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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 74701. |
12 cm5 cm13 cm |
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Answer» suno tm ek que upload karo mai bhi karunga dono ek dusre ka best accept kar lenge 100 points milenge l am liked Your answer like my answer |
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| 74702. |
A square is inscribed in a circular table cloth of radius 35 em. If the cloth is tobe colored blue leaving the square, then find the area to be colored. |
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| 74703. |
Two plots of land have the same perimeter. One is a square of side 64 m and the other a rectangleength 80 m. Which plot has the greater area and by how much?wihmeter is 320 m. If laving of grass costs 7.50 per sq |
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| 74704. |
with its vertex at one end of the major axis.9. A tank with rectangular base and rectangular sides, open at the top is to beconstructed so that its depth is 2 m and volume is 8 m. If building of tank costsRs 70 per sq metres for the base and Rs 45the cost of least expensive tank?per square metre for sides. What is |
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Answer» Step 1:Let the length and breadth of the tank be x metre and y metro respectively. The depth of it is 2m.Volume of tank = 2×x×y = 2xyVolume = 8m3⇒ 2xy = 8 xy = 4-----(1) Step 2:Area of base = xyArea of sides = 2.2(x+y) = 4(x+y)Cost of construction= Rs[70xy+45×4(x+y)] = Rs[70xy+180(x+y)] = Rs[70xy+180(x+y)]-----(2) Step 3:Put the value of y in (2) from (1) we havexy = 4y = 4/xC = 70.4 + 180(x + (4/x)) = 280 + 180(x + (4/x)) Step 4:Differentiating with respect to x we get,dc/dx = 0 + 180(1 − 4x^2) = 180((x^2−4)/x^2) Step 5:For maxima or minima dc/dx=0x^2 − 4=0x2 = 4x = ±2dc/dx changes sign from -ve to +ve at x=2∴c is maximum at x=2[length of the tank cannot be negative]⇒x=2 and y = 4/xy = 4/2 = 2Thus tank is a cube of side 2m Step 6:Least cost of construction = Rs[280 + 180(2 + 4/2)] = Rs [280 + 720] = Rs1000 |
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| 74705. |
C the midpoint of the line joining A (2, p) & B (,j is 3,5. Calculats the numenical valtue ot o a& B (c,4 is 3,5. Calculate the numerical vatue ot p |
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| 74706. |
किक ot(i) 4" —Betrd |
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Answer» 4x*x - 8x + 4 = 4(x*x - 2x + 1) = 4(x-1)(x-1) |
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| 74707. |
Use Ď =-ot6kmhr mocomplete the t2 The mean and median of 100 observations are 50 and 5respectively. The value of the largest observation is 100was later found that it is 110 not 100. Find the true mean and. Then52adowof the24. The ssum of fterms is 16001 median. |
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Answer» Median is the middle value or the average of the middle values. So it will not change with increasing the biggest observation Also let the sum of all the observations be x mean = x/100 = 50 x = 5000 x+10 =5010 new mean = 5010/100 = 50.10 |
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| 74708. |
(2a^2)^3/b in ca^p b^q form |
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Answer» (2a²)³/b = 8a⁶b⁻¹ |
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| 74709. |
find the volume of cuboidl= 10 cmb= 8 cmh= 3 cm |
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Answer» Volume = lbh = 10*8*3 cm³ = 240 cm³ thanks how are you |
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| 74710. |
R?3. In the given figure, what is the value of tan P- cot6 cm10 cmGgure |
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| 74711. |
a ^ { 3 } + b ^ { 3 } = ( a + b ) ^ { 3 } - 3 a b ( a + b ) |
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Answer» (a+b)^3 - 3ab(a+b)(a+b) {(a+b)^2 -3ab}(a+b)( a^2+b^2 -ab)a^3+ b^3 |
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| 74712. |
1 = 12./13 cm. Ans.r in a canal, 6 m wide and 1.5 m deep, is flowing with a speed of 10 km/h. Htowarea will it irrigate in 30 minutes, if 8 cm of standing water is neededh |
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| 74713. |
Find the total surface area of a hemisphere of radius 10 cm. (User -3 14) |
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| 74714. |
hat IS ItS area3) The length of a square canvas cloth is 15 m. Find the areaof the cloth ? |
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Answer» area if sqaure cloth is a^2 where a is length so 15^2 is 225m^2. |
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| 74715. |
hu Its volume.The height of a tent is 9 m. Its base diameter is 24 m. What is its slant height?cost of canvas cloth required if it costs 14 per sq.m. |
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Answer» hug DP road near Mehran masjid bunder Mumbai India. please approval for inspire awards |
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| 74716. |
Practice Set S1g onions cost 140 rupees, how much must we pay for 12 kg onions?1 hor many will 1280 rupees buy? |
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| 74717. |
Practice Set 37i ki onions cost 140 rupees, how much must we pay for 12 kg onions? |
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Answer» 7 kg is of 140 rupees 12 kg is of 12*140/7 = 240 rupees. If you find this answer helpful then like it. |
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| 74718. |
I1 7 kg onions cost 140 sopy tor |
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Answer» Cost of 7kg onions is ₹ 140 Cost of 1 kg is 140/7 = ₹ 20 Cost of 12 kg is ₹20 × 12 = ₹240 |
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| 74719. |
5a^2 - 7ab + 5b^2 from 3ab —2a^2 — 2b^2 |
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Answer» 3ab - 2a*a - 2b*b - ( 5a*a - 7ab + 5b*b ) = 3ab - 2a*a - 2b*b - 5a*a + 7ab - 5b*b = 10ab - 7a*a - 7b*b If you find this answer helpful then like it. |
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| 74720. |
5)38. If a = 5 and x = 2, then 2a*-2 -2.lo |
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Answer» 0 is the right answer👍👍 0 is the right answer 👍👍 2ax-2 -2 2×5 2-2 -210 0 -210 -28 answer a = 5 , x = 22a^x-2 -2= 2(5)^2-2 -2=10^0 -2=0 -2 =0therefore 0 is the answer |
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| 74721. |
2 A path 2 m wide runs inside a squase fekd of side 72 tm. Find the aves di tue yati.3 A photo is mounted on a cardboard of diruensions 12㎝ x 10 or. E the pr oo wasnes8 |
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| 74722. |
\int \frac{\sec ^{2} x}{\cos c e^{2} x} d x |
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| 74723. |
2. A path 2 m wide runs inside a square field of side 72 m. Find the area of the path. |
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| 74724. |
ii)Expressthefollowingas a product of prime factors only in Exponential form 108 x 192i) A path 5m wide runs along inside a square park of side 100m. find the area of the path.Also find the cost of cementing it at the rate of #250 per 10m2. |
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Answer» Length of the big square = 100 mlength of the small square = 5 mSide of the smaller square = Side of the bigger square - 2(width of the path) = 100 - 2(5) = 90 mArea of the path = (100)² - (90)² = 10000 - 8100 = 1900 sq m Cost of cementing at the rate of Rs 250 per 10 m² = 250 x 190 = Rs 47500 |
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| 74725. |
If a/b = 2/3 then find the value of 2a^2/3b^2 |
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| 74726. |
\int \sec ^{2} x \cos e c^{2} x d x |
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| 74727. |
ORA heap of rice is in the form of a cone of base diameter 24 m and height 3.5 m. Find the volume of the rice. Howmuch canvas cloth is required to just cover the heap? |
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Answer» Answer is wrong |
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| 74728. |
A heap of rice is in the form of a cone of basediameter 24 m and height 3.5 m. Find the volumeof the rice. How much canvas cloth is required tojust cover the heap?Solution:h 10 cmr 3.5 cm |
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Answer» Base diameter of cone = 24m Radius = 12mHeight of cone = 3.5mVolume of rice in conical heap = 1/3πr2h = 1/3 × 22/7×12×12×3.5 = 528m3now, slant height = √h2 + r2 |
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| 74729. |
OReap of rice is in the form of a cone of base diameter 24 m and height 3,5 m. Findof a 'cone of base diameter 24 m and height 3.5Findthe volume of the rice. How much canvas cloth is required to just cover the heap? |
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| 74730. |
matha woorksh1. factoou se the followingla x2x72 to2. 4x²-162 +15 y 2 tortor3. 16x² -254. 42²4x4S. xa 2+16. ad traal 42 4x² -16x + 15 = 40ZMT7. 32x +48x778 |
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| 74731. |
11 Samita has a recurring deposit account in a bank of 2000 per month at the rate of10% pa. If she gets?83100 at the time of maturity, find the total time for which theaccount was held.Hint.Let the account be held for x months, then+ 2000 x r(r.1)X-102×12 1002000 χ |
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Answer» Given Monthly installment = 2000Maturity value = 83100R = 10% Now let time for which account was held be x Then,2000x + 2000*x(x+1)/(2*12) * (10/100) = 83100 2000(x + x(x+1)/240) = 83100 20(240x + x^2 + x) = 831*240 x^2 + 241x - 831*12 = 0 x^2 + 241x - 9972 = 0 x^2 + 277x - 36x - 9972 = 0 x(x + 277) - 36(x + 277) = 0 (x - 36)(x + 277) = 0 x = 36, - 277 Negative value not possible Therefore, account was held for 36 months. |
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| 74732. |
If 7 kg onions cost 140 rupees, how much must we pay for 12 kg onions? |
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Answer» 240 is the answer the answer is correct |
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| 74733. |
Find the compound interest for Rs. 2000for 3 years at the rate of 10% per annum |
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| 74734. |
perimeter is 240 m.Apath 2 m wide runs inside it, along its boundary. Find the cost of paving the path atThe length and breadth of a park are in the ratio 2:l and its3 per sq m. |
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| 74735. |
A rectangular park is 60 m length and 30 mbreadth. A path 2 m wide runs along inside thevectanqular park. Find the area of the path |
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Answer» Area of path = 60*30 - 56*26= 1800 - 1456= 344 m² Please hit the like button if this helped you |
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| 74736. |
7. The length and breadth of a park are in the ratio 2: 1 and its perimeter is 240 m. A path2 m wide runs inside it, along its boundary. Find the cost of paving the path at t S0 per m' |
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Answer» Thank you so much deepika, 😀😀🙂😍☺👍👍👍 |
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| 74737. |
)A path 5m wide runs along inside a square park of side 100m. find the area of the path.Also find the cost of cementing it at the rate of 250 per 10m2. |
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Answer» Length of the big square = 100 mlength of the small square = 5 mSide of the smaller square = Side of the bigger square - 2(width of the path) = 100 - 2(5) = 90 mArea of the path = (100)² - (90)² = 10000 - 8100 = 1900 sq m Cost of cementing at the rate of Rs 250 per 10 m² = 250 x 190 = Rs 47500 |
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| 74738. |
I+sinx.siny.sin A cos A (sin2 A- cos2 A) (1- 2 sin2 A. coscot4 A + cot2 A = cosec 4A-coset,2A2 sec 2 A-sec 4 A-2 cosec2A + cosec4A_ cot4 A-ta(sin A + cosec A)2 + (cos A+ sec A)2= tan2 A+ cota(1 + cot A-cosec A) (1 + tan A+ sec A) = 2) |
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Answer» starting with LHS : =>sin⁸A - cos⁸A we know that :-sin⁸A = (sin⁴A)²cos⁸A = (cos⁴A)² This can be written as :- =>(sin⁴A)² - (cos⁴A)² Now this is in the form of an identity : a² - b² = (a+b) ( a - b) =>(sin⁴A + cos⁴A) ( sin⁴A - cos⁴A) sin⁴A = (sin²A)²cos⁴A = (cos²A)² =>(sin²A)² +(cos²A)² (( sin⁴A - cos⁴A)) (sin²A)² +(cos²A)² can be in the identity : a² + b² = (a+b)² - 2ab [ (sin²A)² +(cos²A)² = (sin²A + cos²A)² - 2sin²Acos²A ] => [(sin²A + cos²A)² - 2sin²Acos²A ] (( sin⁴A - cos⁴A)) Now ,sin⁴A - cos⁴Athis can be written in the form of the identity a² - b² = (a+b) (a -b) sin⁴A = (sin²A)²cos⁴A = (cos²A)² sin⁴A - cos⁴A = (sin²A + cos²A) (sin²A - cos²A) =>=> [(sin²A + cos²A)² - 2sin²Acos²A ](sin²A + cos²A) (sin²A - cos²A) we know that ,sin²A + cos²A = 1 [ by identity ] hence, => [(1)²- 2sin²Acos²A ](1)×(sin²A - cos²A) => ( 1 -2sin²Acos²A ) (sin²A - cos²A) =>RHS Thank you Question thik se post karo |
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| 74739. |
7 The length and breadth of park are in the ratio 2 :1 and its perimeter is 240 m. A path2 m wide runs inside it, along its boundary. Find the cost of paving the path atHiat. Let the length-2 x m and the breadthm80 per mThen, 2 (2 x + x) = 240x40. |
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| 74740. |
e sec x (1+ tan x) dx |
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| 74741. |
13 Differentiate the following.(2) ex + log X-sin xcixi 5x2 + 8x + 9(4) sec x + cosec x + cot(3) VX + tan x(6) x2 sin x(5) xe*+(8) TX(7) (1 + x2) tan x |
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| 74742. |
-(a %2B 2*b)*(a %2B 3*b) - b*x %2B x^2*(x*(i*v)) |
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| 74743. |
e: 20kgs of rice is needed for a family of4 members. How many kgs of rice wilrequired if the number of members in the house increases to 10? |
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Answer» rice for 4 members=20kgrice for 1 member=20/5=4kgwhen members are 10;rice required=4×10=40kg |
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| 74744. |
12.For a group of 200 candidates, the mean and standard deviation were found to be40 ad 15 respectively. Later on, it was found that the score 43 was misread as 34.Find the correct mean and correct standard deviation. |
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| 74745. |
Missp3900. Later, she huru2. The coach of a cricket team buys 3 bats and 6 balls forhat and 3 more balls of the same kind for 1300. Represent this situation algeand geometrically0. Later, she buys anestehis situation algebraicafmnes on a day was found to be 10 |
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| 74746. |
39. (A) Seven speakers A, B, C, D, E, F, G are invited in a programme to deliverspeech in random order. Find the probability-that speaker B delivers speechimmediately after speaker A.7 (B5If P(A): 25, PLA)= 12 and PIB/sample space of a random experiment, then find P(A(B)2 for two events A and B İn theB) and P(B) |
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Answer» 6/7 of the time A is not the last speaker, so one of the others follows him or her and it is equally likely to be any of the other 6, so the conditional probability that the one who follows A is B is 1/6. This means there’s a (6/7) * (1/6) = 1/7 chance that B follows A. Like my answer if you find it useful! |
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| 74747. |
The area of a rectangular garden is 2400 mIf its length is 60 m, then find the width othe garden. |
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Answer» breath will be 40thank |
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| 74748. |
The cost of carpeting a room 15 m long with a carpet of width 75 cm at 80 per metre isて19200, Find the width of the roomofland are in the ratio of 5:3. If the total cost |
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| 74749. |
1.C,sin(240°+α(ii) cU(i)sin α + sin(120° + α)sin 8x cosin(A + B |
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Answer» sin(120+a) = sin120cos(a) +cos(120)sina = √3/2*(cosa) -1/2*(sina) sin(240+a) = sin(240)cosa + cos(240)sina = -√3/2*cosa - 1/2sina so, adding all the terms we get =sina +√3/2*(cosa-cosa) -1/2*(sina+sina)=sina + 0-sina = 0 |
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| 74750. |
A path 3.5 m wide runs inside along the boundary of a square field whose side is 65 m.Find the area of the path. Also find the cost of manuring the rest of the field at the rateof 25 per square metre. |
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Answer» Side of outer sq = 65m width of path = 3.5mcost of measuring = 25 rupees/sq metreside of inner sq = 65 - (2 * 3.5) = 58marea of path. = 65 * 65 - 58 * 58 = 4225 - 3364 = 861 sq metrescost of measuring the rest of the field = 3364 * 25 = ₹ 84100 |
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