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76251.

Ciicles. Prove that BP BQIn any triangle ABC, if the angle bisector of ZA and perpendicular bisector of BCintersect, prove that they intersect on the circumcircle of the triangle ABC.1

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76252.

4 quadratic polynomial has no real zero, then the graphtouches x-axis at any pointintersect y-axis in two distinct point (D) is in one hall plane(B) intersect x-axis in two dist

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See if the graph is completely above x axis, what does that means ? This means that there is no solution for which equation will be zero.

no real roots

Hence no real solution.

76253.

EXER1. Is it possible to have a triangle with t(i)2 cm, 3 cm, 5 cm

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no.. , because sum of two smaller sides should always be greater than the biggest side.but here , 2+3 = 5 , is not greater than 3rd side.

76254.

5. The locus of the vertices of the family of parabolas3,-2y-a3" +"2-2a is(a) xy=-64.(c) xy=161S105(b) xy 43564(d) xy = 105(AIEEE 2006)

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76255.

15 How many line/lines passes from three distinct collinear points and threedistinct non-collinear points?

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, 3collinear pointswill make an uniquelinewhich then can be madeto pass through manyplanes, simplybyrotating one plane abouttheline

76256.

o which figure is formed a17 Three Collinear Points2 Three non-collinear point2

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76257.

4. Howmany line /lines are passes from three collinearanthree non-collinear points?

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Only one line passes through the three collinear points and no line passes through the three non-collinear points.

76258.

2. Compare the following:(a) -2- (-21)................- 21 +( 2)(b) Additive inverse of 32 ................. - 45 - (-13)Š Successor of -75.................. Predecessor of additive inverse of 74Smallest odd positive integer .................. Largest odd negative integer

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1=> and 2=-32 and 3=75 and 4=0

1.<2. -323. 754. 0

76259.

Exercise 11.2actorise the following (1 to 11) polynomials1. ( a+ xy-x-y(i) y-ya-Sy+5(i) 6xy.3xy-10y + 5(i) x2 + xy(1 + y) + y3(ii) 13-3x2 + x-3(n) Sax - 6ay-8by + 4bx(ii) y.xy(1-x)-z?(i) 2a-4b-xa+ 2bx4.

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thanks but questions no.5 and 6

76260.

What is the largest and smallest negative integer?

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largest is -1 and smallest is -100 or above

-1 and -100 is the correct answer of the given

larges -1 and smallest undefined

76261.

AR TIESE(1)12legers(d) an integer smaller thanWrite a pair of integers whose sunt gives(a) a negative integerinteger smaller than both the integeran integer greater than both the integeris a pair of intepers whose differene gives#) a negative integerweer smaller than both the intepers.an integer greater than both the integer(h) ter) a megonly oned indeos

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it is right answer copying

76262.

10.3on areal numberRepresentline

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76263.

) A sum of Rs. 980 is divided to give 7 cash prizes to students of a school for theirperformances in different games. If each prize is Rs. 30 less than its precedingprize, find value of each of the prizes. 5

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a=2302nd prize = 230-30= 200third = 200-301704th =170-30=1405th = 140-30= 1106th = 110-30= 807th = 80-30= 50

76264.

16. A sum of700 is to be used to give seveft cash prizes to students of a school for theiroverall academic performance. if each prize is?20 less than its preceding prize, find thevalue of each of the prizes.

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76265.

11(c) 31.2 RYA body of mass 100 kg is moving with avelocity of 10 m/s. It is stopped at a distanceof 100 m by a resisting force. Calculate theforce of resistance.COM

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76266.

bulb is selected at randullTSECTION-Dson,A shopkeeper buys a number ofamount, each book would have cost him R 10 less. How many book23.books for 7800. If he had bought 4 more books for the satnezero.r lhat if a line is drawn parallelto one side of a triangle to intersectDuovnnints, then the other two sides are divided

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Let the shopkeeper buy x number of books.

According to the given condition, cost of x books = Rs. 80

Therefore cost of each book = Rs. 80/x

Again, when he had bought 4 more books, then total number of books in this case = x + 4

So, cost of each book in this case = Rs. 80/x+4

According to the question,

Cost of each book in first case - cost of each book in second case = 1 Rupee

80/x - 80/x+4 = 1

80(x+4) - 80x / x(x+4) = 1

x^2+ 20x - 16x - 320 = 0

(x - 16)(x + 20) = 0

x = 16 or x = -20

Hence, the shopkeeper bought 16 books.

76267.

A television set is sold at a loss of 10% for rs 2700.00 find the cost price of the television set

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(100-10)/100 * Cost = 2700=>90/100 * Cost = 2700=> Cost = 2700*100 / 90=> cost = Rs. 3000

correct answer

76268.

A shopkeeper gives 11% discount on a television set, hence the costis Rs. 22,250. Then find the marked price of the television

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76269.

(iii) Also,Thus, the total production of TV sets in fEXER1. Find the sum of the following APs:(1) 2, 7, 12, ..., to 10 terms.

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2,7 ,12so a = 2d = 7-2 = 5so a(n) = 2+ (n-1) 5 = 2 + 5n -5= 5n -3

it's is wrong it's answer is 250

oo u want sum wait let me do it

76270.

सन है लि |(o R R 7, % है» 8 O G

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a=x-7d=(x-2)-(x-7)=5T10= a + (n-1)d = (x-7)+9(5) = x +38

76271.

6. The cost of 5 - kg of mangoes is 189. At what rate per kg are the mangoes being sold?

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36 is the answer of this

36 is the correct answer of the given question

36 is the right answer

36 is the correct answer

36 RS per kg is the answer

Rs36 is the right answer

Your correct answer is Rs 36

36

36 is the correct answer

36 is the correct one

36 is the right answer

76272.

I8,900. Plnd the selling price, if it is sold at 153. A television is sold for 29,760 and a loss of 4% is incurred. What was thetelevision?

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Let the price be x4 % of x =0. 04xAo tv sold at x - 0.04x = 0.96 x = 29760.So x = 31000.

76273.

and R are three collinear points. P and Q are (3,4) and (7, 7) respectively, and, 10 units. Find the coordinates of R.

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Given P=(3,4) and Q=(7,7)PQ=√(3-7)^2+(4-7)^2=√16+9=√25=5But PR=10unitsQR=5unitsSo Q is mid point of PRLet (X,y) be coordinates of RSince Q is midpoint of PR3+X/2=7x=114+y/2=7y=10Coordinates are (11,10)

76274.

2+3-13 and 5-3-1 then find 'xy5 3-1 then find 'xyc y) Ir

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76275.

Find the area of a circle if r = 7andπ-l.Area of a circle is given by7ttho folloing exnress

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Area=pie*r*r=22/7*7*7=154

76276.

9. Find the sum of first 8 mulbples of 310. Find the ratio in which P(4. m) divides the line segment joining the points A(2, 3) and B6, -3) Hence find m

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76277.

hiogctslesshan-10.For the following statements, write True (T) or False (F). If the statement is fcorrect the statement.(a) -8 is to the right of-10 on a number line.(b)-100 is to the right of-50 on a number line.c) Smallest negative integer is-1.a-26 is greater than 25.

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76278.

(b) Solve the following inequation and write the sorunon13x-5 &lt; 15x +4 &lt;7x + 12, xERRepresent the solution on a real number line.

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76279.

16. A sum of t 700 is to be used to give seves cash prizes to udets of a scbol lior toverall academic performance If each prize is20 less than its proceding rizt, tndvalue of each of the pruzes

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76280.

' A Shopkeeper buys two bicycles for Rs. 750. He sells first bicycle at a profit of 22% andthe second bicycle at a loss of 8%. What is the SP of first bicycle if in the whole transactionthere is no profit no loss?

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Wrong answers

76281.

11The marked price of a T. V. Set is 50000. The shop keeper sold it at 15%discount. Find the price of it for the customer.EF 0001

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Answer for this question is ₹42500

The prize for the customer is=42500

42500 is a right answer 🇨🇮

42500 is the correct answer

76282.

A shop keeper sold an article for Rs.2564What was his profit prcent if the cost priceof the article was Rs. 2000?

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CP=2000SP=2564so profit=(2564-2000)/2000*100=28.2%

76283.

If four TV sets cost 1,12,000, how much will twenty-three sets cost?would it travel in 7 hours?

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1 tv set = 112000÷4

23 tv set = (112000 x 23)÷4 = 644000

76284.

many literate persons are there in the town.16. The cost price of 23 celour television sets is 570055. Determine the cost price of each TVset if each costs the same.

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570055/23=24785 is the answer

24785 is the right answer

76285.

o) A fruit vendor had 56 8 kg of pomegranate. He sold 32 5 kg and 18 15 kg of them in 2days, and bought 24 12 kg more. How much kg of pomegranate does he have now?

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76286.

Convert into gram:1/4 kg(b) 1/8 kg(c) 3/10kg(a)-10

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thank u sir

76287.

Thrs whof#cricket imams buys 7 bats and 6 balls for r 3800Lair she buys hts sad

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Let the cost of each bat be x and cost of each ball be y

Then,As per given condition

7x + 6y = 3800......(1)3x + 5y = 1750......(2)

Multiply eq(1) by 5 and eq(2) by 635x + 30y = 19000.....(3)18x + 30y = 10500.....(4)

eq(3) - eq(4)17x = 8500x = 8500/17 = 500

Put value of x in eq(1)7*500 + 6y = 38006y = 3800 - 35006y = 300y = 300/6 = 50

Therefore, cost of bat = Rs 500cost of ball = Rs 50

76288.

AP:-11, -7, -3,...., 45IFind the middle term of the AP: -11, -7, -3,,. 45.

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For AP - 11, - 7, - 3,........, 45a= -11 a2= -7a3= -3d= a2- a= -7+11= 4also = a+ (n-1)d45 = -11+(n-1)445 = -11 + 4n-445 = 4n-1545+15 = 4n60 = 4nn = 15

So, It means the Given AP have odd no. of terms so, the middle term is the 8th termapplying the formula as:-= -11 + (8-1)4=-11 +28=17 So the middle term is 17

76289.

Find the middle terms in the expansions ofio.r7.

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tqsm 😘

76290.

- ’%&amp;n.bDLtht b0 000 cter o दि ला .; Gzt of So0p Coch fo. eoL paoget 0F [yQo panfut लग0 ८ लाल 0 ८

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CP of both fans =Rs 3000×2=Rs6000.

SP of one fan at a profit of Rs 500 = Rs(3000+500)=Rs3500.

SP of 2nd fan = Rs3000 +(5%of3000)=Rs 3000+(5/100×3000)=Rs3000 + 150=Rs 3150

Total SP =₹(3150+3500=)=₹6650

So profit =₹(6650-6000)=₹650

Therefore profit %=(₹650/₹6000×100)%=10.83%(approx.)

Hit like if you find it useful

76291.

e integer which is1. Using the number line write the integer(a) 3 more than 5(b) 5 more than 5(c) 6 less than 2(d) 3 less than-2number line and add the following inte

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OK is the correct address

1) 3 more than 5=3+5=8; b)5 more than -5=5-5=0; c)6 Less than 2=6-2=4; d)3 less than -2=3-2=1

option C is the correct answer

76292.

2. Write the number which is :(a) 30,000 less than 4,56,38,396.(c) 600 more than 3,254, 540.(e) 700 less than 4,68,600.3. Fill in the blanks:

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(a) 45638396 - 30000 = 45608396

(b) 3254540 + 600 = 3255140

(c) 468600 - 700 = 467900

76293.

Lyman series:2=R

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In physics and chemistry, the Lyman series is a hydrogen spectral series of transitions and resulting ultraviolet emission lines of the hydrogen atom as an electron goes from n ≥ 2 to n = 1 (where n is the principal quantum number), the lowest energy level of the electron.

76294.

A shopkeeper buys two TV sets of same type he sells one of them at a profit of 20% and other at a loss of 5% if difference in selling price is rupees 700 find cost price of each TV set

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Let the cost of one TV set be x.

Find the selling price of the one that was sold at a profit of 20%:

profit = 20% of x = 0.2x

Selling price = x + 0.2x = 1.2x

Find the selling price of the one that was sold at a loss of 5%:

Loss = 5% of x = 0.05x

Selling Price = x - 0.05x = 0.95x

Solve x:

Difference in the selling price in term of x = 1.2x - 0.95x = 0.25x

Difference in the selling price = ₹700 (Given)

0.25x = ₹ 700

x = 700 ÷0.25

x = ₹ 2800

Answer: The cost price of a TV set is ₹ 2800.

76295.

A shopkeeper buys two TV sets of the same type he sells one of them at profit of 20% and other at a loss of 5% if difference in selling prices is rs700 find cost price of each TV set

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76296.

A shop keeper sold two TV sets at 9, 900 each. He sold one at a proat a loss of 10%. On the whole whether he gets profit or loss. If so wthof 10% and the o

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76297.

If four tv sets cost Rs. 112000. How much will twenty-three sets cost?

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76298.

A vendor purchased eggs at R 16 per dozen and soldthem at 10 for 18. Find his gain or loss per cent?13.

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Let the no of bananas be bought xso total cost price = 16x/12 = 4x/3so total selling price 18x/10 = Rs 9x/5

we see that Selling price is more than cost price so

The gain percentage = (9x/5 - 4x/3)/4x/3 x 100 = 35 %

76299.

11. If the price of 2 kg almonds is equal to the price of 8 kgwalnut and the price of 5 kg almonds and 16 kg walnut is1080, then what is the price per kg of almonds?

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Let the cost of 1 kg of Almond = Rs x

and the cost of 1 kg of walnut = Rs y

therefore, 2x= 8y

= > x = 8y/2 = 4y

= > 5 kg of Almond = 5 (4y) = 20y

5kg almond and 16 kg of Walnut is Rs 1080

=> 20 y + 16 y = Rs 1080

= > 36 y = Rs 1080

=> y = 1080/36 = Rs 30

=> 1 kg almond = 4 kg of walut = Rs 30 * 4 = Rs 120

Therefore, the cost of 1 kg of almond = Rs 120

76300.

8. Nihaal bought 20kg.of rice at18per kg andtwo|25kg of rice at 16 per kg. He mixed thevarieties and sold the mixture at 12-per kg. | 21.Find his gain per cent in the whole transaction.

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