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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 77401. |
u vweEk.3. Archana requires 255 ml of milk every day. How much milk did sheconsume in November? |
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Answer» Daily milk require = 255 mlIn November no. Of days = 30Milk consume in November= 255*30= 7650 ml= 7lit 650ml |
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| 77402. |
3. Find the length the wooden strip required to frame a photograph whose length and breadth are6.2 m and 5.9 cm respectively. |
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| 77403. |
.Find the area of the rectangle whose(i) length = 42.5 cm, breadth = 15.6 cm(ii) length = 29 m, breadth = 13 m1 cale fertele whose |
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Answer» area of rectangle _ Length × breathso'42.5×15.6CM so multiple both number |
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| 77404. |
6.Thé surface area of a sphere is 154 cm?. The volume of the sphere is(A) 179 c(B) 359 cm(C) 1434-c㎡(D) of the7. In a shower 5 cm of rain falls The |
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Answer» Answer:A)1792/3 cm2Explanation: |
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| 77405. |
5. Is it possible to design a rectangular mango grove whose length isand the area is 800 m2? If so, find its length and breadth.INCERT] |
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Answer» thanks |
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| 77406. |
Find the volume of 20 ice cubes, each of side 5 cmSwati's almirah is 80 cm long, 40 cm wide and 90 cme volume of the almirah?If cvolume of a wooden plank is 33,750 cu. cmcm in length, 15 cm in width and 5 cm in heightoden plank, how many pieces of cuboids can be che |
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| 77407. |
8. Find the length of the longest pole that can be placed in a room whose length, breadth and height20 m, 20 m and 10 m respectively. |
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Answer» longest pole or we have to find the HCF of 20,20 and 10so it will be 20= 2*2*520=2*2*510= 2*5so longest pole will be of 10 m |
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| 77408. |
ships for underwater rocks, a lighthousea red coloured light over a sector of angleistance of 16.5 km. Find the area of the sea12. To warnver which the ships are warned. (Use3.1 |
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| 77409. |
MATHEMATICSC is the mid-point of PO if P is (4. x). C is 0,-1) and Q is (-2, 4), then x and yrespectively are3.6 and 14. 6 and -22.-6 and 21.-6 and 113 and 16 3) then the value of y. |
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Answer» Answer: -6&1Explanation |
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| 77410. |
wy1609/Find the perimeter of the parallelogram PORS, where PO SR = 12 cm and QRISFind the anple of measure x in the fique |
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Answer» 90° is x angle ..this shape is rectangle |
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| 77411. |
Section- E2x8 = 16Four points P.QR and S are such that PR = QS. Is po-RS? Justify it and also statethe Euclid's postulate or axiom used here11. |
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| 77412. |
dnsnaretheages(inyears)of360patients,gettingmedicaltreatmentinahosswerlowing(inyears)ㅡㅡ 10-20 20-301 30-40 40-501 50-6이 60-70Nunber of patients 90Fo5060805030the cumulative frequency table for the above data |
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| 77413. |
In the given figure, POR PRS. IF PR = 6 cmand PS = 2 cm, then PO is equal to(m) 12 cm() 18 cm(b) 16 cm(d) 20 cm |
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Answer» angle pqr=PRS( given)pr=pr(common)triangle pqr is congurent to triangle PRS by sa criteriapr÷pq=ps÷pr6÷pq=2÷6pq=6×3=18 |
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| 77414. |
A soft drink is available in two packs - (i) a tin can with a rectangular base of length5 cm and width 4 cm, having a height of 15 cm and (ii) a plastic cylinder with circularbase of diameter 7 cm and height 10 cm. Which container has greater capacity and byhow much?3. |
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| 77415. |
70 patients in a hospital consume 1350 L of milk in 30 days. At the same rate, how many patients willconsume 1710 L in 28 days? |
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| 77416. |
,then range of f is2. Let A = [-5, 5]-(0) and f : A → R is defined by f (x) = |
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| 77417. |
Half the perimeter of a rectangular garden, whose length is 4 m more than its width, is 36 m. find the dimensions of the garden |
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| 77418. |
5. Half the perimeter of a rectangular garden, whose length is 4 m more than its width, is36 m. Find the dimensions of the garden. |
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| 77419. |
Half the perimeter of a rectangular garden, whose length is 4 m more than its width, is36 m. Find the dimensions of the garden.5.There |
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Answer» thanks |
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| 77420. |
Half the perimeter of a rectangular garden, whose length is 4 m more than its width, is16 m, Find the dimensions of the garden.5. |
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| 77421. |
y ^ { 2 } + \frac { 1 } { 3 } y = 2 \quad ( 6 ) 5 x ^ { 2 } + 13 x + 8 = 0 |
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| 77422. |
7. Int he figure if AB-Sem and PE 3em, then AE-a) 5 cmb) 5.5 cmc) 6 cmd) 7 cm |
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Answer» givenAB=8cm PE=3cm AB=ACandAC=AE+CE PE=CE=3cm AndAB=8cm alsoPD=BD ∴AE=AC−CE AE=8−3cm =5cm |
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| 77423. |
16. If AD and PM are medians of triangles ABC and PQR, respectively whereAB ADΔ ABC ~ Δ PQR, prove that POPM |
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| 77424. |
ICS (गणित) )15है+7:० ० ० ०1. दो समीकरण यमों: +7=0, ५-20 तथा ?-20,v+7= 0 के ग्राफीय हल द्वारा बनता है।(1) वर्गीय क्षेत्र(2) आयताकार क्षेत्र(3) त्रिभुजाकार क्षेत्र(4) समलंब क्षेत्र० ० ० ०1-96.0802. आकृति में 2CAB = 90°तथा ADL BC है। यदि AC=25cm, AB=1m तथा BD=96.08 cm हो तो AD कामान क्या होगा:(1) 23 cm257० ० ०(2) 98 cm(3) 24.02 cm |
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| 77425. |
Solve the given exponential equations.(16)*-?=1po(ii)34x =(ii)(12)* = 28(iv)22x + 1 = 42x- |
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| 77426. |
21 Find the number of metallic circular discs with 15 cm base diameter and height0-2 cm to be melted to form a circular cylinder of height 10 cm and diameter 4-5 cm. |
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| 77427. |
Some people of a society decorated their area withflags and tricolour ribbons on Republic day. Thefollowing data shows the number of persons indifferent age group who participated in thedecoration.19.Age (in years) 5-15 15-25 25-35 35-45 45-55 55-65Number ofPatients611 | 21 | 23 | 14Find the mode of the above data. |
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| 77428. |
Find the maximum distance between two points on the perimeter of a rectangular gardenwhose length and breadth are 100 metres and 50 metres?A. 100 m.4.B. 110 mD. 112.2 m |
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Answer» Option c is correct Explanation:Maximum distance is between two opposite pointsIt is the hypotenuse whose length is [(100)^2+(50)^2]^.5 = (10000 + 2500)^.5 = (12500)^.5 = 111.8m |
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| 77429. |
(x+ 2 x1I. 1. If the function f is defined by f (x) = 2 ,-15x31, then find the values|x-1,3<x<-1f (0),f (-1.5),$ (3),f (2)+ f (-2),f(-5) |
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| 77430. |
1 31 y 01 [5 60 x 1 2 8 |
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| 77431. |
Wpindxandy if[101[3]-[x]0 -14 |
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Answer» 1(3)+0(4)=xx=3 0(3)+(-1)(4)=yy=-4 |
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| 77432. |
Find the perimeter of:(a)5 cm6 cm7 cm |
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Answer» plus all the perimeter 6+7+5=18cm so ans is 18 perimeter of triangle =A+B+c=5cm+6cm+7cm =18cm perimeter of a triangle=5+6+7=18 5cm+6cm+7cm=18cmso, answer is 18cm triangle perimeter a+b+c hota hai to 5+7+6 18 5+6+7=18 answer is 5 + 6 + 7 plus is equals to 18 perimeter of triangle =sum of all sides =(5+6+7) =18cm 6+7+5=18cm ans .perimeters of triangle is 18 cm 18cm. h💝☯😘 https://media.tenor.com/images/1fe2aae9be541890daf791517424a87e/tenor.gifhttps://media.tenor.com/images/1fe2aae9be541890daf791517424a87e/tenor.gifhttps://media.tenor.com/images/1fe2aae9be541890daf791517424a87e/tenor.gifhttps://media.tenor.com/images/1fe2aae9be541890daf791517424a87e/tenor.gifhttps://media.tenor.com/images/1fe2aae9be541890daf791517424a87e/tenor.gifglohttps://media.tenor.com/images/05ca02c443932a0ac224a89445b8dae4/tenor.gifjjjhttps://media.tenor.com/images/e402cd1cc69917e54507cebca97e286b/tenor.gifhttps://media.tenor.com/images/e402cd1cc69917e54507cebca97e286b/tenor.gifnb. https://media.tenor.com/images/e402cd1cc69917e54507cebca97e286b/tenor.gifhttps://media.tenor.com/images/17807d685e2b91d76deb5b2a5889fd10/tenor.gifhttps://media.tenor.com/images/e402cd1cc69917e54507cebca97e286b/tenor.gifhttps://media.tenor.com/images/e402cd1cc69917e54507cebca97e286b/tenor.gif Perimeter of given triangle is 18cm 5+6+7=18because perimeter is sum of all sides 18 is a corract answer v=L W H/3 so 6into7into5/3 = 210 18 is the right answer 6+7+5=18 cm so answer is [18] 5+6+7 =18 so answer is 18 5+6+7 = 18 cm this is the write answer 5cm × 6cm × 7cm 30cm × 7cm 21 cm U can add all the sides of a triangle to get ur answer p= s+s+s =7 +6 + 5=18 perimeter of triangle =A+B+C=5cm+6cm+7cm=18cm perimeter of triangle=sum of all side =5+6+7 =18 18 cm perimeter of triangle :sum of all sides = 5+6+7=18 5+6+7=18 perimeter of a triangle so and 18 perimeter is 185+6+7=18 perimeter of a triangle= 5+6+7= 18 5 cm + 6 cm +7 cm = 18 cm 5 cm + 6 cm + 7cm =18 cm the ans 18 .. to add 3 sides of triangle 6+7+5 18cm so and is 18 the perimeter of the triangle = 18cm Perimeter=7+5+6=18 , perimeter=sum of all sidesi.e,5+6+7=18cm the primiter of triangle =sum of all edge=5+6+7=18 perimeter of triangle =7+5+6=18 perimeter of triangle is equal to sum of sidesthen 5+7+6 =18 cm 5+6+7=18 so the ans is 18 Perimeter of a triangle =Sum of all sides ?=5+6+718=5+6+7therefore, 18 is the answer the perimeter of triangle is =18 perimeter of triangle=a+b+c 6+7+5=18 perimeter of triangle =A+B+C=5cm+6cm+7cm=18cm perimeter of triangles = sum of side =(5+6+7) =18 the perimeter of triangle =A+B+C =5+6+7=18 Perimeter =sum of all sides=5cm+6cm+7cm=18cm perimeter of triangle =A+B+C =5cm+6cm+7cm=18 |
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| 77433. |
DELTA PO NOSDillenatale16) - x&#x2 +1 polith dispoot26de |
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| 77434. |
-Find the volume of the cuboids whose(0 1 15 cm, b 7 cm and h 6 cm(i) 1- 2.3 m, b 30 cm and h 7 cm |
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Answer» (i) 630m or 6.3cm,(ii)0.0976cm |
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| 77435. |
UIlIDe1ormedby these points?lsonsideAB,BC, CA respectively. HowA boxs contains two white, three black and four red balls. Determine the number of wayshich three balls can be selected from this box. In which at least one black ball iscompulsorye different coloured flags, taking one or more then ggiven?cos By 6bO |
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Answer» thanks |
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| 77436. |
xn-2nf(x) =1ベ.2,x,x=215)x-280 |
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| 77437. |
xn-1- when x + 1;Show that the function f(x) = 1 x-1n, when x = 1is continuous |
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| 77438. |
Question No. I to 50 have four options,option, on the OMR- Sheet(A)+k(C) xn+1 + kn-1(A) [1 0 01 |
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| 77439. |
There are 5 different balls and 3 different boxes, eachbox can hold all the five balls. Then the number ofdifferent ways these five balls can be placed in 3boxes such that no box remains empty is |
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Answer» there are 150 different ways these five balls can be replaced in 3 boxes such that no box remains empty. |
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| 77440. |
Tie angles of a Tange ase ta the balO s |
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| 77441. |
Estimate each sum to the nearest thousand:20. (32836 +16466)21. (46703 +11375)22. There are 54 balls in box A and 79 balls in box B. Estimate the total number of balls in boththe boxes taken together. |
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| 77442. |
If x1, x2, x3,.., Xn are the means of ngroups with ni, n2 ng, n number ofobservations respectively, then find themean x of all the groups taken together. |
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| 77443. |
70. If' mean 'x'mean'รท' mean '+' and '--'n1648ร6-2+12=?mean 'x', then |
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Answer» 16÷8x6-2+12If + = ÷, x=-, ÷=+, - = x Then equation become16 + 8 - 6 x 2 ÷ 12= 16 + 8 - 6x1/6= 16 + 8 - 1= 24 - 1= 23 ans |
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| 77444. |
1Find the number of ways of selecting 9 balfrom 6 red balls, 5 white balls and 7 blue ballsif each selection consists of 3 balls of eachcolour. |
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| 77445. |
- GOOD T10400)21. (46703 +11375)22. There are 54 balls in box A and 79 balls in box B. Estimate the total number of balls in boththe boxes taken together. |
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| 77446. |
20. (32830+10There are 54 balls in box A and 79 balls in box B. Estimate the total number ofthe boxes taken together.balls in both |
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| 77447. |
Ive the following equatio,natbtx20 |
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| 77448. |
her homework in8. Richa finished her homework in hours anfinished homework in longer time and by how muchMultiplication of Fractionhours and Sumit finished his homework inhours. Whe |
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Answer» 9/12 = 0.75 hours 3/5 = 0.6 hours difference = 0.75–0.6 = 0.15 hours Richa finished in longer time by 0.15 hours |
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| 77449. |
Lostulplastd A solid right circular cylinder of height 1.21 m and diameter 28 cm is melted and recast, hto 7 equal solid cubes. Find the edge of each cube.dug out to make a well 20 m deep and 2 |
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Answer» Volume of cylinder = pi*r*r*hGiven,r = 14 cm, h = 121 cm Volume of cylinder Vcy = 22/7*14*14*121 = 74536 cm^3 Volume of cube Vcu = (edge) ^3 According to the given condition7*Vcu = Vcy7*(edge)^3 = 74536(edge)^3 = 10648Edge = 22 cm |
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| 77450. |
In a survey of 450 people, it was found that 110 play cricket, 160play tennis and 70 play both cricket as well as tennis. How manyplay neither cricket nor tennis? |
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Answer» If 110 play cricket and of those, 70 play tennis and cricket, then 110 - 70 = 40 play cricket only. If 160 play tennis and of those, 70 play tennis and cricket, then 160 - 70 = 90 play tennis only. Finally, it is given that 70 play both cricket and tennis Hence, Sport playing people : 40 + 90 + 70 = 200 Therefore, Non-sport playing people : 450 - 200 = 250.250 people play neither tennis nor cricket. |
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