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The output can be { HH, HT, TH, TT}

a) p( getting exactly 1 head)= 2/4 = 1/2

b) p(getting no head) = 1/4

c) p(getting both heads) = 1/4

The output can be { HH, HT, TH, TT}

a) p( getting exactly 1 head)= 2/4 = 1/2

b) p(getting no head) = 1/4

c) p(getting both heads) = 1/4

none of these because,when a coin toss it is noylt guaranteed it getting a head so first option is wrong,the second option is also incorrect because it is not guaranteed no heads come and the 3rd options is incorrect because it is not guaranteed two heads is come so answer is none of these

sorry I am incorrect

mth term is n so a + (m-1)d = n a + md - d = n nth term is m so a + (n-1)d = m a + nd - d = m a + md - d - a - nd + d = n - m (m-n)d = -1*(m-n) d = -1 a - m + 1 = n a = m + n - 1 mnth term a + (mm-1)d = m + n - 1 - mn + 1 = m + n - mn

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there is value in question

Incorrect Mean =X’ = 160

No of observations = 40

Incorrect Sum of observations =sum’= 160 x 40 = 6400

Correct sum of observations = = sum’ – 125 +165

= 6400 +40

= 6440

Correct mean = X = 6440/ 40 = 161

I don't understand the incorrect sum...plz explain

Sum of all 50 observations = mean * no of observation = 80.4x 50 = 4020 now according to question 96 was misread by 69 So the new sum of observation = 4020 - 69 + 96 = 4020 + 27 = 40.47 now new mean = 4047/50 = 80.94 answer

Hi Vishal,

Here is the answer to your question.

L.C.M. of 6, 15 and 18

2 | 6, 15 ,183 | 3, 15, 93 | 1, 5, 35 | 1,5, 1

= 2 x 3 x 3 x 5 = 90

Therefore the required number = 90 + 5 = 95

L.C.M of 6,15 and 18 2l6, 15,183l3, 15,93l1, 5,35l1, 5,1=2×3×3×5so, the correct answer =90+5=95

Lets = Sushma's age nowLetv= Vijay's age nows+3= Sushma's age in 3 yearsv-3 = Vijay's age 3 years agogiven:(1)S= v+ 15(2)S+3=8(v-3) From (2):S+3= 8v-24By substitution:v= 6And, from (1),S= 21She is 21 and he is 6

Explanation : 5 मजदूर 10 दिन मे काम करते है 10 मजदूर को लगने वाले दिन = 10×5/10 = 5 दिन

Solution : 10 दिन

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1) 5x + 3y = 15..... (1) 7x - 15y = 21......(2)

Multiply eq(1) by 5 and then add both equation25x + 15y = 757x - 15y = 21

32x = 96x = 3

Put x = 3 in eq(2)7*3 - 15y = 2121 - 15y = 21y = 0

2)3x + y = 5..... (1) 5x + 3y = 3......(2)

Multiply eq(1) by 3 and then subtract both equation9x + 3y = 155x + 3y = 3

4x = 12x = 3

Put x = 3 in eq(2)5*3 + 3y = 315 + 3y = 33y = - 12y = - 4

1

2

thanjs

thanks

sequence =11/5,14/5,17/5,20/5,23/5,26/5Please like the solution 👍 ✔️

Explanation:

The first thing to understand is that if you place one value on the other side you must put it on the other side as well.

−2x−13=−x−27

−2x+x−13=−x+x−27

−x−13+13=−27+13

−x=−14

−x−1=−14−1

x=14

The last thing you can do is check if you have the correct answer. The way to do this is to substitute the value you got forxinto the original equation. If both sides are equal then you have the right answer, if not go back and find your mistake.

−2(14)−13=−(14)−27

−28−13=−14−27

−31=−31

(a) Put n = 1 6n + 1 = 7 Put n = 2 6n + 1 = 13 Put n = 3 6n + 1 = 19 Therefore, the sequence is 7, 13, 19, ......

(b) When each term of the sequence is divided by 6, the remainder is 1.(c) 6n + 2 is the required expression

(a) put n =16n+1=7put n=26n+1=13put n=36n+1=19Than the Sequence is 7,13,19.......

As Arnav's father age is 49 years

So let's take Arnav age be x

Equation:-

49= 4x+949-9=4x40=4x40/4=x10 years=x

49 = 4x + 9; 4x= 49-9=40; x = 40/4=10

As the area of a square is directly proportional to the square of its side ,hence ,when the length of the side of a square is halved the area will become one fourth.Option 3 is correct.

hello this is a nice question

Q4)No.of boys = 850No.of girls = 200-850= 1150

1 - 1150 : 850

When simplified, we get 23:17

2 - 2000 : 850

When simplified, we get 40 : 17

hope this will help you like my answer and Mark it as best answer

2)6:4=3:23)i)25:100=1:4II) 25/100=1/4 that part of tank is filled4)i)1150:850=23:17II) 850:2000=17:40

ayushree ge higher answer as 7/8>4/5

66 2/3 % of questions are answered correctly and 7 answers were incorrect.Let the number of questions be x.

66 2/3 % of questions= 200/3 % of questions= (200/3*100) *x = 2x/3

2x/3 + 7 = xor, 2x + 21 /3 = xor, 2x + 21 = 3xor, 21 =3x-2xor, 21 = x

Total no. of questions = x =21 questionsAnswers he answered correctly = 2x/3 = 2*21/3 = 42/3 =14 questions

Let marks scored by gurudas be xThen ramesh scored=x+15Leela scored=x-7Total score=83x+15+x+x-7=833x+8=833x=83-83x=75x=75/3x=25Therefore marks scored by gurudas is 25

25 could be the answer.

The calculation is based on this (48÷6×1/3) + (2/3×3/2)

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In ΔOAB,AB = OA = OB (radii)Hence ΔOAB is an equilateral triangleThat is each angle of ΔOAB is 60°∴ ∠AOB = 60°∠AOB = 2∠ACB [Angle subtended by an arc of a circle at the centre is double the angle subtended by it on any part of the circle]Hence∠ACB = 30°In cyclic quadrilateral ADBC∠ADB +∠ACB = 180° (Sum of opposite angles in cyclic quadrilateral is 180°)⇒ ∠ADB = 180° − 30° = 150°Therefore, angle subtended by the chord at a point on the major arc and the minor arc are 30° and 150° respectively.

middle term of the AP = 55 + 1/2= 28

thanks for your knowlage

all are power of 17 so we can directly compute the following as: 3.5+x=8 so x=8-3.5=4.5

Option 2 is correct.