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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 79751. |
कड़ा 0, 13, 17, 19, 12, 1578 उ20, 19 और 17 का बहुलक ज्ञात कीजिए। 1 |
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Answer» एक आयताकार बाग का अर्ध परिमाप 36 मी है जिसकी लंबाई , चौड़ाई से 4 मी अधिक है। बाग की विमाएँ ज्ञात कीजिए। |
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| 79752. |
(c) Number of boys to the total number ul stud11. Out of 1800 students in a school, 750 opted basketball, 800 opted cricket and remaäiopted table tennis. If a student can opt only one game, find the ratio of(a) Number of students who opted basketball to the number of students whotable tennis.(b) Number of students who opted cricket to the number of students opting bas(c) Number of students who opted basketball to the total number of studentsf0 hall nens is 56 Find the rtoo |
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| 79753. |
Mohan went to buy a Trapezium shaped field its side along the river is parallel to and twice the side along the road if the area of this field is 10500 square and the perpendicular distance between the two parallel sides is 100 find the length of the side along the river |
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| 79754. |
2. One kind of cake requires 200g of flour and 25g of fat, and another kind of cakerequires 100g of flour and 50g of fat. Find the maximum number of cakes whichcan be made from 5kg of flour and 1 kg of fat assuming that there is no shomageof the other ingredients used in making the cakes. |
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| 79755. |
One kind of cake requires 200g of flour and 25g of fat, and another kind of cakerequires 100g of flour and 50g of fat. Find the maximum number of cakes whichcan be made from 5kg of flour and 1 kg of fat assuming that there is no shortageof the other ingredients used in making the cakes.2. |
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| 79756. |
tudents passed with first division in the class A of 25 students. In class B,24 students passed with first division out of 30 student? From which classmore part of students passed with first division? |
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| 79757. |
Using a suitable identity, Without actually finding the cubes evaluate (-28)^{3}+(9)^{3}+(19)^{3}. Also mention the identity used. |
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Answer» tq |
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| 79758. |
EXERCISe a suitable identity to get |
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Answer» (x+3)(x+3) = (x+3)² (a+b)² = a²+2ab+b² (x+3)² = x²+6x+9 |
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| 79759. |
Evaluate: (104)8 using a suitable identity |
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Answer» the identity used is (a+b)³ = a³+b³ +3a²b + 3ab² here the no is 104 = 100+4so 104³ = (100+4)³ => (100+4)³= 100³+4³+3(100)²(4) + 3(100)(4)² => 104³ = 1000000 +64+120000+4800 => 104³ = 1,124,864 thanks |
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| 79760. |
The following data indicates the marks of 53 students in Mathematics.MarksNumber of students0-1010-2020-3030-4040-5050-6060-7044470-8080-9090-100aw less than type ogive for the data above and hence find the median |
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| 79761. |
36 x ^ { 2 } - 49 ( y - x ) ^ { 2 } |
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Answer» (6x)^2-(7(y-x))^2=(6x+7y-7x)(6x-7y+7x)=(7y-x)(13x-7y) |
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| 79762. |
8. Factorise the following(iiix+82+19 12(v)x3+2x+2 |
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Answer» 3) thanks |
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| 79763. |
A school has 9 periods a day each of 40 minutes duration. How long would each period be, iflllIIJllIS.T10Wlarcanittravfel7.in25minutesthe school has 8 periods a day, assuming the number of school-hours to be the same?25xt-4 |
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| 79764. |
A tea party is arranged for 16 people alongtwo sides of a long table with 8 chairs on eachside. Four men wish to sit on one particularside and two on the other side. Then thenumber of ways that they can be seated is |
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| 79765. |
There are 104 students in class X and 96 students in class IX in a school. In a houseexamination, the students are to be evenly seated in parallel rows such that no twoadjacent rows are of same class. Find(a) the maximum number of parallel rows of each class for the seating arrangement.(b) the number of students of class IX and class X in a rowCBSE 2013] |
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Answer» There are a total of 200 students (104 and 96). Both 104 and 96 are divisible by 8, i.e. 104/8 = 13 and 96/8 = 12. a). Therefore the maximum number of parallel rows would be 12+13 = 25. And, 200/8 = 25. b). Number of students in each row would be 8. c). The objective of the school behind such an agreement would be to easily arrange the students in rows such that no adjacent rows have students belonging to one class. |
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| 79766. |
3. The length and breadth of a hall of a school are 26 m and 22 m respectively. If onestudent requires 1.1 sq. m area, then find the maximum number of students to beseated in this hall. |
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Answer» Area of hall= length * breadth= 26*22= 572 m^2 If each student requires 1.1 sq m area Then,Number Of students to be seated in hall = 572/1.1 = 520 |
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| 79767. |
The number of hours for which students of a particularholidays is shown through the given graph.Answer the following.0 For how many hours did the maximum number of students(ii) How many students watched TV for less than 4 hoursof hours for which students ofa puricular class |
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| 79768. |
13, The number of hours for which students of aparticular class watched television during holidays32shown in the histogram alongside.竝2-1Answer the following:) For how many hours did the maximum number12of students watch T.V?(i) How many students watched T.V. for less thanHours of TV watched per day4 hours?(ifi) How many students spent more than 5 hours in watching T.V.?ln) How many students spent more than 2 hours but less than 4 hours in watchingT.V.? |
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| 79769. |
ToW nany students are there in totalooow inany students are there in total13. Kumar spends 30% of his pocket money on stationary and 3 % on sweets. In a particularmonth, he spends 231 on these two items. What is his total pocket money for thisth 2 |
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Answer» He spent total (30+3) = 33% of his pocket money. Let his pocket money be XThen, (33/100)*X = 231=> X = (231*100)/33= ₹ 700Please hit the like button if this helped you |
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| 79770. |
3. Expand 902-462 by wing suitableidentity? |
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Answer» aa we know that :- ( a^2 -b^2 ) = (a+b)( a+b)(3a +2b)(3a- 2b) (a+b)(a+b)(3a+2b)(3a-2b) |
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| 79771. |
EXAMPLELE Find the missing frequencies in the following frequency distributionetable, if N 100 and median is 32.0-10 10-20 20-30 30-40 40-50 50-60 TotalNumber of10 25 30 10 100students |
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| 79772. |
EXAMPLE 8.1n theo notEvaluate the following :(b)-25+-16(d) v/-36-./-49t(a) 100roots-25 |
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Answer» a) √-100 = √100.√-1 = 10i similarly b) √-25+√-16 = √25i+√16i = 5i+4i = 9ic) √-8 -√-2 = √8i-√2i = 2√2i-√2i = √2i d) √-36.√-49 = 6i.7i = 42i² = -42e) √-25/√-5 = 5i/√5i = √5 |
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| 79773. |
Given $\Delta \mathrm{ABC}-\Delta \mathrm{PQR},$ if $\frac{\mathrm{AB}}{\mathrm{PQ}}=\frac{1}{3},$ then find $\frac{\mathrm{ar} \Delta \mathrm{ABC}}{\mathrm{ar} \Delta \mathrm{PQR}}$ |
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| 79774. |
$ \Delta A B C $ and $ \Delta $ DEF are equilateral triangles. If $ A(\Delta A B C) : A(\Delta D E F)=1 : 2 $and $ A B=4, $ find $ D E $ . |
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| 79775. |
An army contingent of 616 members is to march behind an army band of 32 members ina parade. The two groups are to march in the same number of columns. What is themaximum number of columns in which they can march?3. |
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| 79776. |
(Army Tech. 20 |
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Answer» please like my answer if you find it useful |
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| 79777. |
29 x 5-12 x 7 - 13 x 5 + 82 x 8 |
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Answer» first make the question in order first make the question in order 29×5+82×8-12×7-13×5145+656-84-65801-149652 giridhari you must be thinking.Why l added first it should be subtracted according to the formula?but if we add 65+164 Then the answer will come in minus points.please accept my answer is best 652 is the right answer According to my calculation,652 is the correct answer 652 is a right answer🇨🇮🏡😂👈🙏💖🌎🌎👈🏡😍👏🙏 652 is correct answer of this question 652 is the correct answer the answer of the question is 652 this question answer is 652 Answer is 734because of bodmas rule First we should to arrange the question in order29×5-12×7-13×5+83×8=29×5+82×8-12×7-13×5=145+656-84-65=801-149=652652 is the right answer of the question 652 is the best answer me hence answer is 652 correct .... 652 is right answer. 29×5=145-12=133×7=931-13=918×5=4590+82=4672×8=37376 answer 29×5-12×7-13×5+82×8145-84-65+656145+656-84-65801-149652 ans 29×5+82×8-12×7-13×5145+656-84-65801-149652 652 is the right answer of this question 29*5=145145_12=133133*7=931931_13=918918*5=4590 4590+82=46724672*8=37376 first make the question in order29×5+82×8-12×7-13×5145+656-84-65801-149652 145 - 84 - 65 + 656 = 652 652 is correct answer 145-84-65+656=652.okk 652 is the best answer. 752 is correct answer 652 is correct answer sorry for previous post is wrong By "DMAS" rule we firstly solve divide, multiplication, addition, subtractionSo,29*5-12*7-13*5+82*8145-84-65+656801-149=652 652 is correct answer 652 is the correct answer h answer is 29×5+82×8-12×7-13×5145+656-84-65801-145=652 652 is the correct answer right answer is 652 in this question firstly make the answer in order 29×5+82-12×7-13×5145+656-84-65 801-149652 is answer 5thousand 216 ans is right find the 145+656-84-65=801-149=652is the answer. 145-84-65+626=771-149=622 652 is right answer from BODMAS theorem 29×5-12×7-13×5+82×8801-149=652 -60467 Right answer 29×5+82×8-12×7-13×5145+656-84-65801-149652 this is the solution your answer will be 660 answer this question is 660 Make the nos. in order,then= 29*5+82*8-12*7-13*5=652 29×5+82×8-12×7-13×5145+656-84-65801-149652 answer 652 because 145-84-65+656=652 652 is the right answer hi que is ans is the 717 29*5-12*7-13*5+82*8=145-84-65+656 801-149=652 652 is the correct answer 652 is the answer of this question 29×5-12×7-13×5+82×8 145-84-65+656145-149+656652 29×5=145 _ 21×8=84 145 _ 84=61_ 13×5=65 65_61 =4 82×8 =576 4+576=580 so the answer is 580 29*5-12*7-13*5+82*8145-84-65+656801-149=652 652 is right answers 652 is right answer nvbm hhbm jjfnn 652 because it was very easy the correct answer is 660 652 is the correct answer.yes 37376 is the right answr 652 is the correct answer. 29×5+82×8-12×7-13×5=145+656-84-65 =501-149=652 29×5+82×8-12×7-13×5=145+656-84-65 =501-149=652is write answer 652 is the correct answer of your question. 29*5-12*7-13*5+82*8145-84-65+656. =660 29*5-12*7-13*5+82*8145-84-65+656. =660 |
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| 79778. |
In 10th Class, if three students sit on each bench one student will be left. If fourstudents sit on each bench, one bench will be left. Find the number of studentsand the number of benches in the class. (Use any appropriate method otherthan Graph) |
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Answer» Let no.of benches=x students=yif 3 students sit on each bench 1 student will be lefty=3x+1..............1if 4 students sit on each bench one bench will be lefty=4(x-1)...........2on resolving 1and 2x=5 y=16no.of benches=5no.of students=16 |
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| 79779. |
51.10 IIT and 2 RPET students sit in a row. The number of ways in which exactly 3 IIT students sit between 2 RPET studentsis(1) 18 x 10!(2) 16 x 10!(3) 16 x 12(4) none |
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Answer» 16*12! is the correct answer how |
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| 79780. |
Q8. A teacher decided to play a game in which she wants all the 20 students of thedassroom to sit along a dirde. In how many ways all 20 students is to be seated if2particular students are always to sit together? |
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Answer» Consider two particular persons as one person. We have 19 persons in all. These 19 persons can be seated around a circular table in (19-1)! = 18! Ways. But two Particular persons can be arranged between themselves in 2! ways. So Total number of arrangements = 18! X 2! |
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| 79781. |
Expand using suitable identity: (2x-y+z)? |
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Answer» 4x²+y²+z²-4xy-2yz+4xz is the correct answer of the given question |
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| 79782. |
(d) The value of 4+tan30ill be2200 Will be(ii) cos 60°(iv) cot 60°1 + tan 30°(i) sin 60°(iii) tan 60° |
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Answer» Answer : i) sin 60Explanation : |
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| 79783. |
Example 25Find the approximate value of 18 x 82 |
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Answer» 146 is correct answer of following question |
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| 79784. |
PAGE NO:DATE:1the value of aand b.©. Find7+157-15+77-15715 |
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Answer» a=0 and b = 1 answer answer is a=0 & b=1 a=0 and b=1 answer is correct |
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| 79785. |
DuyPage No.Date :1in the sum of two consuntive meterMembers is 177 find the number |
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| 79786. |
(a) 4(b)5In 10 years, A will be twice as old as B was 10 years ago, If A is now 9 yearsolder than B, the present age of B is:(d) 49 vears |
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Answer» Let B's present age = x years. Then, A's present age = (x + 9) years. (x + 9) + 10 = 2(x - 10) => x + 19 = 2x - 20 => x =39 |
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| 79787. |
The age of a man is same as his wife's age with the digits reversed. Then sum of theirages is 99 years and the man is 9 years older than his wife. How old is the man?(A) 50 years(B) 49 years (C) 54 years (D) 44 years |
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Answer» the age of the man is 54if it was reversed we got 45 is the age of wife the sum 54+45=99the man is 9 years older than his wife (54-45=9)  1 Secondary SchoolMath5 points The age of a man is same as his wife's age with the digits reversed. The sum of their ages is 99 and the man is 9 years older than his wife. How old is the man? Answers Let the digits of age of the wife be 10x + y (While writing two digits number, it's format is 10a + b) So reverse = 10y + x Given that, reverse of wife's age = man's age => Man's age = 10y + x Also given that, Wife's age + 9 = man's age 10x + y + 9 = 10y + x => 9 = 10y + x - 10x - y => 9 = 9y - 9x => 9y - 9x = 9 => 9(y - x) = 9 => y - x = 9/9 => y - x = 1 .......... equation (1) Also given that,Wife's age + man's age = 99 => 10x + y + 10y + x = 99=> 11x + 11y = 99 => 11(x + y) = 99 => x + y = 99/11 => x + y = 9 .......(equation 2) Adding equation 1 and equation 2, we get y - x + x + y = 1 + 9 => 2y = 10 => y = 10/2 => y = 5 Putting the value of y in equation 1 y - x = 1 => 5 - x = 1 => -x = 1 - 5 => -x = -4 => x = 4 Now age of wife = 10x + y => 10(4) + 5 => 40 + 5 => 45 And age of man is reverse => 54 So age of man = 54age of wife = 45 Hope it helps dear friend ☺️✌️Nice question! Here is your solution Given that :- The age of a man is same as his wife age with the digits reversed then sum of their ages is 99 and the man is 9 years order than his wife Let The man age = 10x +y wife age = 10y +x sum of the ages = 99 10x+y +10y +x =99 11x +11y =99 x+y =9................................................ (1) man age = wife age+9 10x +y = 10y +x+910x-x +y -10y =99x -9y =9 x-y =1 ...............................................(2) Adding equation (1) and (2) 2x =10x= 10/2x= 5 putting the value of x=5 in equation (1) y= 4 Hence, man age =10x+y= 10*5 +4 =50+4 = 54✔ Age of wife = 45 years. ✔ Hope it helps you |
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| 79788. |
In X class, if three students sit on each bench, one student will be left. If four students sit oneach bench, one bench will be left. Find the number of students and the number of benchesin that class. |
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Answer» Let no.of benches=x students=yif 3 students sit on each bench 1 student will be lefty=3x+1..............1if 4 students sit on each bench one bench will be lefty=4(x-1)...........2on resolving 1and 2x=5 y=16no.of benches=5no.of students=16 tnks ans other also |
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| 79789. |
9.Find the product of (x- *)(x + )(x2 + ) using suitableidentity.OIA |
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| 79790. |
25. Some students planned a picnic. The budget for food was Rs. 240. Since, four studentsof the group did not go to picnic, the cost of food increased by Rs. 5 per student. Howmany students went for the picnic? |
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| 79791. |
Find the value of 86 x 82 by using a suitable identity. |
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| 79792. |
Evaluate (998)3 using suitable identitiesConstruct a triangle ARC in which B |
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| 79793. |
52+43+45+40+47+48+50+52+53+56+60 |
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Answer» 52+43+45+40+47+48+50+52+53+56+60=546 |
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| 79794. |
9. The final marks in mathematics of 30 students are as follows:53, 61, 48, 60, 78, 68, 55, 100, 67,90RepThe81,54,PreTh1575, 88, 77, 37, 84, 58, 60, 48, 62, 5644, 58, 52,64, 98, 59, 70, 39, 50, 60(i) Arrange these marks in the ascending order, 30 to 39 one group, 40 to 49 secondgroup, etc.Now answer the following(i) What is the highest score?(ii) What is the lowest score?(iv) What is the range?(v) If 40 is the pass mark how many have failed?(vi) How many have scored 75 or more?(vi) Which observations between 50 and 60 have not actually appeared?(vii) How many have scored less than 50? |
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| 79795. |
90 tickets of a theatre show were sold for乏13,000. If the tickets were sold in the denominaof27100 and200, how many tickets of each denomination were sold? |
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| 79796. |
Sagar bought 30 tickets in.all, of which some cost 15 and the-rest. cost 20.the total cost of the tickets was 54how many tickets of 20 were boughtow man |
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Answer» Let the no. of 15 rs tickets be x and 20rs ticket be y hencex+y=30....(1) case 2 15x+20y=540 .....(2) dividing whole equation by 3 we get 3x+4y=108 by elimination method x+y=30.. X3 3x+4y=108-3x-3y=-90hence y=18 x= 30-18 , x=12 y=18 |
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| 79797. |
DELTA Page 1Datefind Iso that19 |
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Answer» (-3/19)^8 * (3/19)^-18 = (3/19)^3x (-1)^8 * (3/19)^[8 - 18] = (3/19)^3x (3/19)^[-10] = (3/19)^3x 3x = - 10 x = - 10/3 Therefore, value of x = - 10/3 |
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| 79798. |
In an exhibition 300 tickets were sold. The total sale of tickets was 1250. Ifof two denominations of 2.50 and 5. How many tickets ofeach denomination were sold? |
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Answer» 100rs 2.5tickets200rs 5tockets |
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| 79799. |
2. Rajeev bought some Army Day tickets for 5 and 10. If he spent $150 and bought 18 tickets in all, find howmany tickets of each kind he bought? |
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| 79800. |
. In lO years, A will be twice as old as B was 10 years ago, If A is now 9 yearsolder than B, the present age of B is:(a) 19 years (b) 29 years(c) 39 years(d)49 years |
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