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5)i)22/5=4 quotient; 2=remainder; ii)47/2=23 quotient; 1= remainder; iii)103/9=1 quotient; remainder=4; iv) 437/17=25 quotientremainder 12

1) 22/5 = 22÷5 quotient=4 remainder=2ans. 4&2/52) 47/2 = 47÷2 quotient =23 remainder = 1ans. 23&1/23) 103/9 = 103÷9 quotient =11 remainder= 4ans. 11&4/94) 437/17 quotient =25 remainder= 12ans. 25&12/17

3 2/7=7*3+2=22/7 is the answer

7×3+2=23/76×8+1=49/87×9+4=67/9

thanks😀😁😂

Let age of Amit = 5xLet age of Amit sister = 4x

Given age of Amit = 45

Then,5x = 45x = 45/5 = 9

Age of Amit sister = 4x = 4*9 = 36 years

Let the age of rohan be x

Rohan's mother=x+26

after 3 years,

(x+26+3) (x+3)=(x+29)(x+3)=x²+3x+29x+87=360=x²+32x=273x(x+32)-273=0

solve it x=7,

Mother's age=7+26=33

Let take Rohan's age = x years

Rohan’s mother is 26 years older than him

Rohan's mother age = x + 26 years

3 years from now

Rohan's age = x + 3

Age of Rohan's mother will = x + 26 + 3 = x + 29

The product of their ages (in years) 3 years from now will be 360 so that

(x + 3)(x + 29) = 360

or, x²+ 29x + 3x + 87 = 360

or, x²+ 32x + 87 - 360 = 0

or, x²+ 32x - 273 = 0

This is our required equation

Let Rohan's age be x ....... Therefore Rohan's mom's age is x+26...... Now Roahn age after 3 yrs x+3 and his mothers age after three years x+29...... Now we know (x+3)(x+29) = 360 ...... ... x²+3x+29x+87 = 360 ...... x²+32x+87=360 ....... x²+32x=360-87 ...... = 273 x(x+32)=273 After solving we get x=7 So, age of Rohan = 7 yrs The solution for how to get x is Take one factor of the equation x²+32x-273 = 0 First factorise .... Factors are x-7 and x+32 ...... So take any one factor and solve it and you will get two solutions of the quadratic equation...... X-7.....x=7 And x+32.....x=-32 Now put your logic age can't be in minus so x=7 is correct solution for this question...Hence solved।

you can check from reference book

a. and d. are improper fraction and b. and c. are proper fraction

Proper=a, dImproper=b, c

proper=a,dimproper=b,c

this sum 3D geometry ....so slove another method

A Cartesian plane is a graph with one x-axis and one y-axis. These two axes are perpendicular to each other. For the y-axis, numbers below zero are negative and numbers above are positive. The Cartesian plane showing several ordered pairs, which represent points on the graph.

thanks for answering

tnx shrivali

marking a point on a Cartesian plane using thier coordinate is called coordinate graphing

Present Chandrika age = 12 yrsPresent Piyush age = 4 yrs

Let after n yrs Chandrika is twice old as Piyush

Then12 +n = 2(4+n)12 + n = 8 +2nn = 12-8= 4

After 4 yrs Chandrika is twice old as Piyush

Given the dimensions of classroom is 10m×6.4m×5m , area = 10*6.4 = 64m² so the volume of the class room will be = 320m³

now each student needs 1.6m² on the floor so no. of Student = room area/(Student area) = 64/1.6 = 40 Students.

now volume of air for each student will be = total volume/no. of Student = 320/40 = 8m³

Let ages of father and son be 6x years and x years respectively.

So, 6x + 4 = 4(x+4)or, 6x + 4 = 4x + 16or, 2x = 12or, x = 6So, 6x = 6*6 = 36

Answer:- (C) - 6 and 36

Let take Rohan's age = x years

Rohan’s mother is 26 years older than him

Rohan's mother age = x + 26 years

3 years from now

Rohan's age = x + 3

Age of Rohan's mother will = x + 26 + 3 = x + 29

The product of their ages (in years) 3 years from now will be 360 so that

(x + 3)(x + 29) = 360

or, x2+ 29x + 3x + 87 = 360

or, x2+ 32x + 87 - 360 = 0

or, x2+ 32x - 273 = 0

This is our required equation

Let Rohan age is x yrsRohan mother age = x + 26

After 3 yrsRohan age = x + 3Rohan mother age = x + 3 + 26

As per given condition(x+3)(x+29) = 360x^2 + 32x + 87 = 360x^2 + 32x - 273 = 0x^2 + 39x - 7x - 273 = 0x(x + 39) - 7(x+39) = 0(x-7)(x+39) = 0x = 7, - 39

Rohan present age = 7 yrs

30%=200+10=21030%x=210x=210/30%x=210*100/30x=700Total marks=700

In one whole circle from positive x axis then anticlockwise, it is 360°.Now in one round= 360°2 rounds= 360 x 2 = 720So 750 - 720 = 30Implies this will lie in the first quadrant

This number = (1/4+1/5)/2= 9/40 will lie between 1/4 and 1/5

i)(2,-3) is in 2nd quadrant.

ii)(3,2) is in 1st quadrant

iii)(-5,-7) is in 3rd quadrant

iv) (5,-2) is in 2nd quadrant

From which book have you taken this question? Please tell us so that we can provide you faster answer.

(iii) inconsistent, ifa1/a2=b1/b2not equal to c1/c2i.e. the lines represented by equations are parallel and non-coincident

x=3 should satisfy the given equation,(3)^2-2k(3)-6=0 9-6k-6=0 3-6k=0 6k=3k=1/2

Rahul is 12 year old

Rahul is 12 years old.

Rahul is 17 year old

let X = rahul ageY = father age

a/q,Y= 535+4X = 534X = 48X = 12rahul age is 12

rahul is 22 year old

let the Rahul's age be 4x

according to question,4x + 5 = 534x = 53 - 54x = 48x = 48/ 4x = 12Rahul's age is 12 year old

rahul is 12 year old

rahul is 12 years old

According to question Rahul's age-(53-5)/4= 48/4 =12

53=5+(4*X)X=12Rahul is 12 years old

let mohit's age be xhence 50 = 4 + 3x

if akanksha =15shweta=15-3=12ankit=12-2=10

Answer:

24 years

Step-by-step explanation:

Let her present age is 'x' years.

According to the given condition, we get

=> (1/3)[x - 3] + (1/2)[x + 2] = 20

=> (x-3)/3 + (x + 2)/2 = 20

=> 2(x-3) + 3(x+2) = 20 * 6

=> 2x - 6 + 3x + 6 = 120

=> 5x = 120

=> 5x = 120

=> x = 24.

Therefore, She is 24 years old.

Let present age of mother be x and daughter be yx-2/y-2=8/1x-2=8y-16x-8y=-14.......(1)

x+2/y+2=4/1x+2=4y+8x-4y=6….......(2)

Subtract equation 1 from 24y=20y=5x=6+4(5)=6+20=26Mother is (26-5) total 21 years elder than her daughter

Let the present age be xAfter 12years=x+124 years ago =x-4x+12=3(x-4)x+12=3x-1212+12=3x-x24=2x24/2=x12=x

distance=speed*hour =36*4=144km

distance =speed×timedistance=36×4=144km/h

144 km/ hr is the right answer

speed = 36 km/h, time = 4hrs, 36 x 4 = 12 + 24 = 144

144km/hr is the correct answer

so, distance is 144km.

distance=speed × timedistance is 144km.

144km is the distance.

144km is the distance is the right

144 km/h is right answer

144km total covered in 4hour

where is the answer

sorry I got my answer