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76051.

Find x if (39% of 640) + (x % of 590= 414.8.(A) 24 (B) 28 (C) 31 (D) 32IIMO Stage II 2016

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76052.

14.Find the mean of following distributionx12 16 20 24 28 323

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76053.

13. By what number shouldbe multiplied to geplied to get (3)

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76054.

(e) 2800(f) 1620). A school collected 7056 for Prime Minister's Relief fund. If each student collected as many paise orthere were students in the school. How many students were there in the school?

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There were 74 students in school.Number of students multiplied by number of rupees.So,x to the power of 2 is equal to 7056.Thus, x equals to 84.

Let no. of students be xThen no. of student =no. of rupeesThus, x^2=7056x=84 correct answerPlease like the answer if it correct and mark it as best

76055.

हल वर" व ———e [00 - रा (9व AR whe of रन -

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76056.

ompute Mode of the following series-ge-Group o-5 -110-15 15-20 20-25 |25-30 30-35 35-40 40-45requency 20 24 32 28 2016 34 108Ans. Z 13.33] (Awadh,2004, M.A, 2003, Meerut, 2007, Jiwaji, 2005, Agra, 2005)3 41 0

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76057.

2. Find the area of the pentagon as shown in the figure, if AD15 cm, AH 10 cm, AG 8 mAF 5 cm, BF 6 cm, GE 3 cm and CH 9 cm.

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76058.

dotalamound collected2cou SYoua many hisket tose soldhinna 2

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Cost of each ticket = Rs 65 /2

Total amount collected by the boy is = 2 × 877 + 1

= 1754 + 1 = Rs 1755

No. of tickets sold = 1755 / 65 / 2

= 1755 × 2 / 65

= 3510 / 65

= 54

So 54 tickets were sold by the boy.

thanks bro

thamxx

76059.

b) A pair of dice is thrown and one die shows a four. The probability that theother die shows 5 is

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As there is nothing told about the dies , let us assume the dies are identical. So as one die has 6 faces viz. 1,2,3,4,5,6 , if we through two dies we have (6×6=)36 sample points.

n(S)=36

Let A be the event that one die results in 4.

Let B be the event that other die results in 5.

So, required probabiity=p(B|A)

We know ,p(B|A)=p(A intersection B)/p(A)

Now the event ‘A intersection B' has 1 sample point (4,5) [as dies are identical, the points (5,4) & (4,5) ,aren't considered as different sample points].

So, p(A intersection B)=1/36

Again, the event A has 6 sample points in its sample space and 1 point in favourable case. So, p(A)=1/6

So,p(B|A)=(1/36)÷(1/6)=1/6

76060.

4 Use factor theorem to detsmins whe ther02 +2

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76061.

3 Find the renailluel ooTlgl4) Factorise : a) (a+ b)2-2a (a +b);

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Taking out (a+b)=(a+b)(a+b-2ab)

76062.

Two dice are thrown simultaneously. Findthe probability of getting a multiple of 2 onone die and a multiple of 3 on the other die.

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Answer---11/36

Explanation-:

Case 1- when dice 1 is getting a multiple of two and dice 2 is getting multiple of 3. so in this case , combination will be-

p(a)= (2,3) , (2,6), (4,3) , (4,6) , (6,3) , (6,6) = Six way

case 2- when dice 2 is getting a multiple of two and dice 1 is getting multiple of 3. so in this case , combination will be-

p(b) = (3,2) , (6,2) , (3,4) , (6,4) , (3,6), (6,6) = Six way

p(a∩b) = (6,6) = 1 way

total no of chances= p(a)+p(b)-p(a∩b) = 11

total operation = 6*6 = 36

hence probability = 11/36

76063.

wheoबन हिi

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76064.

Whe änd WIIUWhat Bharatmala project? Explain.the toursn

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Bharatmala Pariyojana is a centrally-sponsored and funded road and highways project of the Government of India.

The total investment for 83,677 km committed new highways is estimated at ₹5.35 lakh crore, making it the single largest outlay for a government road construction scheme

76065.

2)İs a part of CPU and do arithmetic calculations.a) cUb) ALUc)M U

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ALU -Arithmetic Logic Unit is a part of CPU which does arithmetic calculations.

76066.

233m a point on a bridge across a river, the angles of depression of thete sides of the river are 30° and 45°, respectively. If the bridge is at a heightca m from the banks, find the width of the river.

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76067.

4x+5-520.4x

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76068.

In what time will Rs 64000 amount to Rs 68921 at 5% per annum interest being payable half-yearly?unt if interest is

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The value of n will be equal to 3/2.

76069.

Mamta bought a pen for2375 after getting 5% discount on it. What is its list price?unt o 150 TAThat nercent

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76070.

9-0 (1०५3 9 0०» Lo m 224 ८ abwe परT peik .2.1 e deo b U sआय कि ool S

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76071.

-plans с псоuѕ oco us.U. Find the minimum number ofe. Find theiruy that the numberId ABThere are 500 children in a school. For a PT.manner that the number of rows is equal to numberwould be left out in this arrangement.For a P.T. drill they have to stand in such aHal to number of columns. How many childrenTITTA

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22×22=484 that is a perfect square number so rows and column are 22 and 16 students have to left

They should stand in a order of 22*22 . And 16 students are left

to make a square arrangement the students will have to stand in the equal number of calumns and rows..here we need only 22×22=484 student to make a square. . thus 500-484=16 students have to left out in this arrangement.

76072.

i) Anuj has an equal number of two-rupee and five-rupee coins. He has also someone-rupee coins. If the total number of coins is 40 and their value is Rs 120, how manyfive-rupee and two-rupee coins does he have?

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76073.

7. Simplify each of the following and express each as a rational number:Lan (3) 09-09fondanrece each as a rational number:

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(3/2)^4 x (1/5)^2=(81/16)×(1/25)= (9/4)^2×(1/5)^2=9/4×5=45/4, (iii)(2/3)^2×(-3/5)^3×( 7/2)^2=(2)^2/(3)^2×(3)^3/(5)^3×(7)^2/(2)^2=1/1×3/5^3×49==49×3/5^3=147/125

76074.

tuills 8t the heightd) Meena, Beena and Leena are climbing thesteps to the hill top. Meena is at step s, Beenas behind.Where are Beena and Meena? The total numberof steps to the hill top is 10 less than 4 timeswhat Meena has reached. Express the totalis 8 steps ahead and Leena steps belindnumber of steps using s

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76075.

A line passes through the point (3, 4) and cuts off intercepts from the coordinates axes such that their sum is 14Theequation of the line is(A) 4x-3y=24(B) 4x+3y =24(C) 3x-4y =24(D) 3x+ 4y =24

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76076.

3x 4x-4Factorise4. p +6p +87. x2 +13x+4010. x -10x +24

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76077.

(4x + 5)(4x + 1)

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76078.

26. Divide the polynomial 24 + 8x3 +4x +72 +3 by x + 3. Also, verify youranswer

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Remainder = 0it is completely divisiblePlease like the solution 👍 ✔️

ok

76079.

(4x + 5) (4x - 1)

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(4x + 5) (4x - 1)(4x)² - 4x + 20x - 516x² + 16x - 5

76080.

sum of ages of all the three after 12 yedl(1) 124 (2) 160 (3) 108 (4) 1443. Rasik has thrice five rupee notes than 10 rupee notes Ramesh has. The total amount with300. How many five rupee notes Rasik has with him?(7130 (3) 12 (4) 6them is ?

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Let the number of 10 rupee notes be x.Then, Number of 5 rupee notes = 3x.According to the question,3x*5 + x*10 = 300=> 15x + 10x = 300=> 25x = 300=> x = 12. Number of 5 rupee notes = 3x = 3*12 = 36.

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76081.

Rational NumbersMultiplicative Inverse. For any rational numberInvers7. Additive anda. a = 0..a is called the additive inverse of a(a) b

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Please post a question to help you.

76082.

8. Find thr sum of additive inverse and multiplicative inverse of 9.

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additive inverse of 9 is -9multiplicative inverse of 9 is 1/9sum of additive inverse and multiplicative inverse of 9 is

=-9+1/9

=-82/9

76083.

Express the following common fractions as decimal fractions:a) 1/5b) 1/2c) 1/8d) 1/16

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1/5 = 0.21/2 = 0.51/8 = 0.1251/16 = 0.0625

76084.

The common difference of an A.P 1/p , 1-p / p , 1 - 2p /p , ............... is :

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76085.

11-p 1-2p1. Find the common difference of the AP:,

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It is given that ,

1/p , ( 1 - p )/p , ( 1 - 2p )/p .... is an A.P

Common difference = a2 - a1

d = [ ( 1 - p )/p ] - 1/p

= ( 1 - p - 1 )/p

= -p/p

= -1

Therefore ,

Common difference = d = -1

76086.

Ex. (4) 4x = 244x24.. x = 0

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4x=24X=24/4X=6 answer

4x=24x=24/4x=6 is correct answer.

correct answer is x = 6

x=6 is the right answer

x= 6 is the right answer

x=6 is the right answer

x= 6 is the right answer

x= 6 is the right answer

X=24/4X=6 answer .....

4x=24x=24/4x=6 answer

6 is the correct answer of the given question is about

76087.

4x-2(3x-5)+2/3(4x-7)=0

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12x-6(3x-5)+2(4x-7)= 0

12x-18x+30+8x-14 = 0

2x+16 = 0

2x = -16

x = -8

76088.

3x2-4x=0

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76089.

108144(A) 34(B) 35(C) 36(D) 37

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108 = 2*2*3*3*3144 = 2*2*2*2*3*3

H.C.F = 2*2*3*3 = 36

76090.

21. A certain quality of wood costs 250 per m.Asolid cubical block of such wood is bought for182.25. Calculate the volume of the block anduse the method of factors to find the length of(ICSE)one edge of the block.

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the cost of a solid cubical block fine wood costs Rs256Rs500 per m³its volume &the length of each side is required whereby;cost of 1000000cm³ of block=Rs5001m³=1000000cm³volume of the block in Rs2561000000*256/500=512000cm³length of the block=512000^1/3=80cm³

76091.

0-5256Write the additive inverse of each of the following

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additive inverse ofi) -2/8ii)5/9iii) -6/5 for additive inverse we have to take negative of the given no.and in last case both sign of numerator and denominator cuts each other

(i) Additive inverse of 2/8 is -2/8(ii) Additive inverse of -5/9 is 5/9(iii) Additive inverse of -6/-5 or 6/5 is -6/5 .

76092.

Exercu1. Write the additive inverse of each of the followingwho

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additive inverse of X is -x1)-7/82)4/93)29/304)25/37

76093.

Wte the coeficiens af si in cach of the ollowinghabinomial of degree 35, and

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76094.

4. Simplify the following question/expression/ fraction4- + 2-of--4-6 8 6 6. Simplify the common111

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6*4+1/8*2+1*1/6-6*4+1ans-18.443

the correct answer is 18.443

the correct answer is 18.443

76095.

Add and Simplify 3x -6y +8y -3x +4x -7xy Subtract and Simplify 4mn + 2n -(-6mn) +4m -(-10m) +8mn

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Answer of add and simplify - +4x +2y -7xyAnswer of subtract and simplify - -2m-2n+10mn

76096.

(ICSE2003line.Givensolution on the number line:)that xel, solve the inequation and graph thex-4x0 32322(ICSE 2004)

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3>=(3(x-4)+2x)/6>=218>=3x-12+2x>=230>=5x>=146>=x>=14/5

76097.

Lind A and B.Atbi5 = 313-1536 37

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76098.

30. A solid cubical block of fine wood costs? 256 at? 500 per m3. Find its volume and thelength of each side.

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76099.

256 at 500 per m". Find Its volume and the30. A solid cubical block of fine wood costslength of each side.

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volume of cubical block is 512m3 , the length of each side

76100.

inEXERCISE 1.11. Using appropriate properties find.2 315 31-5*5+2 5972. Write che additive inverse of each of the following-6

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