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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 79051. |
LA, मव्न काना:\frac{\sqrt{5}}{\sqrt{3}+\sqrt{2}}-\frac{3 \sqrt{3}}{\sqrt{2}+\sqrt{5}}+\frac{2 \sqrt{2}}{\sqrt{3}+\sqrt{5}} |
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| 79052. |
17) in the given figure, if AB=AC, ABAD = CAE than prove that LADE is an isosceles triangle.ARC DR R |
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Answer» Given :AB=AC Thus <ACB = <ABC (as angles opposite to equal sides are equal) Also, <BAD = <CAE ----- (1)<ABC = <ACB Hence, <ABD = <ACE ----(2)Adding (1) + (2) <BAD + <ABD = <CAE + <ACESince, external angle of a triangle is equal to the sum of two opposite internal angles. <ADE = <BAD + <ABD and <AED = <CAE + <ACE Therefore, <ADE = <AED Hence, two angles are equal in the triangle ADE and it can be said to be an isosceles triangle. Hence proved |
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| 79053. |
How will you know if a triangle is a right-angled triangle? |
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Answer» We can use Pythagoras' Theorem tocheck if a triangle is right-angled, using the following method: Square the two shorter sides and add the values together. Square the longest side. Check if the results are same. we can know whether a triangle is a right-angled triangle by seeing the sides one of them should be 90 degree and two of the other sides should be acute angles i.e. less than 90 degree |
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| 79054. |
\frac { \sqrt { 2 } ( 2 + \sqrt { 3 } ) } { \sqrt { 3 } ( \sqrt { 3 } + 1 ) } - \frac { \sqrt { 2 } ( 2 - \sqrt { 3 } ) } { \sqrt { 3 } ( \sqrt { 3 } - 1 ) } |
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| 79055. |
3 \text { Simplify: } \frac { 7 \sqrt { 3 } } { \sqrt { 10 } + \sqrt { 3 } } - \frac { 2 \sqrt { 5 } } { \sqrt { 6 } + \sqrt { 5 } } - \frac { 3 \sqrt { 2 } } { \sqrt { 15 } + 3 \sqrt { 2 } } |
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| 79056. |
25. I a survey of 400 students in a school, 100 were listed as taking apple juice, 150 as taking orange juice and 75were listed as taking both apple as iwell as orange juice. Find how many students were taking neither apple juicenor orange juice |
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| 79057. |
In a survey of 400 students in a school, 100 were listed as taking apple Juice, 150 astaking orange juice and 75 were listed as taking both apple as well as orange Juice,Find how many students were taking neither apple Juice nor orange juice. |
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| 79058. |
Suresh and Ramesh together invested144000 rupees in the ratio 4:5 andbought a plot of land. After some yearsthey sold it at a profit of 20%. What isthe profit each of them got? |
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| 79059. |
. Find the value ofT TOL e9. Without using distance formula, show that points (2,-1), (4,0), (3,3) and (-3,2)are the vertices of a parallelogram |
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| 79060. |
19 A trust has Rs 30,000 that must be invested in two differenttypes of bonds. The first bond pays 5% interest per year andsecond bond pays 7% interest per year. Using, matrixmultiplication, determine how to divide Rs 2000 among the twotypes of bond if the trust fund obtains an annual total interest of(a) Rs. 1800(b) Rs 2000 |
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| 79061. |
Convert:a) 40 months into years and months |
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Answer» 12 month= 1 year1 month= 1/12 year40month= 40/12= 20/6= 10/3 year the answer is 10 /3 .......,.... . |
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| 79062. |
1. What is the present worth of a sum of 7,488due six months hence at 8% p.a. simpleinterest |
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| 79063. |
the lenght of the two sides of a right angled triangle cointaing the right angle differ by 2cm.If the area of the triangle is 24cm square, then find the perimeter of the triangle |
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| 79064. |
: The difference between the sides of a right angled triangle containing the right angleis 7em and its area is 60 cm2. Calculate the perimeter of the triangle. |
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| 79065. |
its first (m + n) terms is zero.10. The perimeter of a right triangle is 60 cm. Its hypotenuse is 25 cm. Find the area of the triangle. |
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Answer» Perimeter of that triangle = 60cm the measure of hypotaneous = 25cm then the rest sides must measure = 60-25= 35 let one side be xthen, thw measure of the third side must be 35 - xusing pythagoras theorem (25)^2 =(x)^2 + (35-x)^2625 = x^2 + x^2 - 70x + 1225 x^2 + x^2 - 70x + 1225 = 625x^2 + x^2 - 70x + 1225 -625 = 02 x^2 - 70x + 600 = 02x^2 - 40x - 30 x + 600= 02x (x-20) -30 ( x - 20) = 0(x-20)(2x-30)=0x -20 = 0x = 20 2x -30 =02x =30x = 15so,one of the side measure either 20 cm 15 cmif one side measure 20cm then the other must measure 35 -20 = 15cmand if it measured 15 cm then the other side measure 35-15 = 20 cmso,we will get 20cm and 15 cm as our remaining sides. one of then will be height and the other misy be the base,now apply the formula of area of triangle i.e (1/2) (height)(base)= (1/2 )(20)(15) = 150 cm^2so, the area of that triangle will be 150 cm^2. |
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| 79066. |
(-2*sqrt(5) %2B 3*sqrt(3))/(2*sqrt(5) %2B 3*sqrt(3)) %2B (2*sqrt(3))/(-sqrt(3) %2B sqrt(5)) |
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| 79067. |
: Pooja sold a T.V for? 15,000 and earned profit or 2500. Find heprofit %? |
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| 79068. |
rpenter workNOTSwere asked to choose their favourite fruit. One-fourth choose apple, one-hind dhoschoose orange and three people choose litchi. FHow many people were thee in thealue Based Questiono-fifthOut of junk food and fruits which one do you prefer and why? |
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Answer» Let's say there are x people in total:x/4 chose applex/3 chose banana2x/5 chose orange3 chose litchiwe can now see that the sum of these 4 terms will give us x,x/4 + x/3 + 2x/5 + 3 = xhence , solve this equation (it's easy)solution: x/4+ x/3 = 7x/127x/12 + 2x/5 = 59x/60so we have:59x/60 + 3 = x3 = x - 59X/603 = (60x-59x)/603*60 = x = 180 |
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| 79069. |
8. An amount of money invested trebled in 6 years. Find the rate of interestearned. |
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| 79070. |
Vaishali invested rupees 25000 with an institution which would pay the rate of interest 8%per annum during the first year and 6 percent per annum in the second year find the amount she will get back after 2 years |
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Answer» From which book have you taken this question? Please tell us so that we can provide you faster answer. |
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| 79071. |
interest. How much money did shl mOCLL13. Vijay had some bananas, and he divided them into two lots A and B. He sold thefirst lot at the rate of Rs 2 for 3 bananas and the second lot at the rate fRe I per banana, and got a total of Rs 400. If he had sold the first lot at the rate oRe 1 per banana, and the second lot at the rate of Rs 4 for 5 bananas, his tolcollection would have been Rs 460. Find the total number of bananas he had |
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Answer» He soldall the first lot at the rate of 2 for 3 andthe second lot and rate of 1 per banana and got a total of 400 (A/3)2 + B = 400 2/3A + B = 400 ------- (i) If he had sold the first lot at the rate of 1 per banana and the second lot at the rate of 4 for 5 banana his collection would have been for 60 A + (B/5)4 = 60 A + 4/5B = 60 --------- (ii)2/3A + B = 400 ------- (i) x 3/2 A + 4/5B = 60 --------- (ii) A + 3/2B = 600 --------- (iii) Subtract (iii) from (ii) -7/10B = -540 B = 771(3/7) A + 4/5(771 3/7)= 60 --------- (ii) A = -557(1/7) Since the value of B is a fraction and the value of A is negative, the problem has no solution |
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| 79072. |
1. Convert 2:5 ratio to percentage.iniont of each ter |
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Answer» 40 is a good answer 2/5 ×100 = 40% is the answer 40 is the correct answer😎😎 40 % is the best answer |
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| 79073. |
prize=15X60 = Rs 40.Divide Rs 1380 among Ahmed, John and Babita so that the amount Ahmedreceives is 5 times as much as Babita's share and is 3 times as much as John'sshare. |
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Answer» share of ahmad =900,share of John =300,share of babia =180 |
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| 79074. |
At the rate of 8-% p.a. simple interest, a sum of Rs. 4800 will earn how muchinterest in 2 years 3 months ?(a) Rs. 796(b) Rs. 816(c) Rs. 918(d) Rs. 956 |
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| 79075. |
The price of a refrigerator has increased by 12%few months back the price was 9600. Find thepresent price of the refrigerator. |
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| 79076. |
1.What is the present worth of a sum of 7,488due six months hence at 8% p.a. simpleinterest? |
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| 79077. |
1 ^ 2 %2B 2 ^ 2 %2B 3 ^ 2 %2B \ldots %2B n ^ 2 = \frac n ( n %2B 1 ) ( 2 n %2B 1 ) 6 |
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| 79078. |
uutyafter%ARldater s6days, the employee receivdays 6 days, the employee receiVe(C) 13 daysn becomes 5600 in a year. Find how(C) 2950(B) 19 days(D) 18 dauy57. Therenumber of worincrea eincreased by 1 500 then th0 population in a village. If the number ofincreased by 10% and thewere therein itvill o3075n the villagethen the total population becomesS600ina(B) 3205(D) 3000 |
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Answer» Suppose number of males =mand number of females =fso m+f=5000after increase males by 10% m1=110m/100and female by 15% f1=115f/100and m1+f1=5600so putting values of m1 and f1equation become 110m+115f=560000 after solving both equations we get f=2000 and m=3000so no of males =3000 answer is (d) |
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| 79079. |
Assume π--,unless stated oderwise.7LDiameter of the base of acone is 10.5 ㎝ and its slant height is 10 cm. Find its curace area |
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Answer» thank u |
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| 79080. |
dence, Base 2x-24 cm or, 10 cm.EXAMPLE 9 The perimeter ofa right triangle is 60 cm. Its hypotenues is 25 cm. Find the area of theriangle.UITION Let ABC be the given right angled triangle such that base BC x cm and[CBSE 2016] |
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Answer» Perimeter of that triangle = 60cm the measure of hypotaneous = 25cm then the rest sides must measure = 60-25= 35 let one side be xthen, thw measure of the third side must be 35 - x using pythagoras theorem (25)^2 =(x)^2 + (35-x)^2625 = x^2 + x^2 - 70x + 1225 x^2 + x^2 - 70x + 1225 = 625 x^2 + x^2 - 70x + 1225 -625 = 0 2 x^2 - 70x + 600 = 02x^2 - 40x - 30 x + 600= 02x (x-20) -30 ( x - 20) = 0(x-20)(2x-30)=0 x -20 = 0x = 20 2x -30 =02x =30x = 15 so,one of the side measure either 20 cm 15 cm if one side measure 20cm then the other must measure 35 -20 = 15cm and if it measured 15 cm then the other side measure 35-15 = 20 cm so,we will get 20cm and 15 cm as our remaining sides. one of then will be height and the other misy be the base,now apply the formula of area of triangle i.e (1/2) (height)(base)= (1/2 )(20)(15) = 150 cm^2 so, the area of that triangle will be 150 cm^2. |
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| 79081. |
-40*f*m*o*r*text*x %2B 3*x - 17 |
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Answer» 8x-17 - 3x-58x-3x-17-55x-22 Ans 5x-22 the correct answer of the given questio (8x-17)-(3x-5)8x-17-3x+55x-12 |
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| 79082. |
glapnnt in a hospital is given soup daily in a cylindrical bowl of diameter 7 cm. If theatiel is filled with soup to a height of 4 cm, how much soup the hospital has to preparebowdaily to serve 250 patients? |
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| 79083. |
doce buildingneeds to be painted f thecircumference of the base of thedome is 17 .6 m Find the cost ofpainting it, given the cost of paintine s(i) 5 Rs per 100 cm'ĺ4per 100 cm. |
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| 79084. |
A shopkeeper earned a profit of 5% by selling a television for8500. Find the cost price of the television. |
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Answer» let cost price be xsox + 5% of x = 8500x + x/20 = 850021x/20 = 8500x = (8500× 20)/21x = ₹8,095.23 |
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| 79085. |
A survey of 550 T.V Watchers produced the followinginformation.285 watch football game, 195 watch hockey game, 115watch cricket,45 watch football and cricket, 70 watch football andhockey,50 watch hockey and cricket. 100 do not watch any of threegames.How many people watch exactly one of the three games?How many people watch all three games? |
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Answer» 1st anawer = 4502nd answer=203rd answer=325 Answer meplease try again |
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| 79086. |
re alone would have made the tyre flat in 9 minutes and thee it in 6 minutes. If air leaks out at constant rate, how long does it take. A tyre has two punctures. The first punctusecond alone would have donboth the punctures together to make it flat?3 |
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| 79087. |
togethel.Tsc ow tOng will tap A take to 1 uheter tank has 3 inlets. Inlet A alone can fill the tank in 30 minutes. Inlet B can fill it in 40C can fill it in 60 minutes. If all the 3 inlets are opened together, how long will it take to niwa5.l it in 40 minutes.g will it take to fill thetank?hr Tan O can empty the |
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Answer» Let t = the time to the fill the tank t/30 + t/40 + t/60= 1 40X60t +30X60t +30X40t = 30X40X60 24t.+18t + 12t = 120X6 4t+ 3t + 2t = 120 9t= 120 t =120/9 t =13 minutes and 3/9*60 = 13minutes and 20 seconds |
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| 79088. |
The cost of constructing a road is Rs 5,000 per 100 m2. Find the cost of constructing a road 5mbroad surrounding a garden 100 m long and 10 m broad. |
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| 79089. |
sla UL ULULUThe cost of a wheat bag weighing 100 kg is Rs 725. What is the cost of 7 kg of thiswheat?Otstofich das ? |
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Answer» cost of a wheat bag weighing100kg = 725 cost of 1kg = 725/100 = 7.25 ₹ cost of 7 kg = 7×7.25 = 50.75₹ ans |
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| 79090. |
2. If a dozen pastries coSl RS 2.00One quintal of rice costs Rs 880. What is the cost of 20 kg of rice? (I quintal 100le of a class is Rs2 940. How much feecuIe of 2 dlasi is Rs 940 H much fre3. |
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Answer» 1 quintal is 100kghence 100kg Costs 880 rupeeshence20 kg will be as 100/5=20hence880/5=176rupees |
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| 79091. |
The mean of 18 observation is 7 and if each observation 5 is added, then the new mean will bea) 220.b) 12c) 7d) 17 |
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Answer» Each observation will be +5so mean will be +5 with the original as wellso new mean will be7+5= 12 |
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| 79092. |
A computer costs39,600. In the last 6 months, the price had come down by 12 per cent. What wasthe price of the computer six months back? |
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Answer» thanks |
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| 79093. |
2^40 %2B 2^40 |
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Answer» 2^40 + 2^40 = 2^40(1 + 1) = 2^40*2 = 2^(40 + 1) = 2^41 |
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| 79094. |
- b ) x + ( a + b ) y = a ^ { 2 } - 2 a b - b ^ { 2 } \text { and } ( a + b ) ( x + y ) = a ^ { 2 } + b ^ { 2 } |
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Answer» ax-bx+ay+by=a^2-2ab-b^2ax+bx+ay+by=a^2+b^2subtract 2nd from 1st-2bx=-2ab-2b^2so x=a+bby putting x in 1st equation(a-b)(a+b)+(a+b)y=a^2-2ab-b^2a^2-b^2+(a+b)y=a^2-2ab-b^2so y=-2ab/(a+b) |
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| 79095. |
\frac{a+b}{a-b}+\frac{a-b}{a+b}+\frac{a^{2}+b^{2}}{b^{2}-a^{2}} |
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| 79096. |
25*(y^2*(quad*text)) %2B 16*x^2 %2B 40*(x*y) |
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Answer» i) 16x² + 40xy + 25y² (4x)² + 2 × ( 4x) × (5y) + (5y)² (4x + 5y)² ii) 81x⁴ - 121x² x² ( 81x² - 121) x² ( (9x)² - 11²) x² ( 9x - 11) ( 9x + 11) |
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| 79097. |
16. How many cubes of 5 cm can be cut out from acuboid of 25 cm x 19 cm x 10 cm?17. A fish tank of length 80 cm and breadth 50 cmcontains 120 dm^3 of water. Find its height.18. The volume of a cube is 8000 cm^2. Find ts totalsurface area. |
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Answer» 18)we know that ;volume of cube = a³andsurface area of cube = 6a² where a is the side of cube. here,According to given= a³ = 8000 cm³= a = 20 cm now,surface area of cube = 6a² = 6 * 20² 6 * 400 = 2400 cm² 16)suppose n cubes can be made out of this dimensionso n * 125= 25*19*10n= 4750/125=38 thnx bro |
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| 79098. |
8 cmFind the volume of the right circular cone with0 radius 6 cm, height 7 cml.(u) radius 3,5 cm, height 12 cm |
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| 79099. |
A water tap A takes 7 minutes more than water tap B for filling up a tank with water4The tap A takes 16 minutes more than the time taken by both the taps together tthe tank. Find the time each tap alone would take to fill the tank. |
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Answer» Let the time taken by A is x minutes and B is y minutes, Hence from the 1st statement we have, x-y = 7 = > y = x-7..........................eq1 Now, in one minute tank filled by A = 1/x and in one minute tank filled by B = 1/y So combine together both can fill = 1/x + 1/y tank in one minute, Hence time taken by both the taps to fill the tank = 1/(1/x + 1/y) = xy/x+y Now from the second statement, x- xy/x+y = 16 => x² + xy - xy = 16(x+y) => x² -16x - 16y = 0 Putting the value of y from eq1 x²-16x - 16(x-7) = 0 => x² - 32x + 112 = 0. Solving the above quadratic eqn, we get x = 28 or 4 rejecting 4 as x can't be less than 7 x = 28 y = x-7 = 28-7 = 21 Hence time taken by both the taps are 28 and 21 minutes alone. hit like if you find it useful |
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| 79100. |
27. The angle of elevation of a tower from a point on the same level as the foot of the tower is 30°.n advancing 150 metres towards the foot of the tower, angle of elevation of the tower becomes 60°tto tlho airole making an anole of 30° with a lineShow that the height of tower is 129.9 metres. |
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