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78251.

喻何て,Find HCF and LCM of 404 and 96 and verify that HCF x LCM Product of the twogiven numbers

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78252.

Find the ratio of the price of a pencil to that of a ball pen if pencils cost ? 96 perball pens cost13.score an50.40 per dozen.

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78253.

13.Find HCF and LCM of 404 and 96 and verify thatHCF x LCM = Product of the two given numbers.

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78254.

Date:Worksheet 31. Write the Hindu-Arabic numerals for the following.a. LIV 54b. XXXVII_37d. LXIV_64-e LIX2. Write the Roman numerals for the following.a. 42 XILILb. 57d. 75 LXXVe. 55 LVC. CL 150f. XCIC. 98 XCVIf. 83 LXXX3. Round off to the nearest 100 and 1000.NumberNearest 100Nearest 10003,42825,44380,397d.56,971e.67,8032,22,8259,87,7982,96,0174,92,646Teacher's remarks:earning outcome: Write Romanumerals and round off numbers

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78255.

65 A man arranges to pay off a debt of3600 by 40 annual instalments which form anarithmetic series. When 30 of the instalments are paid, he dies leaving one-third of thedebt unpaid, find the value of the first instalment.

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78256.

A tourist bus left town A and travelled at an average speed of 85 km/hr to town B which was 34away. If it reached town B at 1:15 p.m., at what time did it start?

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Time taken to travel 340 km at speed of 85km/hr = 340/85=4 hrsHence the bus started at 9.15 A.M

78257.

teacher day is celebrated on

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teacher day is celebrated on 5 September

78258.

Q.1 How many cubic blocks of wood of side 20 cm can be cut from ablock of wood having dimensions of 20 cm, 80 cm, and 40 cm?

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Volume of block of wood

= 20 cm × 80cm × 40cm

=64000 cm³

Volume of 1 cube = 20 × 20 × 20

= 800 cm³

No of boxes = 64000/800

= 80 boxes

galat h bhai

it's wrong

20×20×20=not 80020×20×20=8000

78259.

By selling 125 pens, a shopkeeper gainsthe selling price of 25 pens. His gainpercent is

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78260.

Exercise 22B1, If 24 ball pens cost56,find the cost of 18 such pens.

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Cost of 24 pen is ₹56

Cost of 1 pen is ₹56/24 = ₹4

Cost of 18 pen is 18 × ₹4 = 72

78261.

16. For each pair of numbers, verify that their product = (HCF X LCM).87, 145u) 186, 403ii) 490, 1155

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145/5=29/1=29,, 87/1=87; 403 , 186/2=372; 403/1=403;

78262.

What is the percentof change from186 to 77?| Cround to the nearest percent)

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percentage change will be there= 86-77/86*10010.46 percentage

78263.

A briefcase is sold for Rs. 450 cash orfor Rs. 210 cash down payment and Rs. 125 isto be paid in two equal instalments. Find therate of interest charged under the instalmentplan.

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cash price of briefcase = 450cash down payment = 210

78264.

lurlice area of the coneieis Fd i riangle ABC with sides 5 cm, 12 cm and 13 am is revalved abour the sie 12md the volume of the solid so obtained

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Put volume of triangle l×b×h =12×13×5 = 780

The right answer is '780

78265.

E 8 cm D6. Find the area enclosed by the given figure ABCDEF as perdimensions given herewith8 cm20 cm20 cn20 cm

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78266.

14. By selling 90 ball pens for ? 160, a personloses 20%.How many ball pens should be sold forhave a profit of 20%?96 so as to

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thanks bro

Rs 80 is the cp of ???

78267.

23Rohit deposited Rs. 8000 with a finance company for 3 years at an interest of 15%per annum. Find the compound interest Annual2

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78268.

DatePage니 -32C4

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78269.

2. Find the nature of the roots of the equation x 186

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x - 18/x = 6

x² - 6x - 18 = 0

Discrimanat = b² - 4ac

= (-6)² - 4 × (1) × (-18)

= 26 + 72

= 98

78270.

The H.C.F of 186 and 496 is 62. What is their L

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78271.

If one root of the Quadratic Equation is 2+√3 , then what is the other root . also find the equation

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the other root will be the conjugate of this root that is 2-√3

78272.

31. The perimeter of a square is 20 cmA rectangle has the same width asthe square. The length of therectangle is double its width. Thearea, in square cm, of the rectangleis(1) 30(2) 50(3) 100(4) 25

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answer is option (2). 50

explaination:- perimeter of square=20

4s=20, s=5. so each side is 5.

width of sqaure=width of rectangle=5=b

length is double the width in rectangle so 5×2=10=l

area of rectangle = l×b

5×10=50cm²

so area of rectangle is equal to 50cm².

50 is answer please mark best i am new in this app

50 is the right answer

2)50 is the right answer of the following

78273.

7. A bookseller purchased 70 pens at the rate ofof乏3.50 and remaining pens at the rate of3 per pen. He sold 60% of the pens at the rate5 per pen. Find his profit per cent

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78274.

13. Rohit buys 15 dozens of pens at 7 40 per dozenand sold it at 24 per 8 pens. Hlow manypercent profit or loss he gain?vita sold a garden at 20% profit. If Kavitatotal profit at 35000, then find the selling pricof garden.

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I am agree with your answer but in answer sheet the answer was 12.5 percent

78275.

Andrew purchased 20 pens and sold 16 ofthem for the same amount as the total cost of20 pens. What is the profit percentage?

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Let the CP of 20 pen = SP of 16 pen = xCP of 1 pen = x/20SP of 1 pen = x/16Gain = SP-CP =x/80Gain% ={ (x/80)/(x/20)}* 100 = 25%

78276.

write its decimal expansion withoORo numbers have 18 as their HCF and 380 as their LCM? Give186PAGE NO.DATE

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nice

thanks

78277.

clAssnAteDatePage2 &8

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Let the number be x

As per given conditionx + 24 = 110x/10010(x + 24) = 11x10x + 240 = 11x11x - 10x = 240x = 240

Therefore, Number is 240

(d) is correct option

78278.

Evaluate cosec (π/6). cos (π/3), tan3 (r/4), see? (r/4) cot (π/6).

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78279.

Page No.Date -7-32-8

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rational number

7-3x-8=7-8=3x=-1=3xx=3/-1x=-3

78280.

2422. A confused bank teller transposed the rupees and paisewhen he cashed a cheque for Shailaja, giving her rupeesinstead of paise and paise instead of rupees. After buying atoffee for 50 paise, Shailaja noticed that she was left withexactly three times as much as the amount on the cheque.Which of the following is a valid statement about thecheque amount ?(a) Over Rs 4 but less than Rs 5(b) Over Rs 13 but less than Rs 14(C) Over Rs 7 but less than Rs 8(d) Over Rs 22 but less than Rs 23(e) Over Rs 18 but less than Rs 1912 il

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78281.

(v) 50 rupees 90 paise

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rupees =100 paisaSo50 rupees 90 paisa can be written as

1)50.90 Rupees Answer

78282.

Find quadratic equation such that its roots are square of sum of the roots asquare of difference of the roots of equation 2r +2(p + q)x p 0

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the roots of the required quation be M and N let the roots of the equation 2x²+2(p+q)x+p²+q²=0 be a and ba + b = -(p+q)ab = (p^2 + q^2) / 2(a+b)^2 = (p+q)^2(a-b)^2 = (a+b)^2 - 4ab(a-b)^2 = -(p - q)^2we wanted the values of square of sum of the roots and square of difference of the rootsNow M = (a+b)^2 = (p+q)^2 and N = (a-b)^2 = -(p - q)^2M + N = 4pqMN = (p+q)^2 [-(p - q)^2]MN= -(p^2 - q^2)^2hence the required equation isx^2 - (4pq)x - (p^2 - q^2)^2 = 0

78283.

) Sanyafl ards. Complete the table for their cards:a. Aarushi, Manav and Kabir made greetingds. Cocard Length Width Perimeter Areawhose10 cmanya11 cm8 cmManavAarushiabir44 cm8cm80 square om40 cm100 square em

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78284.

हि.जाली RTR PN gl /G2 BID i Tek BsEgm PRk Tebikl PEREs B '8 १06Gl We [rTY Rite WP exigie 5 है M. hन एन TV Rle W e

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If you will post question in language of except English or Hindi then how India will understand ?

78285.

3. A note book is made up of sheets folded in themiddle and stapled. Each sheet forms two leavesi.e., four pages. On removing some papers of thefirst-half and second-half of the book, Joe foundthe number of the leaves in the first case as odd andin the second-case as even. If the sum of the num-bers of the pages on the last leaf of the book is 63,then what could be the maximum possible sum ofthe numbers on the pages of leaves that were left inthe book?

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We know that the two last pages are 31 and 32 since their sum is 63. So the pages in the first half of the book are 1-16, and the second half 17-32.

He removed odd number of leaves in the first half (1 - smallest) and even number in second half (2-smallest). To maximize the sum of whats left, he should be removing pages 1&2 from first half and pages 17,18,19 &20 from second half.

Total number of pages is (1+32)(16) = 528. Subtract the pages that were removed. 528 - (1+2+17+18+19+20) = 451

Like my answer if you find it useful!

78286.

After buying a book, I am left with rupees 5 out of my fifty-rupee note.What is the cost of the book?

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Cost of the book = Money I had - Money I have = 50 - 5 = Rs. 45.

78287.

Ill. Convert follow lng numbers into Binary & Decina! :-i 91ii) 89iv) 100I'、w rite lhe function key :-CommandFunction

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1.

2.

3.

78288.

A shopkeeper earns a profit of 5 by selling one note book and incurs a loss of 1 by selling an oldpen. In a particular month, the shopkeeper earns a profit of 185. If he sold 75 old pens, find thenumber of the note books sold.

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Profit per pen = re.1profit for 45 pens = rs.45if profit is always in positive then loss for the month is -5so 45+x = -5x = -50so the loss is -50pencils sold = (50/0.40) = 125Do as same as this

pen is profit Rs, 1, profit 45 pens = Rs. 45, profit in positive then loss for month = -5; 45 + x = -5; x = -45 + -5=-50;; pencil sold = ( 50 / 0. 40) =125.

78289.

R i i 5l byl r—1 o;(gn?a & P P49 =a=xyP L, b=xy" R c=xy" T, (क्‍्थेंडि (, a9 b P ¢& 1 2(T B {8

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Put the values of a , b and cthen(xy^p-1)^q-r (xy^q-1)^r-p(xy^r-1)^p-qafter solving

78290.

4. Find the sum :27lat9 12

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78291.

(a) 8 rupees 50 paise-(c) 23 p

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78292.

104. What is the value of r ifP(5, r) P(6 r-1) ?

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P(5,r) = P(6,r-1)

We know that P(n,r) = n!/(n-r)!

=> 5!/(5-r)! = 6!/(6-r+1)!

=> (7-r)!/(5-r)! = 6!/5! (By rearranging terms)

Also n! = n(n-1)!

=> (7-r)(6-r)(5-r)!/(5-r)! = 6×5!/5!

=> (7-r)(6-r) = 6 (Cancelling terms)

=> r^2 - 13r + 36 = 0

=> (r-9)(r-4) = 0

Hence r = 4,9

78293.

24. If the roots of the quadratic equation p(y-r)? + q(r-p)r + rip-q) = 0 are equal, show that1+1 2()Or

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Like if you find it useful

are u in grade 9.

78294.

Calculate simple and weighted arithmetic mean from theWorkers | Daily wages | No. of workersMen60Women30Children2020

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When you find ameanfor a set of numbers, all the numbers carry an equalweight. For example, if you want to find thearithmetic meanof 1, 3, 5, 7, and 10: Add up your data points: 1 + 3 + 5 + 7 + 10 = 26. Divide by the number of items in the set: 26 / 5 = 5.2.

workers daily wages no.of workers total money men 60 50 30,00 women 40 30 1200 children 20 20 400 =/100 4600 mean /f(x)=4600/100=46

78295.

their radii.The diameter of the wheel of a cart is 140 cm. What will be the distance that cart will cover if its wheel hasmade 40 complete revolutions?12

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78296.

e a point O on your note book and draw circles of radiuseach having the came centre O.Tak

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78297.

The wheels of a car are of diameter 80 cm each. How many complete revolutions doeseach wheel make in 10 minutes when the car is travelling at a speed of 66 km per hour?

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78298.

8. Rohit and Ranveer are brothers. Rohit is 4 ycars old now. If his age is 1 year more thanth of Ranveersage. How old is Ranveer?

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Let the age of Ranveer=x

1+(1/6)x=4(1/6)x=3x=6*3x=18

ty

78299.

1. In Fig. 9.15, ABCD is a parallelogram, AE L DCand CF丄AD. If AB = 16 cm, AE = 8 cm andCF 10 cm, find AD

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78300.

find the gain or loss percent when:1) CP=rupees 250, overhead expenses= rupees 50 and loss rupees 50

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Thank u so much akka! !!!!!!!!!