InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 76951. |
14. Prove that a diagonal of a parallelogram divides it into two congruent triangles |
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Answer» tqu |
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| 76952. |
cmx 10em/How many tiles will be requtred to cover a vwall13. A marble tile measures 12 cm x 10km/How many tiles will be required to cover a wall ofsize 4 m by 3 m? Also, find the total cost of the tiles at t 22.50 per tile. |
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| 76953. |
Define anglef deviation. List the factors on which the angle or deviation ihmigl a nist drai t |
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Answer» The angle of deviation through a triangular prism is defined as the angle between the incident ray and the emerging ray (angle δ). It can be shown that when the angle of incidence i is equal to the angle of refraction r' for the emerging ray, the angle of deviation is at a minimum. The deviation angle in a prism depends upon: Refractive index of the prism: The refractive index depends on the material and the wavelength of the light. The larger the refractive index, the larger the deviation angle. Angle of the prism: The larger the prism angle, the larger the deviation angle. |
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| 76954. |
rate of interest.A sum of money lent at simple interest amounts to 783 in 2 years and to 837 in 3 yearsFind the sum and the rate per cent per annum.t mounts to4745 in 3 years and to 5475 in |
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| 76955. |
In Δ PQR, right-angled atsin P, cos P and tan P.5cm. Determine the values of.Q,PR+QR-25 cm and PQ |
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Answer» where 50 came from??? |
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| 76956. |
15. The sum upto n terms of an A.P. is n2. Find the commonİfference, what term is 59 ?W.B.U.T 2009] |
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| 76957. |
25. PQR is an isosceles triangle inscribed in a circle withcentre O such that PQ PR 13 cm and QR -10 cm. Findthe radius of the circle. |
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| 76958. |
Adjecent diagram is Rectangle PQRS where / (PS) I (QR) 7 cm. A semicircle withcentre C' is drawn as shown. Radius of semi circle is 7 cm. then area of the markedportion will be?(1) 77 cm(2) 31 cm2(3) 25 cm2(4) 21 cm2 |
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| 76959. |
6.In the given figure, PQ-8 cm and A is the mid-point ofPQ. Find AB. |
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| 76960. |
(SSC COL Mains Exam 201640.PQ and RS are commontangents to two circlesintersecting at A and B. ABwhen produced both sides,meet the tangents PQ and RSat X and Y, respectively. If AB3 cm, XY 5 cm, then PQ (inem) will be |
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Answer» please let me know if you have understood it or not thanks |
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| 76961. |
(1) On a number line the coordinates of two points P and Q are-8 and-3respectively. Find d(P. Q) |
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| 76962. |
38. A diagonal of a parallelogram divides it into two congruent triangles. |
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Answer» Given:- A parallelogram ABCD and AC is its diagonal . To prove :- △ABC≅△CDA Proof :- In△ABC and△CDA,we have ∠DAC =∠BCA [alt. int. angles, since AD| | BC] AC = AC [common side] And ∠BAC=∠DAC[alt. int. angles,since AB| | DC] ∴ By ASA congruence axiom, we have △ABC≅△CDA Hope it helps you |
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| 76963. |
How many cuboids of size 4 cm x 3 cm x 2 cm can be made from a cuboids12 cm x 9 cm x 6 cm? |
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Answer» 4CM x 3cm x 2cm = 24 cms, 12CM x 9 cm x 6 cm =12×54=62+48=648cm 24 x 24 x 24 = 12, 824, 12x9x6=108×6=648=(2)^3×(3)^3 ×3 648 I rightMay this help you 12cm×9cm×6cm________________ =27cm4cm×3cm×2cm when we will divide the volume of bigger and smaller cuboid you can get answer. answer is 942 |
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| 76964. |
18. Two concentric circles are of radii 5 cm and3 cm. Find the length of the chord of the largercircle which touches the smaller circle. |
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| 76965. |
A sum of money invested at 8% per annum for simple interest amounts2 years. What will it amounts to in 2 year 8 months at 9% rate of interest?In vars=650 amounts to8810 |
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Answer» how long will it take for a sum of rupees 12600 in invested at 9 percent per annum become to rupees 15624 aacha he hai bhai pasand aaya mujhe thnks |
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| 76966. |
10. In Δ PQR, right-angled at Q, PR + QR-25 cm and PQ-5 cm. Determine the values ofsin P, cos P and tan P. |
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| 76967. |
Find the sum of the following G.P upto n terms0.6 +0.66 +0.666+... |
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| 76968. |
2. In Fig. 7.48, sides AB and AC of Δ ABC areextended to points P and Q respectively. Also,Z PBC< QCB. Show that AC> AB |
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| 76969. |
ht-angled at Q, PR+QR 25 cm and PQ-5 cm. Determine the values ofIn A PQR, rigsin P, cos P and tan P. |
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| 76970. |
What is the condition required to make given triangles congruent by SAS congruence condition,if already given AB PQ 5 cm and AC PR 7 cm.8.CQ |
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| 76971. |
In the Fig. given below sides AB and AC of AABC are extended to points P and Q respectively.Also LPBC = <QCB. Show that AC> AB.2. |
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| 76972. |
Sole ore geometrical figures.rea of a square whose perimeter is 164 cm. Express the area in squaremetres. |
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Answer» perimeter= 4* side164=4* sideso value of side will be 41 cmnow the area of a square is side * sideso 41*41 = 1681 cm^2 will be the answer |
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| 76973. |
How many silver coins, 1.75 cm in diameter and of thickness 2 mm, must be melted to forma cuboid of dimensions 5.5 cm x 10 cm x 3.5 cm? h 0 0 |
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| 76974. |
16. Find the area enclosed between two concentric circlesof radii 3. 5 cm and 7 cm. A third concentric circleis drawn outside the 7 cm circle so that the areaenclosed between it and the 7 cm circle is the sameas that between the two inner circles. Find the radiusof the third circle, correct to one decimal place.Take Ď =(ICSE)17 4niuo |
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Answer» thanks.... |
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| 76975. |
TUUThe surface area of a ( 10 cm x 4 cm x 3 cm) brick |
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Answer» 120cm is the surface area surface area of the brick= 2[(10*4)+(4*3)+(3*10)=2(40+12+30)= 2×82=164cm3 |
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| 76976. |
If the radii two concentric circles are 12 cm and 8 cm. Find the areabetween the two circles. |
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| 76977. |
Wher we ope a dicot seed then its embryo shows two pars. Name these twofunctions.partsandwriet |
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Answer» When we open a dicot seed,then it's embryo shows two parts namely:1) Radicle - It grows into roots {Future Root}2)Plumule - It grows into shoots {Future Shoot} |
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| 76978. |
12, The four walls of a room-6 m long, 3 mmbroad and 3.5 m high are to be painted. Ifthe rate of painting is 650 per m2, find thetotal cost of painting. |
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Answer» Given,Length of wall l = 6m, Breadth b = 3m, Height h = 3.5m Area of four walls of room= 2(l*h + b*h) = 2(6*3.5 + 3*3.5)= 2(21 + 21/2)= 2(42 + 21)/2= 63 m^2 Therefore, total cost of painting = 63*650= Rs 40,950 |
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| 76979. |
Select the correct option corresponding to the sumof series upto n terms, given by S=+5. (3)3.5 5.7(37.9 (2n +1) (2n+3)is equal to7. If(2)2(2n +3)3(3n + 2)3(2n +3)2(3n + 2) |
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Answer» 3) option is correct |
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| 76980. |
a + ( a + d ) + ( a + 2 d ) + \dots \text { upto } n \text { terms } = \frac { n } { 2 } [ 2 a + ( n - 1 ) d ] |
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| 76981. |
( 4 \times 10 ^ { 3 } ) + ( 2 \times 10 ^ { 2 } ) + ( 3 \times 10 ^ { 1 } ) + ( 5 \times 100 ) |
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Answer» 4000+200+30+5 = 4235 |
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| 76982. |
(a) Find the height of a mountain, if the elevation of its top at an unknown distance from the base is 30and at a distance 10 km further off from the mountain, along the same line, the angle of elevation i15° |
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Answer» Thnxx.. I did get 5 m However the answer given was 5.04 thus I have my doubt clarified thnxx for your help.. One query though how did the the second line have a denominator as: 1 + tan 45* tan30?? |
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| 76983. |
Construct a quadrilateral PQRS, given that PQ 5 cm, RS 4cm, PS 8cm, PR 10cm and7cm. Measure the fourth side |
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Answer» thank you let god bless you |
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| 76984. |
3) Construct a quadrilatiral ABCD in which sides ABAC= 6.5cm. Draw diagonal BD and measure it.BC = 4cm, CD = AD = 5cm and diagonal |
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| 76985. |
2) Show that 5+ /5 is an irrational num |
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| 76986. |
206Universal iaimemu3. Find the side of a square tile whose perimeter is 176 cm.nnt in scal a hex in the shape of a regular octagon of side 15 cnm |
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Answer» 😰 perimeter =4×side 176=4×side176/4=side44 cm =side |
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15 m13. Top surface of a raised platform is in the shape of a8 mregular octagon as shown in adjoining figure.Find the area of the octagonal surface. |
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| 76988. |
EXEAC5E 12(b)l1. Find the area of a:regular pentagon ABCDE of side 5 cm and AD- BD-4 cm. |
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Answer» thank you you for giving the answer you really nailed it thank you thank you thank you thank you thanks a lot hundred times thank you |
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| 76989. |
How many planks of dimensions (5 m X25 cm X 10 cm) can be storin a pit which is 20 m long, 6 m wide and 80 cm deep?1 |
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| 76990. |
7. The Fig.shows two concentric cirdles with centre O. AB and APQ are tangents tothe inner circle from point A lying on the outer circle. If AB-75 em then AQ is equalto :56.(C) 12 em(D) 10 em(A) 18 em(B)15 cm |
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| 76991. |
Find the sum of the series 1 +3 +5+7+... upto n ternSolution |
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Answer» Sum will be because this is an Arithmetic serieswith a = 1 and comman difference = 2n/2 [2a+(n-1)d]n/2[2+(n-1)2]n/2[2+2n-2]n/2*2nn^2 |
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| 76992. |
-2 310. If A- 45 and B7 3,find a matrix C such that7 3 ,find a matrix C such that1 -6A + B-CO. |
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Answer» karna desai aap ne second step me +4 ko -4 kr diya h gor kijie wese dhanvad |
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| 76993. |
If two sides of a triangle measure 4cm and 6cm find all possible measurements (positiveIntegers) of the third side. How many distinct triangles can be obtained? |
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Answer» All possible measurement for the third side are 3cm, 4cm, 5 cm, 6 cm, 7 cm, 8 cm and 9 cm.Total 7 triangles can be obtained.sum of two sides is always greater than 3rd side.a=4b=6c= numbers we leta+b>cb+c>ac+a>b |
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| 76994. |
four xational num |
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| 76995. |
ace of a raised platform is in the shape ofa regular octagon as shownthe figure. Find the area of the octagonal surface.10. There is a pentagonal shaped park as shown in the figureFor finding its area Jyoti and Kavita divided it in two different ways.30 m15 m5111Joyti's diagramKavita's diagramFind the area of this park using both ways. Can you suggest some other wayof finding its area? |
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| 76996. |
There is a hexagon MNOPQR of side 5 cm .Aman andRidhima divided it in two different ways |
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| 76997. |
(१) लिंडुसो (7, 5) सने (2, 5) चय्येलु संतर कर कप) (M-07, J-07, M-10)(A0 (BY7 (८१5 (B2 s e 2 |
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Answer» √(2-7)^2+(0)^2√255 |
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| 76998. |
[CBSE (D) 2010)1. Find the zeroes of the following quadraticpolynomial and verify the relationship between zeroesand their coefficient :(1) 372x2 + 13x + 62 (ii) 415x2 – 17x – 3/5[CBSE Sept. 2010]. 11of the |
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Answer» 3√2 x² + 13 x + 6√2= 3√2 x² + 9x + 4x + 6√2= 3x(√2 x + 3) + 2√2(√2x + 3)= (√2x + 3)(3x + 2√2) Zeroes of the polynomial:(3x + 2√2) = 0⇒ x =2√2/3(√2x + 3) = 0⇒ x =-3/√2Sum of the roots = 2√2/3 -3/√2 = -13/3√2Product of the roots = 2√2/3 × 3/√2 = 2 Sum of the roots = -b/a = -13/3√2Product of the roots = c/a = 6√2 / 3√2 = 2. 3√2x^2 + 13 X +6√2. = 3√2x^2+9x + 4x + 6√2. =3x( V2x +3)+ 2V2( V2x +3) (3x + 2V2)( V2x + 3); 3x = -2V2; x = -2V2/3; V2x = -3; x = -3/-V2 = 3/V2 |
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| 76999. |
6. The area of a trapezium is 35 sq. em and the distance between theparallel sides is 10 em. If one of the parallel sides is of length 5 cm.Find the length of the other.35 cm2Hint : Here, area (bi + b2) h. Thus, 35-or 70 5010b2, solving b2 cm](5+ b2) x 105 cm20 |
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| 77000. |
o5. A man carns T18.000 per month. He spends®sof his tncome on househiold tems and 3 ofSorn household e o i3 income on other expenses. Tind s monthly saving, |
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