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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 77701. |
Example I1 : A hemispherical tank full of water is emptied by a pipe at the rate of 34litres per second. How much time will it take to empty half the tank, if it is 3m indiameter? (Take Ď -)7 |
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| 77702. |
421. A hemispherical tank full of water is emptied by a pipe at the rate of 3 litres per second. Howmuch time will it take to empty half the tank, if it is 3 m in diameter? |
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| 77703. |
4Example 11: A hemispherical tank full of water is emptied by a pipe at the rate of 3litres per second. How much time will it take to empty half the tank, if it is 3m indiameter? (Take |
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| 77704. |
A farmer mixes two brands A and B of cattle feed.Brand A, costing R 500 per bag, contains 6 unitsof nutritional element P, 5 units of element Q and4 units of element R. Brand B costing 400 perbag contains 3 units of nutritional element P, 25units of element Q and 6 units of element R. Theminimum requirements of P, Q and R are 36, 90and 48 units respectively. Determine the numberof bags of each brand that should be mixed inorder to produce a mixture having a minimumcost per bag. What is the minimum cost per bag?What is the minimum cost of the mixture perbag? |
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| 77705. |
526MATHEMATICsA farmer mixes two brands P and Q of cattle feed. B and P, costing Rs 250 perbag, contains 3 units of nutritional element A. 2.5 unis of element B and 2 unitof element C. Brand Q costing Rs 200 per bag contins 1.5 units of nutritionelement A. 11.25 units of clement B, and 3 units of clement C. The minimumrequirements of nutrients A. B and C are 18 units, 45 uns and 24 units respectivelyDetermine the number of hags of each brand which should be mixed in order tproduce a mixture having a minimum cost per bag' at is the minimum cost ofthe mixture per bag"2. |
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| 77706. |
20. A man bought two consignments of eggs, first at18 per dozen and anequalnumberat 20 per dozen. He sold the mixed egges atて23.25 per dozen. Find his gainpercent. |
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Answer» 4.75 paise profit per eggs..So 24*4.75=114 total profit. |
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| 77707. |
Os. How much money will you get back from a s00 rupee note if you buy 7 boxes of crayons cachXcosting 32.25? |
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Answer» Cost of 1 box=Rs32.25Cost of 7 crayons=7*32.25=225.75Amount left=500-225.75=274.25 |
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| 77708. |
A hotel has 26 tables and each table has either 2 or 4 chairs. If thereare 94 chairs to go with the 26 tables, how many tables haveexactly 4 chairs? |
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| 77709. |
egg.WhatisthesellingprieSudha bought eggs for 15 a dozen and sold it at ? 2.50 perdozen? And what is her gain or loss? |
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Answer» please like my answer if you find it useful all correct thankyou so much |
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| 77710. |
Make some more such patterns and as youQue.4 (a) Write a pair of integers whose sum gives: (i) -8 (i) O(b) Write a pair of integers whose difference gives: (i) - 10 (ii)2 .71 fiy) 19 x-1) (v) 6x (-19) |
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Answer» 4a)i)(-4)+(-4)=-8 ii)(-4)+4=0B)i)2-12=-10ii)2-2=0 |
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| 77711. |
a + 0 = 0 = 0 + aTRY THESE1. Write a pair of integers whose sum gives(a) a negative integer(e) an integer smaller than both the integers.(e) an integer greater than both the integers.(b) zero(d) an integer smaller than only one of the in |
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Answer» Negative = -5+-5 = -10 Zero will get = -5 + 5 = 0 |
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| 77712. |
1. Write a pair of integers whose sum gives(a) a negative integer(b) zero(c) an integer smaller than both the integers. (d) an integer smaller than only one of the integer(e) an integer greater than both the integers.2. Write a pair of integers whose difference gives(a) a negative integer.(b) zero.(c) an integer smaller than both the integers. (d) an integer greater than only one of the integer(e) an integer greater than both the integers. |
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Answer» gxxhjhxseyhvcdeujjbxddryuhbcxdt send questions one by one so you will get good answers and also like my answer 1.(a).-5 and -4 (b).-2 and 2 (c). -3 and -2 (d).-2 and 1 (e). 2 and 5 a)-5+4=1b)-5+5=0c)-5+3=2d)-5+4=1e)3+4=7 |
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| 77713. |
Questien mambers 23 to 30 carry marks edel23 Speed of a boat in still water is 15 km/h. It goes 30 km upstream and returns back at the samepoint in 4 hours 30 minutes. Find the speed of the stream. |
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| 77714. |
(b) zero(d) an integer smaller than only one of the integer1. Write a pair of integers whose sum gives(a) a negative integer(c) an integer smaller than both the integers.(e) an integer greater than both the integers.2. Write a pair of integers whose difference gives(a) a negative integer.(c) an integer smaller than both the integers.(e) an integer greater than both the integers.(b) zero.(d) an integer greater than only one of the integer |
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Answer» -5+4=-1-5+5=0-5+-5=-10-5+4=-13+4=7 |
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| 77715. |
2. Write a pair of integers whose difference gives(a) a negative integer.(b) zero.(c) an integer smaller than both the integers. (d) an integer greater than only one of the integg(e) an integer greater than both the integers. |
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Answer» (1)-12+5=-7(2)5-5=0(3)-4-3=-1(4)-4-1=-3(5)-12-13=1 a) -2-4=-6b)-2+2=0c)4-3=1d)4-2=2e)6-(-4)=10 |
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| 77716. |
Anil changed 10 rupee note into coins.If all the coins are 25 paise coins,how many coins he has now? |
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Answer» We know,One rupee = 100 paise 10 rupees = 10*100 = 1000 paise Therefore,Number of 25 paise coins equivalent to 10 rupee note= 1000/25= 40 coins 1 rs. 100 paisethenin 1 ra. 4 coin of 25 paiseso in 10 rs.10 * 4 = 40 coins 1 rupee = 100 paise10 rupee = 10×100 = 1000 paiseSo, No. of 25 paise coins = 1000/25= 40 1 rupee = 100 paise10 rupee = 10×100 = 1000 paise25 paise coins=1000/25= 40the answer is 40 |
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| 77717. |
5. By selling 33 tables a shopkeeper gains theselling price of 11 tables. Find the gainpercent. |
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Answer» Let the sp of each table be rs 1. Sp of 33 table = rs 33 Gain = sp of 11 = rs 11 So, cp = sp - gain = 22 Gain percent = gain/cp*100= 11/22*100=50%(ans) |
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| 77718. |
88. In a shop, shirts are usually soldat 40% above the cost price.During a sale, the shopkeeperoffers a discount of 10% off theusual selling price. If hemanages to sell 216 shirts for?13,608, then his cost price pershirt, (in) is |
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Answer» Let the C.P of 1 shirt = Rs. 100 M.P. of 1 shirt = 140% of 100 = Rs. 140 S.P. of 1 shirt = 90% of 140 =90100×14090100×140 = Rs. 126 Actual S.P. of 1 shirt =1360872=Rs.1891360872=Rs.189 126 -> 189 100 ->189×100126=Rs.150 |
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| 77719. |
4. Rashida bought 25 dozen eggs at the rate of 9.60 per dozen. 30 eggs were bnuBaintransaction and she sold the remaining eggs at one rupee each. Find herloss percentage.thet on its renairs Tf it |
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| 77720. |
(b) zero(d) an integer smaller than only one of the integers,1. Write a pair of integers whose sum gives(a) a negative integer(c) an integer smaller than both the integers.() an integer greater than both the integers.2. Write a pair of integers whose difference gives(a) a negative integer.(c) an integer smaller than both the integers.(e) an integer greater than both the integers.(b) zero.(d) an integer greater than only one of |
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Answer» 1st is (c) and 2nd is (d) (1) =c(2) = d.please like my answer 1st is C. 2nd is Dplease like my answer |
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| 77721. |
Write a pair of integers whose sum gives(a) a negative integer(b) zero(c) an integer smaller than both the integers. (d) an integer smaller than only one of the integers.(e) an integer greater than both the integers.Write a pair of integers whose difference gives(a) a negative integer.(b) zero.(c) an integer smaller than both the integers. (d) an integer greater than only one of the integers(e) an integer greater than both the integers. |
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Answer» option e is correct and point c is correct op E & C is the correct answer. E and C is the correct answer. |
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| 77722. |
3. Mona bought some notebooks for65.50, a pen for22.80 and a textbook forthe shopkeeper a five-hundred rupee note, how much money did she get back?206.40. If she gave |
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| 77723. |
Read the questions carefully and decide whether to add, subtract,Il1. A shopkeeper sells 72 shirts in a day. How manyshirts does he sell in 24 days?much money |
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Answer» In one day 72 shirts are soldin 24 days no. of shirt sold = 72× 24= 1728 tysm soo much |
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| 77724. |
for ,709per cent?A shopkeeper bought 6 dozen eggs at the rate of 50 per dozen, On thethe shop, 6 eggs broke. At what rate per egg does he need to sell the re4.mai smake a profit of 10%?1 12 of them at 7400 each |
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| 77725. |
9. Use commutative and distributive properties to simplify =roperties to simplify + x3 3 1 195 8 8 4 2014 20 CM |
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Answer» ........................ |
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| 77726. |
Calculate the value of \frac{83^{3}+17^{3}}{83^{2}-83 \times 17+17^{2}} |
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| 77727. |
14. Simplify ( +)3-3-5)' |
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Answer» (x/3+y/5)(x/3+y/5)(x/3+y/5) - (x/3-y/4)(x/3-y/5)(x/3-y/5) = x*x*x/27 + 3x*xy/45 + 3xy*y/75 + y*y*y/125 - (x*x*x/27 - 3x*xy/45 + 3xy*y/75 - y*y*y/125) = x*x*x/27 + x*xy/15 + xy*y/25 + y*y*y/125 - x*x*x/27 + x*xy/15 - xy*y/25 + y*y*y/125 = 2(x*x*x/27 + y*y*y/125) If you find this answer helpful then like it. |
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| 77728. |
sin a2Tt7sin αSii dof cos π + cos-π + cos-π +cos-ラ-+cos-it +cos-+cos7IS7evalueテ777 |
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| 77729. |
7. A car travels 60 km in 35 minutes. At the same rats,how many kilometres will it travel in one hour? |
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Answer» So here velocity is not given… so we have to calculate the velocity of the car from given data. Car travel 60 km in 35 minutes. First of all, we have to convert 35 minutes in hours by dividing 35 to 60 hour = 35/60 Next, we have to calculate distance in kilometres so distance =velocity ×time. Velocity =distance / time Velocity =60/(35/60) Velocity=3600/35 Distance = velocity ×time In one hour… it will travel… Distance =(3600/35) ×1.=102.85km |
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| 77730. |
4) Which of the following gives negative integers?(i) 0-(-7)(ii) -7-(-2)(iii) 7-(-7)(iv) 9+ (+7) |
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Answer» option (ii) is the right answer (2) option is right.it is too simple option 2 is right it's simple |
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| 77731. |
4 . \operatorname { sin } 10 ^ { \circ } + \operatorname { sin } 20 ^ { \circ } + \operatorname { sin } 40 ^ { \circ } + \operatorname { sin } 50 ^ { \circ } = \operatorname { sin } 70 ^ { \circ } + \operatorname { sin } 80 ^ { \circ } |
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| 77732. |
Folve the following equations.1) y-5=1 (2) 8 = 1 +5(3) 4x = 52(4) 19 = m - 4(6) x + 10=5(7) m-5= - 12(8) p + 4 = -1Nmotion as an equation and find its solution. |
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Answer» y=1+5y=6correct answer y=6t= 3x= 13m= 23p= 36x= -5m= -7p= -5 is the correct answer of the given question y=6t=3x=13m=24p=36x=-5m=-7p=-5 4x=52x=52/4x=13is the best answer y=6t=3x=13m=24p=36x=-5m=-7p=-5 (4) 19= m-4 m=19+4 m=23is the best answer 5) p/4=9 p=9×4 p=36is the best answer 6)x+10=5 x=5 -10 x=-5is the best answer y=6 is the best answer y-5=1 One solution was found : y = 6 x+10=5 One solution was found : x = -5 |
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| 77733. |
\operatorname { sin } x + \operatorname { sin } 2 x + \operatorname { sin } 4 x + \operatorname { sin } 5 x = 4 \operatorname { cos } \frac { x } { 2 } \operatorname { cos } \frac { 3 x } { 2 } \operatorname { sin } 3 x |
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Answer» Sinx+sin2x+sin4x+sin5x=2sin(x+2x)/2cos(x-2x)/2+2sin(4x+5x)/2xos(4x-5x)/2[sinC+sinD=2sin(C+D)/2cos(C-D)/2]=2sin3x/2cosx/2+2sin9x/2cosx/2 [∵, cos(-x)=cosx]=2cosx/2(sin3x/2+sin9x/2)=2cosx/2{2sin(3x/2+9x/2)/2cos(3x/2-9x/2)/2}=2cosx/2(2sin12x/4cos6x/4)=4cosx/2sin3xcos3x/2=4cosx/2cos3x/2sin3x (Proved) |
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| 77734. |
\operatorname { in } \theta \operatorname { sin } ( \theta + 2 \phi ) - \operatorname { sin } \phi \operatorname { sin } ( \phi + 2 \theta ) = \operatorname { sin } ( \theta - \phi ) \operatorname { sin } ( \theta + \phi ) |
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| 77735. |
cm7 2 7 21 8 1 8 |
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Answer» m. cm 72 72-18 18=54 54 |
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| 77736. |
8. Two brands of chocolates are available in packs of 24 and 15 respectively. If I need to buy anequal number of chocolates of both kinds, what is the least number of boxes of each kindwould need to buy? |
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| 77737. |
What Is His vel3. Hundred rupee shares of a company areavailable in the market at a premium of 20.Find the rate of dividend given by thecompany when a man's return on hisinvestment is 15 percent. |
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| 77738. |
For the Curious MindA shopkeeper bought a crockery set at 15% less than its marked price. He then makeit 50% more than what he had paid and sold the same at 30% discount. Find theprice of the crockery set if the shopkeeper earns 255 as profit on the MP |
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Answer» 15/11 is the correct answer 15/12 is the right answer 15 /11 is the right answer 15/11 is the right answer |
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| 77739. |
25%. Find the CP ofthe laptop.A shopkeeper bought 50 shirts for 30,000. He found that 10 shirts are defective so he sold them at aloss of10%. At what price should he sell the remaining shirts to gain 30% profit on whole transaction? |
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Answer» the selling price of a laptop is equal to 1 -1/8 of the cost price. find the profit percent |
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| 77740. |
Find the area of a trapezium whose parallel sides are 25 cm, 13 cmthe other sides are 15 cm each.an |
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| 77741. |
12) Simplify :> 1735 (-3)1016) Simplify :=25%osU5-6 X 6-2 |
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| 77742. |
A bullock-cart travels 35 km in 5 hours and a car travels 130 km in 2 hours. Find the ratioof their speeds. |
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Answer» bullet cart speed = 35/5= 7kmphcar's speed= 130/2= 65kmphso the ratio will be 7:65 thanks |
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| 77743. |
37.III. 1716150 is divisible by:I. 2II. 5(1) I only (2) II only(3) I and II (4) II and III(5) I, II and III |
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Answer» and is option 3 ok😃 5 no. option is right |
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| 77744. |
1 (x) = 3x+7 then which of thefollowing is the correctformulafor f (x) ?o)s)-7 )-7(2) f (x)-3x-21 (4) f(x) 3x+21x)--3x+21 |
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| 77745. |
\frac { \operatorname { sin } \theta + \operatorname { sin } 3 \theta + \operatorname { sin } 5 \theta + \operatorname { sin } 7 \theta } { \operatorname { cos } \theta + \operatorname { cos } 3 \theta + \operatorname { cos } 5 \theta + \operatorname { cos } 7 \theta } = \operatorname { tan } 4 \theta |
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Answer» Taking the numerator i.e. sinx + sin3x+sin5x +sin7x= (sinx +sin7x) + (sin3x + sin5x)applying formula of sinc +sind , we get ,= 2sin4xcos3x + 2sin4xcosx =2sin4x (cos3x+cosx)--- -------- ---- --------1Similarly taking the denominator i.e. (cosx + cos7x) + (cos3x + cos5x)applying formula of cosC +cosD, we get = 2cos4xcos3x + 2cos4xcosx =2cos4x (cos3x + cosx) ---------- ------------2Now dividing 1 by 2 =we get sin4x/cos4x = tan4x |
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| 77746. |
r s(x)-3x+2 shoshow that3x 2f(x)+1 3xf(x)-12 |
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| 77747. |
\begin{array}{l}{\text { Simplify : }} \\ {\left[5\left[8^{1 / 3}+27^{1 / 3}\right]^{3}\right]^{1 / 4}}\end{array} |
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| 77748. |
\frac ( \operatorname sin \theta %2B \operatorname cos \theta ) ( \operatorname sin ^ 2 \theta %2B \operatorname cos ^ 2 \theta - \operatorname sin \theta \operatorname cos \theta ) \operatorname sin \theta %2B \operatorname cos \theta %2B \operatorname sin \theta c |
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Answer» Cancel (sinA+cosA)hencesin^2A+cos^2A-cosAsinA+sinAcosA=1-0=1 |
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| 77749. |
(5*(8^(1/3) %2B 27^(1/3))^3)^(1/4) |
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| 77750. |
(5^2*(8^(1/3) %2B 27^(1/3))^3)^(1/5) |
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