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Let the four consecutive numbers in AP be (a - 3d), (a - d), (a + d) and (a + 3d)

So, according to the question.a-3d + a - d + a + d + a + 3d = 324a = 32a = 32/4a = 8 ......(1)

Now, (a - 3d)(a + 3d)/(a - d)(a + d) = 7/1515(a² - 9d²) = 7(a² - d²)15a² - 135d² = 7a² - 7d²15a² - 7a² = 135d² - 7d²8a² = 128d²

Putting the value of a = 8 in above we get.8(8)² = 128d²128d² = 512d² = 512/128d² = 4d = 2

So, the four consecutive numbers are 8 - (3*2)8 - 6 = 28 - 2 = 68 + 2 = 108 + (3*2)8 + 6 = 14

Four consecutive numbers are 2, 6, 10 and 14

Solution:-Let the four consecutive numbers in AP be (a - 3d), (a - d), (a + d) and (a + 3d)So, according to the question.a-3d + a - d + a + d + a + 3d = 324a = 32a = 32/4a = 8 ......(1)Now, (a - 3d)(a + 3d)/(a - d)(a + d) = 7/1515(a² - 9d²) = 7(a² - d²)15a² - 135d² = 7a² - 7d²15a² - 7a² = 135d² - 7d²8a² = 128d²Putting the value of a = 8 in above we get.8(8)² = 128d²128d² = 512d² = 512/128d² = 4d = 2So, the four consecutive numbers are 8 - (3*2)8 - 6 = 28 - 2 = 68 + 2 = 108 + (3*2)8 + 6 = 14Four consecutive numbers are 2, 6, 10 and 14

3/2*x^3y^4-9/2x^2y^5+15/2x^2y^4+3/5x^3y^2-2/5xy^4+3/5x^2y^4=3/2*x^3y^4-9/2x^2y^5+81/10x^2y^4+3/5x^3y^2-2/5xy^4

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let the number of camel is x

Number of camels was seen in the forest = x/4

Number of camels had gone to the mountains = 2√x

number of camels were seems on the bank of river = 15

so, total number of camels = x/4 + 2√x + 15 = x

or, 2√x + 15 = 3x/4

or, 8√x + 60 = 3x

or, 64x = 9x² + 3600 - 360x

or, 9x² + 360x + 64x + 3600 = 0

or, 9x² + 424x + 3600 = 0

After solving with help of formula to find root of quadratic equation

We get, x = 36 and 100/9

Hence, number of camels = 36

ten's digit=xunit digit=ynumber= 10x+yaccording to the question10x+y/x+y= 7/110x+y= 7x+7y3x= 6yx= 2y

x= 4+yy= 4x= 8number 10x+y= 80+4= 84

Let the digit at tens place be x&that of ones be yy=4x......................(given)4x-y=0...................(1)by the first given condition10y+x=10x+y+549y=9x+549x-9y=-54x-y=-6.......(dividing through 9)(2)subtracting eqn (2) from (1)3x=6x=2substitute x=2 in eq n(2)y=8Number:10x+y=10(2)+(8)=20+8=28

(i) 1/5 is the base and -7 is the exponent (i) xy/z is the base and 7 is the exponent

(i) 1/5 is the base and -7 is the exponent. (ii) xy/z is the base and 7 is the exponent.

(i) 1/5 is the base and -7 is the exponent(i) xy/z is the base and 7 is the exponent

1)-7 is exponent,1\5 is the bace2)7 is the exponent,xy\z is the bace.

(1) 7.8125 × 10⁴(2) ( x+y)7/z(7)(3) 0.714286 is correct answer

(i) base=1/5exponent=7

(i) base=xy/zexponent=7

Greatest number= 9949

Smallest number= 1040

Can you give answer of c and d part

b)greatest-9949 smallest- 1040c) greatest- 9999 smallest- 1900d) greatest- 1999 smallest-1000

Movement of legs and hands because we can see it with our eye easily, similarly circular motion of fan is also visible.

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The formula for total discount in case of successive-discounts :If the first discount is x% and 2nd discount is y% then ,Total discount = ( x + y - xy / 100 ) %

Given A.P is:-45,39,33....a₁=45;d=39-45=-6Given:-Sₙ=180n=?n/2[2a₁+(n-1)d]=180=>n/2[90+(n-1)×-6]=180=>n[90-6n+6]=360=>-6n²+96n-360=0=>6n²-96n+360=0=>n²-16n+60=0=>n²-10n-6n+60=0=>n(n-10)-6(n-10)=0=>(n-10)(n-6)=0=>n=10 or 6

Maya has ballet lesson on every 6th day and swimming lesson every 4th day

In order to find day on which Maya have both lessons take LCM of 4 and 6 = 12

Therefore, Every 12th day Maya have both lessons on same day

on 12th day maya have bath lessons on the same day again

Profit = 16,756 × 18 /100 = 3016.08 = ₹ 3016 cost price = selling price - Profit = 16,756 - 3016 = ₹ 13,740

13,740 is the correct answer of the given question

13740 is the right answer to your question

Thanks

thnq

2 correct the answer

(x-2)(x-4)(x-5)(x-2)

seg AB and CD represents two poles. AB = 18 m, CD = 7 m

seg AC represent the length of the wire. AC = 22 m

□EBDC is a rectangle

∴ EB = CD = 7 m [Opposite sides of rectangle]

AB = AE + EB [∵ A - E - B]

∴ 18 = AE + 7

∴ 18 – 7 = AE

∴ AE = 11 m

In right angled ∆ AEC,

sin C = opposite side of ∠C/Hypotenuse

∴ sin C = AE/AC

∴ sin C = 11/22

∴ sin C = ½ .........(i)

But,

sin 30º = ½ ......(ii)

From equation (i) and (ii), we can conclude that

sin C = sin 30º

∴ ∠C = 30º

∴The angle made by the wire with horizontal is 30º.

1) x^3 - 2x^2 - x +2= x^2 (x-2) - 1(x-2)= (x^2 - 1)(x-2)= (x+1)(x-1)(x-2)

So your answer is No, Like take two 14 and 6 , it is asked to find Greatest number that come in both of numbers multiple, for just take 14× 6 = 84 , so 84 comes in both table of 14 and 6 also. but question is that... is it really greatest number. No .like take 14×6 × 100000000 this is also a multiple of 14 and 6 . so there are infinite possiblity. So finding Greatest common multiple is not possible.

No, its not possible to find greatest common multiple. Multiples of a number range up to infinity. So, their common multiple range upto infinity.Every number has infinity as its multiple, as you can keep on multiplying it indefinitely.For eg, the common multiple between 15 and 7 is 105. But 105*2 is also a multiple of 15 and 7 so is 105*35 and so is 105*213245 or 15* any arbitrary number.

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Percentage of money spent on football = 45/360 * 100= 12.5 %

So, 12.5 % of total money = 9000=> (1/8) * Total = 9000=> Total = 9000*8= Rs. 72000

the student MARKS list mean is 23

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The mean of the following data is 23 of upward given data

1) one inch equal to 2.54 cmThen, 40 inches equal to = 40*2.54 = 101.6 cm

2) Subtract 5 5/12 from 7 17/24185/24 - 65/12= (185 - 130)/24= 55/24= 2 7/24

35 is the right answer.......

lcm of 5&7 is 35 is the best answer

35 is the right answer to your question