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80751.

A square and an isosceles triangle have the same perimeter. The base of the isosceles triangle is12 cm and each side of the square is 5 cm shorter than each of the equal sides of the isoscelestriangle. Find the perimeter of the square.29.

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80752.

Ifis a root of the equation x2+ kx-0, then find the value of k.5243. In an AP, if the common difforu

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80753.

average45. A car takes 12y hours to cover a distance of (6x x 10y) km. What is thespeed of the car?

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80754.

. Sound travels al 315. Chennai Express takes 21 hrs and 48 min in reaching Warangal from New Delhi at an vengespeed of 72 km/hr. How far is Warangal from New Delhi?nart in 1 hr 20 min. If it travels for

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80755.

A and B travel the same distance at the speeds of 10 kmph and 15 kmph respectively. If A takes 30 minuteslonger than B then distance travelled is1.(A) 15 km(B) 20 km(C) 90 km(D) 30 km

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80756.

7.A takes 3 hours more than B to walk a distance of 30 km. But, if A doubles his pace he is ahead of B by2hrs. Find their speeds of walking.

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80757.

t2200 to paint the inner curved surface of a cylindrical vessel 10the cost of painting is at the rate of t 20 per m2, find€2200 to paint the inner curved surface of a cylindrical vessel 10inner curved surface area of the vessel,0)(i) radius of the base,(i) capacity of the vessel.

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80758.

sidals he was o yeatrs ag.now ord s nann todayA bag contains 25-paisa and 50-paisa coins whose total value is 30. If the number of25-paisa coins is four times that of 50-paisa coins, find the number of each type of coins.

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80759.

. A metal pipe is 77 em long. The inner diameterofacrosssection is 4 cm. the outer diameter being 4.4 cm(see Fig. 13.11). Find its(i) inner curved surfacc arca.(i) outer curved surface area.(iii) total surface area.Fig, 13ll

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80760.

7, The inner diameter of a circular well is 4.2 m.It is 12 m deep. Find () its inner curved surface areathe cost of plastering the inner curved surface at the rate of R 50 per m

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Given height h = 12m.Given the diameter of the circular well d = 4.2 meter.Then the radius of the circular well r = d/2 = 4.2/2 = 2.1m.

(1) Inner curved surface Area = 2πrh = 2 * 22/7 * (2.1) * 12 = 2 * 22 * 0.3 * 12 = 158.4m^2.

(2) Given that cost of plastering per m^2 = 50. Then the cost of plastering of 158.4m^2 area = 158.4 * 50 = 7920.

80761.

Find the value of p so that the quadratic equation px(er 3)+ 9-0 has twoequal roots.

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80762.

Find the value of p so that the quadratic equation px(r-3)+9 0 has twoequal roots.

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px^2-3px+9=0

a=p , b=-3p , c=9

b^2-4ac= (-3p)^2-4(p)(9)

=9p^2-36p

having equal roots

b^2-4ac = 9p^2-36p = 0

9p^2-36p = 0

9p(p-4) = 0

9p=0 (or) p-4=0

since, p=4

80763.

(3) Write the quadratic equation for which α+ β=-4 and αβ--3.(B) 2+x3and Xp=(A) x2 +4x-3-0(C) x2-4x-3-0(D) x2-3x + 4 = 0

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80764.

X-- 6x +3=0.2. 13x2 + 2x -- 873 = 0.3. x2 – 3x - 10 = 0.4. x2 + x -20 = 0.5. x2 - 9x +18=0.6. 4x2 – 2x + = = 0.7.- 213x2 - 14x+4+3 = 0.8. y2 - (p+q)y + pq = 0.9. 2x2 + x - 6= 0.10. x-3-1x211. 3x2 + 7x+5V2 = 0.12. 2x2 + ax -- a2 = 0, (FET a arkeaan =13. 413x2 + 2x - 2/3=0.

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x^2+x-20=0; x^2+5x-4x-20 =0; x( x+5)-4( x+5)=0; ( x-4)( x+5)=0; x = 4 & -5

3)x^2-3x-10=0x^2-5x+2x-10=0x(x-5)+3(x-5)=0(x-5)(x+3)=0either x-5=0, x=5or x+3=0, x= -3

80765.

6. Without using the Pythagoras theorem, show that the points (4,4),0,9(-1,-1) are the vertices of a right angled triangle.

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80766.

8 Prove that angles opposite to equal sides of an isosceles triangle are equal.

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80767.

(1)x2 + 10x6-0(4)x2-3/6x + 12 = 0

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80768.

4.'ajThe equations x2 - 2x + 1 = 0, x2 - 3x + 2 = 0 have a common root then thatcommon root is

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80769.

10. A car takes 2 hours to reach a destination by travelling at 60 km/hr. How long will it takewhile travelling at 80 km/hr?(a) 1 hr 30 min (b) 1 hr 40 min(c) 2 hrs 40 min(d) none of these

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ans 1 hr 30 minute aaya h book m sir

80770.

A man is running along the side of a square at a speed of 8 m/s. If he takes 1 min 30 s tocbver the perimeter once, find the area of the square

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thanks

80771.

ohi travels 300 km to her home partly by train and partly by bus. She takes 4hours if she travels 60 km by train and the remaining by bus. If she travels 100 kmby train and the remaining by bus, she takes 10 minutes longer. Find the speed ofthe train and the bus separately.

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80772.

It takes 7 men 2 hours to build awall. How long does it take 3men to build the same wall?

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please explain

7 men can take 2 hoursso 1 men 2/7 hours

3 men takes 6/7 hours

80773.

19. A bag contains 25-paisa and 50-paisa coins whose total value is30. If the nunaisa cotns is four times that of 50-paisa coins, find the number of each type

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80774.

ofbag contains 25-paisa and 50-paisa coins whose total value is 30. If the number25-paisa coins is four times that of 50-paisa coins nd the number of each type of coins.9Aice Find the price of

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80775.

from a metal sheel.110WA metal pipe is 77 cm long. The inner diameter of a crosssection is 4 cm, the outer diameter being 4.4 cm(see Fig. 13.11). Find its1) inner curved surface area(i) outer curved surface area,(ii) total surface area.

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80776.

& A metal pipe is 77 cm long, the inner diamcter of the cross-section is 4 cm and the outer diamcter is4.8 cm. Find the (i) inner curved surface arca (ii) outer curved surface area i) total surface area

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Here, h = 77 cm,

Outer radius (R) = 4. 4/ 2cm = 2.2 cm,

Inner radius (r) = 4/ 2 cm = 2 cm

(i) Inner curved surface area of the pipe

= 2πrh

= 2 × 22/ 7 × 2 × 77 cm2

= 2 × 22 × 22 cm2=968 cm2Ans.

(ii) Outer curved surface area of the pipe = 2πRh

= 2 × 22/ 7 × 2.2 × 77 cm2= 44 × 24.2 cm2

= 1064.80 cm2Ans.

(iii) Total surface area of the pipe = inner curved surface area + outer

curved surface area + areas of the two base rings.

= 2πrh + 2πRh + 2π (R2– r2)

= 968 cm2+ 1064.80 cm2+ 2 × 22/ 7 [(2.2)2– 22] cm2

= 2032.80 cm2+ 5.28 cm2=2038.08 cm2Ans

80777.

romm Ă hietal SIOOLA metal pipe is 77 cm long. The inner diameter of a crosssection is 4 cm, the outer diameter being 4.4 cm(see Fig. 13.11). Find its inner curved surface area,() outer curved surface area,3.total surface area.

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80778.

from a metal sheet.no0 momA metal pipe is 77 cm long. The inner diameter of a crosssection is 4 cm, the outer diameter being 4.4 cm(see Fig. 13.11). Find its(1) inner curved surface area,(ii) outer curved surface area,(ii) total surface area.20817

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80779.

7. Find the value ofp so that the quadratic equation pr(x-3) + 9 = 0 has two equal roots.8. Find the HCF and LCM of 120 and 144 by Fundamental Theorem of Arithmetic.

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80780.

Using Theorem 6.1, prove that a line drawn throughthe mid-point of one side of a triangle parallel toanother side bisects the third side. (Recall that youhave proved it in Class IX)7.

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80781.

ORProve that angles opposite to equal sides of an isosceles triangequal

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80782.

= 2x2 × (5-9x + 7x2) = 2x2 (7x2-9x + 5)TRY THESEDo yformFactorise:(i)12x+36(ii) 22y-33z(iii) 14pq +35pqr:

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i) 12(x+3)ii) 11(2y-3z)iii) 7pq(2+5r)

80783.

ind the area of a rhombus one side of which measures 20 cm and one of whose diagonal is24 cm.

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80784.

Find the area of a rhombus each side of which measures 20 cm and one of whose diagonis 24 cm12.

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80785.

QWhat will be the interest earned on Rs 990in 5 years 16% simple interest perannum?(A) 891(C) 796Q47(B)(D)829792

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Interest = 990*5*16/100

= 7920/10

= 792

80786.

Exercise - 21. A man takes 5 hours 45 min. in walking to a cer-tain place and riding back. He would have gained2 hours by riding both ways. The time he wouldtake to walk both ways is:A. 11 hrs 45 minB. 3 hrs 45 minC. 7 hrs 30 minD. 7 hrs 45 min

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Distance travelled by man is not mentioned in the question, so let us take distance as x metre in order to avoid confusion.

Time taken to walk x km + Time taken to ride x km = 5 hour 45 min { According to the question - ''A man takes 5 hours 45 min. in walking to a certain place and riding back''}

⇒=545\60hour =5 3\4hour =23 \ 4hour .......{ Let us take this as equation no .1}

⇒Then ,

Time taken to ride {2× xkm] = 5 h 45 m - 2 = 3 h 45 m [ Because in the question it has been written that ''He would have gained 2 hours by riding both ways'' . so we subtract it from total time taken].

=345 \60hour =3 3\4hour =1 5\4hour..{ Let us take this as Equation 2 }

⇒By solving equation 1 and 2 we get as -{Equation 1×Equation 2}

⇒Time taken to walk 2x km+ Time taken to ride 2x km =

⇒ 23 \ 2 hrs ..[Let us take this as equation 3 }

⇒Subtract equation 3 from equation 2 -

So we get as ⇒ 23 \ 2 - 15 \ 2 = 31 \4 hrs

So we get as 7 3 \ 4 ..

⇒So the answer is 7 hrs 45 min

80787.

I He distance between two cities is 380 km. A train takes 6 hours 40 minutes to cover the distthe speed of the train

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no matching

80788.

4. A car travelling at a speed of 72 km/h takes 7 hours to complete a journey. If the car can tae30 kmih, how long would t take to complete the same journey?(a) 8 hours(b) 9 hours(c) 6 hours(d) 5 hours2

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80789.

From a group of 2 boys and 3 girls, two childrenare selected at random. Then the probability, suchthat at least one boy is selected, is:

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Probability of selecting atleast one boy= no of boys/ no of children=2/5

80790.

12 A bag contains 25-paisa and 50-pais coins whose total value is t 30. If the number of 25-paisa coin atstimes that of 50-paisa coins, find the number of each type of coins

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80791.

18. The adjoining figure shows a metal pipe 77 cm longThe inner diameter of cross section is 4 cm and theouter one is 4.4 cm.Find its(i) inner curved surface area(ii) outer curved surface area(ii) total surface area.

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Givenheight=77cminner radius=4/2=2cmouter radius=4.4/2=2.2cmTo find..I) inner curved surface area..C.S.A = 2πrh2×22/7×2×77968cm²ii)outer curved surface area..C.S.A = 2πrh2×22/7×22/10×771064.8cm²iii) total surface area...2πrh+2πRh+2π(r²-R²)968+1064.8+2×22/7(2²-2.2²)2032.8+2×22/7×2/10×42/102032.8+5.282038.08cm²...

80792.

3.A metal pipe is 77 cm long. The inner diameter of a crosssection is 4 cm, the outer diameter being 4.4 cnm(see Fig. 13.11). Find its(j) inner curved surface area.(ii) outer curved surface area,(ii) total surface area.Fig,

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80793.

22, Prove that: The angles opposite to equal sides are equal

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80794.

Angles opposite to equal sides of an isosceles triangle are equal

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80795.

Prove that the angles opposite to equal sides of a triangle are equal.

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thank you😊☺️

80796.

other dlagonaFind the area of a rhombus,each side of which measures 20 cm and one of whose diagonals iscm249HISTORY-8 69

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thanx

80797.

Simplify (81)14- 8 (216)131/3

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please like my answer if you find it useful

80798.

Simplify:0 28-796 13-42 2-555

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=28.796 - 13.42 =15.376=15.376-2.555=(12.821) Ans...

28.796-13.42-2.55515.376-2.55512.821

80799.

id miiutĂŠs to m4 hours 15 minutes8 hours 18 minutes-

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1 4hr and 15 minutes 2 8hr and 18 minutes

80800.

3x+5x+9x=7+9

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3x+5x+9x=7+9=8x+9x=16=17x=16x=16/17

3x+5x+9x=7+917x=16x=16/17