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<aqp=20 and <prc=22to find the value <qpr=xx=180-44=136to find the value of<pqr=yy=180-78=102

Thanxx sirr

if the tangents have to be parallel, then the perpendicular drawn from the point of intersection of the tangent and the circle which will meet at the centre should form the straight line hence the distance between these tangents is equal to the diameter of the circle.9cm

As6n = 6×nas a number ends with when it has 5 as its factor exclude 5.so here onlyn can take 5 or multiple of 5

Given: ABCD is a trapezium where, AB ll CDDiagonals AC and BD intersect at point O.

Construction: Draw a line EF passing through O and also parallel to AB.

Now, AB ll CD, since by construction, EF ll AB ⇒ EF ll CDConsider the ΔADC,EO ll DCThus, by Basic proportionality theorem, (AE / ED) = (AO / OC) .... (i)Now, consider Δ ABD, EO ll AB,Thus, by Basic proportionality theorem, (AE / ED) = (BO / OD) .... (ii)From (i) and (ii), we have, (AO / OC) = (BO / OD) (since L.H.S of i and ii are equal)Hence we proved that, (AO / OC) = (BO / OD)

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radius = 35 cm

length = 200cm

therefore its a rollers wheel

so, curved surface area = 2 * 22/7 * 35 * 200

= 44000cm²

= 4.4 m²

if it takes 60 revolution therefore it covers the area of = 4.4 * 60 = 264 m²

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Given: Quadrilateral ABCD in which diagonals AC and BD intersects each other at O such that AO/BO = CO/DO.

To Prove: ABCD is a trapezium

Construction: Through O, draw line EO, where EO || AB, which meets AD at E.

Proof: In ΔDAB, we have

EO || AB

∴ DE/EA = DO/OB ...(i)[By using Basic Proportionality Theorem]

Also, AO/BO = CO/DO (Given)

⇒ AO/CO = BO/DO

⇒ CO/AO = BO/DO

⇒ DO/OB = CO/AO ...(ii)

From equation(i)and(ii), we get

DE/EA = CO/AO

Therefore, By using converse of Basic Proportionality Theorem, EO || DC also EO || AB

⇒ AB || DC.

Hence, quadrilateral ABCD is a trapezium with AB || CD.

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1)38*63=40*60=24002)54*47=50*50=25003)28*63=30*60=18004)42*75=40*80=32005)64*58=60*60=36006)15*34=20*30=600

runningswimMingsleeping

38 estimate to the nearest ten = 40

parallel lines are the right answer.....

parallel lines is the best answer

volume of Cylindrical tankl × b × h = πr^2 h22×20×h = π (1)^2 × 3.5h = 1/40 mor h = 2.5 cmso the rainfall in cm is 2.5 cm

In one rotation roller covers 2 pi r

In 200 rotation it will cover 200 × 2 pi × r

= 400 pi r

So, According to question

2200 = 400 pi × r

r = 2200/400 pi

r = 22/4pi

r = (22 × 7)/4 × 22

r = 7/4 m

(-1)^131 = -1. 4-¹ + 5-¹ = 1/4 + 1/5 = 9/20.So, (-1)^131 / [ 4-¹ + 5-¹] = -1/ (9/20)= -20/9= -2 2/9.

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add the following rotation number

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tysm..❤❤

Let no. be n2n - 45=3nn = - 45

4n + 10 = 584n = 48n = 12

let the ratio be pso amit, sumit and nimit get 3x, 5x , 7x respectively therefore3x + 5x +7x = 37515x = 375x = 375/15 = 25so amit get ₹75sumit get ₹125nimit get ₹175

It complete 1 rotation in 12 hoursSo in 72 hours, it will complete=72/12=6 rotations

In (x,y), the value of y is three times the value of x

Relation, R ={(1,3),(2,6),(3,9)}

your answer is D it is right answer

option d is right answer

option (d) 5^1/3 is the correct answer

option (d)5^1/3 is the right answer

option (d) 5^1/3 is the correct answer....................

The answer is option d

iska answer c option h

the meeting started at 11:20

6.50+7.50=14.00(2:00 am)

the meeting started at 11:20

Cost Price = 12000+2850=14850selling price = 13860there will a loss of (14850-13860) rupees=990rupeesloss percentage = 900/14850*100= 6.6 percentageand it may be 900/12000*100= 7.5 percentage as well if you take cost price = (12000)

(x^4y)^1/3*1/(xy^7)^1/3x^4/3y^1/3*x^-1/3y^-7/3hence using laws of indicesx^4/3-1/3*y^1/3-7/3x^3/3*y^-6/3X*y^-2=(X/y^2)^-4=(y^2/X)^4=y^8/x^4

answer will y^8/x^4

(c) both positive or negative

c) Both positive and negative

Factorise 5103.After factorising, the result comes-3×3×3×3×3×3×7Two pairs of all 3's are forming but only 7 is left.Therefore, required number=7 (Ans).

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13/3125= 0.0046

17/8= 2.125

answer for this question is 0

(2/1)^5 = 2*2*2*2*2 = 32

cos^2x /1+sinx= 1-sin^2x /1+sin^2x(1+sinx)(1-sinx)/(1+sinx)so it will be (1-sinx)now intregation will be-(-cosx+c)

the correct answer of the given question is

18 - 3p - 11q + 5pq - 2pq*q + 5p*pq - 4p*pq + 3pq - 5pq*q + 8p - 7q + 10 = 28 + 5p - 18q + 8pq - 7pq*q + pq*q

b.2d.2questions not clear. so I can't solve more

Price of 10 balls is Rs 50Price of 1 ball is Rs 50/10 = 5

Then,Price of 15 balls = 15*5 = Rs 75

20*1= 20-2= 18