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A:B = 6:7

multiplying by 3, we get

A:B = 18:21

so A:C = 18:15

3 4/7 =25/7

1m75cm=175cm

175÷25/7

175×7/25

7×7 =49 pieces

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2(x+1)/3 = 3(x -2)/5

10(x + 1) = 9 ( x - 2)

10x + 10 = 9x - 18

10x - 9x = - 18 - 10

x = -28

how can you say PQ parallel to BC

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angle of 90°right angle

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Given:

A right angled ∆ABC, right angled at B

To Prove- AC²=AB²+BC²

Construction: draw perpendicular BD onto the side AC .

Proof:

We know that if a perpendicular is drawn from the vertex of a right angle of a right angled triangle to the hypotenuse, than triangles on both sides of the perpendicular are similar to the whole triangle and to each other.

We have

△ADB∼△ABC. (by AA similarity)

Therefore, AD/ AB=AB/AC

(In similar Triangles corresponding sides are proportional)

AB²=AD×AC……..(1)

Also, △BDC∼△ABC

Therefore, CD/BC=BC/AC

(in similar Triangles corresponding sides are proportional)

Or, BC²=CD×AC……..(2)

Adding the equations (1) and (2) we get,

AB²+BC²=AD×AC+CD×AC

AB²+BC²=AC(AD+CD)

( From the figure AD + CD = AC)

AB²+BC²=AC . AC

Therefore, AC²=AB²+BC²

This theroem is known as Pythagoras theroem...

Volume of the metal used in the box = External Volume - Internal Volume = [(50 * 40 * 23) - (44 * 34 * 20)]cm3= 16080 cm3Weight of the metal =((16080*0.5)/1000) kg = 8.04 kg.

love youthanks

suppose parts are x and y x + y = 40 10x = 9y + 1 10x + 10y = 400 9y + 1 + 10y = 400 19y = 399 y = 21 so x = 19

Given that two different dice are tossed.

Total number of outcomes = 6^2

= 36.

(1) Let A be the event of getting a doublet.

n(A) = {1,1},{2,2},{3,3},{4,4},{5,5},{6,6}

= 6.

Required probability P(A) = 6/36

=1/6.

(ii) Let B be the event of getting a sum of 10 of the numbers of two dice.

n(B) = {6,4},{4,6},{5,5}

= 3.

Required probability P(B) = n(B)/n(S)

= 3/36

=1/12

1)There are a total of 36 possibilities :

{ (1,1), (1,2), (1,3), (1,4), (1,5),(1,6) (2,1)(2,2)… …..(6,5) (6,6)}

The doublets among these are (1,1), (2,2),(3,3)(4,4),(5,5),(6,6)

So the probability of getting a doublet is :

No. Of doublets / total no. of outcomes =6/36=1/6

2)Let B be the event of getting a sum of 10 of the numbers of two dice.

n(B) = {6,4},{4,6},{5,5}

= 3.

Required probability P(B) = n(B)/n(S)

= 3/36

= 1/12

Proof:

In ∆ ADB and ∆ ABC

A= A ( commom )

ADB = ABC ( each 90°)

Hence. ∆ ADB ~ ∆ ABC ( BY AA ) .……...(1)

similarly :

In ∆ BCD & ∆ ABC

C= C ( common )

BCD = ABC ( each 90°)

hence

∆ BCD ~ ∆ ABC ( by AA).……..(2)

FROM eq. (1) and (2).

∆ ADB~∆ ABC & ∆ BDC ~∆ ABC .

NOTE: If one ∆ is similar to another and second ∆ is similar to third ∆

then first and third ∆ are similar

hence :∆ ABD ~ ∆ BCD

PROVED

see the base should not be used as one arm of the right angle

bc should be the hypotenuse

The pair of linear equations represented by these lines a1x + b1y + c1 = 0 and a2x + b2y + c2 = 0

For infinite many solutionsa1/a2 = b1/b2 = c1/c2

Given equations2x + 3y - 7 = 0(a-b)x + (a+b)y - (3a + b - 2) = 0

Then, 2/(a-b) = 3/(a + b) = 7/(3a + b-2)

2(a + b) = 3(a - b).......(1)3/(a+b) = 7/(3a + b - 2).......(2)2a + 2b = 3a - 3ba = 5b

Put value of a = 5b in eq(2),We get3(3a + b - 2) = 7(a + b) 9*5b + 3b - 6 = 7*5b + 7b48b - 6 = 42b48b - 42b = 66b = 6b = 6/6 = 1

a = 5b = 5*1 = 5

As given in question, two angles and a side are equal and mentioned that included side it must be ASA criterion

d) ASA is correct option

bhai mere doo or questions ka reply kar de

write the order of the following surd 5

Volume of each plank= length*breadth*height=500*24*10 cm³=120000 cm³

Volume of place= length*breadth*height=1500*400*60 cm³=36000000

Number of planks= 36000000/120000=300

A tail= 11/20 A head = 11-20/20=9/20

total outcomes of tossing 2 dices together=36i)total duplets=6probability=6/36=1/6ii)sum of 10(4 6)(5 5 )(6 4)=3probability=3/36=1/12

first ka answer hai 1

no 4s answer is (32÷16)*4=2*4=8

1 4 9 32125 124 8-36 -2011 12

1) 12) 23) 34) 85) 256) 27)48) -649) -4

Answer of first is 1

Answer 11= 225÷30=7.5

first ka answer 1 hai

191254-3611432128-2012

question 1 = 0question 2= 1question 3=2

ist ka ans 1, 2nd ka ans 2,3rd ka ans 3 hai

thanks to

exponential form then power add 5+3=7 8

question 1st answer is 1

first ka answer 1 he

ans1=1. ans2=2an3=3. ans4 =8an5=25. ans6=2an7=4. ans8=1an9=4. ans10=9an11=1. ans12=1

1. 12. 23. 34. 85. 256. 27. 48. 19. 410. 911. 112. 1please let me know if you require explanation to any of the answer