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upper boundary is 10

upper boundary will be 10 in this caseThe lower limit for every class is the smallest value in that class. On the other hand, the upper limit for every class is the greatest value in...

The main thing to remember is our basic idea that distance = rate x time.

If we think about it, no matter how far each train travels, when they meet, they will have together travelled 390k.

If we let x = the time travelled by train A, then train B travels x - 1 hours, because it left one hour later.

Train A's distance is then 65x and train B's is 35(x - 1) = 35x - 35.

Together, the trains travel the 390k

65x + 35x - 35 = 390

100x - 35 = 390

100x = 425

x = 4.25 = 4 hours and 15 minutes

So, the two trains meet at 2:15.

a+b/2 = 34 hence a+b = 68 .256 = ab.from here, u get :a(68-a)=256a2-68a+256=0(a-4)(a-64)=0hence,a= 4 or a = 64b=64 or b = 4

hence numbers are 4 and 64.

Due to stoppages, it covers 9 km less.

Time taken to cover 9 km = (9/54) hour= (1/6)*60 minutes= 10 minutes

10 km hi 2 hrs is the answer

The relative speed=50+65=115km/hrthe distance=345 kmtime =345/115=3 hr

Given x + y and xy.Use the identity (x - y)^2 = (x + y)^ - 4xy and find x - y.Solve x + y and x - y and obtain x and y.

a+b=68ab=256Then by substitutiona+256/a=68a²-68a+256=0a=(68+-root(68²-(4*1*256))/2=68+-60)/2=64,4Now find b

Let the Number be x and yxy= LCM x HCFxy= 9 x 819xy = 7 x 9 x 9 x 13The number can be (9,91) (9,819) but because we know that one of the number is in two digitthe numbers are - 9,91

Let the one nu.is x Other x + 72 X+ 72/×=4 ×+72=4× 4x-x=72 3x=72 X=24 ans One number is 24 Other 72+24=94

plz accept as best

y-24, x-96 plz give me point byyyyyyyyyyyyyyyyyyyyy

the least of P would be 8+1 = 9

because in 1 hour only 1 A bus can come.

suppose B comes in every 59 min.

so before end of 8th hour , only 7 A busses would come.

but since 59min will complete first before the completion of that last hour , so bus B will come again.

so min value of B will always be A+1.that is 9.

which of the plant around you need regular watering

[a] the minute hand will take 60 minutes to come back 2 again. [b] yes the hour hand also moves. it takes one hour for 60 minutes to move from one number to the the next number.[c] following are some of the activities that take about one hour to complete. (1) cooking food(2) washing clothes (3) get ready for school (4)

every hour first train will cover 80 km and second train will cover 70 km.first train leave at 10 and second train leave at 9:30.after 3.5 hrs first train will cover 280 km.after 4 hrs second train will cover 280km.that means at 13:30 both train will together and that is 280 km from delhi.

taking x= -10

Let the numbers be a and ba-b=3a^2+b^2=117(a-b)^2=a^2+b^2-2ab3^2=117-2ab2ab=117-92ab=108

(a+b)^2=a^2+b^2+2ab(a+b)^2=117+108√(a+b)^2=√225(a+b)=15A-b=32a=18A=9

Surface area of on revolution = 2∏rh= 2 x 22/ 7 x 60 x 84now for 500 revolution = 2 x 22/7 x 60 x 84 x 500=1584 m2now cost leveling 1 m2 = Rs. 0.30= for 1584 m2 = 0.30 x 1584 = Rs. 475 . 20

3V2/V2+V3-V5 = 3V2(V3+V2+V5)/{( V3+V2-V5}(V3+V2)+V3 = . 3(V6+2+V10)/(V3+V2)^2-(V3)^2= 3V6+6+3V10/3+2+2V6-5= (3V6+6+V10 )× V6/2-6x-6x= 6×3+6V6+V60/2×6= 18+6V6+V60/12

It think the question might be 9 terms instead of q terms. if it is q terms then we would not get the values of the terms in numbers.Here is the solution of the problem if the sum of 9 terms of A.P is 162.Given,

Sum of terms= 162Ratio of 6th term and 13th term= 1:2Formula is an= a₁+(n-1)d

Then the sixth term a₆= a₁+5dThe 13th term is a₁₃=a₁+12dAs given a6/a₁₃ is 1/2(a₁+5d)/(a₁+12d)=1/2

After cross multiplication2(a₁+5d)=1(a₁+12d)2a₁+10d=a1+12d2a₁-a₁=12d-10dTherefore the first term a₁=2dSn=(n/2)[2a+(n-1)d]S₉=(9/2)[2(2d)+(9-1)d]S₉=(9/2)(4d+8d)162=(9/2)(12d)162=9(6d)54d=162d=3a1=2d=2(3)=6a₁₅=6+(15-1)3=6+3(14)=48The first term of A.P is 6The 15th term of A.P is 48

9 hota to may solve nahi kar leta

In which direction? If they’re going north I wouldn’t imagine either would make it very far at all at those speeds.Maybe the guy who sets off second doesn’t WANT to overtake the guy who set off first. Maybe he’s one of those guys who drives really fast up behind you then sits on your arse waiting for you to get out of the way.What cars are they in? They’ll need to stop for petrol at some point.What’s the traffic like? Are the 2 cars able to maintain their speeds given the traffic? Would it be possible to overtake due to cars travelling in the opposite direction?What’s the speed limit? If it’s lower than 80km/h, what are the chances the 2nd driver will be pulled over by the police?Phew… variables done.Now, if it was a nice straight road with no traffic, both cars were the exact same specification and accelerated at the same rate, and neither car had to stop for petrol, the 1st car would’ve been going for 4 hours and the 2nd car for 3, but the question doesn’t specify whether the clock starts when car 1 or 2 sets off.Either way, no roads from Dehradun are suitable for this experiment

The sum of interior opposite angles is equal to the external angle.110=30+xx=80° The sum of all angles in a triangle is80+30+y=180y=70So the other two angles is 70 and 80.

Let the side of the larger square be x.Let the side of the smaller square be y.According to the question, x2 + y2 = 468 --------- (1)Perimeters of the squares = 4x and 4y.⇒ 4x - 4y = 24⇒ x– y = 6⇒ x= 6 + yx^2 + y^2 = 468Substituting the value of x in equation (1)⇒ (6+y)^2 + y^2 = 468⇒ 2y^2 + 12y + 36 = 468⇒ y^2 + 6y + 18 = 234⇒ y^2 + 6y - 216 = 0⇒ (y – 12)(y + 18) = 0⇒ y = 12 or -18Since y denotes a length, it cannot be negative.∴ y = 12⇒ x = (12 + 6) = 18 m

∴ Sides of the squares are 18 m and 12 m.

Given,Diameter = d = 84cmRadius = r = d/2 = 42cmLength = l = 120 cmT.S.A of cylinder = 2πrh = 2 x 22/7 x 42 x 120 = 31680 cm²Area levelled by 500 revolution = Area of playground= 500 x 31680cm²= 15840000 cm² [ change into m]= 1584 m²

what is the area of play ground

Given radius of roller r = 84/2= 42 cmLength of roller h = 120 cm

In one revolution roller cover area = 2*pi*r*h= 2*22/7*42*120= 2*22*6*120= 31680 cm^2= 3.1680 m^2

Area of playground= 500*3.1680= 1584 m^2

If two supplementary angles are equal:The answer is;Supplementary angle =180 degreeequal supplements = 180/2=90°

Therefore : 90 +90 (equal supplements) = add up to give a supplementary angle.

The answer is 90° each.

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