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7 x 7 =4 9 × 3= 3 4 3



1

Secondary SchoolMath13 points

Find the sum of all 3 digit number which are multiple of 7

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dhruvsh

Smallest three digit number divisible by 7 = 105 and the largest = 994An = 994A = 105D = 7n= ?An = A + [ n - 1] Dthus994 = 105 + [ n - 1 ] 7thus by solving furthern = 128

now,Sn = n/2 [ A + An]

Sn = 128/2 [ 105 + 994]thus,Sn = 70336.Thus the sum of all the three di git numbers divisible by 7 is 70336.

70336 is the correct answer of the given question

sum of three digit numbers which are the multiples of 7 is 70336

five three digit numbers that are multiple of 2 are following 128 256 512 714 120

Greatest two digit number = 99. Least three digit number = 100. Difference = 100-99 = 1.

greatest 2 digit no. is 99smallest three digit number is 100then 100-99=1

100 is successor of 99 so 99multiple of 6a=6 d=6 an=9696=6+6n-6so n=16

three digit no. be=100x+10y+zsum of the digits of a 3 digit no.= x+y+zresulting no.= 100x+10y+z-(x+y+z)= 99x+9y

so it is divisible by 9

a, b, c

Let the common difference be d

Let the numbers be: b - d, b, b + d

b - d + b + b + d = 15

= b = 5

Now, 100c + 10b + a + 594 = 100a + 10b + c

100(b+d) + (b - d) + 594 = 100(b - d) + (b + d)

500 + 100d + 5 - d + 594 = 500 - 100d + 5 + d

198d = -594

d = -3

a = 5 - (-3) and c = 5 + (-3)

Hence the original number is: 852

All three digit numbers when divided by 3 leave remainder 2 will form AP series.

The series will be of the form: 101, 104, 107.....995, 998

a = 101, d = 104 - 101 = 3

Total number of terms 998 = 101 + (n-1)3998 = 101 + 3n - 33n = 1001 - 101n = 900/3 = 300

Sum of n terms of an AP isSn = n/2(first term + last term)

Then, sum of given series = 300/2(101 + 998)= 150(1099)= 164850

GG BM HGTV GG fhugoviv a go through with full will DM all will so did d Roswell mark

Let the number be 10x + y.x + y = 10 . . . . . (1)x²/y³ = 10x=> x = 10y³ . . . . . (2)10y³ + y = 10

225 is the answer because in if we divide 100 by 4 it gives 25 and then we multiply it by nine times because we have to find between 100 to 999 so 25×9=225

225 is the correct answer

Thanks yrrrr

Let ones digit = x , tens digit = y , hundreds digit= zSo, number becomes = 100z+10y+xAccording to question-

100z+10y+x = 17(x+y+z) 100z+10y+x = 17x + 17y + 17z 100z-17z +10y-17y + x-17x = 0 83z -7y -16x = 0 -----------------------(1)

Also,100z+10y+x + 198 = 100x + 10y + z100z- z +10y-10y +x - 100x +198 = 099z - 99x +198 = 099x - 99z = 198 x - z = 2x = z + 2 ----------------------------(2)

And, z + x = y-1By putting (2)y = z+z+2+1 y = 2z+3 ----------------------------(3) Putting (3) and (2) in (1) we get83z -7(2z+3) -16(z+2) = 0 83z -14z -21 -16z -32 = 053z = 53z = 1put z = 1 in (3)y = 2(1) +3y = 5

Put z = 1 in (2)x = 1+3= 3So. number = 100(1) + 10(5) + 3 = 153So, number = 153

The list of 3 digit number that leaves a remainder of 3 when divided by 4 is :103 , 107 , 111 , 115 , .... 999The above list is in AP with first term, a = 103 and common difference, d = 4Let n be the number of terms in the AP.Now, an= 999103 + ( n - 1 ) 4 = 999103 + 4n - 4 = 9994n + 99 = 9994n = 900n = 225

Since, the number of terms is odd, so there will be only one middle term.middleterm=(n+12)thterm=113thterm=a+112d=103+112×4=551 Weknowthat,sumoffirstntermsofanAPis,Sn=n2[2a+(n−1)d] Now,Sum=112/2[2×103+111×4]=36400 Sumofalltermsbefore middleterm=36400sum of all numbers= 225/2[2×103+224×4]=123975

Now,sumoftermsafter middleterm=S225−(S112+551)=123975−(36400+551)=87024

HCF ( 306, 657) = 9

HCF × LCM = Product of numbers

9 × LCM = 306 × 657

LCM = (306×657)/9

LCM = 22,338

It will be above the x axis will not cut x axis

option d IS RIGHT AS AFTER REPLACING WE CAN GET OUR REQUIRED RESULT

6x*x+5x-6 =6x*x+9x-4x-6 =3x(2x+3)-2(2x+3) =(3x-2)(2x+3)

Let the digits be a, a+d and a+2d. Their sum i.e. 3a + 3d = 15 => a + d = 5 => second digit must be 5.

You an easily guess the answer: the number has to be of descending order as difference between this and reversed one is positive. So your choices are 654, 753, 852 and 951. Clearly, 852 is the one you're looking for. Let's formally solve it anyway.

100a + 10x5 + (a+2d) = given no.

a + 10x5 + 100(a+2d) = reversed no>

Subtracting,

99a - 99(a+2d) = 594 (gn.)

a - (a+2d) = 6

-2d = 6

d = -3

a + d = 5, so a = 5 + 3 = 8

Now substitute for a, a+d, and a+2d and you'll get the digits and hence the number required

Let the number be (a-d), a, (a+d)

(a+d)×100+a×10+(a−d)=111a+99d

on reversing

(a−d)×100+a×10+(a+d)⟹=111a−99da+d+a+a-d=15a=5 and d =3

wrong

Let a, b, c = the three digitsthen100a+10b+c = "the number":Write an equation for each statement simplify as much as possible::the sum of the digits of a number consisting of three digit is 12.a + b + c = 12:he middle digit is equal to half of the sum of the other two.b = .5(a+c):if the order of the digit be reversed the number is diminished by 198 find be number100c + 10b + a = 100a + 10b + c - 198100c - c + 10b - 10b = 100a - a - 19899c = 99a - 198simplify, divide by 99c = a - 2:

In the 2nd equation, b = .5(a+c), replace c with (a-2)b = .5(a + a - 2)b = .5(2a-2)b = a - 1:In the 1st equation replace b with (a-1); replace c with (a-2)a + (a-1) + (a-2) = 123a - 3 = 123a = 12 + 3a = 15/3a = 5then using the above equations we know that:b = 4andc = 3:543 is the number

b= 5(2a-2) kaise kiyab= a-1

sorry I didn't know

a milk depot sells milk every day=657lit1year=365 daysmilk will sell in 1 year=(657*365)lit=239805lit

Take 1yr =365 days Then 657*365=239805 liters

48×52=(50-2)×(50+2) [∵(a-b)(a+b)=a²-b²]=50²-2²=2500-4=2496

thank you

[3 4 & -5 1]=3×1+4×-5=3-20=(-17)

Since the number contains three digits, it has a hundreds place, a tens place and a ones place.

It is given that the right most digit is 0. Let the digits in the hundreds place and tens place be x and y respectively. Thus, the number is 100x + 10y + 0 = 100x +10y.

It is also given that if the digits in the hundreds place and tens place are interchanged, the difference between the original number and the new number after interchange is 180.

=> 100x + 10y - (100y + 10x) = 180

=> 100x + 10y - 100y - 10x = 180

=> 90x - 90y = 180

=> 90(x - y) = 180

=> x - y = 2 ---> (i)

It is also given that if the digit in the hundreds place is halved and digits in tens place and ones place are interchanged, the difference between the original number and the new number after interchange is 180.

=> 100x + 10y - (100x/2 + 0 + y) = 454

=> 100x + 10y -50x -y = 454

=> 50x + 9y = 464 --->(ii)

Multiplying both sides of Eqn (i) by 50, we get

50x - 50y = 100

Eqn (i) - Eqn (ii) => (50x - 50y) - (50x + 9y) = 100 - 454

=> 50x -50y -50x -9y = -354

=> -59y = -354

=> y = 6

Now, substitute the value of y in the equation x - y = 2.

=> x - 6 = 2

=> x = 8

Therefore, the three digit number xy0 = 860

We know that1 dm = 1 litre

according to questionradius r = 0.7/2 dmand Height h = 1.4 dmthus

Volume of mug = pi r^2 h - 2/3 pi r^3 = pi r^2 (h - 2/3 r) = 22/7 * 0.49/2 (1.4 - 1.4/6) = 0.898 lit

Cost of 1 lit milk = Rs 80So cost of 0.898 lit = 80 * 0.898 = 71.86 Rs

We know that1 dm = 1 litre

according to questionradius r = 0.7/2 dmand Height h = 1.4 dmthus

Volume of mug = pi r^2 h - 2/3 pi r^3 = pi r^2 (h - 2/3 r) = 22/7 * 0.49/2 (1.4 - 1.4/6) = 0.898 lit

Cost of 1 lit milk = Rs 80So cost of 0.898 lit = 80 * 0.898 = 71.86 Rs

Please like the solution 👍 ✔️

answer amount should be charged for 1 mug of milk by Dairy owner b is 35. 93 rupees

Whentwo coins are tossed simultaneouslythen the possible outcomes obtained are {HH, HT, TH, and TT}. Here H denotes head and T denotes tail. Therefore, a total of 4 outcomes obtained ontossing two coins simultaneously.

A = Getting atleast one tail = {HT, TH, TT}

P(A) = 3/4

(100-9)^2=10000+81-18008281

Hindi medium

i) 25 = 5²ii) 36 = 6²iii) 81 = 9² = 3⁴

Given:- the bucket contains 18 litres of the substance.

∴No. of mugs of 1(1/2) litres that can be taken out=18 litres/ 3/2 litres=12 mugs

All possible outcomes -HH, TT, HT, TH

P (at least one tail) = 3/4

(At least 1 tail means 1 or more than 1)

the correct option is 4

XL IS A CORRECT ANSWER

The correct option is 4

option number d is the right answer (d)=XL , please like my answer

XL is correct answer

the correct answer is (4) XL

option 4 is correct for

=1000/500 x1000/50=2x20=40=XL(4) answer is correct