InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 78151. |
6+7+8+9+10+18+8+12 |
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Answer» 6 + 7 + 8 + 9 + 10 + 18 + 8 + 12 = 78 |
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| 78152. |
A survey was conducted by a group of students as a part of their environment awarenessprogramme, in which they collected the following data regarding the number of plants in20 houses in a locality. Find the mean number of plants per house.Number of plants 0-2 2-44-6 6-8 8-10 10-1212-14Number of houses2 |
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| 78153. |
10. An express train takes 1 hour less than a passenger train to travel 132 km betweenMysore and Bangalore (without taking into consideration the time they stop atintermediate stations). If the average speed of the express train is 11km/h more than thatof the passenger train, find the average speed of the two train:s. |
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| 78154. |
(13. In a balanced diet, the components are:proteins12%, fats-25%, carbohydrates63%Find the amount (in calories) of each of the components in a child's dailyintake, who needs 2,600 calories daily.food |
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| 78155. |
If the median of following a observations is 20 then find the value of x (19,X, 16,18, 22, 17, 24, 23, 21) |
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Answer» x=20 is the following question answer. |
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| 78156. |
h that orne part is 10more than the uther. fthe twoparts are in the ratio 5:3, find the number and the two parts |
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Answer» let the parts be: x and y let the number be ztherefore x/y = 5/3=> x= 5y/3 ----------1=> and x = 10+y ---------2thus: z = x+y so from 1 and 25y/3 = 10+y5y/3-y = 102y/3 = 10 y = 15thus x = 25hence z= 25+15=40 |
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| 78157. |
() A number is divided into two partsone part being 4 times the other. Thedifference between the two parts is 15What is the number? |
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Answer» Let first part be x therefore second part is 4x4x-x=15x=15/3=5(first part)2nd part=4x=20therefore required no. =20+5=25 |
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| 78158. |
( 2 x + 5 ) ^ { 2 } - ( 2 x - 5 ) ^ { 2 } |
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| 78159. |
Gross Mulhipticathen maĹhod solve the paun a neqtah on+3 2 |
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| 78160. |
Two lines intersect each other and form four <angles A, B, C and DProve that C and ZD are vertically oppositeangles and are equal in measureB If the measure of ZA is increased by 10°, whotwould happen to 2C? |
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| 78161. |
find the10 Sonatended her school on 204 days in a full year. If hertumber of days on which the school was openedays in a full year. If her attendance is 85% |
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Answer» Number of days school attended/ Total Number days of school × 100= Percentage(%) 204/ x × 100 = 85204/85 × 100= x12/5 × 100= x12×20= x240= Total number of school. Answer Let the number of days the school was opened = Z ∴Percentage of attendance = 85% of Z Now, 85% of Z = 204 ⇒85/100×Z = 204 ⇒Z = 204× 100/85 ⇒Z = 204× 20/17 [Divided by 5] ⇒Z = 12× 20 ⇒Z = 240 85x/100 = 20420400 = 85xX = 20400/85 =240no. of Days school opened= 240 240 is the best answer |
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| 78162. |
15. A wire of length 121 cm is bent so as to lie along the arc of a circle of radius180 cm. Find in degrees, the angle subtended at the centre by the arc. |
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Answer» circumference of circle having R = 180cm = 2*π*180 = 360π cm now, 360π cm makes .. 360° angle.. so, 1 cm → 360/360π = 1/π ° angle..so, 121cm → will make 121/π ° angle = 38.51 ° |
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| 78163. |
4. From a rope 40 meters long, pieces of equal size are cut. If the length of onepiece is - meter, find the number of such pieces |
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| 78164. |
High Order Thinking Skills (HOTS)9. Find the reciprocal of 555 and express i-1296exponential notation. |
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Answer» =-625/1296 is the correct answer of the given question (1). -1296/625 =-625/1296 |
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| 78165. |
1. The following table shows the number of students and the time they utilizeddaily for their studies. Find the mean time spent by students for their studies bydirect method.6-88-10Time (hrs.)No. of students70-24-6181210 |
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| 78166. |
3.Number of calories (in' 00) consumed daily by a sample of 15 years old boys are given belowCalories 1000 1500 20002500 30003500-40002000 2500 3000350000 4500No. of131827104516boysFind median calories consumed daily by a boy.0 |
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Answer» hit like if you find it useful |
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| 78167. |
22 om2 cm2 cm2㎝10 cm11. Find the areas of the shaded parts inF8.7 m-19.6m6.7 m6.2m15 m54 mb)12. A square field has an area of 6. 25 km2. Find tmetre.13. An open tank is 3 m long, 2 m wide and 1 m 50 cninside and outside, if 1 kg of paint covers 20 squ |
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| 78168. |
3. Mean of twenty observations is 15. If two observations 17 and 20 replaced by 8 and9 respectively, then the new mean will bea) 14b)15c) 16d) 17 |
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| 78169. |
e om4om2 om2 om2 om10 cmI1. Find the areas of the shaded parts in Figs (8.7 m6.7 m6.2 m15 m54 m12. A square field has an area of 6. 25 kmmetre13. An open tank is 3 m long, 2 m wide and 1 |
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| 78170. |
TItu two parts,one part being 4 times the otherdifference between the two parts is(iv)What is the number?A)ii) Divide 40 into two parts such that onepart is 10 more than the otheri) Two parts of a number are such thatone is half the other. The sum of the twoparts is 8 more than their difference.What are the parts and what is thenumber? |
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Answer» Let 1st part = x2nd part = x + 10ATQx + x +10 = 402x +10 =402x = 40 -10 = 30x = 30/ 2x = 15 so is part = 152nd part = 15 + 10 = 25 |
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| 78171. |
-2Solve for x if 5 2-4 is singular. |
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| 78172. |
DatePage.| |
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| 78173. |
015. The data regarding marks obtained by 48 students of a class in a class test is given below:Marks | 0-5 1Number25-30-T-30-35-T-35-40-4045-r 45-50-.5-1010-1515-2020-25obtained010252ofstudentsCalculate the model marks of the students |
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| 78174. |
averageThere are 45 students in a class uut of whicb 15 arc girls. The45 kgs and that of 30 hoys is 52 kgs. Find the average weight of the whole slasweight of 5 uirk is |
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Answer» hit like if you find it useful |
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| 78175. |
t equal pieces whot i5 the volumes of cach picte9 |
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Answer» volume of sphere=4/3 *π*r³=4/3 *22/7*21*21*21=4*22*21*21=38808cm³ cut into 4 piecesvolume of 1 piece=38808/4=9702 |
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| 78176. |
tomorrow to coming generations| IMPORTANT QUESTIONS FOR PRACTICEVery Short Answer Type Questions [1 Mark Each]If a wire is bent into the shape of square whose area is 81 cm2. When the same wirebent into a semicircular shape, then find the area of the semicircle.1.cimla of radius 5 7 cm is 27.2 cm, then find the area |
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Answer» Area Of square a^2 = 81 ====> a = 9The wire when bent in a form of Square i.e. the total perimeter of the square Therefore,Perimeter of Square = 4a = 4*9 = 36 which is total length of the wirethe wire which is bent in the form of semicircle forms circumference of semicircle therefore circumference is 22/7r+2r = 36 where 'r' is radius(22+14)*r/7 = 36 r = 7 cm Therefore area of semicircle is {(22/7)r^2}/2 = (1/2)*(22/7)*7*7 we get Area of semicircle = 77 cm^2 |
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| 78177. |
6. (i) Find the mean deviation about the median for thefollowing frequency distribution:Marks 0-10 10-20 20-30 30-40 40-50 50-60No. ofstudents6 8 11 1852 |
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| 78178. |
9. The weight of tea in 70 packets are shown in the following tableof'tea in 70 packets are shown in the following tableWeight (in gms) 200-201 201-202 202-203 203-204 204-205 205-206No. of packets13271810Find the mean weight of packets using step deviation method, |
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| 78179. |
23.The mode of the following observations 8, 9, 10, 8, 7, 6, 8, 9, 8, 3, 4, 12, 15, 17, 20a)7b) 8c) 9d) 6 |
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Answer» 8 appears the most number of times, i.e., 4 times. So, mode = 8 8 is a right answer |
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| 78180. |
ABCD× 9_____DCBA In the multiplication example ABCD and DCBA represents 4 - digit number and different digits. What 4 - digit number does ABCD represents? |
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| 78181. |
9Find the arca of the shaded parts of the following figures.3.5 m |
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| 78182. |
1. The cost of I toy is 250. Find the cost of such 175 toys.air and a table is 235 and 582. Find the cost of such 18 chairs and ltables.In a class of 45 students5 750 were collected for a farewell party. Find the amount |
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| 78183. |
4( The cost price of 10 tables is equal to the selling price of 8 tables. Find the loss or profit per cent. |
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Answer» answer is 25 |
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| 78184. |
.Mohan'sbirthdaycakewascutinto20equalpieces.Sixteenpieceswereservedattheparty.What fraction of cake was not served at the party |
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Answer» pieces not served20-16=4hence 4/20=1/5 parts not served |
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| 78185. |
At a party, everyone shook hands with everybody else. There were 66 handshakes. How many people were at the party? |
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Answer» 12 In general, with n+1 people, the number of handshakes is the sum of the first n consecutive numbers: 1+2+3+ ... + n.Since this sum is n(n+1)/2, we need to solve the equation n(n+1)/2 = 66.This is the quadratic equation n2+ n -132 = 0. Solving for n, we obtain 11 as the answer and deduce that there were 12 people at the party. Since 66 is a relatively small number, you can also solve this problem with a hand calculator. Add 1 + 2 = + 3 = +... etc. until the total is 66. The last number that you entered (11) is n. |
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| 78186. |
veceptedPractice QuestionsCK&UBet Closure & Commutative Property1. Fill in the blanks-100 +45 = 4 3+ (-100)B. 79 + (-151) =__+79C. __+q=p++89 = _+34A |
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Answer» B=(-151),C=p,D=34,89 |
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| 78187. |
\left. \begin{array} { c c c } { 0 - 10 } & { 10 - 20 } & { 20 - 30 } & { 30 - 40 } & { 40 - 50 } \\ { 7 } & { 10 } & { 15 } & { 8 } & { 10 } \end{array} \right. |
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Answer» take out mid terms of each range 5,15,25,35,45so mean=(5×7+15×10+25×15+35×8+45×10)/(50)=1290/50=25.8 |
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| 78188. |
19. Find the mean of the following frequency distribution using stedeviation method.Class 0-10 10-20 20-30 30-40 40-50Frequency 7 10 15 8 10 |
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Answer» the mean of the following question is 29.8 |
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| 78189. |
Fill in the blanks using appropriate signs (,>or -)(1) The measure of one complete angle ......360(l) The measure of an obtuse angl...90(il) The measure of an acute ange...90iv) The measure of right angle...90 |
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Answer» 1) =2) >3) <4) = |
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| 78190. |
Age (in years)Number of childrer1- 22-33 -55-77-1010-1515-17129104Draw a histogram to represent the data above. |
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| 78191. |
Multiple Choice Questions (MCQs)The smallest 8-digit number using three differentdigits can be read as(a) Ten million two(b) One million two(c) One hundred million two(d) One hundred thousand two9. |
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Answer» option is (d). because it is smallest among the numbers and it has 3 different digits Wong ha The smallest 8 digit number having 3 different digits will be formed by using the 3 digits of least priority. They are - 0,1,2 So, 1 will be the leftmost digit followed by 0 six times and the rightmost digit will be 2. So we get the number as - 10000002 - right option a is correct because it have three different digits 1,0,2 so the smallest 8 digit number is 10000002. it is ten million two. |
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| 78192. |
B) If the mean of the following frequency distribution is 14.1, find the value of 'p'.Marks (x 厂 1-10-112 | 14 | 16 | 18 | 20No.of students 4 12 p 842 |
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| 78193. |
5.Formulate a pair of linear equations in two variables “3 pens and 4 books together costRs.50 where as 5 pens and 3 books together cost Rs. 54”. |
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| 78194. |
(iii) 3 chairs and 4 tables cost 18,000, 4 chairsand 3 tables cost * 15,600. Find the cost of achair and a table.Solution : |
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Answer» let cost of one chair is equal to x and cost of one table is equal to y then 3x+4y=18000...1and 4x+3y=15600therefore 7 x + 7 y is equal to 33600therefore x + y is equal to4800which implies x is equal to 4800 - ysubstitute this in equation number 13(4800-y)+4y=1800014400+y=18000which implies y is equal to3600 and x is equal to 1200. 3x+4y=18000; 4x+3y=15600;; 15600+18000=33600; 7 chairs+7 tables:; x+y=equal 4800, 3(4800-y)+4y=18000; 18000-14400=3600 and x=1200 |
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| 78195. |
n u iviathematicquiz. If the number of giris is 4(i) 5 pencils and 7 pens together cost Rs 50, whereas 7 pencils and 5 pens togetherand i , find out whether the lines representing thenore than the number of boys, find the number of boys and girls who took part inthe quiz.cost Rs 46. Find the cost of one pencil and that of one pen.2. Oa comparing the ratios ,a b 2following pairs of linear equations intersect at a point, are parallel or coincident:0 5x-4y+ 80(ii) 9(+ 3y + 12-07x+6y-9 018x+ 6y + 24-0 |
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| 78196. |
A party rental company has chairs and tables for rent. The total cost to rent 12 chairs and 2 tables is $31. The total cost to rent 3 chairs and 5 tables is $37. What is the cost to rent each chair and each table? |
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Answer» sorry idk why it's not completely up there here it is A party rental company has chairs and tables for rent. The total cost to rent 12 chairs and 2 tables is $31. The total cost to rent 3 chairs and 5 tables is $37. What is the cost to rent each chair and each table? sorry I can't really see can you see it now veronica? yes thank you so very much 😊😊 you're welcome :) |
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| 78197. |
(6)The total cost of 6 books and 7 pens is 79 rupees and the total cost of 7 books and 5 pensis 77 rupeess. Find the cost of 1 book and 2 pens. |
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Answer» Let cost of one book=₹xLet cost of one pen=₹y 6x+7y=797x+5y=77 Multiplying first equation by 5 and second by 7,30x+35y=39549x+35y=539 Subtracting two equations,-19x=-144x= ₹ 7.58y=4.79 Therefore,cost of one book=₹ 7.58Let cost of two pens=₹2×4.79=₹9.58 |
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| 78198. |
31. Calculate mean of the followingC.F. 0- 10 10-20 20 30 30-40 40 50101510 |
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| 78199. |
i)16- 13:39liv) - 3710-19. Arrange the following in ascending order:w 4 6 1 -2°-9'7' 101 -6 -13 18 19(ii) - 10' 15 '25' 6020. Arrange theArrange the following in descending order :2 3 5 - 7054-6'121 4 5 7 11(iii) 7 36-244521. Representand - 13 on the number line.22. Without actual division, find which of the followingnon-terminating repeating decimal :()15a 121(i) 1875023. Express each of the following in decimal upto four154 |
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Answer» 23(i) 1.33328(ii)8.666 23(i) 1.33323(ii)= 8.666 23(i) 1.333(ii) 8.666 23(i)1.333(ii) 8.667 23(i) 1.333(ii)8.666 23(i) 1.333(ii) 8.666 23(i) 1.333ii 8.6666 23(i) 1.33323(ii) 8.666 I don't know the answer brooo sorry yar mujah Nahi pata ha yar sorry I didn't find a f 2 A + 3 in bracket(1 3 2 5) = in bracket (5 7 6 3) |
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| 78200. |
贮following fractions represent just three different numbers. Separate them ineroups of equivalent fractions by changing éach one to its simplest form.10e) 60(a) 12(b) 131s (c)1696 (i)1260(j) 7218t |
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