intersect AB at M.

In ∆AOM, angle AMO = 90angle OAM = 30cos 30 = AM/AO√3/2 = AM/21AM = 21×√3/2AB = 2(AM)=2(21×√3/2)=21√3

OM^2 = AO^2-AM^2=21^2-(21√3/2)^2=441-330.51=110.48OM =√110.48OM =10.51

OM = 10.51cm

Area of ∆AOM = 1/2 AB × OM=1/2 ×21√3 ×10.51=191.14cm^2

Area of sector AOBY = 120πr^2/360=120×21×21×22/2520=462cm^2

Area of segment AYB = Area of sector OAYB -Area of∆OAB=462-191.14=270.86

Area of segment AYB is 270.86cm^2._______________

part 1

part 2

glass 1 has 2/3 of a glass alcohol and 1/3 of a glass water

glass 2 has 1/2 of a glass of alcohol and 1/2 of a glass water.

So the mixture in glass 3 (assuming it lage enough to contain the contents of both glass 1 and glass 2 and that glasses 1 and 2 are of equal volumes) has (2/3)+(1/2) of a glass of alcohol and (1/3)+(1/2) of a glass of water.

So the ratio of alcohol to water in the mixture = ((2/3)+(1/2)) : ((1/3)+(1/2)) = 7/6 : 5/6= 7: 5

(b) is correct option

bhoian karne se kya hota hai

Weight of zinc=22.5g

it's right but not clear

In set builder form we can write set A as

A = {x:x = n^2 , n belongs to N }N is natural number

or

A ={ x:x is the square of natural number}

Accounts ke yeh question bhi pchega.. coaching laga le

M =sum of total marks/No of subso here total Marks= 72x5=360according to the question previous total marks 360-10=350New Mean = 350/5 =70

Total persons = 100 +1000 = 1100

Total outcome = 1100

Colour blind man = 5

Probability of getting a blind man = 5/1100 = 0.0045

where is the answer

l

Thank you my solver

your answer is wrong. the answer is 1440

It moves 1min extra in 1 hourso total hour from 7:00am to 10:00pm = 15 hourso time will be10:00 hour+ 15 minutes10:15 PM

this is smallest number 133

The set of subsets of a set A is called the power set of A, sometimes written P(A). Obviously, from the result above, if A has n elements, P(A) has2^nelements.

The set of all natural numbers

Every 10 min, it moves 10 seconds aheadIt means in every 60min, clock will move 60sec ahead. i.e every hour, 1min be aheadSo, from 7:00am to 10:00pm there are 13 hours, so clock will be 13 minutes ahead at 10:00pmTherefore at 10:00pm, clock will show 10:13pm

i) { M,A,R,I,G,E}

ii) 1/2 = 0.5 and 9/2 = 4.5 { 1, 2, 3, 4}

iii)

{ 2, 4, 6, 8, ......} = { set of even numbers}

55)LHS: cotA + tanB / cotB + tanA

= (cotA + 1/cotB) / (cotB + 1/cotA)

= (cotAcotB + 1) / cotB / (cotAcotB + 1) / cotA

= cotA / cotB

= cotAtanB

thanks 😘😘😘😘

what is your question

total 190 marks and fails by 50 marks so passing mark = 190+50 = 240 which is 40% so maximum marks = 100×240/40 = 600

Solution :-Given - 50 % students passed in Mathematics.70 % students passed in Science10 % students failed in both subjects and 300 students passed in at least one subjects.Let x be the total number of students.Total students = 100 %Passed students = 100 - 10(failed in both subjects)= 90Total passed students in at least one subject= (50 + 70) - (90)= 120 - 90= 30 %So, 30 % students passed in at least one subjects.⇒ 30 % of the total students = 300⇒ 30 X of ------ = 300 100⇒ 30x/100 = 300⇒ 30x = 300*100⇒ 30x = 30000⇒ x = 30000/30⇒ x = 1000So, total 1000 students appeared in the examination.

1000 students appeared in the exam.

Let the initial strength be 100After 20% increase it is 120.After 20% decrease it becomes 96.It is less than initial by 4%

Let amount Prema invests = P1 and P2

We know, SI = P*R*T/100

For R=10%, T = 1, P = P1SI1 = P1*10*1/100 = P1/10

For R=8%, T = 1, P = P2SI2= P2*8*1/100 = 2P2/25

SI1 + SI2 = 1640P1/10 + 2P2/25 = 16405P1 + 4P2 = 1640*50....(1)

Next year

For R=8%, T = 1, P = P1SI1 = P1*8*1/100 = 2P1/25

For R=10%, T = 1, P = P2SI2= P2*10*1/100 = P2/10

SI1 + SI2 = 16402P1/25 + P2/10 = 16004P1 + 5P2 = 1600*50......(2)

Multiply eq(1) by 4 and eq(2) by 5. Subtract eq(2) from eq(1)

20P1 + 16P2 = 1640*20020P1 + 25P2 = 1600*250

-9P2 = 328000 - 4000009P2 = 72000P2 = 72000/9 = 8000

Put value of P2 = 8000 in eq(1)

5*P1 + 4*8000 = 820005P1 = 82000 - 32000P1 = 50000/5 = 10000

Amounts Prema deposited are Rs 10000 and Rs 8000