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baki 2 sum ka solutions

Radius of the tent = 12m

Height = 5m

Slant height = √(r²+h²)

= √(5²+12²)

= √(25+144)

=√(169)

=13m

Curved surface area of the tent = πrl

=22/7 × 12 × 13

=490.28

=490.3m²

Cost of 1m² canvas = ₹7

Cost of 490.3m² canvas = 490.3 ×7= ₹3432.1

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Let Original Price was Rs. 100. Then,

With 38% profit the selling price would be

= 100 + 38% of 100 = Rs. 138.

First dealer makes profit of 20%, then he must have sold it at,

= 100 + 20% of 100 = Rs. 120.

Now, Profit for second dealer = 138 - 120 = Rs. 18.Therefore,

% Profit = (18 *100)/120 = 15%.

tqsm sir...😁

iska answer 15 lemon /rupiya diya hai

ColonialAssam(1826–1947) refers to the period ofHistoryofAssambetween the signing of the Treaty of Yandabo and Independence of India whenAssamwas under the British colonial rule. ... The legislature and political alignments that evolved by the end of the British rule continued in the post Independence periodThe legislature and political alignments that evolved by the end of the British rule continued in the post Independence period. The immigration of farmers from East Bengal and tea plantation workers from Central India continue to affect contemporary politics, most notably that which led to theAssam Movementand its aftermath.

Height= 82cminner diametre=12cm r=6cminner TSA=2*22/7*6(82+6)= 3318.8

outter diametre= 16cm r=8cmoutter TSA= 2*22/7*8(82+8)= 4525.7

outter base area= 22/7*8^2= 201.1inner base area= 22/7*6^2= 113.1

area of the thickness= 201.1-113.1=88total thickness of area= 88*2=176

total TSA=3318.8+4525.7+176=8020.5

total surface area =4525.7

thanks bhayya good evening

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the answer of the question is 890

As there were 8 candlesand 4 in eachmeans he bought 2 bags

The probability that the 2 students have the same birthday=1-0.992=0.008

Question you have submitted is incomplete. Please post a complete question.

Let Rehana's present age be x.Then Mother's age = (7/2)x = 3.5xAfter 2 years, (x+2) / (3.5x+2) = 1/3=> 3x + 6 = 3.5x + 2=> 4 = 0.5x=> x = 8 years old.

REHANA IS 8 YEARS OLD PRESENTLY.

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16x³ = 2⁴ x³

- 4x² = - 2² × x²

32x = 2^5 x

Common factor is 1, 2, 2², x, 2x, 2²x

3a²-9ab

= 3a(a-3b)

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Find the prime factorization of 16281628 = 2 × 2 × 11 × 37

Find the prime factorization of 2424 = 2 × 2 × 2 × 3

To find the gcf, multiply all the prime factors common to both numbers:

Therefore, GCF = 2 × 2

GCF =4

total cost =areaxratehence area=5000/9=555.55m^2now area excluding doors and windows as it won't be painted is 555.55-50=505.55m^2hence nowl=46m and b=3m h=?area=2(lb+bh+hl)505.55=2(46*3+3*h+h*46)252.77=138+3h+46h114.77=49hh=2.34m

your answer is 60 km distance

After covering 3/4 of the journey1/4 is leftLet distance=xTherefore distance left=15km=1/4xTherefor x=15*4=60km

let total distance x. so distance left = 15 km =1/4 xso x = 15*4 =60 km

after covering 3/4 of the journey 1/4 is left let distance =x there fore distance left =15km=1/4x therefore x= 15*4=60km

Length of the fence (in metres) = Total cost / Rate = 5280/24 = 220 So, circumference of the field = 220 m Therefore, if r metres is the radius of the field, then 2πr = 220

or, 2 × 22/7× r = 220 or, r = (220 × 7)/(2 × 22) = 35

i.e., radius of the field is 35 m.

Therefore, area of the field = πr2 = 22/7 × 35 × 35 m2 = 22 × 5 × 35 m2

Now, cost of ploughing 1 m2 of the field = Rs 0.50 So, total cost of ploughing the field = Rs 22 × 5 × 35 × 0.50 = Rs 1925

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Given,( a - b)/(a + b) = 1/11

in LHS divide by b both nominator and dinominator.

=>(a/b - b/b)/(a/b + b/b) = 1/11

=> (a/b -1)/( a/b + 1)=1/11

=> 11(a/b) -11 =a/b + 1

=>10(a/b) =12

a/b =6/5

5a=6b

let a =6k b= 5k

now, => (5a + 4b +15)/(5a -4b +3) =?

=>{ 5(6k) + 4(5k) +15}/{5(6k)-4(5k)+3}

=>(30k +20k +15)/(30k-20k +3)

=>(50k+15)/(10k+3)

=>5(10k+3)/(10k+3)

5 : 1 (answer)

R={-5,-4,-3,-2,-1,0,1,2,34}

THE VALUE OF GAS CONSTANT IN JOULES/K/MOLE IS : (A) 8.314

the value of R is 0.0821