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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 74401. |
_11山9Ge 寸he length ,of a rectangulat hul d vloonits perumete 3cofレ |
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Answer» length=100perimeter=300mbreadth=? perimeter of rectangle=2(length+breadth)=2(100+X)=2x100=200B=?if, it's breadth=252(100+50)=2x150=300 |
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| 74402. |
Find < AODBС69690 96AD |
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Answer» add all mesaure and - with 360 remaining it's your ans here, sum of all angles= 360°let angle AOD= xnow, 69° + 69° + 96° + x= 360°234° + x= 360°x= 126° hence, angle AOD= 126° iska write answers 126 degree hoga 126° is the ns of this question 126° is the answer when you will apply 360° theorem 69+69+96+AOD = 360234 + AOD = 360AOD = 360 -234AOD = 126° |
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| 74403. |
HULA momento is made as shown in the figure. Its base PBCR is silver plated from the front side. Find the area whichis silver plated. (Use it =Tombo7cmPЗcm,3cm |
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Answer» find all trigonometric ratios?AB=3 AC=4 CB =is fine find all trigonometric ratios?AB=3 AC=4 CB= is find area of sector =πr square=22/7*7=154cm^2area of triangle=1/2*b*h=1/2*10*10 =50cm^2are of shaded region=154-50=104 17.58 is right answer 17.58 is the right answer 104cm2 is the right answers ans 104 cm2 right answer hoga वृत्त का क्षेत्रफल= 154 सेंटीमीटर स्क्वायरत्रिभुज का क्षेत्रफल=104 cm squire 104 is the correct answer h. |
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| 74404. |
दी 2. (%) SH 10, 13, 17, 19, 12,15, 9, 20, 18 3 16 =छा ज्ञात कीजिए। ही |
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| 74405. |
1)62) 73) 84) 975. If C, 2 P-57:16 then n-еус1) 172) 183) 194) 20 |
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| 74406. |
44. 124 +56 X 1.5 - 12 = ?(1) - 1890(3) 230(5) of these(2) 252(4) 196 |
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Answer» 124 + 56 * 1.5 - 12= 124 + 56*3/2 - 12= 124 + 28*3 - 12= 124 + 84 - 12= 124 + 72= 196 (4) is correct option |
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| 74407. |
cost price of 19 articles is equal to the selling price of 16articles. Gain percentage is(a) 3 9/17%(b) 15 15/19%(c) 18 3/4%(d) 20% |
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| 74408. |
scoreDateNameTeacher0.62520.02511)U0.625O0.950 0.6670708[ 0.667*): 0. .1 006O 0.717_9) 0.6510) j 0.667on wwD16)17)18)19)20)0.8750625[ 040.8250.5920,692WNWN |
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Answer» not clear image pls click again |
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| 74409. |
(ix) (3x - 4y) -252(xii) 1-a2-2ab-b2x)3+62+18dei) 12xy + 25-4x2-9y28.Factorize the following: |
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| 74410. |
47. The moon's distance from the centre of the earth is 360,000 kms its diameter subtends an angle of31' at the eye of the observer .find the diameter of moon.a) 3247.62 km b) 3236.12 km c) 3233.60 km d) 3222. 2 knm |
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Answer» answer of this question is a |
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| 74411. |
5. Articles are bought ator loss per cent.45 per dozen and sold at 85 per score. Find the gain |
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| 74412. |
3 Find the height of the trapezium whose area is 1,080cm2 and lengths of its parallel sides are55.6cm and 34.4cm. |
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Answer» Area of trapezium= 1/2×(sum of parallel side)×height=1080(55.6+34.4)/2×h= 108090/2×h=108045h=1080h= 1080/45h= 36cm |
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| 74413. |
Volume of cone is 1212cm.cu.and its height is 24cm. Find thesurface area of the cone. |
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Answer» volume of cone = 1/3 pi×r² × h (1212 × 3)/24 = r² r² = 151.5 r = √(151.5) r = 12.3 So, Surface area of cone pi × r ( r + √ h² + r²) 3.14 × 12.3 ( 12.3 + √(576 + 151.5)) 3.14 × 12.3 ( 12.3 + 26.9) 38.622 × ( 39.2) 1,513.12 |
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| 74414. |
Find the two parallel sides of a trapezium whose area is 1.6m, altitude is 10 dm and one ofthe parallel sides is longer than the other by 8 dm. |
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Answer» 1/2 * (x+x+0.8) * h = area 1/2*(2x+0.8)*1 = 1.6 x + 0.4 = 1.6 x = 1.2 m The parallel sides are 1.2 and 2 m |
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| 74415. |
[U Q. 17. Prove that . 2N 8+sec8-1= sec + tan ©.tan © —-sec9 -1e |
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Answer» LHS:- tan theta + sec theta - (sec²theta - tan² theta /tan theta - sec theta + 1 =( tan theta + sec theta)(1- sec theta + tan theta )/tan theta +1 - sec theta =tan theta +sec theta =sin theta / cos theta + 1/cos theta = 1+ sin theta / cos theta ⁼sec theta+ tan thetaLHS = RHS Hence proved Please like the solution 👍 ✔️ |
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| 74416. |
3.Solve the following word problems.a) The age of 6 children are 9, 15, 12, 10, 6 and 14 years respectively. Find their average age |
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Answer» average age = total sum / total quantityAverage age = (9+15+12+10+6+14)/6average age = 66/6 = 11 |
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| 74417. |
S Solve the following word problems(a) Two numbers are in the ratio 2:3. The larger number is 30 more than half ofthe smaller number. Find the numbersnare an ornament |
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Answer» Let us consider the two numbers to be x and ySo, x:y=2:33x=2yAnd, y- (x/2)=302y-x=603x-x=602x=60x= 30So, y=45 |
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| 74418. |
19. Find out when y=" and v- £x +7when y=Find- and v=19.Or |
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| 74419. |
D. Solve the following word problems.1. A family drove 287.6 km to watch a cricket tournament and used 12.5 L of diesel.How many kilometres did they drive in 1 L of diesel? |
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Answer» 287.6÷12.5=23.008 is the answer. Your correct answer is 23.008km |
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| 74420. |
5. Convert each of the following fractions into a percentage:9161720(vi) 200(vii) 2U)4 |
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Answer» I want 6th question also |
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| 74421. |
15.Amerchant mixes two varieties of rice, one costingき35 per kg and another at?45 per kg in the ratio of3:2. If he sells the mixed variety at 41.60 per kg, find his gain or loss percent. |
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Answer» 35 per kg and 45 per kg is in 3:2so average price is (35×3+45×2)/5=(105+90)/5=195/5=39now C.P.=39S.P.=41.6so profit=(41.6-39)/41.6=2.6/41.6×100=6.25% |
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| 74422. |
2. A merchant mixes two varieties of rice, one costing * 35 per kg and another att 45 per ke in theIf he sells the mixed variety at 41.60 per kg, find his gain or loss percent. |
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Answer» Let quantity of one type of rice= 3xLet quantity of other type of rice be 2x Then,Total Cost price of rice CP= 3x*35 + 2x*45= 105x + 90x= 195x Selling price of rice= 5x*41.60= 208x Therefore,Gain % = [(SP - CP) / CP]*100=[(208x - 195x)/195x]*100= 1300/195= 6.6 % |
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| 74423. |
sin 29°Evaluate:+ 2 cot 12° cot 20° cot 45° cot 78° cot 700-3 (sec" 480-cot' 429.cos 61。 |
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Answer» sin29= cos 61cot 45= 1cot 12= tan 78cot 20= tan 70please like the solution |
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| 74424. |
Find the sum of the lengths of the bases of a trapezium whose area is 4-2m2 and whose height is280 cm. |
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| 74425. |
geometry ,adjacent side of a rectangle 7cm and 24cm find length of diagonal |
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| 74426. |
The ratlUis 25 metres, findihe ratlU U lengur dhd width of a rectangular ground is 5:3. If the length of25 metres, find the width of the ground,were are 8500 books in a library. If the ratio of bound and unbound books ihe total number of bound books.find the total nu |
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Answer» let x included in the ratiolength=5x,width=3xnow,5x=25 x=5width=3x=3×5=15meter width=15m is the right answer let the ratio be xthen,length=5xwidth=3x5x=25 x=25÷5 x=5then,3x=3×x3x=3×53x=15So,the width of the field is 15metre
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| 74427. |
The cost of a computer is20,000. The company offers it in 36 months, butcharges 10% interest. Find the monthly instalment the purchaser has to pay. |
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Answer» Cost of computer=₹20000Interest=₹(10/100)*20000=₹2000Total cost of computer=₹20000+₹2000=₹22000 Total months of installments=36Installment per month=₹22000/36=₹611.1 this is not a correct answer |
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| 74428. |
5 At what rate percent will a sum of money double itself in 10 years? |
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| 74429. |
\begin{array}{l}{\text { If } u=\sin ^{-1} \frac{x^{2}+y^{2}}{x+y}, x+y \neq 0, \text { then prove that }} \\ {x \frac{\partial u}{\partial x}+y \frac{\partial u}{\partial y}=\tan u}\end{array} |
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| 74430. |
At what rate percent on simple interest will Rs.750 amount to Rs.900 in 5 years |
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Answer» Simple Interest = 900-750=150Rate = (150*100)/(750*5)= 4% |
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| 74431. |
Vreme following word problems.a) Rani spent 30.75 on a cake and *20.25 on fruits. How much money didshe spend on both items? |
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Answer» she spent( 30.75+20.25=51.00) on both items. she spent 30.75+20.25=51.00 on both items. thanks |
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| 74432. |
\begin{array}{l}{\text { If } u=f(y-z, z-x, x-y), \text { prove that }} \\ {\frac{\partial u}{\partial x}+\frac{\partial u}{\partial y}+\frac{\partial u}{\partial z}=0}\end{array} |
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Answer» 2nd part |
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| 74433. |
x=u-v and y=u+vfindd(x,y)/d(u,v) |
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Answer» we are solving it with the help of Jacobian methodwe will do partial diffrentiation thanks |
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| 74434. |
The cost of preparing the walls of a room 12 m long at the rate of 1.35 per misthe cost of matting the floor at 0.85 per m is 91.80. Find the height of theis9.340.29 ineight of the room |
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| 74435. |
2. An isosceles trapezium whose bases have lengths 12 cm and 16 cn isinscribed in a circle of radius 10 cm. The centre of the circle lies in theinterior of the trapezium. Find the area of the trapezium. |
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| 74436. |
ENGINEERING MATHEMATICS -C.S PATIL CELL NO: 944865228CO-ORDINATE GEOMETRYFind the slope of line making an angle 135" with |
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Answer» 4x+8y-162x-9y+8 = 135° slope = tan slope = tan ( 90 + 45) = - tan 45 = - 1 |
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| 74437. |
a class test, 16 students out of 48 passed. Find the ratlu belwe(i) passed students to total number of students.(i) failed students to the number of passed one.7. In |
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| 74438. |
(D) 10(A) 35(B) 36(C) 40(D) 4529 |
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Answer» माना वह संख्या x हैअब18+27+x/3=3045+x=90x=90-45=45 |
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| 74439. |
idl amoull will he receive after 6 months?un took a loan of 390625 from Kuber Finance. If the company charges interest at 16%per annum, compounded quarterly, what amount will discharge his debt after one year?0. Ar |
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| 74440. |
A sum of 40000 was lent for one year at 16% per annum. If the same sum is lent for the same time and at the same rate percent but the compound half-yearly, how much more will the interest be? |
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Answer» Given :Principle amount P = 40,000AndRate r = 16%Time t = 1 year So , Simple interest = 40000 × 16 × 1100 = 400 × 16 = Rs. 6400 And As interest compound half yearly we know formula , As : Amount = P (1 + r2100)2t ,SoCompound money after 1 year compounded half yearlySo,Amount = 40000 ( 1 + 16200)2 = 40000( 1 + 450)2 = 40000( 5450)2 = 40000 × 54 × 5450 × 50 = 16 × 54 × 54 = Rs. 46656Then, Compound interest = 46656 – 40000 = 6656 The more interest would be = 6656 – 6400 = Rs. 256 |
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| 74441. |
tor was purchased one year ago fornased one year ago for 7 20000. Its value depreciates at the rate20000. Its value depreciates at the rate of13. A refrigerator was purchased15% per annum. Find :(i) its present value,(ii) its value after 1 year. |
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| 74442. |
Frame simple word problems for the following addition statementa. 75+42r 1278+3,564 d. 35,276+ 28,357Frab. 135+578 |
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Answer» a)117b)713c)4842d)63633 |
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| 74443. |
Word Problemsr Roy's orchard there are 2714 rows of trees with 68 trees in each rtrees does he have altogether? |
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Answer» No. Of rows =2714No.of trees in 1 row=68Total no. Of trees=68*2714=184552 184552 is the correct answer to this question. 184552 it is the correct answer |
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| 74444. |
A closed cylindrical tank of radius 7 m and height 3 mismade from a sheet of metal. How much sheet of metal isrequired? |
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| 74445. |
x? -9,x3(iv)If f(x)={*If f(x) =x-3m**? iscontinuous u x=3 then value ofmis:is continuous at x=3 then value of mis:() x=3 |
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Answer» Both limits will be same so m = 6 |
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| 74446. |
Two sides of a triangle are 10 cm and 5 cm in length and the length of the median to the thirdside is 6.5 cm. If the area of the triangle is 6 Jpcm, find the value of p(12 |
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Answer» the correct answer is 14 |
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| 74447. |
A closed cylindrical tank of radius 7 m and height 3 mismade from a sheet of metal. How much sheet of metal is7.required? |
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| 74448. |
the cWek2. Find the length of a chord which is at a distance of 5 cm from the centre of a circle niradius 10 cm.. Find the length otn hwith |
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| 74449. |
9. In an examination, 72% of the total examinees passed. If the number of failures is 392, findthe total number of examinees.K. After deducting a commission of 5%, a moped costs? 1 5200. What is its gross value? |
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Answer» The total number of passed examines is 72%. The number of failure examines is 393. Then the calculation for total examines is given below. 100% - 72% = 28% From the given details, 392 are 28% of the total examines. 392 = 28 * x/100 x = 39200 / 28 So the value of x = 1400, which is the total number of examines. Let the original moped cost be =xA/Qx-5%ofx=15200 |
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| 74450. |
16. A company used 75% of its profits to buy new machinery and raw materials. If this amounted to85,071, find the total profit of the company5500 to his daughter and the remaining9000 to his |
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