InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 77501. |
11) 5x = x+76 |
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Answer» 5x = x + 76 5x - x = 4x = 76 x = 76/4 = 19 |
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| 77502. |
MATHS| -2/3-5/7b)2/9-3/7| -7/1|1. Complete the tablea) X 4/93/5-5/11-8/13+6/7-9/11-12/11Indiannianul abiente ...the hole of coloured hardsheets |
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| 77503. |
29.5 question are asked in a question paper out of which 2 question can be solved by two-two methods, two question by three-threemethods and one question can be solved by one method; then the number of possible attempts to solve the question paper are(A) 25(B) 36(C) 144(D) 288 |
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Answer» 2 questions =(1*2)*(1*2)and another 2 questions (3*2)*(3*2)and last question 1 is with the one way so...2*2*6*6*1=144 144 is the right answer |
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| 77504. |
The phenotypic ratio for F2 generation in Incomplete dominance is |
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Answer» 1:2:1 When plants of the F1 generation are self-pollinated, the phenotypic and genotypic ratio of the F2 generation will be1:2:1(Red:Pink:White) for both generations. Co-dominance occurs when the contributions of both alleles are visible in the phenotype. |
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| 77505. |
CBSE[CLASS-X)MATHEMATICS.sin Asin BCOS Acos B11= p and= q , then tan A is equal to : |
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| 77506. |
\frac{\cos 15^{\circ}+\sin 15^{\circ}}{\cos 15^{\circ}-\sin 15^{\circ}} |
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| 77507. |
3. State whether the following quadrilaterals are similar or not:3 cmS 1.5 cm R3 cm3 cm1.5 cn1.5 cm1.5 cm3 cmFig. 6.8 |
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Answer» The given quadrilateral PQRS and ABCD are not similar because their corresponding sides are proportional ,i.e 1:2, but their corresponding angles are not equal. or we can say that PQRS is a rhombus and ABCD is a square, so they cannot be similar. |
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| 77508. |
1. Find the greatest number of 6 digits exactlydivisiblĂŠ by 24, 15 and 3612 C |
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| 77509. |
66863/76 |
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Answer» The answer is 879.776315789 your answer is 879.77631579 66863÷76=879.77 nice |
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| 77510. |
d) 3: 1:212. Ir A: B-1.3B.C-1,and C: D-53, then A: B: C:D-73 9b) 6:8:9:106 4a) 3:2:4:5c) 8:6:10:9 d) 2:3:4:513. Assertion (Ao |
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Answer» A : B = 1/2 : 3/8 = 4 : 3 = 8 : 6 B : C = 1/3 : 5/9 = 3 : 5 = 6 : 10 C : D = 5/6 : 3/4 = 10 : 9 A : B : C : D = 8 : 6 : 10 : 9 9_(_3)+6_2+(_5) |
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| 77511. |
exercise 2.5 question 15 |
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Answer» class is not mentioned |
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| 77512. |
the heignt o the coORCBSE 2001011. A spherical ball of radius 3 cm is melted and recast into three sphericalballs. The radii of two of these balls are 1.5 cm and 2 cm. Find the radiusof the third ball. |
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| 77513. |
2x4 8x343x22x + 35EXERCISE 6EİİUse Cordova Smart Class software on the smartFind the product of the following binomials : (1 to 10)2. (2a -b) (4a - b)1, (5a + 3b) (3a-5b) |
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| 77514. |
, Aof the two of the balls are 15 cm and 2 cm respectively. Deternthird ball.sphericalball of fadius 3 cm is melted and recast into theemine the diaical ballsthe diameter of thevely. De |
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Answer» Radius of ball which is melted = 3cm Radius of first formed ball = 1.5 cmRadius of second formed ball = 2 cmLet Radius of third formed ball = r cm Volume of large ball = sum of volume of 3 formed balls⇒4π/3 × 3³ = 4π/3(1.5³ + 2³ + r³)⇒ 3³ =1.5³ + 2³ + r³⇒ 27 = 3.375 + 8 + r³⇒ r³ = 27 - 8 - 3.375 = 15.625⇒ r = ∛15.625⇒ r = 2.5cm ∴Radius of third ball is 2.5cm |
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| 77515. |
e if the following are in proportion.Determi15, 45, 40, 120 (b) 33, 121,996 (c) 24,28, 36, 48(d) 32, 48, 70, 210 (e) 4,6, 8, 12 33,44, 75 199 |
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Answer» nice |
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| 77516. |
Time taken by thes flightZDmmSo, the flight will reach Gne at 95 mya plays for 1渤30 min m the mommu ant 45 mm mtieereems does Aditye play in a day?i attends school from B:00 am. to 1230 pm. For how maard the schoo? |
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Answer» Total hours = 1 hr 30 min + 45 mim = 2 hr 15 min |
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| 77517. |
23 I+4(3612)] |
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| 77518. |
2 4 6 83'6'9'12 are(a) like fractions(c) equivalent fractions(b) irreducible fractions(d) none of these |
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Answer» thanks option c is the correct answer of the given question a like fractions |
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| 77519. |
45 and 75 write their equiralentfractionswith13and 76 write their equivalent fractions with samedenominators and add the fractions. |
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Answer» equivalent fraction is =1 13+2245+75 =13=13 x 22. = 286 45=45. 75. =3375so, |
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| 77520. |
find the following divisions method perform the following divisions (9x^2 -4)÷(3x+2) |
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| 77521. |
Findthevaluesofty, z,t for whichthematrices15-y y-landt:;+t]mayz- tbe equal. |
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| 77522. |
3-1Two spherical balls of 6 cm diameter are melted and cast into a conical shaped vessel with a base of 12cm diameter. The height of the vessel is:(C 3.5 cm(D) 6 cm |
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Answer» please like my answer if you find it useful |
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| 77523. |
ExerciseUse Cordova Smart Class Software on the srmplete the following skip counting in 100s:8690, 87.90., 58.9.... 8992735, 27.3.5.... 2935 , 3024381234, 1334, 34...3. 4082, 4.9.83. |
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Answer» this is the right answer |
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| 77524. |
(Use Cordova Smaon the smart bdo this E12 436 |
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Answer» Adding 5/12 +1/4Take LCM of 12 and 4 which is 12= (5 + 3)/12= 8/12 = 2/3 ans |
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| 77525. |
15. How many cubic meters of earth must be dugout to sink a well 22.5 m deep and of dimeterAlso, find the cost of plastering the inner curved surface at Rs. 3 per square meter |
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| 77526. |
Ilse Cordova Smart Class Software on the smart board in class to do ExerciseFind five equivalent fractions of each of the following:(i)11 |
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| 77527. |
6. An article marked at800 is sold at a discountof 10%. Find its cost price if the dealer makesa profit of 20%. Also find the profit per cent ifno discount had been allowed |
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Answer» Discount of 10% on marked price=800*10%=80 Selling price=800-80=720 The dealer makes a profit of 20% means is selling the article at 120%. 120%=720 1%=6 Hence, 100%=600 Thus, the cost price of article= 600 If no discount allowed, Selling price will become 800 Profit= SP-CP= 800-600=200 Profit percent=(200/600)*100=33.33% Therefore, the profit percent when no discount allowed=33.33% thanks |
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| 77528. |
2.The bottom of a right cylindrical shaped vessel made fromcylindrical shaped vessel made from metallic sheetis closed by a cone shaped vessel as shown in the figure. The radithe circular base of the cylinder and radius of the circular base of the coneare each is equal to 7 cm. If the height of the cylinder is 20 cm and heightof cone is 3 cm, calculate the cost of milk to fill completely this vessel atthe rate of Rs. 20 per litre.7 cm20 cm |
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| 77529. |
ORolitma nce oftha mean Loc꾏-1-1313-156-1717-1991352 326i pr |
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| 77530. |
O. How many stamps measuring 3 cm × 2 cm can fit on a sheet of paper of size 10 cm × 6cm ? |
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Answer» area of sheet=l×b=10×6=60cmarea of stamp=l×b=3×2=6cmnumber of stamps =60/6=10 stamps can be pasted |
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| 77531. |
R346.50Example 22. A rectangular tank of water is 12 m long, 6 m wide and 2 mdeep. Find the cost of repairing its four walls and floor at the rate of? 15per square meter. |
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| 77532. |
Use Cordova Smart Clasd the discount per cent when:) M.P.-780 and S.P. =60M.P = 120 and S P =96 |
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Answer» m.p=80 s.p=60formula=s.p=m.p-discount 60=80-80×x\looans . will come |
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| 77533. |
. In a furniture shop, a cot and an almirah soldseparately for Rs. 15000 and Rs. 25000, are soldtogether for Rs. 36000. What is the discount percent in this deal? |
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| 77534. |
133. A shopkeeper sold a TV set for *17940, with adiscount of 8% and gained 19.6%. If no discount isallowed, then what will be his gain per cent? |
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Answer» Discount = 8% & S.P.= Rs.17,940 Therefore, M.P. = 17940/0.92 = Rs.19500 Now, gain % = 19.6% => C.P. = 17940/1196 = Rs.15000 MP - CP = Rs.4500 Hence gain % = (4500/15000) ×100 = 30% |
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| 77535. |
1. Three toys, each marked * 120, were sold for 315. What per cent discount wasgiven?(1) |
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| 77536. |
Chalienge!The sides of a triangle have lengths (in cm) 11, 7.5 and x, where x is a whole number. The mininvalue that x can take is(a) 6(b) 4(c) 3(d) 5 |
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Answer» In a triangle, sum of two side is always greater than the third side. Therefore, x+ 7.5 > 11 => x> 3.5 since, x is a whole number, therefore x will have minimum value as 4. Ans: Option B is correct |
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| 77537. |
A metallic right circular cone of height 9 cm andbase radius 7 cm is converted into a cuboid whosetwo sides are 11 cm and 6 cm. The third side ofthe cuboid will be |
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Answer» Volume will be same in each caseso( volume of cone = volume of cuboid)volume of cone = 461.58cm^3 1/3*π r²h = 11*6* third sidethird side = 461.58/66 = 6.9 cm |
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| 77538. |
ChaliengeThe sides of a triangle have lengths (in cm) 11, 7.5 and x, where x is a whole number. The minimvalue that x can take is(a) 6(b) 4(c) 3(d) 5 |
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Answer» the sum of two sides of a triangle is greater than the third sideso, 7.5 + x> 11=>x>11-7.5x>3.5so the answer is (b) 4 |
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| 77539. |
I f the mass of the object is 64 and density is 15kg/m^3 find the volume? |
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| 77540. |
poster of size 10 cm x 8 cm is pasted on a sheet of cardboard so that there is a margin1.75 cm along each side of the poster.of wi5AFind(a) Tho total area of the margin(b) The cost of the cardboard used at the rate of0.96 per cm. |
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| 77541. |
13, Theratioofdimensionsofacuboidalboxis2:3:4OX 1S 2:3:The difference between the cost of wrapping thebox at the rate of74 per square meter andper square meter is R 416. Find the dimensions ofthe cuboidal box.[Board Term II, Set-RQTZFBW, 2016] |
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Answer» Since the ratio of a cuboidal box are 2:3:4.So suppose the dimensions of cuboid box are 2x, 3x and 4x respectively.So total surface area of box =2(2x*3x+3x*4x+2x*4x)=52x^2Cost of wrapping the box at rate of Rs.4.50 per square metre =52x^2*4.50=234x^2And cost of wrapping the box at rate of Rs. 4 per square metre =5x^2*4=208x^2Now according to the question we have;234x^2-208x^2=41626x^2=416x^2=16x=4So dimensions of cuboidal box are(2*4),(3*4),(4*4)Therefore dimensions of box are 8 m, 12 m, and 16 m. |
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| 77542. |
Fig. 11.1710. The length, breadth and height of a room arerespectively 15.35 m, 4.65 m and 6.50 m. If thereare 4 doors of size 1.5 mx1.3 m and 3 windows ofsize 1.5 mx 1.2 m, then find the expenditure onwhitewashing the room at the rate of 3.40 persquare meter. |
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Answer» by by by mare dost by by by by OK yuhgrvcjfskndyhnvdtjnctibdtjbdthbcdun |
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| 77543. |
18. The centre of a citie i 21, 7) and i passes through the point -) if the diametere?the eirele is 20 units. Th. ŕš find the value(s) of: . |
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| 77544. |
A bag marked at Rs. 15,000 is available for Rs. 14,400. Find the discount given and the discount per cent. |
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| 77545. |
Q.8. The 6th term of an AP is zero. Prove that ts tella.9. The length of the line segment joining the points A (2.3) and B (10, y) is 10 units. Find thrive limes the 11 termy, if A and B are in different quadrants.2 tane |
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Answer» Distance=√(x2-x1)^2+(y^2-y1)^210=√(2-10)^2+(3-y)^2100=64+(3-y)^2(3-y)^2=36(3-y)=+-63-y=6y=-3and y=3-y=-6y=3 |
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| 77546. |
S.What is a regular polygon?State the name of a regular polygon of(i) 3 sides (ii) 4 sides ii) 6 sides11) 4 Sides |
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| 77547. |
The side of a regular polygon is 2.5cm. If the perimeter of the polygon is 15cm, then find the number of sides of the polygon. |
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Answer» regular polygon has all the sides equal. let the number of sides be n.perimeter = n x 2.5 cm=> 15 = n x 2.5=> n = 15/2.5n = 6 ans. |
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| 77548. |
. whatistheLET'S EVALUATEC How many bricks will be required for a wall which is 4.9 m long, g m bigh and 2.4 m thick if each brialmeasures 24 cm Ă 12.25 cm x 4 cm?tthe aal, the height of the water |
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| 77549. |
The outer diameter of a pipeis 70cm and it is 21m long.Find the cost of painting the outer surface of the pipeat the rate of rs.10 per square meter. |
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| 77550. |
A rectangular sheet of paper is 12- cm long and 10cm wi37 |
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