InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 73901. |
175ab=1050 and HCFfind the LCM of aof aand b.and 6. |
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Answer» 1050/HCf=Lcm=1050/15=70=,Lcm the lcm of a and b is 70 |
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| 73902. |
(x) -3012 from 62502. Subtract the sum of -1050 and 813 from -23.0979 |
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| 73903. |
g ven equations be α, p; p,y, α.9. Find the values of p if the roots of the equation (p -3)x2-2px +5p 0 are positive. |
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| 73904. |
Rs 3,500 is given at 7% p.a rate of interest .Find the interest which will be received at the end of two years |
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Answer» PRINCIPAL= RS.3500TIME= 2yearsRATE=7%INTREST= PRT= 3500*7*2 / 100= 49000 / 100= 490 👩❤📝😻thankyou |
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| 73905. |
dohsin lent a sum of money at 10% per annum simple interest and received an interest of 2160 in-years. Find the sum. |
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Answer» Imagine the sum is P rupees.so at 10%annum simple interest and the interest is 2160 rupees so , According to the question., (P × 10 × 6) / 100 = 2160or, P × 10 × 6 = 216000or, P = 216000/60or, P = 3600so the sum will be 3600 rs.(Answer) |
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| 73906. |
12. The positive value of k for which the equality x2 +kx+64=0 and x2-8x + k = 0 which have realroots is |
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| 73907. |
12. The positive value of k for which the equality x3 + kx +64-0 and x2-8x +k0 which have real=0 and x2-8x + k = 0 which have realroots is |
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Answer» Solution:- Let D₁ and D₂ be the discriminant of the given equations and these will have equal roots only if D₁, D₂≥ 0 Or, if D₁ = (k² -4 × 64) ≥ 0 and D₂ = (64 - 4k) ≥ 0 Or, if k²≥ 256 and 4k ≤ 64Or, if k≥ 16 and k≤ 16Or, k = 16 Hence the positive value of k is 16 |
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| 73908. |
PizzaMoos. IIIThe adjoining figure shows the food liking of 1080 students ofa school. Read this graph and answer the following questions.How many students like to eat chapatis?(m) How many students like to eat rice?(m) How many students like to eat pizza more than dosa?(i) What percentage of students eat pasta?ECTION B. HOTS QUESTIONfor to the expenditure of the families A and B per month. |
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| 73909. |
8. In an army camp, there wthe camp. How long did the provisions last?ere provisions for 550 men for 28 days. But, 700 men attendednt davs would the rice |
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| 73910. |
13,) At a party, 8 bottles of soft drink are served for every batch of 5 children. How maserved if 40 children were present at the party ? |
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Answer» 8 bottles for 5 children. So, for 40 children = 8×40/5 bottles =64 bottles |
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| 73911. |
The cost of 12 bottles of honey isRs1050. What is the cost of 23 such honey bottles? |
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| 73912. |
\frac { 4 x - 7 } { 3 } - \frac { 2 x - 7 } { 7 } = \frac { 3 x - 7 } { 14 } - \frac { 5 x + 1 } { 9 } |
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| 73913. |
9. A sum of? 1550 was lent partly at5% and partly at 8% simpleinterest. The total interest receivedafter 3 years is t 300. The ratio ofmoney lent at 5% to that at 8% is(a) 5:8(c) 31:6(b) 8:5(d) 16:15 |
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Answer» TRIACKI=R×T5×3 : 8×315:245:8 |
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| 73914. |
29(a) 5:8(C) 31: 6(b) 8:5(d) 16 15 |
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Answer» Sorry we are currently answering the question posted in English. |
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| 73915. |
d)noneof45. Thethe(b) 18 cm(c) cmthese26. If the ratio of the areas of two squares is 16:25, then the ratios of their sides is(a) 5:6(b) 4:5(c) 8:5(d) none of these |
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Answer» We know that area of square = side x sideside^2= 16side= √16=4likewisefor other square it will be √25= 5ratio will be4:5 |
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| 73916. |
EXERCISE 481. Represent each of the following rational numbers on the numbe(111)(vi)?(vii)(vin) -12 |
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| 73917. |
\sqrt{7+\sqrt{7}+\sqrt{7}}tends to a positive rootsx^{2}-x-7=0 as limit. |
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| 73918. |
The cost of 12 bottles of milk is 126. Tabulate the cost of 2, 4,10 and 18 bottles of the milk? |
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Answer» thanks for answer |
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| 73919. |
1.Students of a school collected provisions like rice, pulses, etc., for the floodaffected people of Madhya Pradesh. These provisions were packed in six cubicalcartons each of side measuring 65 cm.(a) Find the volume of cartons packed. |
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Answer» Vol of 1 packet=65*65*65=274625cm^3Vol of 6 packet=6*274626=1647750cm^3 volume of one packet is equal to 27 46 25 centimetre cube. volume of six packet is equal to 16 47750 centimetre cube |
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| 73920. |
16. सिद्ध करें x =-1 निम्न समीकरण का मूल है2-x334-x5%3D0354-x |
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Answer» After putting x= -1determinent of this will be eaual to 0that means its the solution For determinant to be zero one of the condition is that , all of the elements of one raw or coulmn should be same and if x = -1all the elements of first raw will be same hence x= - 1 is the answer |
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| 73921. |
The A.M. of two numbers is 34 and theirG.M. is 16. The numbers are:(a) 60, 8(c) 56, 12(b) 64,4(d) 52, 16 |
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Answer» therefore option b is correct Thank you |
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| 73922. |
S6+ 345+65B168 5s 34 |
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Answer» 1. 12212.12253.2514.451 |
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| 73923. |
13. 14 + 3 {34 - 18 - 14} = 3 16 x 2 + 17 - (2 x 7)] |
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Answer» 3/9 is the correct answer. 3/9 is the correct answer of the given question 1/3 is the answer of the following 1/3 is the right answer plz like my answer Correct Ans of this question is= 102/9 |
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| 73924. |
8.If 7 mango drink bottles cost *196, how much does one bottlecost? |
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Answer» Given:7 mango drink bottles cost Rs 196 Cost of one bottle=196/7=Rs 28 28 is the right answer. 28 is the correct answer of the given question 28 is the correct answer of the following question 28 is the correct answer Cost of 7bottle mango= Rs 196" " 1 " " =196/7=28 cast of one mango =196÷7 =28 28 is the right answer 7 mango drink bottle = ₹ 196therefore one bottle cost = 196/7= ₹ 28. one bottle cost =28right answer 28 rupees is the correct answer |
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| 73925. |
rh12REAL NUMBERSEXERCISE 1.12se Euclid's division algorithm to the HF of(i) 135 and 225196 and 38220 |
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Answer» Since 225 > 135, we apply the division lemma to 225 and 135 to obtain225 = 135 × 1 + 90Since remainder 90 ≠ 0, we apply the division lemma to 135 and 90 to obtain135 = 90 × 1 + 45We consider the new divisor 90 and new remainder 45, and apply the division lemma to obtain90 = 2 × 45 + 0Since the remainder is zero, the process stops.Since the divisor at this stage is 45,Therefore, the HCF of 135 and 225 is 45. |
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| 73926. |
निम्नलिखित बंटन का माध्य-ज्ञात करें -| वर्ग अंतराल | 0-8 | 8-16 | 16-24 | 24-32 | 3240 | 40-48कहL।. बारंबारता 10 20 14 16| |
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| 73927. |
FInd A^{2}-5 A+61, if A=\left[ \begin{array}{ccc}{2} & {0} & {1} \\ {2} & {1} & {3} \\ {1} & {-1} & {0}\end{array}\right] |
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| 73928. |
3416(D) 24(B) 32(C) 16(A) 8 |
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Answer» AD/DB = AE/ECx/16=34/17x=32 hit like if you find it useful |
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| 73929. |
6. Simplify:a. 10 x [50 [-8) x (32 16 4)) |
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| 73930. |
112 '1576 1256196 12 8(a) 8(c) 12(b) 32(d) 16 |
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Answer» 112/14*(24/12)*(16/8)8*2*2= 32 |
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| 73931. |
1824 2(A) 16(C) 32(B) 8(D) 20 |
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Answer» 2×4=8 12345567&^^%% 32 |
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| 73932. |
4.The table below shows the estimated number of tigers in tiger reserves' of India. Draw a bar graph for thesame and answer the questions that follow.StateTiger reserveEstimated number of tigersKarnatakaBandipur89Madhya PradeshBandhavgarh79AssamKaziranga42KeralaPeriyar |
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| 73933. |
168Estimate by rounding. Show how you estimated.4.Hello thank you for helping me theproblem that I circled with the light blue isthe problem I'm stuck with and make youEstimate and round & show how youestimated |
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Answer» 68 ~ 7068 × 7 ~ 70 × 7 ~ 490 Thank you😁 |
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| 73934. |
5. A wire is in the shape of a square of side 10 cm. If the wire is rebent into a rectangle d12 cm, find its breadth. Which figure encloses more area and by how much? |
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| 73935. |
sin3x+sin2x-sinx=4sinx×cosx÷2×cos 3x÷2 |
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| 73936. |
15.A wire is in the shape of a square of side 10 cm. If the wire is rebent into a rectangle of length12 cm, find its breadth. Which figure encloses more area and by how much? |
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| 73937. |
e jâ (sinx+cosx+2) dx |
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Answer» ∫ ( sinx + cosx + 2) dx ∫sinx dx + ∫cosx dx + ∫2 dx - cosx + sinx + 2x + x thank u |
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| 73938. |
n/201+ Sinx |
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| 73939. |
6 2x = 2 sinx cos x = рди |
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Answer» We know, one important identity , sin( A + B) =sinA.cosB + cosA. sinB let A = x, B = x then, sin( x + x ) = sinx.cosx + cosx .sinx sin2x = 2sinx.cosx RHS=2tan x/1+tan^2 x = 2tan x/sec^2 x= 2tan x/1÷cos^2 x = 2 × sin x/cos x ×cos^2 x= 2sin x ×cos x= sin2x Hence proved |
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| 73940. |
(दि The oo of | wle‘ : and bpeocttin Mo] wectnn कट free Piece 75 S Y ¢ 125९०789 Bnd ond [M(]M ) o & |
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Answer» Let X be the common multiplehence6x and 4xas breadth =4x=28x=7cmhence length that is 6x=6*7=42cm |
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| 73941. |
नाटस प्रश्नम.हम अपारामत रूपस अनक अपारमय सख्याए लिख5. निम्न संख्याओं को 2 रूप में व्यक्त कीजिए जहाँ q#0(00.4710ely d.s,T |
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Answer» 1) 4/92) 8/9 is the answerlet 0.4(recarin)=x0.44(recarin)xmultiple with 10 both sides4.44(recarin)= 10x4+.44=10x4+x= 10x4= 10x-x=9xx= 4/9 4/98/9 is the correct answer of the given question |
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| 73942. |
ASSIGNMENT 7.2MCQ) Chood1. Multiple Choice Questions CMo In the following figure, the valuesof x and y are respectively(a) 120°, 80 (b) 40, 100°(c) 100, 40 (d) 80, 12080120C xthe measures of some |
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Answer» In the given triangleAngle x + 80 = 180 Linear pairAngle x = 180 - 80 = 100 Angle c + 120 = 180 Linear pairAngle c = 180-120 = 60 By angle sum property of triangle Angle c + Angle x + Angle y = 18060 + 100 + Angle y = 180Angle y = 180-160 = 20 Thus x = 100, y = 20 |
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| 73943. |
ely.32168 |
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| 73944. |
8-12.ELY )22 |
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Answer» put the value of function in the below equation {COS(X/2)}² - {SIN(X/2)}². = 1-2SIN²(X/2) . we can use the standard formula for this as cos²(x) - sin²(x) = cos2x so here just replace x with x/2 so cos²(x/2) - sin²(x/2) = cos(x). |
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| 73945. |
SECTION AAnswer the following Q.1 to Q.8 with calculation in brief. [2 marks each].Dhavalbhai, his wife Reenaben and their son Rahul start morning walk. The length of their feet are 90 cm, 80 cmand 60 cm respectively. How much distance should be covered to meet each other if each of them take definitewhole number of steps?121121 |
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| 73946. |
Example 1 : Mary wants to decorate her Christmastree. She wants to place the tree on a wooden boxcovered with coloured paper with picture of SantaClaus on it (see Fig. 13.4). She must know the exactquantity of paper to buy for this purpose. If the boxhas length, breadth and height as 80 cm, 40 cm and20 cm respectively how many square sheets of paperof side 40 cm would she require? |
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| 73947. |
A Mary wants to decorbte her Christmas tree. She wants to place the tree on a wooden bowcovered with coloured papers with pictures of Santa Claus. She must know the exartguantity of paper to buy for this purpose. If the box has length 80 cm, breadth 40 cm andheight 20 cm respectively, then how many square sheets of paper of side 40 cm wouldshe require? |
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| 73948. |
The area of a square plot is 800 m2. Find the estimated length of the side of theplot. |
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| 73949. |
Pnd the probability that it will be: (i) black (i) red (ii) not green (iv) whiteThe coordinates of centroid of a triangle is (1, 3) and its two vertices are (-7,6) and (8, 5). Finvertex of the triangle.Section-D |
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Answer» Let vertices of triangle are A (-7, 6), B (8, 5) and C (x3, y3) Given, centroid of triangle (1, 3) Then,1 = (- 7+8+x3)/33 = 1 + x3x3 = 3 - 1 = 2 3 = (6+5+y3)/39 = 11 + y3y3 = 9-11y3 = - 2 Therefore, coordinates of third vertex are (2, - 2) |
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| 73950. |
Area of a field is 6724 m2. How much wire is required to fencethe field?9.(c) 328 m(d) 382 m |
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Answer» Area = 6724assuming it to be square side= √6724= 82mnow perimeter= 4x side= 4*82= 328mplease like the solution 👍 ✔️ |
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