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wood will float as it is having low density

The usual value used in calculations is 1 gram per milliliter (1 g/ml) or 1 gram per cubic centimeter (1 g/cm3

Circumference = 2πr = 176π = 22/72πr = 44r/7 = 176r = 7 x 176 / 44r = 28mSince, the road is 7m wide and a fence is to be put on the outer boundary, the new radius (r) becomes 7 + 28, which is 35m.Therefore, circumference = 2 x π x 35= 2 x 22 x 35 / 7= 2 x 22 x 5= 220mThe rate of fencing is Rs.21 per mThus, the cost of fencing = 21 x 220= Rs.4620

thanx bro

Area of circular park = pi*r*r

Given r = 84/2 = 42 m

Area of circular park Ap= 22/7*42*42= 22*6*42

Area of park including road Ar= 22/7*45.5*45.5= 22*6.5*45.5

Area of road = Ap - Ar= 22(6.5*45.5 - 6*42)= 22(295.75 - 252)= 22*43.5= 957 m^2 or 9570000 cm^2

Cost of constructing the road = 9570000*20= Rs 1,91,400,000

quick

second number correct answer hai

Ans 1 (a) 6000 rupees,(b)2000 rupees,(b) 1000 rupees

Your correct answer is(a)-- 6000(b)---2000(c)---1000

6000, 2000, 1000 is the correct answer of the given question

6000, 2000, 1000 is the correct one

ΔABE is a right triangle, right angled at B

AB²+BE² = AE²……………..(1)

(by the Pythagoras theorem)

ΔDBC is a right triangle, right angled at B

DB²+BC² = CD²…………….(2)(by the Pythagoras theorem

Adding eq 1 & 2

AE²+CD²= (AB²+BE²)+(BD²+BC²)

AE²+CD²= (AB²+BC²)+(BE²+BD²)......(3)

[Rearranging the terms]

ΔABC is a right triangle,

AB²+BC² = AC²…………….(4)(by the Pythagoras theorem)

Δ DBE is a right triangle

DB²+BE² = DE²………………(5)

(by the Pythagoras theorem)

AE²+CD²= (AB²+BC²)+(BE²+BD²)

AE²+CD²= AC²+DE²

7 and 75 have no common factors.So, 7 and 75 are co-prime

Hence, 75 = 3*5^2

Denominator = 3*5^2

Denominator is not of the form 2^n*2^m

Thus, 7/75 is non-terminating repeating decimal expansion.

2% of 36 is 2×36/100=0.72

Number indicated by point B is - 2½

thank you

H. r/4 = 200/4 = 50

I. r/2t = 200/2*10 = 200/20 = 10

J. st/2.8 = 28*10/2.8= 10*10 = 100

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90° is made at 3am,3pm,9am,9pm

1 days = 24 hours. 365 days = 24×365 = 8760 hours.

48.632 , 48.623 , 48.362 , 48.236

how did you find the answer can you explain me

see in all the four terms Left Hand term after the decimal are same that is 48. So we have see the digits which are on the R.H.S of the decimal side. since 46.632 is the highest among the four and 48.236 is the lowest among the four descending order would be 48.632, 48.623, 48.326, 48.236.

0.632>0.624>0.326>0.236

Total buying price of two horses = (40000*2) = 80000

Total selling price of two horse = (80000 - 3600) = 76400

Selling price of the first horse = (40000 * 115)/100 = 46000

Hence, Selling price of the second horse = (76400 - 46000) = Rs 30400

draw a line PQ.Take point M outside it.Through M draw two arc on line.Through the two arcs take convenient radius and construct a perpendicular bisector

First draw a line segment of any measures. Mark a point out of the line and name it has m.through m draw two arcs and construct a bisector

what should be the answer 87.12m2 or 95.04m2

Thank you for helping me

let the number be x.

x+2÷3*x = 70

3x+2x÷3 = 70

5x÷3 = 70

5x = 210

x = 210÷5 = 42

42 is the answer

12181710, 793451, 541039, 68888

for calculating amount of food in each boxtotal weight/no of boxes3600/12300pounds of food.

Aman : Ashok = 3 : 5 % of Aman = 3*100/8 = 37.5 % of Ashok = 5*100/8 = 62.5

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Let total distance covered be DTotal time taken= 84min= 7/5 hrsTime taken= distance./ speed2D/3(4) +D/ 3(5) =7/5(10D+4D)5= 21(20)70D= 420D= 420/70D= 6Therefore total distance covered = 6km

L.H.S.=1+cot^2x=1+cos^2x/sin^2x =(sin^2x+cos^2x)/sin^2x =1/sin^2x=cosec^2x=R.H.S.Hence Proved

1)-15, -10, -9, 0, 3, 4, 7 ; 2) -15, -7, -1, 0, 6, 20, 23

Let the two zeroes be a and b. Then, x²-(a+b)x + ab =0=> x² - √2 x +(1/3) = 0

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